1.

If (1-b) is a root of x^2+bx+(1-b)=0 then find the other root​

Answer»

ANSWER:

1

Step-by-step explanation:

Here (1-b) is a root.

as product of ROOTS =

\alpha \beta = \frac{c}{a}

so..

(1 - b) \times \beta = \frac{1 - b}{1}

then.

\beta = 1

hope it helps

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