332354 + Interview Questions in Secondary School in Math

1.	Square root x/600=square root 6/x
Answer» ANSWER: Squaring both SIDES, x/600=6/x x square=3600 x = 60 Hope it helps If the answer is HELPFUL please MARK it as the BRAINLIEST

1.

Square root x/600=square root 6/x

Answer»

ANSWER:

Squaring both SIDES,

x/600=6/x

x square=3600

x = 60

Hope it helps

If the answer is HELPFUL please MARK it as the BRAINLIEST

Discussion

2.	-6/5*8/-3 find multiplicative inverse
Answer» ANSWER: The MULTIPLICATION of the given question is 16/5 and it's multiplicative INVERSE is 5/16. I hope it HELPS...

2.

-6/5*8/-3 find multiplicative inverse

Answer»

ANSWER:

The MULTIPLICATION of the given question is 16/5 and it's multiplicative INVERSE is 5/16.

I hope it HELPS...

Discussion

3.	Sum of two numbers is 95 . If one exceeds the other by 15 solution on one variable
Answer» Answer: 40 and 55 Step-by-step EXPLANATION: as X+(x+15)=95

3.

Sum of two numbers is 95 . If one exceeds the other by 15 solution on one variable

Answer»

Answer:

40 and 55

Step-by-step EXPLANATION:

as X+(x+15)=95

Discussion

4.	Can denominator be zero in fractions
Answer» Answer: no and yes Step-by-step EXPLANATION: no because it won't be proper fraction yes we can make an improper fraction

4.

Can denominator be zero in fractions

Answer»

Answer:

no and yes

Step-by-step EXPLANATION: no because it won't be proper fraction

yes we can make an improper fraction

Discussion

5.	The present age of Soya’s father is three times his present age. After five years , the sum of their ages is 70 years. Find their present ages.
Answer» ANSWER: Father is 45 years old and Soya is 15 years old. Step-by-step EXPLANATION: Given : Soya’s father is = THREE times of Soya's present age Sum of their ages after 5 years = 70 To find : Their present ages Solution : Consider the present ages as - Soya = y Father = 3y Ages 5 years later - Soya = y + 5 Father = 3y + 5 According to the question, The sum of their ages after 5 years is 70, ⇒ (y + 5) + (3y + 5) = 70 ⇒ 4y + 10 = 70 ⇒ 4y = 60 ⇒ y = 60/4 ⇒ y = 15 Soya is Presently 15 years old. $\rule{300}{1.5}$ ★ Father's age - ⇒ 3 × y ⇒ 3 × 15 ⇒ 45 Father is presently 45 years old. $\therefore$ Father is 45 years old and Soya is 15 years old.

5.

The present age of Soya’s father is three times his present age. After five years , the sum of their ages is 70 years. Find their present ages.

Answer»

ANSWER:

Father is 45 years old and Soya is 15 years old.

Step-by-step EXPLANATION:

Given :

Soya’s father is = THREE times of Soya's present age

Sum of their ages after 5 years = 70

To find :

Their present ages

Solution :

Consider the present ages as -

Soya = y
Father = 3y

Ages 5 years later -

Soya = y + 5
Father = 3y + 5

According to the question,

The sum of their ages after 5 years is 70,

⇒ (y + 5) + (3y + 5) = 70

⇒ 4y + 10 = 70

⇒ 4y = 60

⇒ y = 60/4

⇒ y = 15

Soya is Presently 15 years old.

$\rule{300}{1.5}$

★ Father's age -

⇒ 3 × y

⇒ 3 × 15

⇒ 45

Father is presently 45 years old.

$\therefore$ Father is 45 years old and Soya is 15 years old.

Discussion

6.	If ray bd bisects angle abc and angle abd = 75° then angle abc = ?
Answer» ANSWER: SINCE BF BISECTS ANGLE abc therefore, abc=75+75 =150

6.

If ray bd bisects angle abc and angle abd = 75° then angle abc = ?

Answer»

ANSWER:

SINCE BF BISECTS ANGLE abc

therefore,

abc=75+75

=150

Discussion

7.	38.26 decimals into fraction
Answer» Answer: 3826/100........... ....

7.

38.26 decimals into fraction

Answer»

Answer:

3826/100...........

....

Discussion

8.	Q.no 22 Show that it is realPlease see the attachment for the question. Thnks!
Answer» ANSWER: I can't SEE the ATTACHMENT CLEARLY

8.

Q.no 22 Show that it is realPlease see the attachment for the question. Thnks!

Answer»

ANSWER:

I can't SEE the ATTACHMENT CLEARLY

Discussion

9.	The angle between the minute and hour hand of a clock at 8.30 is
Answer» Step-by-step explanation: So for 8 -hour and 30- MINUTES, the Hour HAND will move= {240+(30 x0.5)= 255° . Therefore the angle between the hour hand and the minute hand will be = (255–180) =75° Hope it helps If you like the answer please mark it as the brainliest

9.

