332354 + Interview Questions in Secondary School in Math

1.	If one root of the equation 2x^2 + ax + 6= 0 is 2 than a =
Answer» 2(2)²+a×2+6=0 8+6+2a=0 2a=-14 a=-7

1.

If one root of the equation 2x^2 + ax + 6= 0 is 2 than a =

Answer»

2(2)²+a×2+6=0

8+6+2a=0

2a=-14

a=-7

2.	Plz tell me the answer of the above questionit is very urgent
Answer» here's your ANSWER MATE: It is FALSE that 0.16 is an IRRATIONAL no.

Discussion

3.	the sides of a quadrilateral taken in order are 5m 12m 14m 15m respectively and the angle contained by the first two sides is a right angle find its area?
Answer» *ANSWER IS IN THE PHOTO CHECK!!!!!*

3.

the sides of a quadrilateral taken in order are 5m 12m 14m 15m respectively and the angle contained by the first two sides is a right angle find its area?

Answer»

ANSWER IS IN THE PHOTO CHECK!!!!!

Discussion

4.	(2) If the product of two whole numbers iszero, con uwe say that one os both ofthem will to be zero? Justify throughexamples.
Answer» Answer: Yes, if the product of two WHOLE NUMBER is zero, then one or both of them will definitely be zero. Step-by-step explanation: For Example : 2 x 0 = 0 ........ Answer is 0 if one number is 0. 2 x 1 = 2 2 x 2 = 4 2 x 3 = 6........ Answer is not 0. 0 x 0 = 0 ........ Answer 0 if both NUMBERS are 0. Thus, Product is 0 if one or both number are 0. *Hope* it *helps* *you* !! Please *MARK* as *brainliest* !!

4.

(2) If the product of two whole numbers iszero, con uwe say that one os both ofthem will to be zero? Justify throughexamples.

Answer»

Answer:

Yes, if the product of two WHOLE NUMBER is zero, then one or both of them will definitely be zero.

Step-by-step explanation:

For Example :

2 x 0 = 0 ........ Answer is 0 if one number is 0.

2 x 1 = 2

2 x 2 = 4

2 x 3 = 6........ Answer is not 0.

0 x 0 = 0 ........ Answer 0 if both NUMBERS are 0.

Thus, Product is 0 if one or both number are 0.

Hope it helps you !!

Please MARK as brainliest !!

Discussion

5.	Factorize a^3+b^3-c^3
Answer» Step-by-step explanation: if the sum for a B and C is 0 then VALVE is 3ABC

5.

Factorize a^3+b^3-c^3

Answer»

Step-by-step explanation:

if the sum for a B and C is 0 then VALVE is 3ABC

Discussion

6.	Determine the value of k for which the equation 2 X square + 3 X + K has equal roots
Answer» HOPE IT HELPS YOU.....

6.

Determine the value of k for which the equation 2 X square + 3 X + K has equal roots

Answer»

HOPE IT HELPS YOU.....

Discussion

7.	Please answers this two question with process please
Answer» ANSWER: I don't Step-by-step EXPLANATION: ajsjsisis

7.

Please answers this two question with process please

Answer»

ANSWER:

I don't

Step-by-step EXPLANATION:

ajsjsisis

Discussion

8.	Plzzz ans these questions...✌✌✌
Answer» ANSWER: ${ \sin(30) }^{2} + { \cos(30) }^{2} \\ = \frac{1}{4} + \frac{3}{4} \\ = 1$ ${ \sec(45) }^{2} - { \tan(45) }^{2} \\ = { \sqrt{2} }^{2} - {1}^{2} \\ = 1$ ${ \csc(60) }^{2} - { \cot(60) }^{2} \\ = { \frac{2}{ \sqrt{3} } }^{2} - { \frac{1}{ \sqrt{3} } }^{2} \\ = 1$ ${ \sin(45) }^{2} + { \cos(45) }^{2} \\ \frac{1}{2} + \frac{1}{2} \\ = 1$ $hope \: u \: undrstand \: dear.... \\ <klux>PLEASE</klux> \: mark \: me \: as \: brainliest$ Please FOLLOW me... ❤️

8.

Plzzz ans these questions...✌✌✌

Answer»

ANSWER:

${ \sin(30) }^{2} + { \cos(30) }^{2} \\ = \frac{1}{4} + \frac{3}{4} \\ = 1$

${ \sec(45) }^{2} - { \tan(45) }^{2} \\ = { \sqrt{2} }^{2} - {1}^{2} \\ = 1$

${ \csc(60) }^{2} - { \cot(60) }^{2} \\ = { \frac{2}{ \sqrt{3} } }^{2} - { \frac{1}{ \sqrt{3} } }^{2} \\ = 1$

${ \sin(45) }^{2} + { \cos(45) }^{2} \\ \frac{1}{2} + \frac{1}{2} \\ = 1$

$hope \: u \: undrstand \: dear.... \\ <klux>PLEASE</klux> \: mark \: me \: as \: brainliest$

Please FOLLOW me... ❤️

Discussion

9.	Please solve this I promise you to mark as brainlist
Answer» ANSWER: what is the QUESTION?????

9.

Please solve this I promise you to mark as brainlist

Answer»

ANSWER:

what is the QUESTION?????

Discussion

10.	Reena climbs up 5 stairs every second and then climbs down 2 stairs over the next second .How many seconds will she take to climb 60 stairs
Answer» ANSWER: IN 1 SECOND SHE CLIMBS UP 5 STAIRS IN THE NEXT SECOND SHE CLIMBS DOWN 2 STAIRS. THEREFORE, IN 2 SECONDS SHE CLIMBS 5-2 STAIRS=3 STAIRS. THIS IMPLIES THAT SHE CAN CLIMB 1 STAIR IN 2/3 SECONDS. THEREFORE, SHE CAN CLIMB 60 STAIRS IN 2/3*60 SECONDS = 40 SECONDS. HOPE IT HELPS YOU.

