1.

2. If the diagonals of a square are 10 cm each, find theside of the square.​

Answer»

Answer:

hello!

here's the answer!

Step-by-step explanation:

Let ABCD be the given square,

THEREFORE, AB= BC= CD =DC = x

AC = DB = 10cm

But,

Angles of a SQUARE are 90°

therefore,

by Pythagoras theorem

in triangle ABC

AC² = AB² + BC²

10² = x +x

100 =2 x²

x ²= 50

x = 52



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