The angle between the minute and hour hand of a clock at 8.30 is

Answer»

Step-by-step explanation:

So for 8 -hour and 30- MINUTES, the Hour HAND will move= {240+(30 x0.5)= 255° . Therefore the angle between the hour hand and the minute hand will be = (255–180) =75°

Hope it helps

If you like the answer please mark it as the brainliest

Discussion

10.	Product of 2x(x-y) is
Answer» Step-by-step EXPLANATION: HELLO the ANSWER is 2x²-2xy

10.

Product of 2x(x-y) is

Answer»

Step-by-step EXPLANATION:

HELLO the ANSWER is

2x²-2xy

Discussion

11.	9,12,15,...find 16 term
Answer» ANSWER: a=9, d=15-12=3 16th term=a+(n-1)d =9+(16-1)3 =9+(15×3) =9+45=54

11.

9,12,15,...find 16 term

Answer»

ANSWER:

a=9, d=15-12=3

16th term=a+(n-1)d

=9+(16-1)3

=9+(15×3)

=9+45=54

Discussion

12.	40. A discount of 15% on one article is the same as a discount of 20% on another article. The labelled price of thetwo articles can be :(A) Rs.40, Rs.20 (B) Rs.60, Rs.40 (C) Rs.80, Rs.60 (D) Rs.60, Rs.40
Answer» ANSWER: answer for this is C) 80 RS and 60RS

12.

40. A discount of 15% on one article is the same as a discount of 20% on another article. The labelled price of thetwo articles can be :(A) Rs.40, Rs.20 (B) Rs.60, Rs.40 (C) Rs.80, Rs.60 (D) Rs.60, Rs.40

Answer»

ANSWER:

answer for this is C) 80 RS and 60RS

Discussion

13.	Héyà Gúys ❤❤Solve by using the method of completing the square :-☺❤☺❤
Answer» $\huge\mathtt{Solution:-}$ $\begin{lgathered}= > x {}^{2} - ( \sqrt{2} + 1)x = - \sqrt{2} . \\ \\ (adding {( \frac{ \sqrt{2} + 1 }{2}) }^{2} on \: both \: side ) \\ \\ = > {x}^{2} - 2 \times x \times ( \frac{ \sqrt{2} + 1}{2} ) + {( \frac{ \sqrt{2} + 1 }{2}) }^{2} = - \sqrt{2} + {( \frac{ \sqrt{2} + 1 }{2}) }^{2}. \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} = - \sqrt{2} + \frac{2 + 1 + 2 \sqrt{2} }{4} . \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} =\frac{ - 4 \sqrt{2} + 2 + 1 + 2 \sqrt{2} }{4} . \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} = \frac{2 - 2 \sqrt{2} + 1}{4} . \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} = {( \frac{ \sqrt{2} - 1}{2} )}^{2} . \\ \\ [ \: taking \: square \: root \: on \: both \: side ,we \: get \:] \\ \\ = > x - ( \frac{ \sqrt{2} + 1 }{2} ) = ±( \frac{ \sqrt{2} - 1 }{2} ). \\ \\ = > x - ( \frac{ \sqrt{2} + 1 }{2} ) = ( \frac{ \sqrt{2} - 1 }{2} ) \: \: or \: \: x - ( \frac{ \sqrt{2} + 1 }{2} ) = - ( \frac{ \sqrt{2} - 1 }{2} ). \\ \\ = > x = ( \frac{ \sqrt{2} + 1 }{2} ) + ( \frac{ \sqrt{2} - 1 }{2} ) \: \: \: or \: \: \: x = ( \frac{ \sqrt{2} + 1 }{2} ) - ( \frac{ \sqrt{2} - 1 }{2} ). \\ \\ = > x = \frac{ \sqrt{2} + \cancel1 + \sqrt{2} - \cancel1 }{2} \: \: \: or \: \: \: x = \frac{ \cancel{\sqrt{2} } + 1 - \cancel{\sqrt{2} } + 1}{2} . \\ \\ = > x = \frac{ \cancel2 \sqrt{2} }{ \cancel2} \: \: or \: \: x = \cancel{\frac{2}{2} }. \\ \\ \\\large{ \bf \therefore x = \sqrt{2} \: \: or \: \: x = 1.}\end{lgathered}$

13.

