332354 + Interview Questions in Secondary School in Math

1.	The difference of place values of 3 in the number 34032 is
Answer» 30000 - 30 =29970 Step-by-step explanation: i HOPE the ANSWER HELPS you

1.

The difference of place values of 3 in the number 34032 is

Answer»

30000 - 30 =29970

Step-by-step explanation:

i HOPE the ANSWER HELPS you

Discussion

2.	How to find class interval if class mark are given
Answer» ANSWER: Class MARK Step-by-step EXPLANATION: Class mark = upper limit - lower limit of given no. /2

2.

How to find class interval if class mark are given

Answer»

ANSWER:

Class MARK

Step-by-step EXPLANATION:

Class mark = upper limit - lower limit of given no. /2

Discussion

3.	In a class of 60 students the number of girls is one third the number of boys.find the number of girls and boys in this class
Answer» Answer: let NUMBER of boys be x then number of girls = 1/3X total students = 60 so, x + 1/3x = 60 4/3x = 60 4x = 60 × 3 x = 180/4 x = 45 therefore boys = 45 girls = 1/3 ×45 = 15

3.

In a class of 60 students the number of girls is one third the number of boys.find the number of girls and boys in this class

Answer»

Answer:

let NUMBER of boys be x

then number of girls = 1/3X

total students = 60

so,

x + 1/3x = 60

4/3x = 60

4x = 60 × 3

x = 180/4

x = 45

therefore

boys = 45

girls = 1/3 ×45 = 15

Discussion

4.	If n is 2 then what will be the answer of this sum2n
Answer» ACCORDING to you n=2 then 2N = 2×2 2n = 4

4.

If n is 2 then what will be the answer of this sum2n

Answer»

ACCORDING to you n=2

then 2N = 2×2

2n = 4

Discussion

5.	The length of a rectangle is 3 times its width and the length of its diagonal is 6√10 cm. Find its perimeter of the rectangle is
Answer» if you are having PROBLEM in solving these questions SIMPLY SEARCH it in Google NCERT for any book SOLUTIONS

5.

The length of a rectangle is 3 times its width and the length of its diagonal is 6√10 cm. Find its perimeter of the rectangle is

Answer»

if you are having PROBLEM in solving these questions SIMPLY SEARCH it in Google NCERT for any book SOLUTIONS

Discussion

6.	Find the zero of polynomial (2x^2+5x-3)
Answer» Step-by-step explanation: 2x²+5x-3 By MIDDLE Term Split, we WANT to get the suitable factor of 6. So the suitable factor of 6 are 6 and 1 to MATCH the equation. So, placing them as 2x²+6x-1x-3 Taking 2x common in the first and -1 in second 2x(x+3)-1(x+3) (2x-1)(x+3) 2x-1=0 2x=1 x=1/2 x+3=0 x= -3 So 1/2 and -3 are the zeroes of the polynomial.

6.

Find the zero of polynomial (2x^2+5x-3)

Answer»

Step-by-step explanation:

2x²+5x-3

By MIDDLE Term Split, we WANT to get the suitable factor of 6.

So the suitable factor of 6 are 6 and 1 to MATCH the equation.

So, placing them as

2x²+6x-1x-3

Taking 2x common in the first and -1 in second

2x(x+3)-1(x+3)

(2x-1)(x+3)

2x-1=0

2x=1

x=1/2

x+3=0

x= -3

So 1/2 and -3 are the zeroes of the polynomial.

Discussion

7.	-3/11 8/11 beffrence ten rational number
Answer» Step-by-step EXPLANATION: PLZ MARK as the BRAINEST plz. PLS

7.

-3/11 8/11 beffrence ten rational number

Answer»

Step-by-step EXPLANATION:

PLZ MARK as the BRAINEST plz. PLS

Discussion

8.	The diagonal of squar is 12√2 cm.find it's perimeter
Answer» hey mate here is UR ANSWER = DIAGONAL =root 2×side 12root2=root2×side side=12. perimeter=4s=12×4=48cm. hope it HELPS. ☆☆☆

8.

The diagonal of squar is 12√2 cm.find it's perimeter

Answer»

hey mate here is UR ANSWER =

DIAGONAL =root 2×side

12root2=root2×side

side=12.

perimeter=4s=12×4=48cm.

hope it HELPS.

☆☆☆

Discussion

9.	Are the following in proportion 2,4,3,6
Answer» ANSWER: Yes Step-by-step explanation: To FIND proportion we do PRODUCT of mean(b×c)=Product of extreme (a×d) 4×3=6×2 12=12 SINCE, LHS =RHS Hence they are in proportion

9.

Are the following in proportion 2,4,3,6

Answer»

ANSWER:

Yes

Step-by-step explanation:

To FIND proportion we do

PRODUCT of mean(b×c)=Product of extreme (a×d)

4×3=6×2

12=12

SINCE, LHS =RHS

Hence they are in proportion

Discussion

10.	An integer who's sum is -7 and difference in -10
Answer» Answer: -5,-2 is a integer WHOSE sum is -7 20,30 is. INTEGERS whose difference is -10. 20-30=-10

10.

An integer who's sum is -7 and difference in -10

Answer»

Answer:

-5,-2 is a integer WHOSE sum is -7

20,30 is. INTEGERS whose difference is -10.

