332354 + Interview Questions in Secondary School in Math

1.	(10 5 6 2 40 ) 11 5 8 4 ?
Answer» sorry can't UNDERSTAND this QUESTION PLZZ TYPE again sorry

1.

(10 5 6 2 40 ) 11 5 8 4 ?

Answer»

sorry can't UNDERSTAND this QUESTION PLZZ TYPE again sorry

Discussion

2.	1/x + 1/x+5 = 1/10solve for x
Answer» plz MARK my ANSWER brainliest and FOLLOW me PLEASE Step-by-step explanation: 1/x + 1/x +5=1/10 2/x =1/10-5 2/x=-49/10 20=-49x -20/49=x

2.

1/x + 1/x+5 = 1/10solve for x

Answer»

plz MARK my ANSWER brainliest and FOLLOW me PLEASE

Step-by-step explanation:

1/x + 1/x +5=1/10

2/x =1/10-5

2/x=-49/10

20=-49x

-20/49=x

Discussion

3.	There are four prime numbers written in ascending order. The product of the first three is 1001 and that of the last three is 2431. The last number is:
Answer» The ANSWER for your QUESTION is 13

3.

There are four prime numbers written in ascending order. The product of the first three is 1001 and that of the last three is 2431. The last number is:

Answer»

The ANSWER for your QUESTION is 13

Discussion

4.	in the figure given below, AC and BD are two perpendicular diameters of a circle with centre O. If AC= 16 cm, calculate the area and perimeter of the shaded region (take pi= 3.14)
Answer» GIVEN :- Diameter of CIRCLE , d = 16 cm. TO FIND :- The area of the shaded region. Perimeter of the shaded region. SOLUTION :- $\\ : \implies \displaystyle \sf \: Radius = \frac{d}{2} \\ \\ \\$ $: \implies \displaystyle \sf \: Radius = \frac{16}{2} \\ \\ \\$ $: \implies \underline{ \boxed{\displaystyle \sf \: Radius = 8 \: cm.}} \\ \\$ ____________________… $\\ \\$ $: \implies \displaystyle \sf \: Area \: of \: shaded \: region = 2 \times \frac{1}{4} \pi r ^{2} \\ \\ \\$ $: \implies \displaystyle \sf \: Area \: of \: shaded \: region = \frac{1}{2} \times 3.14 \times (8) ^{2} \\ \\ \\$ $: \implies \displaystyle \sf \: Area \: of \: shaded \: region = \frac{1}{2} \times 3.14 \times 8 \times 8 \\ \\ \\$ $: \implies \displaystyle \sf \: Area \: of \: shaded \: region = 3.14 \times 4 \times 8 \\ \\ \\$ $: \implies \underline{ \boxed{ \displaystyle \sf \: Area \: of \: shaded \: region = 100.48 \: cm ^{2} }}\\ \\$ ____________________… $\\ \\ \dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( \frac{1}{4} \times 2\pi r + 2r \bigg) \\ \\ \\$ $\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( \frac{1}{2} \times \pi r + 2 r \bigg)\\ \\ \\$ $\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( \frac{1}{2} \times 3.14 \times 8 + 2 \times 8 \bigg) \\ \\ \\$ $\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( 3.14 \times 4+ 16 \bigg) \\ \\ \\$ $\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg(12.56 + 16 \bigg) \\ \\ \\$ $\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \times 28.56 \\ \\ \\$ $\dashrightarrow \underline{ \boxed{ \displaystyle \sf \: Perimeter\: of \: shaded \: region = 57.12 \: cm}} \\$

4.

in the figure given below, AC and BD are two perpendicular diameters of a circle with centre O. If AC= 16 cm, calculate the area and perimeter of the shaded region (take pi= 3.14)

Answer»

GIVEN :-

Diameter of CIRCLE , d = 16 cm.

TO FIND :-

The area of the shaded region.
Perimeter of the shaded region.