Héyà Gúys ❤❤Solve by using the method of completing the square :-☺❤☺❤

Answer»

$\huge\mathtt{Solution:-}$

$\begin{lgathered}= > x {}^{2} - ( \sqrt{2} + 1)x = - \sqrt{2} . \\ \\ (adding {( \frac{ \sqrt{2} + 1 }{2}) }^{2} on \: both \: side ) \\ \\ = > {x}^{2} - 2 \times x \times ( \frac{ \sqrt{2} + 1}{2} ) + {( \frac{ \sqrt{2} + 1 }{2}) }^{2} = - \sqrt{2} + {( \frac{ \sqrt{2} + 1 }{2}) }^{2}. \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} = - \sqrt{2} + \frac{2 + 1 + 2 \sqrt{2} }{4} . \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} =\frac{ - 4 \sqrt{2} + 2 + 1 + 2 \sqrt{2} }{4} . \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} = \frac{2 - 2 \sqrt{2} + 1}{4} . \\ \\ = > {[x - ( \frac{ \sqrt{2} + 1 }{2} )]}^{2} = {( \frac{ \sqrt{2} - 1}{2} )}^{2} . \\ \\ [ \: taking \: square \: root \: on \: both \: side ,we \: get \:] \\ \\ = > x - ( \frac{ \sqrt{2} + 1 }{2} ) = ±( \frac{ \sqrt{2} - 1 }{2} ). \\ \\ = > x - ( \frac{ \sqrt{2} + 1 }{2} ) = ( \frac{ \sqrt{2} - 1 }{2} ) \: \: or \: \: x - ( \frac{ \sqrt{2} + 1 }{2} ) = - ( \frac{ \sqrt{2} - 1 }{2} ). \\ \\ = > x = ( \frac{ \sqrt{2} + 1 }{2} ) + ( \frac{ \sqrt{2} - 1 }{2} ) \: \: \: or \: \: \: x = ( \frac{ \sqrt{2} + 1 }{2} ) - ( \frac{ \sqrt{2} - 1 }{2} ). \\ \\ = > x = \frac{ \sqrt{2} + \cancel1 + \sqrt{2} - \cancel1 }{2} \: \: \: or \: \: \: x = \frac{ \cancel{\sqrt{2} } + 1 - \cancel{\sqrt{2} } + 1}{2} . \\ \\ = > x = \frac{ \cancel2 \sqrt{2} }{ \cancel2} \: \: or \: \: x = \cancel{\frac{2}{2} }. \\ \\ \\\large{ \bf \therefore x = \sqrt{2} \: \: or \: \: x = 1.}\end{lgathered}$

Discussion

14.	a man takes 10 rupees at simple interest and he return one rupee per month calculate the rate of interes
Answer» Answer: 10 percent. Step-by-step EXPLANATION: It's so EASY but you don't KNOW it

14.

a man takes 10 rupees at simple interest and he return one rupee per month calculate the rate of interes

Answer»

Answer:

10 percent.

Step-by-step EXPLANATION:

It's so EASY but you don't KNOW it

Discussion

15.	A man spends 15% of his monthly income on rent and 40% of the remainder on clothes. If the monthly savings are Rs.306, find his aanual income
Answer» A man SPENDS 15% of his monthly income on rent. The annual income is RS 7200 Solution: GIVEN, a man spends 15% of his monthly income on rent and 40% of the REMAINDER on clothes. The monthly savings are Rs.306. We have to find his annual income. Now, his monthly income = rent payment + clothes payment + monthly savings Monthly income = 15% of Monthly income + 40% of (monthly income – rent payment) + 306 rupees Let monthly income = "m" m = 15% of m +40% of m – 40% of 15% of m + 306 $\mathrm{m}=\frac{15}{100} \times \mathrm{m}+\frac{40}{100} \times \mathrm{m}-\frac{40}{100} \times \frac{15}{100} \times \mathrm{m}+306$ $\mathrm{m}=\mathrm{m}\left(\frac{15}{100}+\frac{40}{100}-\frac{40}{100} \times \frac{15}{100}\right)+306$ $m-m\left(\frac{55}{100}-\frac{2}{5} \times \frac{15}{100}\right)=306$ $m\left(1-\frac{55}{100}+2 \times \frac{3}{100}\right)=306$ On simplification we GET, $m\left(1-\frac{55}{100}+\frac{6}{100}\right)=306$ $\mathrm{m}\left(1-\frac{49}{100}\right)=306$ $\begin{array}{l}{\mathrm{m} \times \frac{51}{100}=306} \\\\ {\mathrm{m}=306 \times \frac{100}{51}=600}\end{array}$ Hence monthly income = 600 So, annual income = 12 x 600 = 7200 Hence, annual income of the person is RS 7200

15.

A man spends 15% of his monthly income on rent and 40% of the remainder on clothes. If the monthly savings are Rs.306, find his aanual income

Answer»

A man SPENDS 15% of his monthly income on rent. The annual income is RS 7200

Solution:

GIVEN, a man spends 15% of his monthly income on rent and 40% of the REMAINDER on clothes.

The monthly savings are Rs.306. We have to find his annual income.

