332354 + Interview Questions in Secondary School in Math

1.	What is the value of x 8^6×8^-5=x/y
Answer» 8^6*8^(-5)=x/y 8^(6-5)=x/y 8^1=x/y x=8y Hope it HELPS...

Discussion

2.	M={1,a,7,-8} n={-2,3,b,5} find a and b if m+n={-1,2,9,-3} matrices
Answer» ANSWER: a= -1 b= 2 Explanation m+n ={-1, 2, 9, -3} by APPLYING values of given m and n {1, a, 7, -8} + {-2, 3, b, 5} = {-1, 2, 9, -3} solving the eqn {(1-2), (a+3), (7+b), (-8+5)} = {-1, 2, 9, -3} {-1, a+3, 7+b, -3} = {-1, 2, 9, -3} comparing the respective terms 2nd and 3rd term from the equation a+3=2 ; 7+b=9 a=2-3 ; b=9-7 a= -1 ; b=2

2.

M={1,a,7,-8} n={-2,3,b,5} find a and b if m+n={-1,2,9,-3} matrices

Answer»

ANSWER:

a= -1
b= 2

Explanation

m+n ={-1, 2, 9, -3}

by APPLYING values of given m and n

{1, a, 7, -8} + {-2, 3, b, 5} = {-1, 2, 9, -3}

solving the eqn

{(1-2), (a+3), (7+b), (-8+5)} = {-1, 2, 9, -3}

{-1, a+3, 7+b, -3} = {-1, 2, 9, -3}

comparing the respective terms

2nd and 3rd term from the equation

a+3=2 ; 7+b=9

a=2-3 ; b=9-7

a= -1 ; b=2

Discussion

3.	By what numumber should 6 whole 2/9 be multiple get 42?
Answer» Step-by-step EXPLANATION: see in the photo if it helps MARK me as brainliest ANSWER

3.

By what numumber should 6 whole 2/9 be multiple get 42?

Answer»

Step-by-step EXPLANATION:

see in the photo

if it helps MARK me as brainliest ANSWER

Discussion

4.	Estimate each sum to the nearest hundred also find the difference between the estimated sum and the actual sum 437+293
Answer» ANSWER: ygxifyxhbjiggiucydgxycch Step-by-step EXPLANATION: TIK TOK chalao

4.

Estimate each sum to the nearest hundred also find the difference between the estimated sum and the actual sum 437+293

Answer»

ANSWER:

ygxifyxhbjiggiucydgxycch

Step-by-step EXPLANATION:

TIK TOK chalao

Discussion

5.	Multiply and write the product its lowest terms - 7 / 4 X 12/ 21 x (-1/2)
Answer» Answer: 7/4×12/21×(-1/2) 1/1×3/3×(-1/2) 1×1×(-1/2) -1/2

5.

Multiply and write the product its lowest terms - 7 / 4 X 12/ 21 x (-1/2)

Answer»

Answer:

7/4×12/21×(-1/2)

1/1×3/3×(-1/2)

1×1×(-1/2)

-1/2

Discussion

6.	10. A flower garden is 22.05 m long and 15 m wide. Sana wants to make aborder along one length using bricks that are 0.25m long.How many bricks will be needed?
Answer» Step-by-step EXPLANATION: PERIMETER of Flower GARDEN = 2 (22.05) + 2 (15) = 74.1 m = 7410 cm No. of Bricks needed $= \frac{7410}{25} = 296.4$ Therefore, 296.4 Bricks are required to MAKE border. Bricks USED to border 1 longer side = 88.2 Bricks used to border 1 shorter side = 60 Hope it Helps!

6.

10. A flower garden is 22.05 m long and 15 m wide. Sana wants to make aborder along one length using bricks that are 0.25m long.How many bricks will be needed?

