This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 4. |
14 9 12 20 , 4 9 8 10, 12 13 7 20 , 3 3 11 ? , 20 42 19 40 find the missing number |
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| 5. |
Find the greatest number that will divide 33,44 and 66 |
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| 6. |
1. Sunil bought a cycle for 380 and spent 182 on its repairing. How much moneydid Sunil spend on the cycle in all? |
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Answer» Answer: 562 Step-by-step EXPLANATION: |
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| 7. |
.....,........... solve the question |
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Answer» Answer: we have NEED put the value of sin, cos and TAN FORMS.. afterthat this will be essey |
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| 8. |
verify whether 1,1,-3 are the zeroes of the polynomial x3+3x2-3 check the relationship between zeroes and coefficient |
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Answer» fddddddddddddrrrrrrr . Step-by-step EXPLANATION: rrrrrrrrrrrrrrrrrdddd |
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| 9. |
* home quarantine puzzle *A customer came to a shopkeeper, bought a grocer's note worth Rs 400 and gave a note of Rs 2000 to the shopkeeper. Since it was morning, the shopkeeper did not have enough money, so he went to the neighboring shopkeeper. Withdrew, and threw four hundred bucks into the lane. In the afternoon, the shopkeeper came with a note of 2000 and said "The note you gave in the morning is false". ? |
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Answer» Answer: no. The money is real but the shopkeeper WANTED extra PROFIT. HOPE it’s CORRECT Step-by-step explanation: |
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| 10. |
34. A circus tent is cylindrical to a height of 3 m and conical aboveitbase radius is 52.5 m and the slant height of the conical portion is 9),find the area of canvas needed to make the tent. |
Answer» Given :-
To Find :-
Formula used :-
Solution :-Putting VALUES we get :-→ Area of canvas needed to make the tent = π * 52.5 * 9 + 2 * π * 52.5 * 3 → π * 52.5 [ 9 + 2*3 ] → π * 52.5 * 15 → (22/7) * 52.5 * 15 → 22 * 7.5 * 15 → 2475m². Hence, Area of canvas needed to make the tent is 2475m². |
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| 11. |
B)c)The population of a certain town is 3,43,280. (round in thousands)4,725 people visited the zoo on Tuesday. (round in thousands) |
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Answer» Answer: 343000 5000 Step-by-step EXPLANATION: PLS MARK it as BRAINLIEST pls... |
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| 12. |
In the diagram, ABCDEF is a regular hexagon and ABGH is a squarea) find angle ABC and angle CBGb) find the angle of triangle ACG |
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Answer» Answer: Given that ABCDEF is a regular hexagon, so all sides of it are equal in length. Sum of the angles of a n− sided polygon =(n−2)×180 Hence, Sum of all angles of a hexagon =(6−2)×180 =720 And, Each angle of a regular hexagon = 6 720
=120.......(1) Quadrilateral ABEF contains half the angle measure of the hexagon. Hence, its interior angle measure =720/2=360 ∠AFE=120.......(ii) [ from (1)] In △AFE, AF=EF [ SINCE, they are a part of regular hexagon].......(iii) ⇒∠FAE=∠FEA [ Angles OPPOSITE to equal sides are equal] In △AFE, ∠FAE+∠FEA+∠AFE=180 [ sum of all angles of a triangle is 180 o ] SUBSTITUTING (ii) & (iii) in above equation, ∠FAE=∠FEA=30 o
∠FAE+∠EAB=120 o [ Angle of a regular hexagon] ∴∠EAB=90 o .......(iv) ∠ABE=1/2×120 o [∵∠ABE bisects ∠ABC] =60 o
In △ABE, ∠AEB+∠ABE+∠EBA=180 o
[ sum of all angles of a triangle] ∠AEB=180 o −60 o −90 o =30 o [ from (iv) & (v) ] ∠ABE=60 o ∠EAB=90 o ∠AEB=30 o |
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| 13. |
Hola ❤Good morning guys ❤plzz solve it ❌No spam ❌ |
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Answer» REFER TO THE ATTACHMENT FOR THE ANSWER
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| 15. |
Mrs. Avery is going to randomly select one student from her class to read a poem out loud. There are 15 boys and 13 girls in her class.What is P (boy)? |
Answer»
To find :