Now, his monthly income = rent payment + clothes payment + monthly savings

Monthly income = 15% of Monthly income + 40% of (monthly income – rent payment) + 306 rupees

Let monthly income = "m"

m = 15% of m +40% of m – 40% of 15% of m + 306

$\mathrm{m}=\frac{15}{100} \times \mathrm{m}+\frac{40}{100} \times \mathrm{m}-\frac{40}{100} \times \frac{15}{100} \times \mathrm{m}+306$

$\mathrm{m}=\mathrm{m}\left(\frac{15}{100}+\frac{40}{100}-\frac{40}{100} \times \frac{15}{100}\right)+306$

$m-m\left(\frac{55}{100}-\frac{2}{5} \times \frac{15}{100}\right)=306$

$m\left(1-\frac{55}{100}+2 \times \frac{3}{100}\right)=306$

On simplification we GET,

$m\left(1-\frac{55}{100}+\frac{6}{100}\right)=306$

$\mathrm{m}\left(1-\frac{49}{100}\right)=306$

$\begin{array}{l}{\mathrm{m} \times \frac{51}{100}=306} \\\\ {\mathrm{m}=306 \times \frac{100}{51}=600}\end{array}$

Hence monthly income = 600

So, annual income = 12 x 600 = 7200

Hence, annual income of the person is RS 7200

Discussion

16.	The weight of a cylinder filled with gas is 30 kilogram 250 gram and the weight of empty cylinder is 14 kilo gram 480 gram how much is the weight of gas contained in it
Answer» Answer: 15 KILOGRAM 770 GRAM GAS CONTAINED in it

16.

The weight of a cylinder filled with gas is 30 kilogram 250 gram and the weight of empty cylinder is 14 kilo gram 480 gram how much is the weight of gas contained in it

Answer»

Answer:

15 KILOGRAM 770 GRAM GAS CONTAINED in it

Discussion

17.	The area of a square garden is 143641 m square. Find the length of its side
Answer» Answer: 379 m Step-by-step EXPLANATION: AREA of square=l^2 l=√143641 l=379 m

17.

The area of a square garden is 143641 m square. Find the length of its side

Answer»

Answer:

379 m

Step-by-step EXPLANATION:

AREA of square=l^2

l=√143641

l=379 m

Discussion

18.	Two lines intersect in more than one point.
Answer» ANSWER: DISTINCT LINES Step-by-step EXPLANATION: The distinct lines are that two lines INTERSECT in more than one point

18.

Two lines intersect in more than one point.

Answer»

ANSWER:

DISTINCT LINES

Step-by-step EXPLANATION:

The distinct lines are that two lines INTERSECT in more than one point

Discussion

19.	A drum full of rice weights 241/6 kg..If the empty drum weight 55/4 kg, find the weight of rice in the drum
Answer» ANSWER: WEIGHT of rice=217/12

19.

A drum full of rice weights 241/6 kg..If the empty drum weight 55/4 kg, find the weight of rice in the drum

Answer»

ANSWER:

WEIGHT of rice=217/12

Discussion

20.	What 267696 be multiplied may become a perfect square
Answer» ANSWER: heyyo ...the answer is 11 because Step-by-step EXPLANATION: when we prime factorize the number given in the QUESTION ...we can PAIR all the factors except 11 ... therefore 11 is the smallest number which when MULTIPLIED with 267696 will definitely give u a perfect square

20.

What 267696 be multiplied may become a perfect square

Answer»

ANSWER:

heyyo ...the answer is 11 because

Step-by-step EXPLANATION:

when we prime factorize the number given in the QUESTION ...we can PAIR all the factors except 11 ... therefore 11 is the smallest number which when MULTIPLIED with 267696 will definitely give u a perfect square

Discussion

21.	The dimensions of a rectangular plot of land are 23.5m and 16.8m . Find the area of the plot. If the entire plot is fenced, what is the length of wire required per ground?
Answer» Step-by-step EXPLANATION: AREA of the PLOT = 394.8 m SQ

21.

The dimensions of a rectangular plot of land are 23.5m and 16.8m . Find the area of the plot. If the entire plot is fenced, what is the length of wire required per ground?

Answer»

Step-by-step EXPLANATION:

AREA of the PLOT = 394.8 m SQ

Discussion

22.	In an exam with 100 questions 2 marks are given for every correct answer and -0.5 for every incorrect answer and 0 for not attempted Alok got 20 questions wrong and left 26 questions unattempted if the passing marks are 100 at least how many questions should he answer right to passr
Answer» Answer: Step-by-step EXPLANATION: For 20 wrong question NEGATIVE marks will be 20 x -0.5 = -10 26 are left UNATTEMPTED . So remaining question:- 54 If he gets all 54 correct, marks for it will be - 54 x 2 = 108 So TOTAL marks - 108 - 10 = 98 So he will not PASS. He need to attempt 1 answer out of 26 left answer and get it right to pass.

22.

In an exam with 100 questions 2 marks are given for every correct answer and -0.5 for every incorrect answer and 0 for not attempted Alok got 20 questions wrong and left 26 questions unattempted if the passing marks are 100 at least how many questions should he answer right to passr

Answer»

Answer:

Step-by-step EXPLANATION:

For 20 wrong question NEGATIVE marks will be 20 x -0.5 = -10

26 are left UNATTEMPTED .

So remaining question:- 54

If he gets all 54 correct, marks for it will be - 54 x 2 = 108

So TOTAL marks - 108 - 10 = 98

So he will not PASS.

