1.

The present age of Soya’s father is three times his present age. After five years , the sum of their ages is 70 years. Find their present ages.

Answer»

ANSWER:

Father is 45 years old and Soya is 15 years old.

Step-by-step EXPLANATION:

Given :

Soya’s father is = THREE times of Soya's present age

Sum of their ages after 5 years = 70

To find :

Their present ages

Solution :

Consider the present ages as -

  • Soya = y
  • Father = 3y

Ages 5 years later -

  • Soya = y + 5
  • Father = 3y + 5

According to the question,

The sum of their ages after 5 years is 70,

⇒ (y + 5) + (3y + 5) = 70

⇒ 4y + 10 = 70

⇒ 4y = 60

⇒ y = 60/4

⇒ y = 15

Soya is Presently 15 years old.

\rule{300}{1.5}

★ Father's age -

⇒ 3 × y

⇒ 3 × 15

⇒ 45

Father is presently 45 years old.

\therefore Father is 45 years old and Soya is 15 years old.



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