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Show that one and only one out of n,(n+1)and(n+2) is divisible by 3 where n is an positive integerplzz do it step by step |
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Answer» Let a = N be a positive integer b = 3 By Euclid's division lemma a = bq + R where r = 0 , 1 , 2 because If r = 0 ; then a = 3q n = 3q If r = 1 ; then a = 3q + 1 n = 3q + 1 n + 1 = 3q + 1 + 1 n + 1 = 3q + 2 If r = 2 ; then a = 3q + 2 n = 3q + 2 n + 2 = 3q + 2 + 2 n + 2 = 3q + 4 Therefore only one out of n , (n + 1) & (n + 2) only n is divisible.... But ( n + 2 ) & (n + 4 ) will be divisible ..... |
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