He need to attempt 1 answer out of 26 left answer and get it right to pass.

Discussion

23.	3xy (8xsquare + 7xy)
Answer» Answer: 24x^3+21x^2y^2......

23.

3xy (8xsquare + 7xy)

Answer»

Answer:

24x^3+21x^2y^2......

Discussion

24.	[2 (cos 210° + i sin 210°)] [4 (cos 120°+ i sin 120°)].:o
Answer» ANSWER: -4i EXPLANATION: $2( - \sqrt{3} \div 2 - i \div 2) \times 4( - 1 \div 2 + \sqrt{3} i \div 2) \\ \\ ( - \sqrt{3} - i)( - 2 + 2 \sqrt{3} i) \\ - 2 \sqrt{3} + 2i - 6i + 2 \sqrt{3} \\ - 4i$

24.

[2 (cos 210° + i sin 210°)] [4 (cos 120°+ i sin 120°)].:o

Answer»

ANSWER:

-4i

EXPLANATION:

$2( - \sqrt{3} \div 2 - i \div 2) \times 4( - 1 \div 2 + \sqrt{3} i \div 2) \\ \\ ( - \sqrt{3} - i)( - 2 + 2 \sqrt{3} i) \\ - 2 \sqrt{3} + 2i - 6i + 2 \sqrt{3} \\ - 4i$

Discussion

25.	2025 plants are to be planted in a garden in search of a dirty joke hunting as many plant is number of wrote find the number of Ro
Answer» ${\huge{\fcolorbox{cyan}{lime}{\fcolorbox{yellow}{blue}{\sf{\color{yellow}{QuesTion:- }}}}}}$ 2025 plants are PLANTED in a garden, no of plant in a row is equal to the no of palnt in arow find the plant number ${\huge{\fcolorbox{cyan}{lime}{\fcolorbox{yellow}{blue}{\sf{\color{yellow}{AnsWer:- }}}}}}$ Let X be the number of rows and X be the number of plants in each row. Total no. of plants:- ? $\implies \sf{x \times x = {x}^{2} }$ $\implies \sf{ {x}^{2} = 2025 }$ $\sf{ {x}^{2} = 3 \times 3 \times 3 \times 3 \times 5 \times 5 }$ $\implies \sf{ {x} = \sqrt{2025} }$ $\implies \sf{ {x} = 3 \times 3 \times 5 }$ $\implies \sf{ {x} = <klux>45</klux>}$ Number of rows and columns is 45.

25.

2025 plants are to be planted in a garden in search of a dirty joke hunting as many plant is number of wrote find the number of Ro

Answer»

${\huge{\fcolorbox{cyan}{lime}{\fcolorbox{yellow}{blue}{\sf{\color{yellow}{QuesTion:- }}}}}}$

2025 plants are PLANTED in a garden, no of plant in a row is equal to the no of palnt in arow find the plant number

${\huge{\fcolorbox{cyan}{lime}{\fcolorbox{yellow}{blue}{\sf{\color{yellow}{AnsWer:- }}}}}}$

Let X be the number of rows and X be the number of plants in each row.

Total no. of plants:- ?

$\implies \sf{x \times x = {x}^{2} }$

$\implies \sf{ {x}^{2} = 2025 }$

$\sf{ {x}^{2} = 3 \times 3 \times 3 \times 3 \times 5 \times 5 }$

$\implies \sf{ {x} = \sqrt{2025} }$

$\implies \sf{ {x} = 3 \times 3 \times 5 }$

$\implies \sf{ {x} = <klux>45</klux>}$

Number of rows and columns is 45.

Discussion

26.	A certain sum of money amounts to 19688 in 7 years at 15% per annum simple interest find the sum
Answer» Step-by-step EXPLANATION: LET the SUM of MONEY be y SI=PRN 100 y ×15×7=19688 100 y=19688×100/15×7 y=18750.47

26.

A certain sum of money amounts to 19688 in 7 years at 15% per annum simple interest find the sum

Answer»

Step-by-step EXPLANATION:

LET the SUM of MONEY be y

SI=PRN

100

y ×15×7=19688

100

y=19688×100/15×7

y=18750.47

Discussion

27.	Which is a better buy 15 kg apples for rupees 525 or 18 kg apples for rupees 612
Answer» When you are BUYING 15 Kg APPLES for rupees 525, $\frac{525}{15} = 35$ Then you have to PAY ₹35 for 1Kg While when you are buying 18 Kg apples for rupees 612, $\frac{612}{18} = 34$ Then you have to pay ₹34 for 1Kg which is BETTER than paying ₹35 for 1 Kg. So you should go for ₹612 for 18 Kg of Apples. !!!!!!!! *Mark* *as brainliest* !!!!!!!!

27.