Answer»

Step-by-step EXPLANATION:

PERIMETER of Flower GARDEN = 2 (22.05) + 2 (15) = 74.1 m = 7410 cm

No. of Bricks needed $= \frac{7410}{25} = 296.4$

Therefore, 296.4 Bricks are required to MAKE border.

Bricks USED to border 1 longer side = 88.2

Bricks used to border 1 shorter side = 60

Hope it Helps!

Discussion

7.	Simplify(1-1/2)(1-1/3)1-1/4)....(1-1/200)
Answer» Answer: 1/200 Step-by-step EXPLANATION: (1-1/2)(1-1/3)1-1/4)....(1-1/200)= 1/22/33/4....199/200= all NUMBERS GET cancelled apart from 1 and 200 =1/200 Answer is 1/200

7.

Simplify(1-1/2)(1-1/3)1-1/4)....(1-1/200)

Answer»

Answer:

1/200

Step-by-step EXPLANATION:

(1-1/2)(1-1/3)1-1/4)....(1-1/200)=
1/2*2/3*3/4*....*199/200= all NUMBERS GET cancelled apart from 1 and 200
=1/200

Answer is 1/200

Discussion

8.	Find the difference between the place value of
Answer» ANSWER: what is the QUESTION of you

8.

Find the difference between the place value of

Answer»

ANSWER:

what is the QUESTION of you

Discussion

9.	If two positive integers a and b are expressible in the form of a=p(q^2) and b=(p^3)q;p,q being prime numbers then find the lcm (a,b) and hcf(a,b)
Answer» ANSWER: GOD you SUCCESS to acheieve DONE DEAL

9.

If two positive integers a and b are expressible in the form of a=p(q^2) and b=(p^3)q;p,q being prime numbers then find the lcm (a,b) and hcf(a,b)

Answer»

ANSWER:

GOD you SUCCESS to acheieve DONE DEAL

Discussion

10.	Find the rationalising factor of 7-√5
Answer» Answer: the rationalising FACTOR of 7 - √5 is 7 + √5 because if we MULTIPLY both we GET a rational NUMBER.

10.

Find the rationalising factor of 7-√5

Answer»

Answer:

the rationalising FACTOR of 7 - √5 is 7 + √5

because if we MULTIPLY both we GET a rational NUMBER.

Discussion

11.	2+2=........................
Answer» Step-by-step explanation: 2+2=4................

11.

2+2=........................

Answer»

Step-by-step explanation:

2+2=4................

Discussion

12.	What is the equivalent fraction of 2/7 having numerator 10
Answer» Answer: 10/35 Step-by-step explanation: EASY easy MULTIPLY 5 in 2 we get numerator as 10. so, multiplying 5 in both numerator and denominator we get 10/35

12.

What is the equivalent fraction of 2/7 having numerator 10

Answer»

Answer:

10/35

Step-by-step explanation:

EASY easy MULTIPLY 5 in 2 we get numerator as 10.

so, multiplying 5 in both numerator and denominator we get 10/35

Discussion

13.	find zeroes of the quadratic polynomial √3x2+10x-8√3 and verify the relationship between the zeroes and the coefficient
Answer» √3x2+10x-8√3 Relationship between zeroes and coefficients SUM of zeroes=-(coefficient of X)/coefficient of x^2=-10/√3 Product of zeroes=constant term/coefficient of x^2=-8√3/√3 I hope it's HELP you Plz MARK my answer as a BRAINLIEST answer

13.

find zeroes of the quadratic polynomial √3x2+10x-8√3 and verify the relationship between the zeroes and the coefficient

Answer»

√3x2+10x-8√3

Relationship between zeroes and coefficients

SUM of zeroes=-(coefficient of X)/coefficient of x^2=-10/√3

Product of zeroes=constant term/coefficient of x^2=-8√3/√3

I hope it's HELP you

Plz MARK my answer as a BRAINLIEST answer

Discussion

14.	Cot (20°-Q) tan(70+Q)/sin (70° + Q)*sin (20°-o)
Answer» Answer: the RANGE off the DATA 13, 5,8,6,13,4,14 is:(a)10(B)13(C)1(d)14

14.

