1. The heat loss h (in Watts) through a single-pane glass window varie

1.	1. The heat loss h (in Watts) through a single-pane glass window varies jointly with the window’s area A (in square metres) and the difference between the inside and outside temperatures d (in Kelvins).(a) Write an equation relating h, A, d, and a constant, k.(b) A single-pane window with an area of 1 square metre and a temperature difference of 1 Kelvin has a heat loss of 5.7 Watts. What is the heat loss through a single-pane window with an area of 2.5 square metres and a temperature difference of 20 Kelvins?This is a math word problem on variables please answer it like a math problem, not a science problem. Thanks.
Answer» Answer: a) h=kAd, b) 285 Watts Step-by-step explanation: Heat LOSS- h, Window's are- A, Temperature DIFFERENCE- d, Constant- k h varies jointly with A and d, then the EQUATION will be: a) h=kAd b) A= 1 m², d= 1 Kelvin, h= 5/7 Watts Equation will reflect this as: 5.7=k 11 => k=5.7 When A= 2.5 m², d= 20, h=? h=kAd= 5.72.520= 285 Watts Answer: a) h=kAd, b) 285 Watts*

1. The heat loss h (in Watts) through a single-pane glass window varies jointly with the window’s area A (in square metres) and the difference between the inside and outside temperatures d (in Kelvins).(a) Write an equation relating h, A, d, and a constant, k.(b) A single-pane window with an area of 1 square metre and a temperature difference of 1 Kelvin has a heat loss of 5.7 Watts. What is the heat loss through a single-pane window with an area of 2.5 square metres and a temperature difference of 20 Kelvins?This is a math word problem on variables please answer it like a math problem, not a science problem. Thanks.

Answer»

Answer:

a) h=kAd, b) 285 Watts

Step-by-step explanation:

Heat LOSS- h, Window's are- A, Temperature DIFFERENCE- d, Constant- k

h varies jointly with A and d, then the EQUATION will be:

Equation will reflect this as:

When A= 2.5 m², d= 20, h=?

Answer: a) h=kAd, b) 285 Watts