Step-by-step explanation: Question is saying that Mrs. Avery is randomly SELECT one student from her class to read a poem out loud. And, There are 15 boys and 13 girls in her class. [Given] And it is Asking that What is the Probability of boy's. Now, Finding the Probability of the boy's, Firstly we have to find the total number of students in whole class, Total number of students in whole class = Total number of girls + Total number of boys. Substituting the VALUES, we GET, = 15 + 13 = 28. Therefore, Total number of students in whole class = 28. Now, Finding the Probability of the Boy's, Probability of Boys = Total number of Boys /Total number of students. Substituting the values, we get, = 15/28 Hence, The Probability of Boys in fraction form = 15/28. Now, The Probability of Boys in DECIMAL form, = 15 / 28 = 1.87. Therefore, The Probability of Boys in decimal form = 1.87. |
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| 16. |
Write four rational number greater than minus one |
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Answer» Answer: 0,1,2,3,4,5 and so on...... |
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| 17. |
X side of the triangle |
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| 18. |
Which term of AP - 18 - 20, -22,_ _ _ _ is zero? |
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Answer» it cannot possible |
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| 19. |
Only *22* Km of road can be constructed. But all 4 cities to be connected. How? |
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Answer» Step-by-step explanation: The Golden Quadrilateral (GQ) is a national highway network connecting most of the major industrial, agricultural and cultural centres of India. It forms a quadrilateral connecting the four major metro cities of India, viz., Delhi (north), Kolkata (east), Mumbai (west) and Chennai (south). Other cities connected by this network include Ahmedabad, Bengaluru, Balasore, Bhubaneswar, Cuttack, Durgapur, JAIPUR, Kanpur, PUNE, Surat, Vijayawada, Ajmer, VIZAG, Bodhgaya, Varanasi, Agra, Mathura, DHANBAD, Gandhinagar, Udaipur, and Vadodara. The main objective of these super highways is to reduce the DISTANCE and time between the four mega cities of India. |
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| 20. |
Find the value of the log in the above picture |
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Answer» it's answer is 3924 was I this a answer |
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| 21. |
Cotθ+ cot2θ + cot3θ = cotθ cot2θcot3θhow can I solve this math? |
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Answer» Step-by-step EXPLANATION: please MARK BRILLIANTplease mark brilliant |
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| 22. |
Describe the following set by roaster meathod. {x:4x-15 |
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Answer» Step-by-step EXPLANATION: A={1,2,3,4,5,6,7,8,9,10} hope it helps u please mark as BRAINLIEST |
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| 23. |
X+ay=b ax-by=c by cross multiplication |
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Answer» Please MARK it as brainliest answer if you LIKE the answer and FOLLOW me ☺️☺️ |
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| 24. |
Match the description of each circle to the equation of the circle |
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Answer» we have to match the DESCRIPTION of each CIRCLE to the EQUATION of the circle. solution : If (a, b) is the centre of circle and r is the radius of the circle then equation of circle is given by, (x - a)² + (x - b)² = r² 1. A circle with centre on (7,0) with a radius 9. equation : (x - 7)² + (y - 0)² = 9² ⇒(x - 7)² + y² = 81 2. A circle with centre on the ORIGIN and point on (4, -2). so the radius of circle, r = √{(4)² + (-2)²} = √20 Therefore equation : (x - 0)² + (y - 0)² = (√20)² = 20 ⇒x² + y² = 20 3. A circle with centre (-3,-3) with a point on (-3, -2) so the radius of circle, r = √{(-3+3)² + (-3+2)²} = 1 therefore equation : (x + 3)² + (y + 3)² = 1² ⇒(x + 3)² + (y + 3)² = 1 4. A circle with centre (0, -2) and a radius of 9. the equation : (x - 0)² + (y + 2)² = 9² ⇒x² + (y + 2)² = 81 |
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| 25. |
N(a)=30 (aunionb)=50 n(a intersection b)=12 then find n(b)please very urgent if you answer I will mark your answer as best answer please please |