Cot (20°-Q) tan(70+Q)/sin (70° + Q)*sin (20°-o)

Answer»

Answer:

the RANGE off the DATA 13, 5,8,6,13,4,14 is:(a)10(B)13(C)1(d)14

Discussion

15.	Prove that: cosA/ 1-tanA + sinA/ 1-cotA = sinA+cosA
Answer» ANSWER: Step-by-step EXPLANATION: I HOPE YOU UNDERSTAND ;-)

15.

Prove that: cosA/ 1-tanA + sinA/ 1-cotA = sinA+cosA

Answer»

ANSWER:

Step-by-step EXPLANATION:

I HOPE YOU UNDERSTAND ;-)

Discussion

16.	If f( x ) = -3x +8, find f ( 5 )
Answer» Answer: F(x) = -3x+8 f(5) = -3(5) +8 = -15+8 = -7 f(5)= -7

16.

If f( x ) = -3x +8, find f ( 5 )

Answer»

Answer:

F(x) = -3x+8

f(5) = -3(5) +8

= -15+8

= -7

f(5)= -7

Discussion

17.	Find cube root of 6859 step by step pls
Answer» Step-by-step EXPLANATION: Since 6859 is a whole number, it is a perfect cube. The nearest previous perfect cube is 5832 and the nearest NEXT perfect cube is 8000 . 6859 is said to be a perfect cube because 19 X 19 x 19 is equal to 6859. .PLEASE *MARK* AS *BRAINLIST* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS* *PLS. PLEASE* *MARK* *BRAINLIST* *PREVIOUS* *ONE* *ALSO* I *HAVE* *GIVEN* *ANSWER* *TWICE*!!!!!

17.

Find cube root of 6859 step by step pls

Answer»

Step-by-step EXPLANATION:

Since 6859 is a whole number, it is a perfect cube. The nearest previous perfect cube is 5832 and the nearest NEXT perfect cube is 8000 . 6859 is said to be a perfect cube because 19 X 19 x 19 is equal to 6859.

.PLEASE MARK AS BRAINLIST PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS PLS.

PLEASE MARK BRAINLIST PREVIOUS ONE ALSO

I HAVE GIVEN ANSWER TWICE!!!!!

Discussion

18.	2+2=only to my friend
Answer» 2+2=4. hope it helps U ✔

18.

2+2=only to my friend

Answer»

2+2=4.

hope it helps U ✔

Discussion

19.	Simplify (2/3)-³/(2/3)-⁴ step by step pls
Answer» $\huge\underline\red{Answer}$ $(−2)⁷ × (−2)³ × (−2)⁴$ $= (-2)⁷⁺³ × (-2)⁴$ $= (-2)¹⁰ × (-2)⁴$ $= (-2)⁽¹⁰⁺⁴⁾$ $= (-2)¹⁴$ $Hence, \:(−2)⁷ × (−2)³ × (−2)⁴ = (-2)¹⁴$ $Or\: (−2)⁷ × (−2)³ × (−2)⁴ = 16384$

19.

Simplify (2/3)-³/(2/3)-⁴ step by step pls

Answer»

$\huge\underline\red{Answer}$

$(−2)⁷ × (−2)³ × (−2)⁴$

$= (-2)⁷⁺³ × (-2)⁴$

$= (-2)¹⁰ × (-2)⁴$

$= (-2)⁽¹⁰⁺⁴⁾$

$= (-2)¹⁴$

$Hence, \:(−2)⁷ × (−2)³ × (−2)⁴ = (-2)¹⁴$

$Or\: (−2)⁷ × (−2)³ × (−2)⁴ = 16384$

Discussion

20.	How to pass 9 th boards
Answer» simple concentrate on STUDIES ☑️☑️

20.