10.

Reena climbs up 5 stairs every second and then climbs down 2 stairs over the next second .How many seconds will she take to climb 60 stairs

Answer»

ANSWER:

IN 1 SECOND SHE CLIMBS UP 5 STAIRS

IN THE NEXT SECOND SHE CLIMBS DOWN 2 STAIRS.

THEREFORE, IN 2 SECONDS SHE CLIMBS 5-2 STAIRS=3 STAIRS.

THIS IMPLIES THAT SHE CAN CLIMB 1 STAIR IN 2/3 SECONDS.

THEREFORE, SHE CAN CLIMB 60 STAIRS IN 2/3*60 SECONDS = 40 SECONDS.

HOPE IT HELPS YOU.

Discussion

11.	Solve the following pair of linear equations by theelimination method:0.3x - 0.8y = -1.10.5x -0.7y =0.7
Answer» Step-by-step EXPLANATION: We Have :- $0.3x - 0.8y = - 1.1 \\ \\ \\ 0.5x - 0.7y = 0.7$ To FIND :- $value \: of \: x \: and \: y$ METHOD USED :- $elimination \: method$ SOLUTION :- $0.3x - 0.8y = - 1.1 - - - (1)\\ \\ \\ multiply \: (1) \: with \: 5 \\ \\ \\ 1.5x - 4y = - 5.5 - - - (2) \\ \\ \\ \\ 0.5x - 0.7y = 0.7 - - - (3) \\ \\ \\ multiply \: (3) \: with \: 3 \\ \\ \\ 1.5x - 2.1y = 2.1 - - - (4) \\ \\ \\ subtracting \: (4) \: from \: (2) \\ \\ \\ \: \: \: \: \: 1.5x - 4y = - 5.5 \\ \\ \\ - (1.5x - 2.1y = 2.1) \\ \\ \\ - 1.9y = - 7.6 \\ \\ \\ 19y = 76 \\ \\ \\ y = 4 \\ \\ \\ putting \: this \: value \: in \: (1) \\ \\ \\ 0.3x - 0.8(4) = - 1.1 \\ \\ \\ 0.3x - 3.2 = - 1.1 \\ \\ \\ 0.3x = - 1.1 + 3.2 \\ \\ \\ 0.3x = 2.1 \\ \\ \\ 3x = 21 \\ \\ \\ x = 7$

11.

Solve the following pair of linear equations by theelimination method:0.3x - 0.8y = -1.10.5x -0.7y =0.7

Answer»

Step-by-step EXPLANATION:

We Have :-

$0.3x - 0.8y = - 1.1 \\ \\ \\ 0.5x - 0.7y = 0.7$

To FIND :-

$value \: of \: x \: and \: y$

$0.3x - 0.8y = - 1.1 - - - (1)\\ \\ \\ multiply \: (1) \: with \: 5 \\ \\ \\ 1.5x - 4y = - 5.5 - - - (2) \\ \\ \\ \\ 0.5x - 0.7y = 0.7 - - - (3) \\ \\ \\ multiply \: (3) \: with \: 3 \\ \\ \\ 1.5x - 2.1y = 2.1 - - - (4) \\ \\ \\ subtracting \: (4) \: from \: (2) \\ \\ \\ \: \: \: \: \: 1.5x - 4y = - 5.5 \\ \\ \\ - (1.5x - 2.1y = 2.1) \\ \\ \\ - 1.9y = - 7.6 \\ \\ \\ 19y = 76 \\ \\ \\ y = 4 \\ \\ \\ putting \: this \: value \: in \: (1) \\ \\ \\ 0.3x - 0.8(4) = - 1.1 \\ \\ \\ 0.3x - 3.2 = - 1.1 \\ \\ \\ 0.3x = - 1.1 + 3.2 \\ \\ \\ 0.3x = 2.1 \\ \\ \\ 3x = 21 \\ \\ \\ x = 7$

Discussion

12.	7+2+1+2=?6+2+1+2=163 1+9+8=297+3+4+5=69
Answer» Answer: 7 +2+1+2-- 12 6+2+1+2:-- 11

12.

7+2+1+2=?6+2+1+2=163 1+9+8=297+3+4+5=69

Answer»

Answer:

7 +2+1+2-- 12

6+2+1+2:-- 11

Discussion

13.	Find the solution by quadratic equation formula : 3x^2-13x-100=0
Answer» Given An Equation 3x²-13x-100=0 To find The factor by QUADRATIC formula. Solution Quadratic formula $\frac{-b\pm{\sqrt{b^2-4ac}}}{2a}$ Or $\frac{-b\pm{\sqrt{D}}}{2a}$ *Also* *D=b²-4ac* So finding discriminant D=-13²-4×3×-100 =169+1200 putting the VALUE in quadratic formula $\implies\frac{-b\pm{\sqrt{D}}}{2a}$ $\implies\frac{13\pm{\sqrt{1369}}}{2\times3}$ Taking plus value X= $\frac{13+37}{6}$ X= $\frac{50}{6}$ Taking negative value X= $\frac{13-37}{6}$ X= $\frac{-24}{6}$

13.

Find the solution by quadratic equation formula : 3x^2-13x-100=0

Answer»

Given

An Equation

3x²-13x-100=0

To find

The factor by QUADRATIC formula.