Which is a better buy 15 kg apples for rupees 525 or 18 kg apples for rupees 612

Answer»

When you are BUYING 15 Kg APPLES for rupees 525,

$\frac{525}{15} = 35$

Then you have to PAY ₹35 for 1Kg

While when you are buying 18 Kg apples for rupees 612,

$\frac{612}{18} = 34$

Then you have to pay ₹34 for 1Kg which is BETTER than paying ₹35 for 1 Kg.

So you should go for ₹612 for 18 Kg of Apples.

!!!!!!!! Mark as brainliest !!!!!!!!

Discussion

28.	A fraction which has numerator as 1 is called
Answer» Answer: unit FRACTION since they represent a unit of the whole score some easy POINTS by MARKING BRAINLIST plspls

28.

A fraction which has numerator as 1 is called

Answer»

Answer:

unit FRACTION since they represent a unit of the whole

score some easy POINTS by MARKING BRAINLIST plspls

Discussion

29.	A-3.The value of,183 +7 +3. 18.7.25/36 +6.243.2 +15.81.4+20. 27.8 +15.9.16 +6.3.32 +64is :(A) 1(B) 27(C)3(D) none
Answer» ANSWER: OPTION is D OK NONE Step-by-step EXPLANATION: CORRECT answer is 318.67173472

29.

A-3.The value of,183 +7 +3. 18.7.25/36 +6.243.2 +15.81.4+20. 27.8 +15.9.16 +6.3.32 +64is :(A) 1(B) 27(C)3(D) none

Answer»

ANSWER:

OPTION is D OK NONE

Step-by-step EXPLANATION:

CORRECT answer is 318.67173472

Discussion

30.	Please help me solve no. 26 and no. 27
Answer» AABE YEAH to chutiyon waala QUESTION hai Randi ke EEK RAAT ke liye aapni maa de de phir saare answers baayunga

Discussion

31.	Factorise the following polynomials.1. a(f+g)+b(f+g)
Answer» Answer: In the same way as you COULD factor trinomials on the form of x2+bx+c You can factor POLYNOMIALS on the form of ax2+bx+c If a is positive then you just proceed in the same way as you did PREVIOUSLY EXCEPT now ax2+bx+c=(x+m)(ax+n) wherec=mn,ac=pqandb=p+q=am+n

31.

Factorise the following polynomials.1. a(f+g)+b(f+g)

Answer»

Answer:

In the same way as you COULD factor trinomials on the form of

x2+bx+c

You can factor POLYNOMIALS on the form of

ax2+bx+c

If a is positive then you just proceed in the same way as you did PREVIOUSLY EXCEPT now

ax2+bx+c=(x+m)(ax+n)

wherec=mn,ac=pqandb=p+q=am+n

Discussion

32.	Sum of money was lent for 3 years years
Answer» HEY MATE COMPLETE UR QUESTION

32.

Sum of money was lent for 3 years years

Answer»

HEY MATE COMPLETE UR QUESTION

Discussion

33.	Unlucky mening in punjabi
Answer» ANSWER: ਬਦਕਿਸਮਤ is UNLUCKY in PUNJABI

33.

Unlucky mening in punjabi

Answer»

ANSWER:

ਬਦਕਿਸਮਤ is UNLUCKY in PUNJABI

Discussion

34.	Find the square root of 2 (1 - √3 i)
Answer» ANSWER: 2-2√3i Step-by-step EXPLANATION: this is answer is CORRECT ithink

34.

Find the square root of 2 (1 - √3 i)

Answer»

ANSWER:

2-2√3i

Step-by-step EXPLANATION:

this is answer is CORRECT ithink

Discussion

35.	If AB \|\| EF. DE \|\| BC, AC \|\| DF, find x and y.
Answer» ANSWER: angle y = 120 and angle X = 110 Step-by-step explanation: given above..........

35.

If AB || EF. DE || BC, AC || DF, find x and y.

Answer»

ANSWER:

angle y = 120 and angle X = 110

Step-by-step explanation:

given above..........

Discussion

36.	Date .......Page No- 4+8 + 16 corectasinta
Answer» ANSWER: PLEASE COMPLETE your QUESTION

36.

Date .......Page No- 4+8 + 16 corectasinta

Answer»

ANSWER:

PLEASE COMPLETE your QUESTION

Discussion

37.	Divide the sum of - 3/4and5/6 by their difference
Answer» Answer: Hey mate Here is your answer ⏬⏬⏬⏬⏬ According to the QUESTION (-3/4+5/6)/(-3/4-5/6) (-9+10/12)/(-9-10/12) (1/12)/(-19/12) (1/12)*(-12/19) -1/19 Therefore the answer is -1/19 plz mark it as the brainliest. Thank you Have a GREAT DAY.

37.

Divide the sum of - 3/4and5/6 by their difference

Answer»

Answer:

Hey mate

Here is your answer

⏬⏬⏬⏬⏬

According to the QUESTION

(-3/4+5/6)/(-3/4-5/6)

(-9+10/12)/(-9-10/12)

(1/12)/(-19/12)

(1/12)*(-12/19)

-1/19

Therefore the answer is -1/19

plz mark it as the brainliest.