20-30=-10

Discussion

11.	Find the surface area of sphere of diameter 14 cm, 21cm, 3.5m
Answer» Answer: 1) 176 sq.cm 2) 264 sq.cm 3) 44 sq.m Step-by-step explanation: 1) radius =14 cm surface area of SPHERE = 4πr square 4 × 22/7 × 14 = 176 sq.cm 2) radius= 21 cm surface area of sphere = 4 × 22/7 × 21 = 264 sq.cm 3) radius = 3.5 m surface area of sphere = 4 × 22/7 × 3.5 = 44sq.m

11.

Find the surface area of sphere of diameter 14 cm, 21cm, 3.5m

Answer»

Answer:

1) 176 sq.cm

2) 264 sq.cm

3) 44 sq.m

Step-by-step explanation:

1) radius =14 cm

surface area of SPHERE = 4πr square

4 × 22/7 × 14

= 176 sq.cm

2) radius= 21 cm

surface area of sphere = 4 × 22/7 × 21

= 264 sq.cm

3) radius = 3.5 m

surface area of sphere = 4 × 22/7 × 3.5

= 44sq.m

Discussion

12.	___= 54* * ___= 120 * __*_= 56= = = 96 180 21Plz whole solution
Answer» The question is shown below: $\quad$ $\begin{array}{ccccccc}\boxed{}&\times &\boxed{}&\times&\boxed{}&=&54\\ \times &&\times &&\times&&\\ \boxed{}&\times &\boxed{}&\times&\boxed{}&=&120\\ \times &&\times &&\times&&\\ \boxed{}&\times &\boxed{}&\times&\boxed{}&=&56\\ =&&=&&=&&\\ 96&&180&&21&&\end{array}$ We have to fill those boxes with digits 1 to 9 without repeating any. Solution: $\quad$ $\begin{array}{ccccccc}\boxed{6}&\times &\boxed{9}&\times&\boxed{1}&=&54\\ \times &&\times &&\times&&\\ \boxed{<klux>8</klux>}&\times &\boxed{5}&\times&\boxed{<klux>3</klux>}&=&120\\ \times &&\times &&\times&&\\ \boxed{2}&\times &\boxed{4}&\times&\boxed{7}&=&56\\ =&&=&&=&&\\ 96&&180&&21&&\end{array}$ Explanation: Along the rows: 6 × 9 × 1 = 54 8 × 5 × 3 = 120 2 × 4 × 7 = 56 Along the columns: 6 × 8 × 2 = 96 9 × 5 × 4 = 180 1 × 3 × 7 = 21 Read more on Brainly.in $\quad$ Put all following numbers 1 to 9 so as to no NUMBER should be left and no ONE should be repeated. brainly.in/question/16742693

12.

___= 54* * ___= 120 * __*_= 56= = = 96 180 21Plz whole solution

Answer»

The question is shown below:

$\quad$ $\begin{array}{ccccccc}\boxed{}&\times &\boxed{}&\times&\boxed{}&=&54\\ \times &&\times &&\times&&\\ \boxed{}&\times &\boxed{}&\times&\boxed{}&=&120\\ \times &&\times &&\times&&\\ \boxed{}&\times &\boxed{}&\times&\boxed{}&=&56\\ =&&=&&=&&\\ 96&&180&&21&&\end{array}$

We have to fill those boxes with digits 1 to 9 without repeating any.

Solution:

$\quad$ $\begin{array}{ccccccc}\boxed{6}&\times &\boxed{9}&\times&\boxed{1}&=&54\\ \times &&\times &&\times&&\\ \boxed{<klux>8</klux>}&\times &\boxed{5}&\times&\boxed{<klux>3</klux>}&=&120\\ \times &&\times &&\times&&\\ \boxed{2}&\times &\boxed{4}&\times&\boxed{7}&=&56\\ =&&=&&=&&\\ 96&&180&&21&&\end{array}$

Explanation:

Along the rows:

6 × 9 × 1 = 54
8 × 5 × 3 = 120
2 × 4 × 7 = 56

Along the columns:

6 × 8 × 2 = 96
9 × 5 × 4 = 180
1 × 3 × 7 = 21

Read more on Brainly.in

$\quad$ Put all following numbers 1 to 9 so as to no NUMBER should be left and no ONE should be repeated.

brainly.in/question/16742693

Discussion

13.	OPQ is the sector of a circle who's canter is O , radius x cm and angle POQ is 80°. Given that the area of a sector OPQ is 308 cm^ , calculate the value of x (22/7)
Answer» ANSWER: AREA of SECTOR = 308 80/360×πrsquare =308 cancel at least possible calculation then rsquare /63=7 rsquare =441 RADIUS =+or -21 but radius is always positive

13.

OPQ is the sector of a circle who's canter is O , radius x cm and angle POQ is 80°. Given that the area of a sector OPQ is 308 cm^ , calculate the value of x (22/7)

Answer»

ANSWER:

AREA of SECTOR = 308

80/360×πrsquare =308

cancel at least possible calculation

then rsquare /63=7

rsquare =441

RADIUS =+or -21

but radius is always positive

Discussion

14.	If the price of 6 books and 7pens is 79rs. and 7 books 5pens is 77rs. then find the cost of 1book and 2pen.
Answer» Answer: 6 books+7pens=79 7books+5pens=77 let BOOK and DETERMINE be X and y so,6x+7y/7x+5y=79/77 77(6x+7y)=79(7x+5y) 462x+539y=553x+395y 539y-395y=553x-462x 144y=91x y=91x/144

14.