Solution

Quadratic formula

$\frac{-b\pm{\sqrt{b^2-4ac}}}{2a}$

Or

$\frac{-b\pm{\sqrt{D}}}{2a}$

Also

D=b²-4ac

So finding discriminant

D=-13²-4×3×-100

=169+1200

putting the VALUE in quadratic formula

$\implies\frac{-b\pm{\sqrt{D}}}{2a}$

$\implies\frac{13\pm{\sqrt{1369}}}{2\times3}$

Taking plus value

X= $\frac{13+37}{6}$

X= $\frac{50}{6}$

Taking negative value

X= $\frac{13-37}{6}$

X= $\frac{-24}{6}$

Discussion

14.	If one root of equation 3x^2 -10x +3 = 0 is 1/3 then the other root is
Answer» Answer: SOLUTION : GIVEN, 3X^2-10x+3=0 3x^2-9x-x+3=0 3x(x-3)-1(x-3)=0 (x-3)((3x-1)=0 x-3=0 or 3x-1=0 (zero PRODUCT law) x=3 or x= 1/3 hence, the other root is 3

14.

If one root of equation 3x^2 -10x +3 = 0 is 1/3 then the other root is

Answer»

Answer:

SOLUTION :

GIVEN,

3X^2-10x+3=0

3x^2-9x-x+3=0

3x(x-3)-1(x-3)=0

(x-3)((3x-1)=0

x-3=0 or 3x-1=0 (zero PRODUCT law)

x=3 or x= 1/3

hence, the other root is 3

Discussion

15.	What is the steps for √35
Answer» ANSWER: ∴ √35 ≅ 5.916.........

15.

What is the steps for √35

Answer»

ANSWER:

∴ √35 ≅ 5.916.........

Discussion

16.	Find the next number in the series2 3/4 5/7 7/10 11/13 13/16 ?
Answer» 13+2/16+3=15/18 Therefore the NEXT NUMBER in the SERIES is 15/18

16.

Find the next number in the series2 3/4 5/7 7/10 11/13 13/16 ?

Answer»

13+2/16+3=15/18

Therefore the NEXT NUMBER in the SERIES is 15/18

Discussion

17.	Evaluate the following 3 by 4 + (minus 2 by 3) minus 5 by 4
Answer» I don't know Step-by-step EXPLANATION: PLEASE SEARCH on GOOGLE

17.

Evaluate the following 3 by 4 + (minus 2 by 3) minus 5 by 4

Answer»

I don't know

Step-by-step EXPLANATION:

PLEASE SEARCH on GOOGLE

Discussion

18.	If x=1-√2, find the value of (x-1/x)3
Answer» Step-by-step EXPLANATION: (1-√2-1/1-√2)3 (-√2/1-√2)*3 -3√2/1-√2

18.

If x=1-√2, find the value of (x-1/x)3

Answer»

Step-by-step EXPLANATION:

(1-√2-1/1-√2)3

(-√2/1-√2)*3

-3√2/1-√2

Discussion

19.	in a triangle ABC right angled at C if AC is equal to 20 cm and a b minus AC is equal to 8 cm then find the value of secA + tanA
Answer» Answer: please REFER to photo✌ Step-by-step EXPLANATION: MARK as BRAINLIEST if it helps✌

19.

in a triangle ABC right angled at C if AC is equal to 20 cm and a b minus AC is equal to 8 cm then find the value of secA + tanA

Answer»

Answer:

please REFER to photo✌

Step-by-step EXPLANATION:

MARK as BRAINLIEST if it helps✌

Discussion

20.	Simplify the product cube root 2 ×4root 2× 12 root 32
Answer» Answer: 768 Step-by-step EXPLANATION: $2 * 4\sqrt{2} * 12 \sqrt{32} \\\\=2 * 4\sqrt{2} * 12\sqrt{22222} \\= 24\sqrt{2} 48\sqrt{2} \\=848\sqrt{2} \sqrt{2}\\=848*2\\=768$ HOPE this HELPS.

20.

Simplify the product cube root 2 ×4root 2× 12 root 32

Answer»

Answer:

768

Step-by-step EXPLANATION:

$2 * 4\sqrt{2} * 12 \sqrt{32} \\\\=2 * 4\sqrt{2} * 12\sqrt{2*2*2*2*2} \\= 2*4\sqrt{2} *48\sqrt{2} \\=8*48*\sqrt{2} *\sqrt{2}\\=8*48*2\\=768$

HOPE this HELPS.

Discussion

21.	What is the ratio of volume to surface area of a sphere?
Answer» Answer: This ratio can be NOTED as SA:V. To find this ratio, you divide the formula for surface area by the formula for volume and then you simplify. If you are given the numbers, then you simply divide the surface area NUMBER by the volume number. *Hope u like it my ans* *Dost PLZ MARK as brainlist dear* ❤☺❤

21.

What is the ratio of volume to surface area of a sphere?

Answer»

Answer:

This ratio can be NOTED as SA:V. To find this ratio, you divide the formula for surface area by the formula for volume and then you simplify. If you are given the numbers, then you simply divide the surface area NUMBER by the volume number.

Hope u like it my ans Dost PLZ MARK as brainlist dear ❤☺❤

Discussion

22.	A machine was purchased for Rs 500000. Its rate of depreciation is 10% in the first year and 5% per annum after wards. Find the depreciated value of the machine after 15 years.
Answer» Answer: Step-by-step EXPLANATION: FIRST it was 500000 2nd yr it was 10%=450000 3yr it was 5%=427500 so 15 yr will be 427500/15=28500

22.

A machine was purchased for Rs 500000. Its rate of depreciation is 10% in the first year and 5% per annum after wards. Find the depreciated value of the machine after 15 years.

