This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 2. |
7. A company declares a dividend of 11.2% tov all its share-holders. If its * 60 share isavailable in the market at a premium of 25%,how much should Rakesh invest, in buying theshares of this company, in order to have anannual income of * 1,680 ? |
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Answer» Step-by-step explanation: Nominal value of 1 SHARE =Rs. 60 Market value of 1 share =Rs. 60+25% of Rs. 60=Rs. 60+Rs. 15=Rs. 75 Let no. of SHARES purchased =n Then nominal value of n shares =Rs. (60n) DIVIDEND(%)=11.2% Dividend =Rs. 1680 ∴11.2% of 60n=Rs.1680 ⇒ 100 11.2
×60n=1680 ⇒n |
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| 3. |
Howto find cube root Simple method |
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| 4. |
Find the value of i ^29+i ^39+i ^49 / i ^30+i ^40+i ^50pls ASAP |
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| 5. |
42. A body travelsbe the distance travelled in the oth second*43. A body travels 10 m in first three seconds and 15 m in the next four seconds. Whatis the velocity at the end of gth second?(Ans. 2.54 ms-1)hody starts from rest and is uniformly accelerated. It travels a distance x in t s.14 |
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Answer» ANS 2.54ms-1 Step-by-step EXPLANATION: which Q 42or43 |
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| 7. |
Find the volume of a wall 30 cm thick to build a room 10 m ling,8m wide and 3.5 m high leaving 1.06 m3 of the volume for the doors and windows |
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Answer» Answer: It is given, walls of a room, this MEANS the LATERAL SURFACE area we know that lateral surface area =2h(l+b) =2×5(10+8) 180 {m}^{2}180m 2
\begin{lgathered}length \: of \: the \: paper \: REQUIRED \\ = \frac{180}{50}\end{lgathered} lengthofthepaperrequired = 50 180
=3.6 m is the length of paper required. |
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| 8. |
2. If the diagonals of a square are 10 cm each, find theside of the square. |
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Answer» Answer: hello! here's the answer! Step-by-step explanation: Let ABCD be the given square, THEREFORE, AB= BC= CD =DC = x AC = DB = 10cm But, Angles of a SQUARE are 90° therefore, by Pythagoras theorem in triangle ABC AC² = AB² + BC² 10² = x +x 100 =2 x² x ²= 50 x = 5√2 |
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| 9. |
4.The number of szorousx² + 4x + 2a) 1b 2c 3 |
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Answer» Step-by-step EXPLANATION: |
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| 10. |
A is 70% more efficient than B. In how many A days will the work that A alone could complete in 9 days be done by both of them together |
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Answer» Answer: 70/@09×9 |
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| 11. |
A1. ABCD is a rectangle. E is a pointon AB such that AD = AE. FindZx and Zy. |
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Answer» |
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| 12. |
Find the value of 'b' for whichthe points A (1, 2) 13 (-13b) andC (-3,-4) are collinear |
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Answer» B = -38 |
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| 13. |
इसको समझ कर पढ़ो और लिखो फिर मेरे को भी इसको समझ कर दिखाओ और आंसर भेज दो |
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Answer» a B a b is the answer for QUESTIONS and for 2 one you should write 11 12 13 14 15 16 17 18 19 |
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| 14. |
EXERCISE C)much shouldof 2three persfor 3 gangproa proto windng pnoe of these themhe perbentage pront on the* Moran bugtenfor 500 H of them at percentAwhatprice shoulding noteDOORSto gain 10%Raju selis a atch at 5 prone Madhe soldfor 24 more, he would have gained 11%Find the cost pnce of thesold a bicycle at 5% profit the costne orangeto be bought andfor so gainingof ancies bought |
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| 15. |
Give Examples for:Squares of any 5 even numbersSquares of any 5 odd numbersSquares of numbers ending with 1Squares of numbers ending with 2, 8 |
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| 16. |
Hey guys please solve this question this question has to be solved from formula of geometric progression... |
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Answer» ANSWER: 4/3 Step-by-step explanation: |
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| 17. |
15.The perimeter of a rectangle is 13 cm and its width is 2 3/4 cm. find its length.Perimeter aadec= 13cm.ga rectangle |
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Answer» As we know,perimeter of rectangle=2× (l+b) THEREFORE, 2×(2 3/4+b) Now again as we know, perimeter=13cm Therefore,2 (2 3/4+b)=13 2(11/4+b)=13 11/4+b=13/2 b=13/2-11/4 b=13×2/2×2-11/4 b=26/4-11/4 b=15/4cm |
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| 18. |
3. Find the value of the polynomial 5x – 4x2 + 3 at x = 2 and x = -1 |
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| 19. |
2. A rhombus is such that one of its diagonals is equalto the side of the rhombus. Find the angles of therhombus. |
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Answer» Let ABCD is a rhombus in which AB=BC=CD=DA=diagonal CA. In triangle BAC BA=BC=CA , therefore ANGLE BAC=angle ABC= angle ACB =60°………(1) Similarly in triangle DAC , DA=DC=CA , therefore Angle DAC=angle ACD=angle ADC=60°……….(2) From eqn. (1) and (2) Angle A=angle BAC+angle DAC=60°+60°=120° Angle B= angle ABC = 60°. Angle C=angle ACB+angle ACD=60°+60°=120° Angle D =angle ADC=60°.