If the price of 6 books and 7pens is 79rs. and 7 books 5pens is 77rs. then find the cost of 1book and 2pen.

Answer»

Answer:

6 books+7pens=79

7books+5pens=77

let BOOK and DETERMINE be X and y

so,6x+7y/7x+5y=79/77

77(6x+7y)=79(7x+5y)

462x+539y=553x+395y

539y-395y=553x-462x

144y=91x

y=91x/144

Discussion

15.	Aman says that he has 7 oranges more than five times the oranges parmeet has . aman has 37 oranges
Answer» Step-by-step explanation: 7+5(X)=37 5x=37-5 5x=32 x=32/5 x=6.5

15.

Aman says that he has 7 oranges more than five times the oranges parmeet has . aman has 37 oranges

Answer»

Step-by-step explanation:

7+5(X)=37

5x=37-5

5x=32

x=32/5

x=6.5

Discussion

16.	From a piece of 26 1/4 m long cloth, how many trousers can be stitched if 1 trouser requires 1 5/4 m of cloth
Answer» Answer: 11 TROUSERS can be stitched Step-by-step EXPLANATION:

16.

From a piece of 26 1/4 m long cloth, how many trousers can be stitched if 1 trouser requires 1 5/4 m of cloth

Answer»

Answer:

11 TROUSERS can be stitched

Step-by-step EXPLANATION:

Discussion

17.	How to find simple interest
Answer» <P>Answer: Use this simple interest calculator to find A, the FINAL Investment Value, using the simple interest formula: A = P(1 + rt) where P is the Principal AMOUNT of money to be invested at an Interest Rate R% per period for t Number of Time PERIODS. Where r is in decimal form; r=R/100; r and t are in the same units of time. I HOPE THIS MAY HELP U.. #gundi.. follow me mark as brainlist..✌✌

17.

How to find simple interest

Answer»

<P>Answer:

Use this simple interest calculator to find A, the FINAL Investment Value, using the simple interest formula: A = P(1 + rt) where P is the Principal AMOUNT of money to be invested at an Interest Rate R% per period for t Number of Time PERIODS. Where r is in decimal form; r=R/100; r and t are in the same units of time.

I HOPE THIS MAY HELP U..

#gundi..

follow me

mark as brainlist..✌✌

Discussion

18.	Please help me plz plz plz plz please
Answer» ANSWER: hmmmm SOOO DIFFICULT for me to do

18.

Please help me plz plz plz plz please

Answer»

ANSWER:

hmmmm SOOO DIFFICULT for me to do

Discussion

19.	X square + 9 X + 18 solution
Answer» ANSWER: x²+9x+18 x²+(6+3)x+18 x²+6x+3x+18 x(x+6)+3(x+6) (x+6)(x+3) ANS

19.

X square + 9 X + 18 solution

Answer»

ANSWER:

x²+9x+18

x²+(6+3)x+18

x²+6x+3x+18

x(x+6)+3(x+6)

(x+6)(x+3) ANS

Discussion

20.	a fraction becomes 9/11 if 2 is added to bith numerator and denominator . if 3 is added to both numerator and denominator it becomes 5/6 find the fraction
Answer» Given : A fraction BECOMES 9/11 if 2 is ADDED to both numerator and denominator. If 3 is added to numerator and denominator both fraction becomes 5/6. To Find : The fraction. Solution : Let the numerator of the fraction be x. Let the denominator of the fraction be y. Fraction = $\bold{\dfrac{x}{y}}$ Case 1 : When 2 is added to the numerator and denominator of the fraction, it becomes 9/11. Numerator = (x+2) Denominator = (y+2) EQUATION : $\implies$ $\sf{\dfrac{x+2}{y+2}\:=\:\dfrac{9}{11}}$ $\implies$ $\sf{11(x+2)=9(y+2)}$ $\implies$ $\sf{11x+22=9y+18}$ $\implies$ $\sf{11x-9y=18-22}$ $\implies$ $\sf{11x-9y=-4}$ $\implies$ $\sf{11x=-4+9y}$ $\large{\sf{x=\dfrac{-4+9y}{11}\:\:\:(1)}}$ Case 2 : If 3 is added to the numerator and denominator, the fraction becomes 5/6. Numerator = (x+3) Denominator = (y+3) Equation : $\implies$ $\sf{\dfrac{x+3}{y+3}\:=\:\dfrac{5}{6}}$ $\implies$ $\sf{6(x+3)=5(y+3)}$ $\implies$ $\sf{6x+18=5y+15}$ $\implies$ $\sf{6x-5y=15-18}$ $\implies$ $\sf{6x-5y=-3}$ $\implies$ $\sf{6\:\Big(\dfrac{-4+9y}{11}\Big)-5y=-3}$ $\bold{\Big[From\:equation\:(1)\:x\:=\:\dfrac{-4+9y}{11}\Big]}$ $\implies$ $\sf{\dfrac{-24+54y}{11}-5y\:=\:-3}$ $\implies$ $\sf{\dfrac{-24+54y-55y}{11}\:=\:-3}$ $\implies$ $\sf{-24+54y-55y=11\:\times\:-3}$ $\implies$ $\sf{-24+54y-55y=-33}$ $\implies$ $\sf{54y-55y=-33+24}$ $\implies$ $\sf{-y=-9}$ $\implies$ $\sf{y=9}$ SUBSTITUTE, y = 9 in equation (1), $\implies$ $\sf{x=\dfrac{-4+9y}{11}}$ $\implies$ $\sf{x=\dfrac{-4+9(9)}{11}}$ $\implies$ $\sf{x=\dfrac{-4+81}{11}}$ $\implies$ $\sf{x=\dfrac{77}{11}}$ $\implies$ $\sf{x=7}$ $\large{\boxed{\bold{Numerator\:of\:the\:fraction\:=\:x\:=\:7}}}$ $\large{\boxed{\bold{Denominator\:of\:the\:fraction\:=\:y\:=\:9}}}$ $\large{\boxed{\bold{\red{Fraction\:=\:\dfrac{x}{y}\:=\:\dfrac{7}{9}}}}}$