Answer»

Answer:

Step-by-step EXPLANATION:

FIRST it was 500000

2nd yr it was 10%=450000

3yr it was 5%=427500

so 15 yr will be 427500/15=28500

Discussion

23.	Simple interest on rs 300 for 7 years at 14 per annum
Answer» Answer: 294 is the answer Step-by-step EXPLANATION: SI=P×R×T÷100 = 300×14×7÷100 =294

23.

Simple interest on rs 300 for 7 years at 14 per annum

Answer»

Answer:

294 is the answer

Step-by-step EXPLANATION:

SI=P×R×T÷100

= 300×14×7÷100

=294

Discussion

24.	SecD=5/4. Evaluate1-tanD/1+tanD
Answer» ANSWER The VALUE of the above EXPRESSION is 1/7 GIVEN: SEC D = 5/4 TO FIND: $\frac{1 - \tan \: d}{1 + \tan \: d}$ SOLUTION: Formula $1 + \tan {}^{2} d \: = \sec {}^{2} d$ Putting Sec d = 5/4 $\implies \: \tan {}^{2} d \: = \sec {}^{2} d - 1 \\ \implies \: \tan {}^{2} d = (\frac{5}{4}) { }^{2} - 1 \\ \implies \: \tan {}^{2} d \: = \frac{25}{16} - 1 \\ \implies \: \tan {}^{2} d \: = \frac{9}{16} \\ \implies \: \tan d \: = \sqrt{ \frac{9}{16} } \\ \implies \: \tan d = \frac{3}{4}$ Putting tan d = 3/4 $= \frac{1 - \tan \: d}{1 + \tan \: d} \\ = \frac{1 - \frac{3}{4} }{1 + \frac{3}{4} } \\ = \frac{ \frac{1}{4} }{ \frac{7}{4} } \\ = \frac{1}{4} \times \frac{4}{7} \\ = \frac{1}{7}$ So , the value of the above expression is 1/7 SOME IMPORTANT FORMULA Tan A = perpendicular/ base Sin A = perpendicular/ HYPOTENUSE Cos A = Base / hypotenuse

24.

SecD=5/4. Evaluate1-tanD/1+tanD

Answer»

ANSWER

The VALUE of the above EXPRESSION is 1/7

GIVEN:

SEC D = 5/4

TO FIND:

$\frac{1 - \tan \: d}{1 + \tan \: d}$

SOLUTION:

Formula

$1 + \tan {}^{2} d \: = \sec {}^{2} d$

Putting Sec d = 5/4

$\implies \: \tan {}^{2} d \: = \sec {}^{2} d - 1 \\ \implies \: \tan {}^{2} d = (\frac{5}{4}) { }^{2} - 1 \\ \implies \: \tan {}^{2} d \: = \frac{25}{16} - 1 \\ \implies \: \tan {}^{2} d \: = \frac{9}{16} \\ \implies \: \tan d \: = \sqrt{ \frac{9}{16} } \\ \implies \: \tan d = \frac{3}{4}$

Putting tan d = 3/4

$= \frac{1 - \tan \: d}{1 + \tan \: d} \\ = \frac{1 - \frac{3}{4} }{1 + \frac{3}{4} } \\ = \frac{ \frac{1}{4} }{ \frac{7}{4} } \\ = \frac{1}{4} \times \frac{4}{7} \\ = \frac{1}{7}$

So , the value of the above expression is 1/7

SOME IMPORTANT FORMULA

Tan A = perpendicular/ base

Sin A = perpendicular/ HYPOTENUSE

Cos A = Base / hypotenuse

Discussion

25.	How many numbers lies between 5 square and 6 square
Answer» Step-by-step explanation: hhey mate here is ur ANSWER 5 square is 25 6 SQAURE is 36 hope it's HELP...... mark me as brainliest

25.

How many numbers lies between 5 square and 6 square

Answer»

Step-by-step explanation:

hhey mate here is ur ANSWER

5 square is 25

6 SQAURE is 36

hope it's HELP......

mark me as brainliest

Discussion

26.	Twosolutionofequation!1 write anyx+y=18.
Answer» ANSWER: x=9 and y=9 x=10 and y=8 Step-by-step explanation: 1) 9+9=18 2)10+8=18

26.

Twosolutionofequation!1 write anyx+y=18.

Answer»

ANSWER:

x=9 and y=9

x=10 and y=8

Step-by-step explanation:

1) 9+9=18

2)10+8=18

Discussion

27.	ANSWER PLEEEEEEEEEEEEEEEASE ToTThe diameter of a metallic sphere is 60 m. The sphere is melted and drawn into a wire of uniformcross-section, if the length of the wire is 36 m, find its radius.
Answer» Answer: Volume of a sphere is : 4/3 × pi × r cube. If r- radius is trebled, it becomes (3r) cube = 27 × r cube= 27 TIMES the ORIGINAL volume. If radius is tripled, then the volume is increased 27 times. If the radius of a sphere is 12 CM, 27 sphere of such radius is MELTED and RECAST to form a new solid sphere.

27.

ANSWER PLEEEEEEEEEEEEEEEASE ToTThe diameter of a metallic sphere is 60 m. The sphere is melted and drawn into a wire of uniformcross-section, if the length of the wire is 36 m, find its radius.

Answer»

Answer:

Volume of a sphere is : 4/3 × pi × r cube. If r- radius is trebled, it becomes (3r) cube = 27 × r cube= 27 TIMES the ORIGINAL volume. If radius is tripled, then the volume is increased 27 times. If the radius of a sphere is 12 CM, 27 sphere of such radius is MELTED and RECAST to form a new solid sphere.

Discussion

28.	Find the value of nnp5 = 6720?
Answer» Answer: nP 5=n! /(n-5)! 6720=n! /(n-5)! 6720=n(n-1) (n-2) (n-3) (n-4) (n-5)! /(n-5)! 6720=n(n-1) (n-2) (n-3) (n-4) 87654=n(n-1) (n-2) (n-3) (n-4) 8(8-1) (8-2) (8-3) (8-4) =n(n-1) (n-2) (n-3) (n-4) so, n=8

28.

