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A chord of a circle of radius 12cm subtends an angle of 120° at the center. Find the area of thecorresponding minor segment of the circle. |
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Answer» Answer: Radius of CIRCLE = 12 cm θ = 120° Area of the segment= {(π/360) × θ - sin θ/2 cos θ/2} r² Area of the segment={(π) × 120/360 - sin 120/2 cos 120/2 } 12² = {(π) × ⅓ - sin 60° cos 60° } ×144 = (π/3 - ½ × √3/2) × 144 = (π/3 × 144 - 144 × √3/4 = 48π - 36√3 = 12(4π - 3√3) = 12( 4 × 3.14 - 3 × 1.73) [π = 3.14 , √3= 1.73] = 12 (12.56 - 5.19) = 12 × 7.37 = 88.44 cm² Hence, the area of the corresponding segment of the circle is 88.44 cm². HOPE THIS WILL HELP YOU Please mark it as BRAINLIEST answer if you like the answer and follow me ☺️☺️ |
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