20.

a fraction becomes 9/11 if 2 is added to bith numerator and denominator . if 3 is added to both numerator and denominator it becomes 5/6 find the fraction

Answer»

Given :

A fraction BECOMES 9/11 if 2 is ADDED to both numerator and denominator.
If 3 is added to numerator and denominator both fraction becomes 5/6.

To Find :

The fraction.

Solution :

Let the numerator of the fraction be x.

Let the denominator of the fraction be y.

Fraction = $\bold{\dfrac{x}{y}}$

Case 1 :

When 2 is added to the numerator and denominator of the fraction, it becomes 9/11.

Numerator = (x+2)

Denominator = (y+2)

EQUATION :

$\implies$ $\sf{\dfrac{x+2}{y+2}\:=\:\dfrac{9}{11}}$

$\implies$ $\sf{11(x+2)=9(y+2)}$

$\implies$ $\sf{11x+22=9y+18}$

$\implies$ $\sf{11x-9y=18-22}$

$\implies$ $\sf{11x-9y=-4}$

$\implies$ $\sf{11x=-4+9y}$

$\large{\sf{x=\dfrac{-4+9y}{11}\:\:\:(1)}}$

Case 2 :

If 3 is added to the numerator and denominator, the fraction becomes 5/6.

Numerator = (x+3)

Denominator = (y+3)

Equation :

$\implies$ $\sf{\dfrac{x+3}{y+3}\:=\:\dfrac{5}{6}}$

$\implies$ $\sf{6(x+3)=5(y+3)}$

$\implies$ $\sf{6x+18=5y+15}$

$\implies$ $\sf{6x-5y=15-18}$

$\implies$ $\sf{6x-5y=-3}$

$\implies$ $\sf{6\:\Big(\dfrac{-4+9y}{11}\Big)-5y=-3}$ $\bold{\Big[From\:equation\:(1)\:x\:=\:\dfrac{-4+9y}{11}\Big]}$

$\implies$ $\sf{\dfrac{-24+54y}{11}-5y\:=\:-3}$

$\implies$ $\sf{\dfrac{-24+54y-55y}{11}\:=\:-3}$

$\implies$ $\sf{-24+54y-55y=11\:\times\:-3}$

$\implies$ $\sf{-24+54y-55y=-33}$

$\implies$ $\sf{54y-55y=-33+24}$

$\implies$ $\sf{-y=-9}$

$\implies$ $\sf{y=9}$

SUBSTITUTE, y = 9 in equation (1),

$\implies$ $\sf{x=\dfrac{-4+9y}{11}}$

$\implies$ $\sf{x=\dfrac{-4+9(9)}{11}}$

$\implies$ $\sf{x=\dfrac{-4+81}{11}}$

$\implies$ $\sf{x=\dfrac{77}{11}}$

$\implies$ $\sf{x=7}$

$\large{\boxed{\bold{Numerator\:of\:the\:fraction\:=\:x\:=\:7}}}$

$\large{\boxed{\bold{Denominator\:of\:the\:fraction\:=\:y\:=\:9}}}$

$\large{\boxed{\bold{\red{Fraction\:=\:\dfrac{x}{y}\:=\:\dfrac{7}{9}}}}}$

Discussion

21.	What is the value of tan90
Answer» Step-by-step EXPLANATION: HEY mate your ANSWER is value of tan90 is not defined . Hope it helps . Please mark as brainlest .

21.

What is the value of tan90

Answer»

Step-by-step EXPLANATION:

HEY mate your ANSWER is

value of tan90 is not defined .

Hope it helps .

Please mark as brainlest .

Discussion

22.	Factorise √3 x^2 + 10 x + 7 √ 3
Answer» ANSWER: (√3x + 7)(x + √3) Step-by-step explanation: √3x² + 10X + 7√3 = √3x² + 7x + 3x + 7√3 = x(√3x + 7) + √3(√3x + 7) =(√3x + 7)(x + √3)

22.