How to pass 9 th boards

Answer»

simple concentrate on STUDIES ☑️☑️

Discussion

21.	Determinant becomes from elementsofco-factors of 1-3너3
Answer» ANSWER: answer ICU and I don't KNOW ANYTHING that

21.

Determinant becomes from elementsofco-factors of 1-3너3

Answer»

ANSWER:

answer ICU and I don't KNOW ANYTHING that

Discussion

22.	Sqrt 3x+4=x slove this by factorisation plzzzz it's very urgent do it fast I will mark your ans as brainleast
Answer» 3x+4=x 4=x-3x 4=-2x -4/2=x x=-2....... here is UR ANSWER..... HOPE it HELPS...

22.

Sqrt 3x+4=x slove this by factorisation plzzzz it's very urgent do it fast I will mark your ans as brainleast

Answer»

3x+4=x

4=x-3x

4=-2x

-4/2=x

x=-2.......

here is UR ANSWER.....

HOPE it HELPS...

Discussion

23.	What's the Solution
Answer» ANSWER: The SOLUTION is 5/489+2(9/8) is 0

23.

What's the Solution

Answer»

ANSWER:

The SOLUTION is 5/489+2(9/8) is 0

Discussion

24.	What is the point of intersection of the lines x=-2020 and y=2020 ?
Answer» ANSWER: The LINES MEET at the POINT (2019,2020) 4.0

24.

What is the point of intersection of the lines x=-2020 and y=2020 ?

Answer»

ANSWER:

The LINES MEET at the POINT (2019,2020)

4.0

Discussion

25.	If(1,2),(4,y),(x,6) and (3,5) are the vertices of a parallelogram taken in order then find x and y...
Answer» ANSWER: so do to HI hgdff hi USD hi JJSD

25.

If(1,2),(4,y),(x,6) and (3,5) are the vertices of a parallelogram taken in order then find x and y...

Answer»

ANSWER:

so do to HI hgdff hi USD hi JJSD

Discussion

26.	If (a+1/a) ^2 =3 then a^3+1/a^3 equals?
Answer» ANSWER: ${\green{\underline{\underline{\huge{\mathfrak\red{your\:answer\:attached\:in\:the\:photo}}}}}}$

26.

If (a+1/a) ^2 =3 then a^3+1/a^3 equals?

Answer»

ANSWER:

${\green{\underline{\underline{\huge{\mathfrak\red{your\:answer\:attached\:in\:the\:photo}}}}}}$

Discussion

27.	Find the polynomial of X^3 - x and the sum of its zeros
Answer» P(X)=x^3-x Relationship between zeroes and COEFFICIENTS Sum of zeroes=-(COEFFICIENT of x^2)/coefficient of x^3=-0/1=0 I hope it's HELP you Plz mark my answer as a brainliest answer

27.

Find the polynomial of X^3 - x and the sum of its zeros

Answer»

P(X)=x^3-x

Relationship between zeroes and COEFFICIENTS

Sum of zeroes=-(COEFFICIENT of x^2)/coefficient of x^3=-0/1=0

I hope it's HELP you

Plz mark my answer as a brainliest answer

Discussion

28.	If 1/x+2 , 1/x+3 and 1/x+5are in Ap, find the value of x
Answer» Answer: THANKS for the FIRST to review my ATTACHED CV

28.

If 1/x+2 , 1/x+3 and 1/x+5are in Ap, find the value of x

Answer»

Answer:

THANKS for the FIRST to review my ATTACHED CV

Discussion

29.	How do we get 60/√3=20√3
Answer» 60/root 3 = root(3600/3) =root(1200) =root(400 * 3) =20 root 3 (PROVED) PLEASE DO MARK ME AS THE BRAINLIEST

29.

How do we get 60/√3=20√3

Answer»

60/root 3

= root(3600/3)

=root(1200)

=root(400 * 3)

=20 root 3

(PROVED)

*PLEASE DO MARK ME AS THE BRAINLIEST*

Discussion

30.	An electrician buys an old refrigerator and spends 175 on painting it. If he sells it for 2720, making a profit of of 13 1/3%, at what price had he bought the refrigerator.
Answer» ANSWER: HIFJFFC Step-by-step EXPLANATION:

30.