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Answer» Step-by-step EXPLANATION: n(a union B) =n(a) +n(b) -n(a INTERSECTION b) 50= 30+ n(b) -12 50= n(b) +18 n(b) = 50-18=32 |
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| 26. |
Dimensions of the garden |
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Answer» b Step-by-step EXPLANATION: because (2x)^2-(8)^2 4x^2-64 |
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| 27. |
Q.6. Show that square of an odd integer is of the form8k+1. |
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Answer» = 8(8m2+14m+6) +1==8q+1. [Where q=8m2+14m+6]. Hence, the square of any ODD POSITIVE INTEGER is the FORM of 8q+1 |
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| 28. |
Write the following in roaster form: A={x:x^2-4x-5=0} |
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Answer» A={x : x²–5x+x–5=0} A={x : x(x–5)+1(x–5)=0} A={x : (x–5)+(x+1)=0} ⇒A={x : x = –1, 5} ∴ A={–1, 5} [in roster FORM] |
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| 29. |
Which term of AP - 3, - 20, -22,_ _ _ _ is zero? |
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Answer» It was not possible Step-by-step explanation: Because a¹=-3 a²=-20 Now, d¹= -20-(-3) = -17 Then,a³=-22 now, d²=-22-(-20) -2 So, d¹not equal to d² Hence,it is not an A.P. Hope it helps you Please mark me as the BRAINLIEST. ;) @ Follow me for follow BACK..... |
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| 30. |
Make 3 more linear equation in general form |
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Answer» Step-by-step explanation: The FORMULA 0 = Ax + By + C is said to be the 'general form' for the equation of a line. A, B, and C are THREE real numbers. Once these are GIVEN, the values for x and y that make the STATEMENT true express a set, or LOCUS, of (x, y) points which form a certain line. |
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| 31. |
When it is that someone becomes a maths Aryabhatta, brainliest question. |
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Answer» When THA PERSON becomes extremely brilliant in maths. It can be achieved by regular practice. Ihope you turn into a Aryabhatta too. You can TAKE PhD in maths. Pls mark it as BRAINLIEST pls... Step-by-step explanation: |
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| 32. |
Hey friends.... good morning.... please answer the above questions .... |
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Answer» Answer: 1.) 4x + 5 = 21 Step-by-step explanation: 4x = 21 - 5 4x = 16 |
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| 33. |
Solve by quadratic formula X square - 4 x minus 40 is equals to minus 8 |
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Answer» REFER TO THE ATTACHMENT FOR THE ANSWER |
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| 34. |
Captain arjun is the captain of the ship . captain if the ship is captain arjun what is the name of the shipplease answer this question |
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Answer» Answer: capiton ARJUN Step-by-step explanation: because in the SECOND sentence you said that "the SHIP is capiton arjun". So,the ship name is capiton arjun. |
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| 35. |
Please give answer fast..what is the area of coloured part in the image..with step by step |
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Answer» Answer: we SEE that it's a square by its LENGTH . area of square=sidexside =10*10=100sq.unit |
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| 36. |
I look like a dice, I have six edges. I can slide down a sloping surface. Who am I? |
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Answer» Answer: a 3 d figure |
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| 37. |
InTriangle ABCB =90, BC² = ACXBDThen prove that BD is bisector of angle ABC. |
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Answer» ANSWER:— In the right angle triangle ABD, we have AD² = AB² - BD² In the right angle triangle ACD we have AD² = AC² - CD² So AC² - CD² = AB² - BD² => AC² = AB² + CD² - BD² => = AB² + (CD + BD)* (CD - BD ) = AB² + BC * [(BC - BD) - BD] = AB² + BC * [ BC - 2 BD ] = AB² +BC² - 2 BC * BD hope this HELPS
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| 38. |