Factorise √3 x^2 + 10 x + 7 √ 3

Answer»

ANSWER:

(√3x + 7)(x + √3)

Step-by-step explanation:

√3x² + 10X + 7√3

= √3x² + 7x + 3x + 7√3

= x(√3x + 7) + √3(√3x + 7)

=(√3x + 7)(x + √3)

Discussion

23.	Q.24 0, 2, 8, 18, ?, 48(a) 20(c) 32(b) 23(d) 25
Answer» ANSWER: b)23 Step-by-step EXPLANATION: hope it HELPS U .............

23.

Q.24 0, 2, 8, 18, ?, 48(a) 20(c) 32(b) 23(d) 25

Answer»

ANSWER:

b)23

Step-by-step EXPLANATION:

hope it HELPS U .............

Discussion

24.	Cross multiplication 1. 2x+3y = 8 and 7x+2y=53
Answer» Step-by-step EXPLANATION: SEE the ANSWERS below thanks

24.

Cross multiplication 1. 2x+3y = 8 and 7x+2y=53

Answer»

Step-by-step EXPLANATION:

SEE the ANSWERS below

thanks

Discussion

25.	What is the smallest number that should be multiplied to 38044 to get a perfect cube
Answer» steps: 1. solve the SQUARE ROOT of 38044 2. WHATEVER no. is left out.. 3. It is your answer MARK IT AS BRAINLIEST N FOLLOW ME....

25.

What is the smallest number that should be multiplied to 38044 to get a perfect cube

Answer»

steps:

1. solve the SQUARE ROOT of 38044

2. WHATEVER no. is left out..

3. It is your answer

MARK IT AS BRAINLIEST N FOLLOW ME....

Discussion

26.	1. Find a quadratic polynomial whose zeroes are -3 and 4.
Answer» hey MATE here is ur ANSWER = sum of roots=-3+4=1 product of roots=(-3)(4)=-12. quadratic EQUATION =x^2-(sum of roots)x+(product of roots) =x^2-1x-12 =x²-x-12 hope it helps. ☆☆☆

26.

1. Find a quadratic polynomial whose zeroes are -3 and 4.

Answer»

hey MATE here is ur ANSWER =

sum of roots=-3+4=1

product of roots=(-3)(4)=-12.

quadratic EQUATION =x^2-(sum of roots)x+(product of roots)

=x^2-1x-12

=x²-x-12

hope it helps.

☆☆☆

Discussion

27.	Write standard form of minus 399 over 603 it is urgent
Answer» Step-by-step EXPLANATION: $Standard \: form \: of \: \frac{-399}{603} \\ \bold{HCF} \: of \: (399 \: and \: 603) = 3 \\ \frac{-399}{603} = \frac{-399 \div 3}{609 \div 3} = \frac{-133}{201} \\ \\ \\ \boxed{\boxed{\bold\blue{Standard \: form \: of \: \frac{-399}{603} is \: \frac{-133}{201}}}}$

27.

Write standard form of minus 399 over 603 it is urgent

Answer»

Step-by-step EXPLANATION:

$Standard \: form \: of \: \frac{-399}{603} \\ \bold{HCF} \: of \: (399 \: and \: 603) = 3 \\ \frac{-399}{603} = \frac{-399 \div 3}{609 \div 3} = \frac{-133}{201} \\ \\ \\ \boxed{\boxed{\bold\blue{Standard \: form \: of \: \frac{-399}{603} is \: \frac{-133}{201}}}}$

Discussion

28.	Synonym of dukh ...☺☺
Answer» ANSWER: Hey mate here is your answer.... UDAS Hope it HELPS you....

28.

Synonym of dukh ...☺☺

Answer»

ANSWER:

Hey mate here is your answer....

UDAS

Hope it HELPS you....

Discussion

29.	If 5 sec theta-12 =0 find the values of sec theta cos theta sin theta
Answer» HEY mate here is ur ANSWER = 5SEC THETA=12 sec theta=12/5 cos theta=1/sec theta cos theta=5/12 sin theta=root(1-cos^2 theta) sin theta=root (1-25/144) sin theta=root(119/144) sin theta=root(119)/12. hope it helps. ☆☆☆

29.

If 5 sec theta-12 =0 find the values of sec theta cos theta sin theta

Answer»

HEY mate here is ur ANSWER =

5SEC THETA=12

sec theta=12/5

cos theta=1/sec theta

cos theta=5/12

sin theta=root(1-cos^2 theta)

sin theta=root (1-25/144)

sin theta=root(119/144)

sin theta=root(119)/12.

hope it helps.

☆☆☆

Discussion

30.	Find the factor of 420
Answer» Step-by-step EXPLANATION: The FACTORS of 420. 1,2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210,420

30.

Find the factor of 420

Answer»

Step-by-step EXPLANATION:

The FACTORS of 420. 1,2,3,4,5,6,7,10,12,14,15,20,21,28,30,35,42,60,70,84,105,140,210,420

Discussion

31.	Statement (A): The point of intersection of the two lines is called origin, denoted by O'.Statement (B) : The plane which is divided by X and Y - axis is called co-ordinate plane (or)cartesian plane.a) Both A and B are trueb) Both A and B are falsec) A is true and B is falsed) A is false and B is true
Answer» Step-by-step EXPLANATION: the both OPTIONS is TRUE ( or ) CORRECT the option is ( a ) so no explanation to the answers pls mark me as a BRILLIANT and follow me as a brilliant

31.