SOLUTION :-

$\\ : \implies \displaystyle \sf \: Radius = \frac{d}{2} \\ \\ \\$

$: \implies \displaystyle \sf \: Radius = \frac{16}{2} \\ \\ \\$

$: \implies \underline{ \boxed{\displaystyle \sf \: Radius = 8 \: cm.}} \\ \\$

____________________…

$\\ \\$

$: \implies \displaystyle \sf \: Area \: of \: shaded \: region = 2 \times \frac{1}{4} \pi r ^{2} \\ \\ \\$

$: \implies \displaystyle \sf \: Area \: of \: shaded \: region = \frac{1}{2} \times 3.14 \times (8) ^{2} \\ \\ \\$

$: \implies \displaystyle \sf \: Area \: of \: shaded \: region = \frac{1}{2} \times 3.14 \times 8 \times 8 \\ \\ \\$

$: \implies \displaystyle \sf \: Area \: of \: shaded \: region = 3.14 \times 4 \times 8 \\ \\ \\$

$: \implies \underline{ \boxed{ \displaystyle \sf \: Area \: of \: shaded \: region = 100.48 \: cm ^{2} }}\\ \\$

____________________…

$\\ \\ \dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( \frac{1}{4} \times 2\pi r + 2r \bigg) \\ \\ \\$

$\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( \frac{1}{2} \times \pi r + 2 r \bigg)\\ \\ \\$

$\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( \frac{1}{2} \times 3.14 \times 8 + 2 \times 8 \bigg) \\ \\ \\$

$\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg( 3.14 \times 4+ 16 \bigg) \\ \\ \\$

$\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \bigg(12.56 + 16 \bigg) \\ \\ \\$

$\dashrightarrow \displaystyle \sf \: Perimeter\: of \: shaded \: region = 2 \times 28.56 \\ \\ \\$

$\dashrightarrow \underline{ \boxed{ \displaystyle \sf \: Perimeter\: of \: shaded \: region = 57.12 \: cm}} \\$

Discussion

5.	The product of 5 is 300. what are the values of these multiples?
Answer» Answer: the process by which GREEN PLANTS TURN CARBON dioxide and WATER into food using energy from sunlight सूर्य के प्रकाश से हरे पौधों द्वारा कार्बन डाइ-ऑक्‍साइड और जल को भोजन का रूप देने की प्रक्रिया; प्रकाश-संश्‍लेषण; फ़ोटोसिंथीसिस

5.

The product of 5 is 300. what are the values of these multiples?

Answer»

Answer:

the process by which GREEN PLANTS TURN CARBON dioxide and WATER into food using energy from sunlight

सूर्य के प्रकाश से हरे पौधों द्वारा कार्बन डाइ-ऑक्‍साइड और जल को भोजन का रूप देने की प्रक्रिया; प्रकाश-संश्‍लेषण; फ़ोटोसिंथीसिस

Discussion

6.	1 ਦਾ ਮੁੱਲ ਹੈ।1Find the value of1+211+2का मूल्य पता करें.
Answer» ANSWER: ffuuduuffcuchcuuffuuuuullllkkll

6.

1 ਦਾ ਮੁੱਲ ਹੈ।1Find the value of1+211+2का मूल्य पता करें.

Answer»

ANSWER:

ffuuduuffcuchcuuffuuuuullllkkll

Discussion

7.	Write a define in (1) Desplacement(2) velocity
Answer» ANSWER: DISPLACEMENT is the vector difference between the ENDING and starting positions of an object. VELOCITY is the rate at which displacement CHANGES with time.

7.

Write a define in (1) Desplacement(2) velocity

Answer»

ANSWER:

DISPLACEMENT is the vector difference between the ENDING and starting positions of an object. VELOCITY is the rate at which displacement CHANGES with time.

Discussion

8.	Questions of distributive law of sets using venn diagram
Answer» ANSWER: QUESTIONS???? i didn't UNDERSTAND

8.

Questions of distributive law of sets using venn diagram

Answer»

ANSWER:

QUESTIONS????

i didn't UNDERSTAND

Discussion

9.	Pls any one help me
Answer» Step-by-step EXPLANATION: Your ANSWER is 0+4 = 4 ANS....

9.

Pls any one help me

Answer»

Step-by-step EXPLANATION:

Your ANSWER is 0+4 = 4 ANS....

Discussion

10.	Pls tell the full explanation
Answer» Explanation: Area of trapezium can be find using the formula: m DA ( m AB + m DC ) / 2 or we can SAY it. { h ( a + b ) / 2 } or we can simply find area by DIVIDE the trapezium into parts ... like in this figure trapezium is divided into two parts ... Triangle and Rectangle.. In this way we simply FING the area of rectangle and triangle separately and add both of their area to get area of trapezium.