Find the value of nnp5 = 6720?

Answer»

Answer:

nP 5=n! /(n-5)!

6720=n! /(n-5)!

6720=n(n-1) (n-2) (n-3) (n-4) (n-5)! /(n-5)!

6720=n(n-1) (n-2) (n-3) (n-4)

8*7*6*5*4=n(n-1) (n-2) (n-3) (n-4)

8(8-1) (8-2) (8-3) (8-4) =n(n-1) (n-2) (n-3) (n-4)

so, n=8

Discussion

29.	Why {3,4} is not a subset of set A = {1,2,{3,4},5}
Answer» Step-by-step EXPLANATION: No , *because* the REAL set is {3,3. 4,4. 4,3 .3,4 } is the correct set of A HOPE YOU UNDERSTAND MAR**K AS BRAINALIEST

29.

Why {3,4} is not a subset of set A = {1,2,{3,4},5}

Answer»

Step-by-step EXPLANATION:

No , because the REAL set is {3,3. 4,4. 4,3 .3,4 } is the correct set of A

HOPE YOU UNDERSTAND

MARK AS BRAINALIEST

Discussion

30.	Greatest commom divisor of 536 and 214
Answer» ANSWER: HCF of 536 and 214 536= 2 ×2×2×67 214=2×107 hence the HIGHEST common factor or gcd of 536 and 214 = 2

30.

Greatest commom divisor of 536 and 214

Answer»

ANSWER:

HCF of 536 and 214

536= 2 ×2×2×67

214=2×107

hence the HIGHEST common factor or gcd of 536 and 214 = 2

Discussion

31.	Reduse the equation into pair of linear equations. above equation
Answer» Answer: x=1/2. y=1 Explanation take 1/x=a. & 1/y=b then EQN becomes 2a+3b=5 5a-8b=2 solve and GET answer written above mark me BRANLIEST

31.

Reduse the equation into pair of linear equations. above equation

Answer»

Answer:

x=1/2. y=1

Explanation

take 1/x=a. & 1/y=b

then EQN becomes

2a+3b=5

5a-8b=2

solve and GET answer written above

mark me BRANLIEST

Discussion

32.	If (1-b) is a root of x^2+bx+(1-b)=0 then find the other root
Answer» ANSWER: 1 Step-by-step explanation: Here (1-b) is a root. as product of ROOTS = $\alpha \beta = \frac{c}{a}$ so.. $(1 - b) \times \beta = \frac{1 - b}{1}$ then. $\beta = 1$ hope it helps MARK as brainliest..

32.

If (1-b) is a root of x^2+bx+(1-b)=0 then find the other root

Answer»

ANSWER:

1

Step-by-step explanation:

Here (1-b) is a root.

as product of ROOTS =

$\alpha \beta = \frac{c}{a}$

so..

$(1 - b) \times \beta = \frac{1 - b}{1}$

then.

$\beta = 1$

hope it helps

MARK as brainliest..

Discussion

33.	Please find the answers
Answer» <P>Answer: Step-by-step EXPLANATION:GIVEN, f(x) = px^2+5x+R and FACTORS are x-2, x-1/2 Substitute x = 2 in place of equation, we get *= p2^2+52+r=0* = 4p + 10 + r = 0 ------------ (i) Substitute x = 1/2 in place of equation. p/4 + 5/2 + r = 0 p + 10 + 4r = 0 ------------------- (ii) On solving (i),(ii) we get 4p+r=-10 and p+4r+10=0 4p+r=p+4r 3p=3r p = r. Hope this helps!

33.

Please find the answers

Answer»

<P>Answer:

Step-by-step EXPLANATION:GIVEN, f(x) = px^2+5x+R and FACTORS are x-2, x-1/2

Substitute x = 2 in place of equation, we get

= p*2^2+5*2+r=0

= 4p + 10 + r = 0 ------------ (i)

Substitute x = 1/2 in place of equation.

p/4 + 5/2 + r = 0

p + 10 + 4r = 0 ------------------- (ii)

On solving (i),(ii) we get

4p+r=-10 and p+4r+10=0

4p+r=p+4r

3p=3r

p = r.

Hope this helps!

Discussion

34.	(14275.If a, b and c be three distinct real numbes in G.P. and a+b+c= xb, then x cannot be:(1) 4(2) - 3(3) 2(4) -2
Answer» ANSWER: answer is 4 MARK my answer BRAINLIEST

34.

(14275.If a, b and c be three distinct real numbes in G.P. and a+b+c= xb, then x cannot be:(1) 4(2) - 3(3) 2(4) -2

Answer»

ANSWER:

answer is 4

MARK my answer BRAINLIEST

Discussion

35.	Which number has 1 hundred,3 more tens than hundred,3 more ones than tens
Answer» Answer: 133 Step-by-step EXPLANATION: =(1 HUNDRED =100)+(3 tens=30)+(3 ones=3) =133 hope you understood plz make BRAINLIEST

35.

Which number has 1 hundred,3 more tens than hundred,3 more ones than tens

Answer»

Answer:

133

Step-by-step EXPLANATION:

=(1 HUNDRED =100)+(3 tens=30)+(3 ones=3)

=133

hope you understood

plz make BRAINLIEST

Discussion

36.	The least square no which is exactlydivisible by each2,3,4
Answer» ANSWER: The LEAST SQUARE no. is 36=√6. PLEASE RATE my answer.

36.

The least square no which is exactlydivisible by each2,3,4

Answer»

ANSWER:

The LEAST SQUARE no. is 36=√6. PLEASE RATE my answer.

