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2. If the diagonals of a square are 10 cm each, find theside of the square. |
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Answer» Answer: hello! here's the answer! Step-by-step explanation: Let ABCD be the given square, THEREFORE, AB= BC= CD =DC = x AC = DB = 10cm But, Angles of a SQUARE are 90° therefore, by Pythagoras theorem in triangle ABC AC² = AB² + BC² 10² = x +x 100 =2 x² x ²= 50 x = 5√2 |
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