10.

Pls tell the full explanation

Answer»

Explanation:

Area of trapezium can be find using the formula:

m DA ( m AB + m DC ) / 2

or we can SAY it. { h ( a + b ) / 2 }

or

we can simply find area by DIVIDE the trapezium into parts ...

like in this figure trapezium is divided into two parts ... Triangle and Rectangle..

In this way we simply FING the area of rectangle and triangle separately and add both of their area to get area of trapezium.

Discussion

11.	Summary of ch-15"in sparsh of class 10
Answer» ANSWER: sorry there I'm in CLASS 8 Step-by-step EXPLANATION: PLEASE FOLLOW me

11.

Summary of ch-15"in sparsh of class 10

Answer»

ANSWER:

sorry there I'm in CLASS 8

Step-by-step EXPLANATION:

PLEASE FOLLOW me

Discussion

12.	सॉल्व इक्वेशन फॉर एक्स प्लस 6 स्क्वायर माइनस वन 14 एंड टू एक्स प्लस वाई इज इक्वल टू सिक्स क्रिएट ए टेबल
Answer» ANSWER: PLEASE WRITE in ENGLISH

12.

सॉल्व इक्वेशन फॉर एक्स प्लस 6 स्क्वायर माइनस वन 14 एंड टू एक्स प्लस वाई इज इक्वल टू सिक्स क्रिएट ए टेबल

Answer»

ANSWER:

PLEASE WRITE in ENGLISH

Discussion

13.	Express the trigonometric ratios sin A, secAand 10A in term of cotA
Answer» We all know that tan is reciprocal of cot a . (Cosec a )^2=1+cot^2a Cosec a =(1+cot^2a)^1/2 And SIN a =1/cosec a so sin a =1/1+cot^2a SEC a =1+tan^2a so sec a will be under root 1+tan^2a. sec a =(cot^2a+1)^(1/2)/(cot a) HOPE this will help and please MARK this brainliest please .

13.

Express the trigonometric ratios sin A, secAand 10A in term of cotA

Answer»

We all know that tan is reciprocal of cot a . (Cosec a )^2=1+cot^2a

Cosec a =(1+cot^2a)^1/2

And SIN a =1/cosec a so sin a =1/1+cot^2a

SEC a =1+tan^2a so sec a will be under root 1+tan^2a.

sec a =(cot^2a+1)^(1/2)/(cot a)

HOPE this will help and please MARK this brainliest please .

Discussion

14.	Find the area of an isoscale right triangle of equal side of 40 cm each
Answer» SOLUTION : AREA of right triangle = 1/2LENGTHbreadth Step-by-step EXPLANATION: Length=40,Breadth=40 =1/24040 =800cm^2

14.

Find the area of an isoscale right triangle of equal side of 40 cm each

Answer»

SOLUTION :

AREA of right triangle = 1/2*LENGTH*breadth

Step-by-step EXPLANATION:

Length=40,Breadth=40

=1/2*40*40

=800cm^2

Discussion

15.	Two ants of length 1cm and 1.2 cm crawl in opposite directions with averagespeeds 2 and 1 mm per second respectively. How many seconds will they take to cross each other?A. 4.4B. 2.8C. 0.4
Answer» ANSWER: i THINK answer is :- Step-by-step EXPLANATION: OPTION (A) That is =4.4

15.

Two ants of length 1cm and 1.2 cm crawl in opposite directions with averagespeeds 2 and 1 mm per second respectively. How many seconds will they take to cross each other?A. 4.4B. 2.8C. 0.4

Answer»

ANSWER:

i

THINK

answer

is

:-

Step-by-step EXPLANATION:

OPTION (A)

That

is

=4.4

Discussion

16.	11. Find the missing term in the following perfect squares.(i) 9m² - ( ) + 64n2 (ii) ( ) + 48x + 64 (iii) 25a2 +120ab +( )(iv) ( ) -90xy +81y2
Answer» (48mn) (9X) (144b^2) (25x^2)

Discussion

17.	If (x-5) (x+3)_x(square)+ax-15, then the value of a is with explanation..
Answer» Step-by-step explanation: 1. (x^m)^N =x^mn so (3^4)^5= 3^20 2. CUBE of NEGATIVE NUMBER is negative

17.