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| 20. |
If Dx = 12 and D = -4, what is the value of x? |
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Answer» Step-by-step EXPLANATION: Dx = 12 -4x = 12 x = 12/-4 x= -3 |
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| 21. |
Find the number of the cube of side 2cm which can be cut from a cube of the side6cm |
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Answer» Step-by-step explanation: 6 CUBES.........hope i BELIEVE UR satisfied.....xD |
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| 22. |
Anb in rule methodPls answer fast Don't spam |
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Answer» Answer: Rule Method This method INVOLVES specifying a rule or condition which can be USED to DECIDE whether an OBJECT can belong to the set. This rule is written inside a pair of curly braces and can be written either as a statement or expressed SYMBOLICALLY or written using a combination of statements and symbols. |
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| 23. |
Which of the following has x=0 as a solution ?A) x+(-2)=0B) x+3=5C) 2x+1=1D) none of these |
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Answer» ANSWER IS A |
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| 24. |
1. One angle of a rhombus is 75º. Find all its angles. |
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Answer» Answer: 75° , 105° , 105° Steps are GIVEN in the ATTACHMENT |
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| 25. |
PLS ANSWER.....FAST...URGENT WITH STEPSsmallest prime factor of the integer 2005^2007 + 2007^2005 |
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Answer» 2005×2007+2007×2005 2005×2005-2007+2007 4020025-9014 the answer is 4011011 follow me and mark as a brainliest |
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| 26. |
Evaluate (1+ tan theta+ sec theta) (1 + cot theta - cosec theta ) |
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Answer» Step-by-step EXPLANATION: |
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| 27. |
Write the smallest digit and the largest digit in the blank space of each of the following numbers so that the number formed is divisible by 11:- 92__3898__9484 |
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Answer» Answer: 2 0 |
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| 28. |
The total cost of 6 books and 7 pens is 79 rupees and the total cost of 7 books and 5 pensis 77 rupeess. Find the cost of 1 book and 2 pens. |
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Answer» Step-by-step explanation: let the number of books Be X let the number of pens be y according to question 6 X + 7 y is equals to 79 rupees------1 7 x + 5 y is equal to 77 rupees-------2 multiply equation 1 by 5 30 X + 35 y is equals to 395 rupees----3 multiplying equation 2 by 7 49 X + 35 y is equal to 539----4 substrating 1 from 2 19x=144 x=7.58 rs I feel that the question is wrong because x is not coming in whole no.. |
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| 29. |
NRESADOSeach offollowing by Rationalizing(6)12 +337-353co)ده6+38-55JS +5SF-2- |
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Answer» Answer: msdjjdjjx Step-by-step explanation: |
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| 30. |
A(b+c) =ab+ac, is it applicable to matrices |
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Answer» Step-by-step explanation: of ANSWERS here, but I think there are still some more things worth saying. It has been noted that AB=ACAB=AC is equivalent to A(B−C)=[0]A(B−C)=[0] . Of course, BB and CC can be anything if A=[0]A=[0] , so let’s assume AA is not the zero matrix. We do not assume that the matrices in question are square! An easy situation in which we can conclude B=CB=C is if AA has a left inverse LL . Since AA is not ASSUMED square, left inverse and right inverse are not necessarily the same thing and we don’t dare write L=A−1L=A−1 ! Still, applying LL to both sides of A(B−C)=[0]A(B−C)=[0] gives