Solve the system of equation:root x + y = 11 ,&x + root y = 7for real

1.	Solve the system of equation:root x + y = 11 ,&x + root y = 7for real values of x, and y?PLEASE DON'T SEND SOLUTION, I ALREADY KNOW THE SOLUTION THAT x = 4y = 9ONLY SEND PROCESS!!!IF YOU KNOW.......
Answer» Step-by-step EXPLANATION: √x+y=11 x+√y= 7 from eq 1... from eq 1...√y=7-x from eq 1...√y=7-xy=(7-x)^2 from eq 1...√y=7-xy=(7-x)^2from eq 2... from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-y from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sides from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4 *from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=** from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the RATIONAL root theorem, POSSIBLE roots are factors of 1444 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation... from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=0 from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=02816-4260+1444=0. -1444+1444=0* -1444+1444=00=0 [Solved..]

Solve the system of equation:root x + y = 11 ,&x + root y = 7for real values of x, and y?PLEASE DON'T SEND SOLUTION, I ALREADY KNOW THE SOLUTION THAT x = 4y = 9ONLY SEND PROCESS!!!IF YOU KNOW.......

Answer»

Step-by-step EXPLANATION:

√x+y=11

x+√y= 7

from eq 1...

from eq 1...√y=7-x

from eq 1...√y=7-xy=(7-x)^2

from eq 1...√y=7-xy=(7-x)^2from eq 2...

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-y

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sides

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the RATIONAL root theorem, POSSIBLE roots are factors of 1444

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=0

from eq 1...√y=7-xy=(7-x)^2from eq 2...√x=11-ysubstitute (7-x)^2 for y√x=11-(7-x)^2square both sidesx=121-22(7-x)^2+(7-x)^4(7-x)^4=(x-7)^2*(x-7)^2=(x^2-14x+49)(x^2-14x-49)=x^4-28x^3+294x^2-1372x+2401x=121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+24010=-x+121-22x^2+308x-1078+x^4-28x^3+294x^2-1372x+2401x^4-28x^3+272x^2-1065x+1444=0from the rational root theorem, possible roots are factors of 14444 is a factor of 1444 and a root of the equation...256-1792+4352-4260+1444=0-1536+4352-4260+1444=02816-4260+1444=0.

-1444+1444=0

-1444+1444=00=0

[Solved..]

Solve the system of equation:root x + y = 11 ,&x + root y = 7for real values of x, and y?PLEASE DON'T SEND SOLUTION, I ALREADY KNOW THE SOLUTION THAT x = 4y = 9ONLY SEND PROCESS!!!IF YOU KNOW.......

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Solve the system of equation:root x + y = 11 ,&x + root y = 7for real values of x, and y?PLEASE DON'T SEND SOLUTION, I ALREADY KNOW THE SOLUTION THAT x = 4y = 9ONLY SEND PROCESS!!!IF YOU KNOW.......​

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Solve the system of equation:root x + y = 11 ,&x + root y = 7for real values of x, and y?PLEASE DON'T SEND SOLUTION, I ALREADY KNOW THE SOLUTION THAT x = 4y = 9ONLY SEND PROCESS!!!IF YOU KNOW.......