Thank you

Have a GREAT DAY.

Discussion

38.	Solve this.. Ans = root 5
Answer» (H) 2-(P2)+(B)2 -(1)2+(2)2 -1+4 -5 √5

38.

Solve this.. Ans = root 5

Answer»

(H) 2-(P2)+(B)2

-(1)2+(2)2

-1+4

-5

√5

Discussion

39.	X, x/5, x/8, x/-8, x/-6, x/2, x/-4 order these numbers from least to greatest.
Answer» ANSWER: x/-4 <×/-6 <×/-8 <×/8 <×/5 <×/2 <×

39.

X, x/5, x/8, x/-8, x/-6, x/2, x/-4 order these numbers from least to greatest.

Answer»

ANSWER:

x/-4 <×/-6 <×/-8 <×/8 <×/5 <×/2 <×

Discussion

40.	5 th question please can you answer
Answer» Answer:it is SOLVED below Step-by-step explanation: GIVEN, SecA={x+(1/4X)} To PROVE: SecA+TanA=2x or (1/2x) SecA=(h/b)=(4x^2+1)/4x We KNOW , Sec^2A-1=tan^2A Or, {(4x^2+1)/4x}^2-1=tan^2A Or, (16x^4+8x^2+1-16x^2)/16x^2=Tan^2A Or, (16x^4-8x^2+1)/16x^2=Tan^2A Or, TanA=√(16x^4-8x^2+1) /4x Now consider LHS= SecA+TanA ={(4x^2+1)/4x}+{√(16x^4-8x^2+1)}/4x ={4x^2+1+(4x^2-1)} / 4x = 8x^2/4x=2x

40.

5 th question please can you answer

Answer»

Answer:it is SOLVED below

Step-by-step explanation:

GIVEN, SecA={x+(1/4X)}

To PROVE: SecA+TanA=2x or (1/2x)

SecA=(h/b)=(4x^2+1)/4x

We KNOW , Sec^2A-1=tan^2A

Or, {(4x^2+1)/4x}^2-1=tan^2A

Or, (16x^4+8x^2+1-16x^2)/16x^2=Tan^2A

Or, (16x^4-8x^2+1)/16x^2=Tan^2A

Or, TanA=√(16x^4-8x^2+1) /4x

Now consider

LHS= SecA+TanA

={(4x^2+1)/4x}+{√(16x^4-8x^2+1)}/4x

={4x^2+1+(4x^2-1)} / 4x

= 8x^2/4x=2x

Discussion

41.	Date8 + 16 cosechIS
Answer» ANSWER: SORRY I don't KNOW I did not HELP you sorry

41.

Date8 + 16 cosechIS

Answer»

ANSWER:

SORRY I don't KNOW I did not HELP you sorry

Discussion

42.	3. The solution of a linear equation in two variables is(a) a number which satisfies the given equation(b) an ordered pair which satisfies the given equation(c) an ordered pair, whose respective values when substituted for x and y in the given equation,satisfies it(d) none of these
Answer» ANSWER: answer will be C .... Step-by-step EXPLANATION: FLW me PLEASE...

42.

3. The solution of a linear equation in two variables is(a) a number which satisfies the given equation(b) an ordered pair which satisfies the given equation(c) an ordered pair, whose respective values when substituted for x and y in the given equation,satisfies it(d) none of these

Answer»

ANSWER:

answer will be C ....

Step-by-step EXPLANATION:

FLW me PLEASE...

Discussion

43.	Water is flowing through a cylindrical pipe , of internal diameter 2 cm,into a cylindrical tank of baseradius 40cm , at the rate of 0.4 m/s . Determine the rise in level of water in the tank in half an hour
Answer» ANSWER: KEEP FOLLWING me I will GIVE you answer

43.

Water is flowing through a cylindrical pipe , of internal diameter 2 cm,into a cylindrical tank of baseradius 40cm , at the rate of 0.4 m/s . Determine the rise in level of water in the tank in half an hour

Answer»

ANSWER:

KEEP FOLLWING me

I will GIVE you answer

Discussion

44.	2. f(x) = 4x² – 3x² – 2x² + x - 7, 8(x) = x - 1
Answer» ANSWER: G(X) = x-1 = x=1 f(x) = 4x2-3x2-2x2+x-7 = -2x2+x-7 = -2(1)2+1-7 = -2+1-7 = -9+1 = -8 HOPE IT WILL HELP YOU

44.