B−C=[0]B−C=[0] and so B=CB=C . AA having a left inverse is equivalent to the columns of AA being linearly independent, also equivalent to the NULL space of AA being zero, in which case one of the infinitely many left inverses is L=(ATA)−1AT.L=(ATA)−1AT. ( ATAATA is square and so capable of being invertible, but you have to CHECK that ATAATA is non-singular if the columns of AA are linearly independent…) So lets suppose the columns of AA are not linearly independent, or equivalently that AA does not have a left inverse, or that the null space of AA is not trivial. Another way of saying A(B−C)=[0]A(B−C)=[0] is that the column space of B−CB−C is contained in the now non-trivial null space of AA , written Col(B−C)⊆Null(A)Col(B−C)⊆Null(A) . In this situation, we can turn things around and describe (in principle) how to create all possible examples of AB=ACAB=AC with B≠CB≠C . Let AA be m×nm×n . The equality AB=ACAB=AC tells us that both BB and CC have to have nn ROWS, and that BB and CC have to have the same number of columns (how many is up to us). So lets say that we’ll concoct BB and CC with kk columns each, which means they will both be n×k.n×k. The condition Col(B−C)⊆Null(A)Col(B−C)⊆Null(A) says that the kk columns of B−CB−C have to span a subspace of Null(A)Null(A) . So take n1,n2,…,nk∈Null(A)n1,n2,…,nk∈Null(A) and let NN be the matrix whose columns are n1,n2,…,nkn1,n2,…,nk . Let CC be an arbitrary n×kn×k matrix and then set B=C+NB=C+N . Then obviously Col(B−C)=Col(N)=Span{n1,n2,…,nk}⊆Null(A)Col(B−C)=Col(N)=Span{n1,n2,…,nk}⊆Null(A) , and so A(B−C)=[0]A(B−C)=[0] as desired. More concisely, A(C+N)=AC+AN=AC+[0]=ACA(C+N)=AC+AN=AC+[0]=AC , but C+N≠C.C+N≠C. Every example of AB=ACAB=AC with B≠CB≠C is of this type To give a pretty trivial example of all this, take A=[100100].A=[100010]. Then Null(A)=Span⎡⎣⎢001⎤⎦⎥.Null(A)=Span[001]. So lets take n1=⎡⎣⎢001⎤⎦⎥ and n2=⎡⎣⎢002⎤⎦⎥, so that N=⎡⎣⎢001002⎤⎦⎥.n1=[001] and n2=[002], so that N=[000012]. Now take C=⎡⎣⎢135246⎤⎦⎥, in which case B=C+N=⎡⎣⎢136248⎤⎦⎥,C=[123456], in which case B=C+N=[123468], and it is obvious that AB=ACAB=AC but B≠CB≠C . Reading back through this, we can say that in order for AA to be “left cancellable,” meaning that AB=AC⟹B=CAB=AC⟹B=C for all possible matrices BB and CC , it is necessary and sufficient that one of the following equivalent conditions hold: The columns of AA are linearly independent. The null space of AA is trivial. AA has left inverses, (one of which is (ATA)−1AT(ATA)−1AT ) |
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| 32. |
The perimeter of a rectangle is 13 cm and its width is 23/4m. find its length. |
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Answer» Answer: perimeter of RECTANGLE = 2(L+b) 13= 2(l + 23/4) 13/2= l + 23/4 length = 13/2 - 23/4 length= 3/4 Hope its help you....❤ |
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| 33. |
What is the number of diagonal In a octagon |
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Answer» Answer: 20 diagonals To FIND the total number of diagonals in a POLYGON, multiply the number of diagonals PER vertex (n - 3) by the number of vertices, n, and divide by 2 (otherwise each diagonal is counted twice). Therefore, There are 20 diagonals in a regular OCTAGON.... |
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| 34. |
4. ABCD is an isosceles trapezium with AB || CD andAD = BC. ZA= 60°, CD = 20 cm, and BC = 10 cm.Find AB. |
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| 35. |
If the product of the zero of the polynomial p(c) = kx²-6x-6 is 4. find the value of k. |
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Answer» Answer: Answer:The VALUE of a is -1.5 and the sum of its ZEROES is -4. , then the sum of zeroes is -b/a and the product of zeroes is c/a. It is GIVEN that the product of zeroes the given polynomial is 4. |
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Solurer pistance10o0km 400m1000.400 m11 Комц 30 min — 16 цолаspeed Distance1000Time160001000 400 1000 250116ooo10040TuooSpeed2.50 km/hy.yo |