An electrician buys an old refrigerator and spends 175 on painting it. If he sells it for 2720, making a profit of of 13 1/3%, at what price had he bought the refrigerator.

Answer»

ANSWER:

HIFJFFC

Step-by-step EXPLANATION:

Discussion

31.	Write all the factors of 95
Answer» Answer: FACTORS of 95 = 1,5,19,95

31.

Write all the factors of 95

Answer»

Answer: FACTORS of 95 = 1,5,19,95

Discussion

32.	Fill in the blanksSimplificatio of-2/11 X 121/2.2 11/3 is
Answer» ANSWER: -2000X/603 Step-by-step EXPLANATION:

32.

Fill in the blanksSimplificatio of-2/11 X 121/2.2 11/3 is

Answer»

ANSWER:

-2000X/603

Step-by-step EXPLANATION:

Discussion

33.	Solve the system of equation:root x + y = 11 ,&x + root y = 7for real values of x, and y?PLEASE DON'T SEND SOLUTION, I ALREADY KNOW THE SOLUTION THAT x = 4y = 9ONLY SEND PROCESS!!!IF YOU KNOW.......
Answer» Step-by-step EXPLANATION: √x+y=11 x+√y= 7 from eq 1... from eq 1...√y=7-x from eq 1...√y=7-xy=(7-x)^2 from eq 1...√y=7-xy=(7-x)^2from eq 2... from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-y from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sides from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4 *from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=** from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the RATIONAL root theorem, POSSIBLE roots are factors of 1444 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation... from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=0 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=02816-4260+1444=0. -1444+1444=0* -1444+1444=00=0 [Solved..]

33.

Solve the system of equation:root x + y = 11 ,&x + root y = 7for real values of x, and y?PLEASE DON'T SEND SOLUTION, I ALREADY KNOW THE SOLUTION THAT x = 4y = 9ONLY SEND PROCESS!!!IF YOU KNOW.......

Answer»

Step-by-step EXPLANATION:

√x+y=11

x+√y= 7

from eq 1...

from eq 1...√y=7-x

from eq 1...√y=7-xy=(7-x)^2

from eq 1...√y=7-xy=(7-x)^2from eq 2...

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-y

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sides

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the RATIONAL root theorem, POSSIBLE roots are factors of 1444

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=0

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=02816-4260+1444=0.

-1444+1444=0

-1444+1444=00=0

[Solved..]

Discussion

34.	Question 12 all of the four
Answer» Answer: 12 a. 7x-1 =13 7x= 14 x=14/7 x=2 B. 2x+3(x-1) =5/2 2x +3x - 3 =5/2 5x = 5/2 +3 5x = 11/2 x= 11/10 c. (2x-3 ) /2 - (x+1)/3 =( 3x -8)/4 (2x-3 )3 - (x+1)2 =( 3x -8)6/4 6x - 9 - 2x -2 = (9x -24 )/2 4x -11=(9x - 24)/2 8x -22 = 9x -24 24-22 = 9x-8x 2= x d. - 1.5x = - 4.5 x= -4.5/-1.5 x = 3 if the answer is useful PLS MARK as brainliest ......plsssssssss

34.