2. f(x) = 4x² – 3x² – 2x² + x - 7, 8(x) = x - 1

Answer»

ANSWER:

G(X) = x-1

= x=1

f(x) = 4x2-3x2-2x2+x-7

= -2x2+x-7

= -2(1)2+1-7

= -2+1-7

= -9+1

= -8

*HOPE IT WILL HELP YOU*

Discussion

45.	The perimeter of a rectangle is 240 cm.If it's length is decreased by 10percent Nd breadth is increased by 20 percent,we get the same perimeter.find the original length and breadth of the rectangle.show the working.
Answer» Given, perimeter of RECTANGLE = 240 cm Let LENGTH of rectangle is L and breadth is B. perimeter of rectangle = 2(length + breadth) 240cm = 2(L + B) or, 120 = L + B L + B = 120 ..........(1) a/c to question, length is decreased by 10% . so, new length of rectangle = L - 10% of L = L - L/10 = 0.9L breadth of rectangle is increased by 20% so, new breadth of rectangle = B + 20% B = B + 20B/100 = 1.2B now, new perimeter of rectangle = 2(0.9L + 1.2B) but according to question, initial perimeter of rectangle = final perimeter of rectangle so, 240 = 2(0.9L + 1.2B) 0.9L + 1.2B = 120.........(2) from equations (1) and (2), MULTIPLYING 5 with equation (2) - 6 with equation (1) 5(0.9L + 1.2B) - 6(L + B) = 5 × 120 - 6 × 120 4.5 L - 6L = -120 -1.5L = -120 L = 80m and breadth = 120 - L = 40m HENCE, length of rectangle = 80m breadth of rectangle = 40m

45.

The perimeter of a rectangle is 240 cm.If it's length is decreased by 10percent Nd breadth is increased by 20 percent,we get the same perimeter.find the original length and breadth of the rectangle.show the working.

Answer»

Given, perimeter of RECTANGLE = 240 cm

Let LENGTH of rectangle is L and breadth is B.

perimeter of rectangle = 2(length + breadth)

240cm = 2(L + B)

or, 120 = L + B

L + B = 120 ..........(1)

a/c to question,

length is decreased by 10% .

so, new length of rectangle = L - 10% of L

= L - L/10 = 0.9L

breadth of rectangle is increased by 20%

so, new breadth of rectangle = B + 20% B

= B + 20B/100 = 1.2B

now, new perimeter of rectangle = 2(0.9L + 1.2B)

but according to question,

initial perimeter of rectangle = final perimeter of rectangle

so, 240 = 2(0.9L + 1.2B)

0.9L + 1.2B = 120.........(2)

from equations (1) and (2),

MULTIPLYING 5 with equation (2) - 6 with equation (1)

5(0.9L + 1.2B) - 6(L + B) = 5 × 120 - 6 × 120

4.5 L - 6L = -120

-1.5L = -120

L = 80m and breadth = 120 - L = 40m

HENCE, length of rectangle = 80m

breadth of rectangle = 40m

Discussion

46.	A plus 1 upon a equals to 1 find a power 100 +apower99 +a power 98
Answer» ANSWER: PLZZZ GIVE me brainliest ans and plzzzz FOLLOW me

46.

A plus 1 upon a equals to 1 find a power 100 +apower99 +a power 98

Answer»

ANSWER:

PLZZZ GIVE me brainliest ans and plzzzz FOLLOW me

Discussion

47.	LCM of the 660,420 and240 only these three are their in the LCM proper method we have to do
Answer» LCM =18480 Step-by-step EXPLANATION: First divide the NUMBERS by 2 ,4 TIMES then divide it by 3 then by 5 then by 7 then by 11 and multiply 2×2×2×2×3×5×7×11 =18480

47.

LCM of the 660,420 and240 only these three are their in the LCM proper method we have to do

Answer»

LCM =18480

Step-by-step EXPLANATION:

First divide the NUMBERS by 2 ,4 TIMES

then divide it by 3

then by 5

then by 7

then by 11

and multiply

2×2×2×2×3×5×7×11

=18480

Discussion

48.	1 minus tan squared theta divided by cot squared theta minus 1 equals to tan squared theta
Answer» ANSWER: this is the answer....

48.

1 minus tan squared theta divided by cot squared theta minus 1 equals to tan squared theta

Answer»

ANSWER:

this is the answer....

Discussion

49.	Write natural numbers form 2 to 20. What fraction of them are prime numbers.
Answer» Answer: the natural NUMBER from 2 to 20 are 2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20. there are 19 natural numbers. PRIME numbers are 2,3,5,7,11,13,17,19. there are 8 prime numbers . fraction of prime numbers =number of prime number ÷ total numbers =8/19

49.

Write natural numbers form 2 to 20. What fraction of them are prime numbers.

Answer»

Answer:

the natural NUMBER from 2 to 20 are 2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20. there are 19 natural numbers.

PRIME numbers are 2,3,5,7,11,13,17,19.

there are 8 prime numbers .

fraction of prime numbers =number of prime number ÷ total numbers

=8/19

Discussion

50.	5. Prove that :(i)sin 20. = tan o1 + cos 20
Answer» ANSWER: Plzz GIVE me brainliest ans and PLZZZZ follow me

50.

5. Prove that :(i)sin 20. = tan o1 + cos 20

Answer»

ANSWER:

Plzz GIVE me brainliest ans and PLZZZZ follow me

Discussion

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