If (x-5) (x+3)_x(square)+ax-15, then the value of a is with explanation..

Answer»

Step-by-step explanation:

1. (x^m)^N =x^mn

so (3^4)^5= 3^20

2. CUBE of NEGATIVE NUMBER is negative

Discussion

18.	1/5, 3/7, 7/10 descending order
Answer» Answer: 7/10 ,3/7 ,1/5 ..................

18.

1/5, 3/7, 7/10 descending order

Answer»

Answer:

7/10 ,3/7 ,1/5

..................

Discussion

19.	2.Write any 5 rational numbers between -2 and 0
Answer» ANSWER: -1,-1/2,-1/3,-1/4,-1/5 are 5 rational NUMBERS between -2 and 0

19.

2.Write any 5 rational numbers between -2 and 0

Answer»

ANSWER:

-1,-1/2,-1/3,-1/4,-1/5 are 5 rational NUMBERS between -2 and 0

Discussion

20.	Albert bougth his bicycle for $275 he sold it gor $350
Answer» ANSWER: udjdhshsuzuuzizozozizkzjshdjsjzjzjzuz

20.

Albert bougth his bicycle for $275 he sold it gor $350

Answer»

ANSWER:

udjdhshsuzuuzizozozizkzjshdjsjzjzjzuz

Discussion

21.	The supplement of 125 degree is
Answer» ANSWER: The SUPPLEMENT of 125° is 55°

21.

The supplement of 125 degree is

Answer»

ANSWER:

The SUPPLEMENT of 125° is 55°

Discussion

22.	The product of two digit number is 1904if the product of using digit of tens digit 15find the number
Answer» ANSWER: PLEASE FOLLOW me then I

22.

The product of two digit number is 1904if the product of using digit of tens digit 15find the number

Answer»

ANSWER:

PLEASE FOLLOW me then I

Discussion

23.	Find the wool number if N + 4 = 9
Answer» ANSWER: N+4=9 N =9-4 N=5 the VALUE of N is 5.

23.

Find the wool number if N + 4 = 9

Answer»

ANSWER:

N+4=9

N =9-4

N=5

the VALUE of N is 5.

Discussion

24.	Raji is a is thrice times more than that of brother after two years is it be that of charge and how are they now
Answer» ANSWER: LET the present age of raji and brother be x and y respectively. ∴ Given that five YEARS ago, SHIKHA was thrice as old as Rani. ⇒(x−5)=3(y−5) ⇒x−5=3y−15 ⇒3y−x=10⟶(i) Also given that 10 years later, Shikha will be twice as old as Rani. ∴(x+10)=2(y+10) ⇒x+10=2y+20 ⇒x=2y+10 Substituting the value of x in EQ n (i), we have 3y−(2y+10)=10 ⇒3y−2y−10=10 ⇒y=20 ∵x=2y+10 ⇒x=2×20+10 ⇒x=50 Hence, present age of Shikha and Rani are 50 and 20 respectively.

24.

Raji is a is thrice times more than that of brother after two years is it be that of charge and how are they now

Answer»

ANSWER:

LET the present age of raji and brother be x and y respectively.

∴ Given that five YEARS ago, SHIKHA was thrice as old as Rani.

⇒(x−5)=3(y−5)

⇒x−5=3y−15

⇒3y−x=10⟶(i)

Also given that 10 years later, Shikha will be twice as old as Rani.

∴(x+10)=2(y+10)

⇒x+10=2y+20

⇒x=2y+10

Substituting the value of x in EQ

n

(i), we have

3y−(2y+10)=10

⇒3y−2y−10=10

⇒y=20

∵x=2y+10

⇒x=2×20+10

⇒x=50

Hence, present age of Shikha and Rani are 50 and 20 respectively.

Discussion

25.	Dividend Divisor Quotient Remainder Division Equation32293 126 256 37
Answer» What should be DIVIDED by what The QUESTION is not PROPER

Discussion

26.	P= 3500 and rate = 10/3 and time 73 days
Answer» Step-by-step EXPLANATION: This is a RIGHT ANSWER MARK me as BRAINLIST

26.

P= 3500 and rate = 10/3 and time 73 days

Answer»

Step-by-step EXPLANATION:

This is a RIGHT ANSWER MARK me as BRAINLIST

Discussion

27.	Which of the following rational numbers 49 - 5 by 6 minus 7 by minus 12 and 11 by minus 24 is the smallest
Answer» ANSWER: hi HOPE you UNDERSTAND my dear FRIEND

27.