Statement (A): The point of intersection of the two lines is called origin, denoted by O'.Statement (B) : The plane which is divided by X and Y - axis is called co-ordinate plane (or)cartesian plane.a) Both A and B are trueb) Both A and B are falsec) A is true and B is falsed) A is false and B is true

Answer»

Step-by-step EXPLANATION:

the both OPTIONS is TRUE ( or ) CORRECT

the option is ( a )

so no explanation to the answers

pls mark me as a BRILLIANT and follow me as a brilliant

Discussion

32.	Which of the two rational number is greater in the given pair? 3 upon 8 or 0
Answer» 3/8 is BIGGER than 0. Because on DIVIDING 3÷8= 0.375 and it is GREATER than 0. THANK YOU

32.

Which of the two rational number is greater in the given pair? 3 upon 8 or 0

Answer»

3/8 is BIGGER than 0. Because on DIVIDING 3÷8= 0.375 and it is GREATER than 0.

THANK YOU

Discussion

33.	Q:2 Which of the following expressions are polynomials in one variable and which are not?y+y3- 5z-4 – 7zx + 5/x√t – 5t
Answer» Step-by-step EXPLANATION: SEE the ATTACHMENT below thx

33.

Q:2 Which of the following expressions are polynomials in one variable and which are not?y+y3- 5z-4 – 7zx + 5/x√t – 5t

Answer»

Step-by-step EXPLANATION:

SEE the ATTACHMENT below

thx

Discussion

34.	1,52,89,923 round nearest lakh and ten lakh
Answer» TEN lakh - 1,50,00,000 Lakh - 1,52,00,000 Hope it HELPS you.. Plz MARK as BRAINLIST

Discussion

35.	.1: Draw a line PQ q to line ST passing through a point A out side the line ST by using set squares
Answer» hlo FRIEND AAP kya KAR RAHE ho

Discussion

36.	Find the decimal form of 15 by 16 without actual division
Answer» ANSWER: answer REQUIRED is 0.937

36.

Find the decimal form of 15 by 16 without actual division

Answer»

ANSWER:

answer REQUIRED is 0.937

Discussion

37.	A man starts frm his house with some money to visit four temples.1. As soon as he enters temple 1 his money gets doubled. He donates 100 rs nd moves.2. At temple 2 again his money is doubled and he donates 100 rs.3. His money is doubled again at temple 3 and he donates 100 rs.4. At temple 4 again his money gets doubled. He donates 100 rs. again and returns home empty handed.How much money he had when he started from his house??? lets see who cracks first
Answer» LET money is x at first temple x-100 2(x-100) =2x-200 at 2ND temple 2x-200-100 2(2x-300) =4x-600 at 3RD temple 4x-600-100 2(4x-700) =8x-1400 at 4th temple 8x-1400-100 2(8x-1500) =16x-3000 now, 16x-3000=0 16x=3000 x=3000/16=187.5 so, REQUIRED money is 187.5

37.

A man starts frm his house with some money to visit four temples.1. As soon as he enters temple 1 his money gets doubled. He donates 100 rs nd moves.2. At temple 2 again his money is doubled and he donates 100 rs.3. His money is doubled again at temple 3 and he donates 100 rs.4. At temple 4 again his money gets doubled. He donates 100 rs. again and returns home empty handed.How much money he had when he started from his house??? lets see who cracks first

Answer»

LET money is x

at first temple

x-100

2(x-100) =2x-200

at 2ND temple

2x-200-100

2(2x-300) =4x-600

at 3RD temple

4x-600-100

2(4x-700) =8x-1400

at 4th temple

8x-1400-100

2(8x-1500) =16x-3000

now,

16x-3000=0

16x=3000

x=3000/16=187.5

so, REQUIRED money is 187.5

Discussion

38.	Convert the following into required measures 10m inmm
Answer» ANSWER: CONVERTING is 1M -10000mm

38.

Convert the following into required measures 10m inmm

Answer»

ANSWER:

CONVERTING is 1M -10000mm

Discussion

39.	PAGE NO.DATE:048) 5 (2x+1) (3745) 2x + 1)
Answer» Answer: 5×10x+5×3745×2x+1 5×10x+17375×2x+1

39.

PAGE NO.DATE:048) 5 (2x+1) (3745) 2x + 1)

Answer»

Answer:

5×10x+5×3745×2x+1

5×10x+17375×2x+1

Discussion

40.	(a) How many thousands make a lakh?(b) How many lakhs make a million?
Answer» ANSWER: a) 100 thousands. b) 10 LAKHS HOPE it helos...

40.

(a) How many thousands make a lakh?(b) How many lakhs make a million?

Answer»

ANSWER:

a) 100 thousands.

b) 10 LAKHS

HOPE it helos...

Discussion

41.	Please solve itplease help me
Answer» *QUESTION* :- 1) $(1 \div 4 + 3 \div 8) \div <klux>2</klux> \\$ 2) $(3 \div 8 + 1 \div 2) \div 2$ _________________________________________ *ANSWER* :- 1) 0.5 2) 0.4375 << *FOLLOW* >>

41.