Circle V is shown. Line segment T V is a radius with length 14 feet.In circle V, r = 14ft.What is the area of circle V?14Pi feet squared28Pi feet squared49Pi feet squared196Pi feet squared |
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Answer» Answer: we know that the AREA of a circle is equal to A=\pi r^{2}A=πr 2
where r is the RADIUS of the circle In this PROBLEM we have r=14\ ftr=14 FT substitute in the formula A=\pi 14^{2}A=π14 2
A=196\pi\ ft^{2}A=196π ft 2
therefore the answer is 196\pi\ ft^{2}196π ft 2 |
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| 39. |
Find the product 7/16×1000 |
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Answer» 7/16×1000=875/2=437.5, PLEASE MARK the ANSWER as BRAINLIEST. |
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| 40. |
How can I find the sum of an infinite geometric series: a1=14 & r=7/3? |
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Answer» Answer: sum of an infinite GEOMETRIC series=a/(1-r) so here a=14 r=7/3 s=14/(1-7/3) = -21/2 Step-by-step EXPLANATION: MARK my ans as BRAINLIEST PLZ |
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| 41. |
The measure of central angle XYZ is 1.25 pi radians.What is the area of the shaded sector?[tex]x/360(\pi r^2)10 units2 20 units240 units280 units2 |
Answer» GiveN :
To FIND :
SolutioN :ANGLE is 1.25 πrad = 180 * 1.25 = 225°
Now, use formula for sector |
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| 42. |
5. What can the maximum number of digits be in the repeating block of digit in thedecimal expansion of 1/17 - ? Perform the division to check your answer. please send the pic of solution |
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| 43. |
Express the HCF of 125 and 70 in the form of 125x+70y. |
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Answer» Given: Two numbers 125 and 70 . To find: Express the HCF of 125 and 70 in the FORM of 125x + 70y. Solution:
125 = 70 x 1 + 55 70 = 55 x 1 + 15 55 = 15 x 3 + 10 15 = 10 x 1 + 5 10 = 5 x 2 + 0
5 = -(10 x 1) + 15 5 = 15 - (55 - (15x3)) 5 = 15 - 55 + (15x3) 5 = 15 x 4 - 55 5 = (70 - 55) x 4 - 55 5 = 70 x 4 - 55 x 3 5 = 70 x 4 - (125 - 70) 5 = 70 x 4 - 125 + 70 5 = 125(-1) + 70(5)
x = -1 and y = 5 Answer: So HCF of 125 and 70 in the form of 125x+70y is 125(-1) + 70(5) |
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| 44. |
The area of circle Z is 64Pi ft2What is the value of r?r = 4 ft Formula to solve:r = 8 ft r = 16 ftr = 32 ft |
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| 45. |
What will be the volume of a cone when r=h compared to volume of a sphere?? |
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| 46. |
DarePageThe value of a' for which the equation3x²+2 (a²+1)2+(a²3a+2) = 0 has roots of oppositesign, liesin |
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| 47. |
Which of the following shows only multiples of 12? |
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Answer» Answer: 12,24,36,48,60,72,84,96,108,120,132,144,156,168,180,192 and so on the FACTORS of 12..... |
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| 48. |
Hello everyone! I need help with this problem!! Please please help :)Find the percent of change from Sunday over the rest of the days (Monday, Tuesday, Wednesday). |
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Answer» Step-by-step explanation: 1.sunday: 2CM---> 2%---> 2÷ 100 x 0.02 (~ 1cm = 0.01m) ans: 0.0004m. 2. MONDAY: 1.42cm----> 142%----> 142 ÷ 100× 0.000142 ans:0.00020164m. 3. Tuesday: 1.02cm----> 102%---> 102 ÷ 100 × 0.0102 amd: 0.010404m. 4. WEDNESDAY: 3.46cm---> 346%---> 346÷100× 0.0346 ans:0.119716m. these are the answers |
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| 49. |
5+2+3=147 3+4+1=48 0+1+5 =273 2+0+4= ???? |
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Answer» Given: To find: value =? In the given equation there is no SIMILARITY, that's why the last equation answer is: 6 which can be DESCRIBED as follows: In the above equation, in the first value that is 5 we cube the value then write second and third value then subtract it. so, it will give the value that is: 147. bu in other equation if we apply this techniques it can't give the value that's why we SIMPLY add the last value that is:
The final answer is= 6. |
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