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Answer» I have not UNDERSTOOD the QUESTION |
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| 39. |
Solve this work sheet fast |
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Answer» your answer is 39.2857142857 ans 2 6ans 3 5.975ans 4 54ans 5 42.8666666667ans 6 25.4ans 7 16.7083333333ans 8 83.5ans |
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| 40. |
1. The heat loss h (in Watts) through a single-pane glass window varies jointly with the window’s area A (in square metres) and the difference between the inside and outside temperatures d (in Kelvins).(a) Write an equation relating h, A, d, and a constant, k.(b) A single-pane window with an area of 1 square metre and a temperature difference of 1 Kelvin has a heat loss of 5.7 Watts. What is the heat loss through a single-pane window with an area of 2.5 square metres and a temperature difference of 20 Kelvins?This is a math word problem on variables please answer it like a math problem, not a science problem. Thanks. |
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Answer» Answer: a) h=kAd, b) 285 Watts Step-by-step explanation: Heat LOSS- h, Window's are- A, Temperature DIFFERENCE- d, Constant- k h varies jointly with A and d, then the EQUATION will be:
Equation will reflect this as:
When A= 2.5 m², d= 20, h=?
Answer: a) h=kAd, b) 285 Watts |
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| 41. |
Formula of perimeter of square |
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Answer» Answer: 2(L+B) HOPE you are SATISFIED from my answer PLEASE MARK my answer as BRAINLIEST and follow me |
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| 42. |
13. एक रेलगाड़ी को 45 सेकण्ड में रोकने के लिये लगने वाले आवश्यकबल की गणना करें जबकि रेलगाड़ी का भार 2200 किग्रा. है औरयह 60 किमी./घंटा के वेग से दौड़ रही है। |
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| 43. |
Maths Questionfactorise the followingA3+27 |
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Answer» (A)^3+(3)^3 since, x^3+y^3=(x+y)(x^2-xy+y^2) THEREFORE, your answer is (A+3)(A^2-3A+9) |
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| 44. |
What is the 100th term of the linear sequence below? − 9 , − 5 , − 1 , 3 , 7 , |
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Answer» Answer: 387 Step-by-step explanation: Here, second is given by + 4 of the previous term. 2nd term = 4( 2 - 1 ) + FIRST term 3rd term = 4( 3 - 1 ) + first term 4th term = 4( 4 - 1 ) + first term' nth term = 4( n - 1 ) + first term Hence, 100TH term = 4( 100 - 1 ) + ( - 9 ) = 396 - 9 = 387 If you are familiar to APS, using its properties nth term = a + ( n - 1 )d, where a is the first term and d is the COMMON difference. 100th term = - 9 + ( 100 - 1 )( 4 ) = - 9 + ( 99 * 4 ) = - 9 + 396 = 387 |
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| 45. |
Find the missing numbers by using the given pattern1 + 2 + 2To f2 + 32 + 6 = 72Hov32 +42 + 122 = 132secc4² +52 + = 212Hou52 +_2 + 302 = 3126²+72+ 2nul |
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Answer» Answer:
Step-by-step EXPLANATION: hope it HELPS you........ |
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| 46. |
How to expand a^3+b^3+c^3 - 3abc |
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Answer»
a3 + b3 + c3 – 3ABC = (a + B + c)(a2 + B2 + C2 – ab – bc – CA)
if a+b+c =0 then a^3 + b^3 +c^3 =3abc hope this helps you. mark me as brainliest.... |
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| 48. |
Write a positive integers and a negative integer whose sum is positive |
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Answer» Their can be MANY Step-by-step explanation: 4+(-2)=4-2=2 2 is positive hope you will LIKE my efforts please mark me brainliest
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| 50. |
20example if non terminating |
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Answer» Pi Pi+1 Pi+2 Pi+3 Pi+4..... |
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