Please solve itplease help me

Answer»

QUESTION :- 1)

$(1 \div 4 + 3 \div 8) \div <klux>2</klux> \\$

2)

$(3 \div 8 + 1 \div 2) \div 2$

_________________________________________

ANSWER :-

1) 0.5

2) 0.4375

<< FOLLOW >>

Discussion

42.	8/5+0=8/5=0+8/5 involved in
Answer» Step-by-step explanation: 8/5 is the ANSWER broooooooo _______________ HYDRA \| DYNAMO _____________ PUBG _____________ FOLLOW ME _____________ LIKE MY ANSWER ___________________________ MAKE ME AS BRAINLIEST ANSWER

42.

8/5+0=8/5=0+8/5 involved in

Answer»

Step-by-step explanation:

8/5 is the ANSWER broooooooo

_______________

HYDRA | DYNAMO

_____________

PUBG

_____________

FOLLOW ME

_____________

LIKE MY ANSWER

___________________________

MAKE ME AS BRAINLIEST ANSWER

Discussion

43.	Find all zeroes of the polynomial x4-3x3-x2+9x-6 if two its zeroes are -√3 and √3
Answer» HOPE IT HELPS YOU..................................

Discussion

44.	Balance the following chemical equationsMg + N₂ - Mg3Na2
Answer» Answer: 3mg + N₂ -Mg3Na2 Step-by-step EXPLANATION: BALANCE the FOLLOWING CHEMICAL EQUATIONS

44.

Balance the following chemical equationsMg + N₂ - Mg3Na2

Answer»

Answer:

3mg + N₂ -Mg3Na2

Step-by-step EXPLANATION:

BALANCE the FOLLOWING CHEMICAL EQUATIONS

Discussion

45.	21. x°-72923. (a+b)-(a - b)25. a? +3a²b + Bab? + bº-827. 2° +1669 - 5a - 10b29. a? - 61232
Answer» ANSWER: HEY ... SORRY for this ..

45.

21. x°-72923. (a+b)-(a - b)25. a? +3a²b + Bab? + bº-827. 2° +1669 - 5a - 10b29. a? - 61232

Answer»

ANSWER:

HEY ...

SORRY for this ..

Discussion

46.	Show that one and only one out of n,(n+1)and(n+2) is divisible by 3 where n is an positive integerplzz do it step by step
Answer» Let a = N be a positive integer b = 3 By Euclid's division lemma a = bq + R where $<klux>0</klux> \leqslant r < b$ r = 0 , 1 , 2 because $0 \leqslant r < 3$ If r = 0 ; then a = 3q n = 3q If r = 1 ; then a = 3q + 1 n = 3q + 1 n + 1 = 3q + 1 + 1 n + 1 = 3q + 2 If r = 2 ; then a = 3q + 2 n = 3q + 2 n + 2 = 3q + 2 + 2 n + 2 = 3q + 4 Therefore only one out of n , (n + 1) & (n + 2) only n is divisible.... But ( n + 2 ) & (n + 4 ) will be divisible .....

46.

Show that one and only one out of n,(n+1)and(n+2) is divisible by 3 where n is an positive integerplzz do it step by step

Answer»

Let a = N be a positive integer b = 3

By Euclid's division lemma a = bq + R where

$<klux>0</klux> \leqslant r < b$

r = 0 , 1 , 2 because

$0 \leqslant r < 3$

If r = 0 ; then a = 3q

n = 3q

If r = 1 ; then a = 3q + 1

n = 3q + 1

n + 1 = 3q + 1 + 1

n + 1 = 3q + 2

If r = 2 ; then a = 3q + 2

n = 3q + 2

n + 2 = 3q + 2 + 2

n + 2 = 3q + 4

Therefore only one out of n , (n + 1) & (n + 2) only n is divisible....

But ( n + 2 ) & (n + 4 ) will be divisible .....

Discussion

47.	if the difference between an exterior angle of a regular polygon of n sides and an exterior angle of another regular polygon of (n+1) sides is 5, find the value of n
Answer» ANSWER: value of n = 5 and TOTAL answer is 6 ... HOPE it helps U

47.

if the difference between an exterior angle of a regular polygon of n sides and an exterior angle of another regular polygon of (n+1) sides is 5, find the value of n

Answer»

ANSWER:

value of n = 5 and TOTAL answer is 6 ...

HOPE it helps U

Discussion

48.	if alpha and beta are the zeros of quadratic polynomial 4x square - 2x +(k-1) and alpha = 1/beta find the value of k
Answer» Step-by-step EXPLANATION: $4 {x}^{2} - 2x + (k - 1) = 0 \\ \alpha = \frac{1}{ \beta } \\ = > \alpha \beta \: = 1 \\ \\ = > \alpha \beta = \frac{c}{a} \\ = > \alpha \beta = \frac{k - 1}{4} \\ = > 1 = \frac{k - 1}{4} \\ = > 4 = k - 1 \\ = > k = 4 + 1 \\ = > k = 5$

48.

if alpha and beta are the zeros of quadratic polynomial 4x square - 2x +(k-1) and alpha = 1/beta find the value of k

Answer»

Step-by-step EXPLANATION:

$4 {x}^{2} - 2x + (k - 1) = 0 \\ \alpha = \frac{1}{ \beta } \\ = > \alpha \beta \: = 1 \\ \\ = > \alpha \beta = \frac{c}{a} \\ = > \alpha \beta = \frac{k - 1}{4} \\ = > 1 = \frac{k - 1}{4} \\ = > 4 = k - 1 \\ = > k = 4 + 1 \\ = > k = 5$

Discussion

49.	What is A×B×C pls display the answer with solution
Answer» $\blue{\bold{\underline{\underline{Answer:}}}}$ $\green{\tt{\therefore{ABC=log_{6}(4)}}}$ $\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$ $\green{\underline \bold{<klux>GIVEN</klux>:}} \\ \tt: \implies A= log_{32}(1024) \\ \\ \tt: \implies B= log_{81}( \sqrt{3} ) \\ \\ \tt: \implies C = log_{6}(256) \\ \\ \red{\underline \bold{to \: find:}} \\ \tt: \implies ABC = ?$ • ACCORDING to given QUESTION : $\tt: \implies A = log_{32}(1024) \\ \\ \tt: \implies A= log_{32} ({32})^{2} \\ \\ \tt: \implies A= 2 \: log_{32}(32) \\ \\ \green{\tt: \implies A= 2} \\ \\ \bold{For \: B : } \\ \tt: \implies B = log_{81}( \sqrt{3} ) \\ \\ \tt: \implies B = log_{( \sqrt{3})^{8} }( \sqrt{3} ) \\ \\ \tt: \implies B= \frac{1}{8} log_{ \sqrt{3} }( \sqrt{3} ) \\ \\ \green{\tt: \implies B = \frac{1}{8}} \\ \\ \bold{For \: C: } \\ \tt: \implies C = log_{6}(256) \\ \\ \tt: \implies C = log_{(2 \times 3)}( {2}^{8} ) \\ \\ \tt: \implies C = 8 \: log_{2 \times 3}(2) \\ \\ \green{\tt: \implies C=8 \: log_{6}(2) } \\ \\ \bold{For \: finding \: value} \\ \tt: \implies ABC = 2 \times \frac{1}{8} \times 8 \: log_{6}(2) \\ \\ \tt: \implies ABC=2 \: log_{6}(2) \\ \\ \green{\tt: \implies ABC = log_{6}(4) }$

49.

What is A×B×C pls display the answer with solution

Answer»

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{ABC=log_{6}(4)}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{<klux>GIVEN</klux>:}} \\ \tt: \implies A= log_{32}(1024) \\ \\ \tt: \implies B= log_{81}( \sqrt{3} ) \\ \\ \tt: \implies C = log_{6}(256) \\ \\ \red{\underline \bold{to \: find:}} \\ \tt: \implies ABC = ?$

• ACCORDING to given QUESTION :

$\tt: \implies A = log_{32}(1024) \\ \\ \tt: \implies A= log_{32} ({32})^{2} \\ \\ \tt: \implies A= 2 \: log_{32}(32) \\ \\ \green{\tt: \implies A= 2} \\ \\ \bold{For \: B : } \\ \tt: \implies B = log_{81}( \sqrt{3} ) \\ \\ \tt: \implies B = log_{( \sqrt{3})^{8} }( \sqrt{3} ) \\ \\ \tt: \implies B= \frac{1}{8} log_{ \sqrt{3} }( \sqrt{3} ) \\ \\ \green{\tt: \implies B = \frac{1}{8}} \\ \\ \bold{For \: C: } \\ \tt: \implies C = log_{6}(256) \\ \\ \tt: \implies C = log_{(2 \times 3)}( {2}^{8} ) \\ \\ \tt: \implies C = 8 \: log_{2 \times 3}(2) \\ \\ \green{\tt: \implies C=8 \: log_{6}(2) } \\ \\ \bold{For \: finding \: value} \\ \tt: \implies ABC = 2 \times \frac{1}{8} \times 8 \: log_{6}(2) \\ \\ \tt: \implies ABC=2 \: log_{6}(2) \\ \\ \green{\tt: \implies ABC = log_{6}(4) }$

Discussion

50.	In a class of 60 students the number of girls is one third of the number of boys ,then find the number of boyband girls
Answer» Answer: 15 GIRLS and 45 boys Step-by-step explanation: Let the NUMBER of girls be $x\\$ . So, we can SAY that the number of boys is $3x$ . Totally, there are 60 students. So, $x\\$ + $3x$ = 60 $4x$ = 60 $x\\$ = 60 ÷ 4 $x\\$ = 15 So there are 15( $x\\$ ) girls and 45(3 $x\\$ ) boys

50.

In a class of 60 students the number of girls is one third of the number of boys ,then find the number of boyband girls

Answer»

Answer:

15 GIRLS and 45 boys

Step-by-step explanation:

Let the NUMBER of girls be $x\\$ .

So, we can SAY that the number of boys is $3x$ .

Totally, there are 60 students.

So,

$x\\$ + $3x$ = 60

$4x$ = 60

$x\\$ = 60 ÷ 4

$x\\$ = 15

So there are 15( $x\\$ ) girls and 45(3 $x\\$ ) boys

Discussion

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QUESTION :- 1)

2)

ANSWER :-

<< FOLLOW >>

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