Discussion

37.	9. Consider a combination lock consisting of 3 buttons that can bepressed in any combination (including multiple buttons at a time), but insuch a way that each number is pressed exactly once. Then the totalnumber of possible combination locks with 3 buttons is(A) 6; (B) 9;(C) 10;(D) 13.
Answer» Answer: OPTION B is the correct answer MARK me as BRAINLIEST and please follow me and thank me for a while

37.

9. Consider a combination lock consisting of 3 buttons that can bepressed in any combination (including multiple buttons at a time), but insuch a way that each number is pressed exactly once. Then the totalnumber of possible combination locks with 3 buttons is(A) 6; (B) 9;(C) 10;(D) 13.

Answer»

Answer:

OPTION B is the correct answer MARK me as BRAINLIEST and please follow me and thank me for a while

Discussion

38.	A chord of a circle of radius 12cm subtends an angle of 120° at the center. Find the area of thecorresponding minor segment of the circle.
Answer» Answer: GIVEN: Radius of CIRCLE = 12 cm θ = 120° Area of the segment= {(π/360) × θ - sin θ/2 cos θ/2} r² Area of the segment={(π) × 120/360 - sin 120/2 cos 120/2 } 12² = {(π) × ⅓ - sin 60° cos 60° } ×144 = (π/3 - ½ × √3/2) × 144 = (π/3 × 144 - 144 × √3/4 = 48π - 36√3 = 12(4π - 3√3) = 12( 4 × 3.14 - 3 × 1.73) [π = 3.14 , √3= 1.73] = 12 (12.56 - 5.19) = 12 × 7.37 = 88.44 cm² Hence, the area of the corresponding segment of the circle is 88.44 cm². HOPE THIS WILL HELP YOU Please mark it as BRAINLIEST answer if you like the answer and follow me ☺️☺️

38.

A chord of a circle of radius 12cm subtends an angle of 120° at the center. Find the area of thecorresponding minor segment of the circle.

Answer»

Answer:

GIVEN:

Radius of CIRCLE = 12 cm

θ = 120°

Area of the segment= {(π/360) × θ - sin θ/2 cos θ/2} r²

Area of the segment={(π) × 120/360 - sin 120/2 cos 120/2 } 12²

= {(π) × ⅓ - sin 60° cos 60° } ×144

= (π/3 - ½ × √3/2) × 144

= (π/3 × 144 - 144 × √3/4

= 48π - 36√3

= 12(4π - 3√3)

= 12( 4 × 3.14 - 3 × 1.73)

[π = 3.14 , √3= 1.73]

= 12 (12.56 - 5.19)

= 12 × 7.37

= 88.44 cm²

Hence, the area of the corresponding segment of the circle is 88.44 cm².

HOPE THIS WILL HELP YOU

Please mark it as BRAINLIEST answer if you like the answer and follow me ☺️☺️

Discussion

39.	In a quadratic equation D>0 then it has,
Answer» Answer: I think answer is C REAL and unequal ROOTS

39.

In a quadratic equation D>0 then it has,

Answer»

Answer:

I think answer is C REAL and unequal ROOTS

Discussion

40.	The diameter of a metallic sphere is 60 m. The sphere is melted and drawn into a wire of uniformcross-section, if the length of the wire is 36 m, find its radius.
Answer» Answer: The METALLIC sphere is Maybe 6m not 60 The wire is in the SHAPE of a cylinder. Since the sphere is melted and a cylindrical wire is formed, their volumes are EQUAL. Volume of a sphere =34πr3 As the diameter of the sphere is 6 cm, its radius r=3 cm Volume of a Cylinder =πR2h Length of the wire h=36m=3600cm Hence, Volume of sphere = Volume of the wire 34πr3=πR2h R2=1001 R=101=0.1cm Hence, radius of the cross-section of the wire =0.1cm

40.

The diameter of a metallic sphere is 60 m. The sphere is melted and drawn into a wire of uniformcross-section, if the length of the wire is 36 m, find its radius.

Answer»

Answer:

The METALLIC sphere is Maybe 6m not 60

The wire is in the SHAPE of a cylinder.

Since the sphere is melted and a cylindrical wire is formed, their volumes are EQUAL.

Volume of a sphere =34πr3

As the diameter of the sphere is 6 cm, its radius r=3 cm

Volume of a Cylinder =πR2h

Length of the wire h=36m=3600cm

Hence, Volume of sphere = Volume of the wire

34πr3=πR2h

R2=1001

R=101=0.1cm

Hence, radius of the cross-section of the wire =0.1cm

Discussion

41.	M is the sister of D.R is the brother of D.N is the father of Mand T is mother R.How is D related to T
Answer» ANSWER: D is SON of R and R is MOTHER of D. hope it will help

41.

M is the sister of D.R is the brother of D.N is the father of Mand T is mother R.How is D related to T

Answer»

ANSWER:

D is SON of R and R is MOTHER of D. hope it will help

Discussion

42.	Estimated sum of 1238 +4298
Answer» ESTIMATED SUM is 5540

Discussion

43.	Short essay on my dream profession to become an engineer
Answer» Step-by-step explanation: . The man-made world which consists of machines and devices aroused my curiosity since I was a child. I used to always keep wondering of how a machine operates and how every part of a machine compliment with each other to function well. As a child, I thought that the creators of these machines must have been magicians who are able to command supernatural powers to make a machinery works. And the reason grows along my age. Despite this, I still believe that engineers are magicians; they are the last remaining practitioners of this art in an increasingly modernised world. They continue to amaze and captivate the world with their creations. And they never seemed to be running out of tricks from their sleeves. The thought of how great the profession of engineering keeps lingering in my mind, and I think it will be the same for everyone. [1]Take a glimpse look around you; can you jot down anything that is not relying to certain degree on the work of engineers? I bet anyone WOULD struggle on it. Because of that particular reason I chose to be on this lane, to serve community with a better technology that will shape the century and change the world. However, it was the entire previous story because right now I have been on the platform of the sound tertiary education that will provide me with the best experience the embryonic engineer can have. Only one problem remains; how to grab this chance to make the DREAM of becoming an engineer come to reality. Time is said to be precious because it is irreversible. Others said that it is eternal. But the main point here is what is done today is not tomorrow, and what is in the past cannot be in the present – because time moves. You cannot predict what will happen today or in the future because it is yet to come but you experienced yesterday’s event however it is not in your jurisdiction to change that occurrence. That is why it is said that time resembles gold caused by its preciousness. This principle goes well with engineers’ life. Time management is not something that you can let it happen by itself, it needs a proper planning. Even though people said that time changes things but, actually we have to change them ourselves. Professional engineer is someone who knows how to juggle many things at one time. They work to enhance welfare, health and safety of all and make professional commitments to boost the wellbeing of society through the exploitation of knowledge and the management of creative terms. But, frankly speaking, I was a student who practised procrastination in my study. I kept saving all the works given on the eleventh hour – this was during the high school era, and in the early life as a university student. However, the HECTIC life of first year student with assignments and tests educates me that engineers will not just be an idle person but need to devote themselves in acquiring and cramming a brand new technology in physical world. However, what happens if I keep saving all the work till the last minute? Will I be able to prepare myself then to discover some new knowledge? These kind of thoughts that kept wandering in my mind, helped me to get a picture that no matter how eventful my life with works is, I need to get them done once I got assigned. So I decided to make an improvement to my study style. I made a to-do list bright and early, as the first task of the commencement of my day; on a clear white paper to prevent me from wasting any time worrying about anything that I might forget. Therefore my whole activities throughout the day tend to follow this list without even a second being wasted. This forces me not to make a group meeting turns to a worthless chat, or whenever I bump into someone it will not become a ‘reunion party’ – because every single second counts. Thus, sometimes I need to say no for a certain matter although it is a very hard thing to do for most people but I believe that it has a tremendous reward. Normally my whole night is filled with either ‘twitter’ing, ‘facebook’ing or watching drama (since I am a drama enthusiast), however, the to-do list that I made has replaced those TIMES with something beneficial to my study; either preparing for laboratories, tests, or make a quick revision for the next lectures. For instance, assignment given to SESM1015 Professional Engineering students (absolutely this essay) makes my night more meaningful. 30 MINUTES watching drama has been replaced by 15 minutes essay writing – even though at first it was a bit hard to get used to.

43.

Short essay on my dream profession to become an engineer

Answer»

Step-by-step explanation:

.

The man-made world which consists of machines and devices aroused my curiosity since I was a child. I used to always keep wondering of how a machine operates and how every part of a machine compliment with each other to function well. As a child, I thought that the creators of these machines must have been magicians who are able to command supernatural powers to make a machinery works. And the reason grows along my age. Despite this, I still believe that engineers are magicians; they are the last remaining practitioners of this art in an increasingly modernised world. They continue to amaze and captivate the world with their creations. And they never seemed to be running out of tricks from their sleeves. The thought of how great the profession of engineering keeps lingering in my mind, and I think it will be the same for everyone. [1]Take a glimpse look around you; can you jot down anything that is not relying to certain degree on the work of engineers? I bet anyone WOULD struggle on it. Because of that particular reason I chose to be on this lane, to serve community with a better technology that will shape the century and change the world. However, it was the entire previous story because right now I have been on the platform of the sound tertiary education that will provide me with the best experience the embryonic engineer can have. Only one problem remains; how to grab this chance to make the DREAM of becoming an engineer come to reality.

Time is said to be precious because it is irreversible. Others said that it is eternal. But the main point here is what is done today is not tomorrow, and what is in the past cannot be in the present – because time moves. You cannot predict what will happen today or in the future because it is yet to come but you experienced yesterday’s event however it is not in your jurisdiction to change that occurrence. That is why it is said that time resembles gold caused by its preciousness. This principle goes well with engineers’ life. Time management is not something that you can let it happen by itself, it needs a proper planning. Even though people said that time changes things but, actually we have to change them ourselves. Professional engineer is someone who knows how to juggle many things at one time. They work to enhance welfare, health and safety of all and make professional commitments to boost the wellbeing of society through the exploitation of knowledge and the management of creative terms. But, frankly speaking, I was a student who practised procrastination in my study. I kept saving all the works given on the eleventh hour – this was during the high school era, and in the early life as a university student. However, the HECTIC life of first year student with assignments and tests educates me that engineers will not just be an idle person but need to devote themselves in acquiring and cramming a brand new technology in physical world. However, what happens if I keep saving all the work till the last minute? Will I be able to prepare myself then to discover some new knowledge? These kind of thoughts that kept wandering in my mind, helped me to get a picture that no matter how eventful my life with works is, I need to get them done once I got assigned. So I decided to make an improvement to my study style. I made a to-do list bright and early, as the first task of the commencement of my day; on a clear white paper to prevent me from wasting any time worrying about anything that I might forget. Therefore my whole activities throughout the day tend to follow this list without even a second being wasted. This forces me not to make a group meeting turns to a worthless chat, or whenever I bump into someone it will not become a ‘reunion party’ – because every single second counts. Thus, sometimes I need to say no for a certain matter although it is a very hard thing to do for most people but I believe that it has a tremendous reward. Normally my whole night is filled with either ‘twitter’ing, ‘facebook’ing or watching drama (since I am a drama enthusiast), however, the to-do list that I made has replaced those TIMES with something beneficial to my study; either preparing for laboratories, tests, or make a quick revision for the next lectures. For instance, assignment given to SESM1015 Professional Engineering students (absolutely this essay) makes my night more meaningful. 30 MINUTES watching drama has been replaced by 15 minutes essay writing – even though at first it was a bit hard to get used to.

