What is A×B×C pls display the answer with solution

1.	What is A×B×C pls display the answer with solution
Answer» $\blue{\bold{\underline{\underline{Answer:}}}}$ $\green{\tt{\therefore{ABC=log_{6}(4)}}}$ $\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$ $\green{\underline \bold{<klux>GIVEN</klux>:}} \\ \tt: \implies A= log_{32}(1024) \\ \\ \tt: \implies B= log_{81}( \sqrt{3} ) \\ \\ \tt: \implies C = log_{6}(256) \\ \\ \red{\underline \bold{to \: find:}} \\ \tt: \implies ABC = ?$ • ACCORDING to given QUESTION : $\tt: \implies A = log_{32}(1024) \\ \\ \tt: \implies A= log_{32} ({32})^{2} \\ \\ \tt: \implies A= 2 \: log_{32}(32) \\ \\ \green{\tt: \implies A= 2} \\ \\ \bold{For \: B : } \\ \tt: \implies B = log_{81}( \sqrt{3} ) \\ \\ \tt: \implies B = log_{( \sqrt{3})^{8} }( \sqrt{3} ) \\ \\ \tt: \implies B= \frac{1}{8} log_{ \sqrt{3} }( \sqrt{3} ) \\ \\ \green{\tt: \implies B = \frac{1}{8}} \\ \\ \bold{For \: C: } \\ \tt: \implies C = log_{6}(256) \\ \\ \tt: \implies C = log_{(2 \times 3)}( {2}^{8} ) \\ \\ \tt: \implies C = 8 \: log_{2 \times 3}(2) \\ \\ \green{\tt: \implies C=8 \: log_{6}(2) } \\ \\ \bold{For \: finding \: value} \\ \tt: \implies ABC = 2 \times \frac{1}{8} \times 8 \: log_{6}(2) \\ \\ \tt: \implies ABC=2 \: log_{6}(2) \\ \\ \green{\tt: \implies ABC = log_{6}(4) }$

Answer»

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{ABC=log_{6}(4)}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{<klux>GIVEN</klux>:}} \\ \tt: \implies A= log_{32}(1024) \\ \\ \tt: \implies B= log_{81}( \sqrt{3} ) \\ \\ \tt: \implies C = log_{6}(256) \\ \\ \red{\underline \bold{to \: find:}} \\ \tt: \implies ABC = ?$

• ACCORDING to given QUESTION :

$\tt: \implies A = log_{32}(1024) \\ \\ \tt: \implies A= log_{32} ({32})^{2} \\ \\ \tt: \implies A= 2 \: log_{32}(32) \\ \\ \green{\tt: \implies A= 2} \\ \\ \bold{For \: B : } \\ \tt: \implies B = log_{81}( \sqrt{3} ) \\ \\ \tt: \implies B = log_{( \sqrt{3})^{8} }( \sqrt{3} ) \\ \\ \tt: \implies B= \frac{1}{8} log_{ \sqrt{3} }( \sqrt{3} ) \\ \\ \green{\tt: \implies B = \frac{1}{8}} \\ \\ \bold{For \: C: } \\ \tt: \implies C = log_{6}(256) \\ \\ \tt: \implies C = log_{(2 \times 3)}( {2}^{8} ) \\ \\ \tt: \implies C = 8 \: log_{2 \times 3}(2) \\ \\ \green{\tt: \implies C=8 \: log_{6}(2) } \\ \\ \bold{For \: finding \: value} \\ \tt: \implies ABC = 2 \times \frac{1}{8} \times 8 \: log_{6}(2) \\ \\ \tt: \implies ABC=2 \: log_{6}(2) \\ \\ \green{\tt: \implies ABC = log_{6}(4) }$