Question 12 all of the four

Answer»

Answer:

12 a. 7x-1 =13

7x= 14

x=14/7

x=2

B. 2x+3(x-1) =5/2

2x +3x - 3 =5/2

5x = 5/2 +3

5x = 11/2

x= 11/10

c. (2x-3 ) /2 - (x+1)/3 =( 3x -8)/4

(2x-3 )3 - (x+1)2 =( 3x -8)6/4

6x - 9 - 2x -2 = (9x -24 )/2

4x -11=(9x - 24)/2

8x -22 = 9x -24

24-22 = 9x-8x

2= x

d. - 1.5x = - 4.5

x= -4.5/-1.5

x = 3

if the answer is useful PLS MARK as brainliest ......plsssssssss

Discussion

35.	Tan inverse [1+cos(x/3) upon sin(x/3)]
Answer» HANG hbwbbeudhgehxuhdvevdhhebrbfjjfr

Discussion

36.	Solve [(3/5)²×(3/5)³]²÷(3/5)⁷ and write your answer in rational number
Answer» Answer:27/125 Step-by-step EXPLANATION: HELLO, HOPE IT WORKS PLEASE MARK IT AS BRAINLIEST !!!

36.

Solve [(3/5)²×(3/5)³]²÷(3/5)⁷ and write your answer in rational number

Answer»

Answer:27/125

Step-by-step EXPLANATION:

HELLO,

HOPE IT WORKS

PLEASE MARK IT AS BRAINLIEST !!!

Discussion

37.	Determine values of p for which the quad eqn 2x^2+3x+p=0 has real roots
Answer» Answer: 2x^2+3x+p=0 I THINK the EQN is WRONG. PLEASE CHECK it.

37.

Determine values of p for which the quad eqn 2x^2+3x+p=0 has real roots

Answer»

Answer:

2x^2+3x+p=0

I THINK the EQN is WRONG. PLEASE CHECK it.

Discussion

38.	Richard and Stephen win some money and share it in the ratio 6:1. Richard gets £60 more than Stephen. How much did they get altogether?
Answer» ANSWER: RICHARD GOT $72 and STEPHEN got $ 12 Step-by-step explanation:

38.

Richard and Stephen win some money and share it in the ratio 6:1. Richard gets £60 more than Stephen. How much did they get altogether?

Answer»

ANSWER:

RICHARD GOT $72 and STEPHEN got $ 12

Step-by-step explanation:

Discussion

39.	How many lakhs are there in 9 million?How many millions are there in 70 crores? I will mark u as brainlist
Answer» Step-by-step explanation: 1. 90 lakhs 2. 700 MILLIONS

39.

How many lakhs are there in 9 million?How many millions are there in 70 crores? I will mark u as brainlist

Answer»

Step-by-step explanation:

1. 90 lakhs

2. 700 MILLIONS

Discussion

40.	Find out of the following an irratitonal number 6root5
Answer» ANSWER: HEY MATE here is your answer $6 \sqrt{5} \\ 13.142$ Step-by-step explanation: Mark as brainliest and follow me

40.

Find out of the following an irratitonal number 6root5

Answer»

ANSWER:

HEY MATE here is your answer

$6 \sqrt{5} \\ 13.142$

Step-by-step explanation:

Mark as brainliest and follow me

Discussion

41.	Find the polynomial of X^3 - x
Answer» Step-by-step explanation: X + (x3 - 1)1/2]5 + [x - (x3 - 1)1/2]5 = 2(5C0x5 + 5C2x3(x3 - 1) + 5C4x(x3 - 1)2) The highest power of TERM is 7

41.

Find the polynomial of X^3 - x

Answer»

Step-by-step explanation:

X + (x3 - 1)1/2]5 + [x - (x3 - 1)1/2]5 = 2(5C0x5 + 5C2x3(x3 - 1) + 5C4x(x3 - 1)2) The highest power of TERM is 7

Discussion

42.	Sachin got a pize moneyof Rs. 1200. He spent2/3 of the money on buying shoes forhimself and gave 1/4 of the remaining moneyfor charity. He also spent 1/3 of the remaining moneyto buy a gift for her friend. How much moneyis left with him?.
Answer» Step-by-step EXPLANATION: REMAINING MONEY 200 ....RIGHT

42.

Sachin got a pize moneyof Rs. 1200. He spent2/3 of the money on buying shoes forhimself and gave 1/4 of the remaining moneyfor charity. He also spent 1/3 of the remaining moneyto buy a gift for her friend. How much moneyis left with him?.