Discussion

44.	Under root x (x-7)=3 under root 2
Answer» Answer: √x(x-7)=3√2 Therefore by making SQUARING on both SIDES.. x(x-7)=(3√2)^2 x^2-7x=18 x^2-7x-18=0 Factorising this EQUATION we get... (x+2)(x-9)=0 Which implies that x can be EQUAL to -2 or 9 Hope it helps... Plz mark brainliest And plz follow

44.

Under root x (x-7)=3 under root 2

Answer»

Answer:

√x(x-7)=3√2

Therefore by making SQUARING on both SIDES..

x(x-7)=(3√2)^2

x^2-7x=18

x^2-7x-18=0

Factorising this EQUATION we get...

(x+2)(x-9)=0

Which implies that x can be EQUAL to -2 or 9

Hope it helps...

Plz mark brainliest

And plz follow

Discussion

45.	Show that the number 336 and 275 are co-primes
Answer» Answer: 336 = 2 × 2 × 2 × 2 × 3 × 7 275 = 5 × 5 × 11 There is no COMMON FACTOR of 336 and 275 other than 1. Hence, 336 and 275 are co-prime numbers.

45.

Show that the number 336 and 275 are co-primes

Answer»

Answer:

336 = 2 × 2 × 2 × 2 × 3 × 7

275 = 5 × 5 × 11

There is no COMMON FACTOR of 336 and 275 other than 1. Hence, 336 and 275 are co-prime numbers.

Discussion

46.	Square ABCD is drawn with vertex C on circle A. If the radius of the circle is 8 cm, then what is the area of the square in square centimeters.
Answer» Step-by-step explanation: ABCD be the square INSCRIBED by the circle. ∴OA=OB=OC=OD ABC is a right angled triangle, as OA=8,OB=8 AB=8+8=16 According to Pythagoras THEOREM, Square of hypotenuse = SUM of squares of other two sides. AC 2 =AB 2 +BC 2 As ABCD is a square all the sides are equal, AB=BC AC 2 =2AB 2 16 2 =2AB 2 ∴AB=8 2 therefore side of the square =8 2 AREA of square =(8 2 ) 2 =128cm 2

46.

Square ABCD is drawn with vertex C on circle A. If the radius of the circle is 8 cm, then what is the area of the square in square centimeters.

Answer»

Step-by-step explanation:

ABCD be the square INSCRIBED by the circle.

∴OA=OB=OC=OD

ABC is a right angled triangle, as OA=8,OB=8

AB=8+8=16

According to Pythagoras THEOREM,

Square of hypotenuse = SUM of squares of other two sides.

AC

2

=AB

2

+BC

2

As ABCD is a square all the sides are equal, AB=BC

AC

2

=2AB

2

16

2

=2AB

2

∴AB=8

2

therefore side of the square =8

2

AREA of square =(8

2

)

2

=128cm

2

Discussion

47.	The cost of 1 chair is rupees 650 ❓ is the cost of 4 such chairs?
Answer» ANSWER: cost of 1 CHAIR is 650 the cost of 4 chairs are 650×4 2,600 is the correct answer

47.

The cost of 1 chair is rupees 650 ❓ is the cost of 4 such chairs?

Answer»

ANSWER:

cost of 1 CHAIR is 650

the cost of 4 chairs are 650×4

2,600 is the correct answer

Discussion

48.	What is the period of 0.123 bar
Answer» Answer: Here it is. Please follow me and mark as Brainliest! :) Step-by-step explanation: Let x=0.123…..(bar 23) (1) MULTIPLYING both SIDE by 100 100x=1.23….(bar 23)(2) Multiplying both side by 1000 1000x=123.23……..(3) Subtract (2) from (3) 1000x-100x=123.23-1.23 990x=122 X=122/990answer

48.

What is the period of 0.123 bar

Answer»

Answer:

Here it is. Please follow me and mark as Brainliest! :)

Step-by-step explanation:

Let x=0.123…..(bar 23) (1)

MULTIPLYING both SIDE by 100

100x=1.23….(bar 23)(2)

Multiplying both side by 1000

1000x=123.23……..(3)

Subtract (2) from (3)

1000x-100x=123.23-1.23

990x=122

X=122/990answer

Discussion

49.	Find the fourth proportional of 16 50 88
Answer» ANSWER: HOPE so it HELPS .:) Step-by-step EXPLANATION: The answer is x=275.

49.

Find the fourth proportional of 16 50 88

Answer»

ANSWER:

HOPE so it HELPS .:)

Step-by-step EXPLANATION:

The answer is

x=275.

Discussion

50.	A number z is 4 times the sum of its digits and twice the product of the digits. find the numbers
Answer» ANSWER: Step-by-step explanation: Given, TWO digit number is four times the sum of its digits. SUBSTITUTE eqn (1) i.e., y=2x in the above eqn. Hence the two digit number is xy=36. Originally Answered: A two-digit number is four times the sum of digit and twice the product of its digits

50.

A number z is 4 times the sum of its digits and twice the product of the digits. find the numbers

Answer»

ANSWER:

Step-by-step explanation:

Given, TWO digit number is four times the sum of its digits. SUBSTITUTE eqn (1) i.e., y=2x in the above eqn. Hence the two digit number is xy=36. Originally Answered: A two-digit number is four times the sum of digit and twice the product of its digits

Discussion

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