Answer»

Step-by-step EXPLANATION:

REMAINING MONEY 200 ....RIGHT

Discussion

43.	Multiply the difference of-6/7 and -2/3 by their sum
Answer» ANSWER: muscular force is the answer.... PLZ mark me as BRAINIEST answers.... plz LIKE my answer.....

43.

Multiply the difference of-6/7 and -2/3 by their sum

Answer»

ANSWER:

muscular force is the answer....

PLZ mark me as BRAINIEST answers....

plz LIKE my answer.....

Discussion

44.	Expand each of the following, using suitable identities. (18x_11y)
Answer» Step-by-step EXPLANATION: Expand each of the FOLLOWING, USING suitable identities. (18x_11y) which of the following?

44.

Expand each of the following, using suitable identities. (18x_11y)

Answer»

Step-by-step EXPLANATION:

Expand each of the FOLLOWING, USING suitable identities. (18x_11y)

which of the following?

Discussion

45.	what is the sign and the ones digit when of the product when (-11) is multiplied with itself by 5 times
Answer» ANSWER: ONES digit 1 and sign - Step-by-step explanation: as you can see 1 when multiplied by 1 gives only 1 so 1×1×1×1×1=1 for ones digit because other digits wont AFFECT ones digit and even time product of - gives + but odd times product gives - so your ans is ones digit as 1 while -sign

45.

what is the sign and the ones digit when of the product when (-11) is multiplied with itself by 5 times

Answer»

ANSWER:

ONES digit 1 and sign -

Step-by-step explanation:

as you can see 1 when multiplied by 1 gives only 1

so

1×1×1×1×1=1

for ones digit because other digits wont AFFECT ones digit

and even time product of - gives + but odd times product gives -

so your ans is ones digit as 1

while -sign

Discussion

46.	If x^a/b =1 , then find the value of a.
Answer» ANSWER: a=0 Step-by-step explanation: as we know that any NUMBER raise to POWER 0=1 so we can also write it as, $x^{\frac{a}{b} } =1^{0} \\$ therefore, $\frac{a}{b} =0\\a=b*0\\a=0$

46.

If x^a/b =1 , then find the value of a.

Answer»

ANSWER:

a=0

Step-by-step explanation:

as we know that any NUMBER raise to POWER 0=1

so we can also write it as,

$x^{\frac{a}{b} } =1^{0} \\$

therefore,

$\frac{a}{b} =0\\a=b*0\\a=0$

Discussion

47.	Under root 2 is a polynomial of degree :(a) 2(b) o(c) 1(d) 1/2
Answer» Answer: 1/2..................

47.

Under root 2 is a polynomial of degree :(a) 2(b) o(c) 1(d) 1/2

Answer»

Answer:

1/2..................

Discussion

48.	How to do this sums
Answer» Answer: Here is your answer Step-by-step EXPLANATION: HOPE this helps pls mark as BRAINLIST

48.

How to do this sums

Answer»

Answer:

Here is your answer

Step-by-step EXPLANATION:

HOPE this helps pls mark as BRAINLIST

Discussion

49.	Pls view the attachment
Answer» Answer: Step-by-step EXPLANATION: Answer is in the IMAGE attached. HOPE this will HELP you.!!!

49.

Pls view the attachment

Answer»

Answer:

Step-by-step EXPLANATION:

Answer is in the IMAGE attached. HOPE this will HELP you.!!!

Discussion

50.	If 1 is the zero of the polynomial p(x) =ax2 -(3a-1)x-1then find the value of a
Answer» HOPE it's RIGHT and HELPS you !!!!

50.

If 1 is the zero of the polynomial p(x) =ax2 -(3a-1)x-1then find the value of a

Answer»

HOPE it's RIGHT and HELPS you !!!!

Discussion

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Mark as brainliest and follow me

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