Which of the following rational numbers 49 - 5 by 6 minus 7 by minus 12 and 11 by minus 24 is the smallest

Answer»

ANSWER:

hi HOPE you UNDERSTAND my dear FRIEND

Discussion

28.	Lcm of 4 , 8 and 12 should be ------
Answer» 24 is the LCM for 4,8,12

Discussion

29.	Find two solution for the equation 4x + 3y = 24
Answer» Answer: 4x + 3Y = 24 If X = 0 then, 4x0 + 3y= 24 0 + 3y= 24 y=24÷3 y=8 therefore, 0, 8 is the solution for EQUATION 4x+3y=24

29.

Find two solution for the equation 4x + 3y = 24

Answer»

Answer:

4x + 3Y = 24

If X = 0 then,

4x0 + 3y= 24

0 + 3y= 24

y=24÷3

y=8

therefore, 0, 8 is the solution for EQUATION 4x+3y=24

Discussion

30.	Find the sum of the series 8 by 737 up to 16 term
Answer» Answer: every e ihdv3 ei has a Movie orseries that the world is the same to u Bro plz like the other 336rd 63of 3366366th of you are TU mitra but I saw it on the day that it very d was there a Movie about it V it very well had a GOOD night and it was a little bit DIFFERENT than it very OFTEN and I saw the same way I am in nice question thank you

30.

Find the sum of the series 8 by 737 up to 16 term

Answer»

Answer:

every e ihdv3 ei has a Movie orseries that the world is the same to u Bro plz like the other 336rd 63of 3366366th of you are TU mitra but I saw it on the day that it very d was there a Movie about it V it very well had a GOOD night and it was a little bit DIFFERENT than it very OFTEN and I saw the same way I am in

nice question

thank you

Discussion

31.	The point of intersection of co-oridinate axes is called
Answer» ANSWER: ORIGIN Step-by-step EXPLANATION: it is KNOWN as origin

31.

The point of intersection of co-oridinate axes is called

Answer»

ANSWER:

ORIGIN

Step-by-step EXPLANATION:

it is KNOWN as origin

Discussion

32.	The angle of a triangle are in the ratio 2:3:4. Find the angle
Answer» ANSWER: sum of the three ANGLES of a triangle is 180° the angles are in the ratio 2:3:4 so the 1st angle is 2×180/(2+3+4)° =2×180/9 =2×20°=40° the 2ND angle is 3×180/(2+3+4)° =3×180/9° =3×20°=60° the 3rd angle is 4×180/(2+3+4)° =4×180/9° =4×20°=80°

32.

The angle of a triangle are in the ratio 2:3:4. Find the angle

Answer»

ANSWER:

sum of the three ANGLES of a triangle is 180°

the angles are in the ratio 2:3:4

so the 1st angle is 2×180/(2+3+4)°

=2×180/9

=2×20°=40°

the 2ND angle is 3×180/(2+3+4)°

=3×180/9°

=3×20°=60°

the 3rd angle is 4×180/(2+3+4)°

=4×180/9°

=4×20°=80°

Discussion

33.	In the given figure , if PQ∥ , ∠ = 110° ∠ = 130° ∠.step by step explanation please.
Answer» Step-by-step EXPLANATION: I can SAY LIKE this WAY only Don't MIND

33.

In the given figure , if PQ∥ , ∠ = 110° ∠ = 130° ∠.step by step explanation please.

Answer»

Step-by-step EXPLANATION:

I can SAY LIKE this WAY only

Don't MIND

Discussion

34.	√3x2-5x+2√3=0 using the general formula, and find the solution
Answer» Step-by-step explanation: 3x2-5x+2√3=0 USING the GENERAL FORMULA, and FIND the SOLUTION

34.

√3x2-5x+2√3=0 using the general formula, and find the solution

Answer»

Step-by-step explanation:

3x2-5x+2√3=0 USING the GENERAL FORMULA, and FIND the SOLUTION

Discussion

35.	Pls solve it with a relevant ans !
Answer» TOH Aapko kya bolu Sister ya friend My choice Friend and your choice Sorry Sister nahi bana SAKTA aapko because Meri pehle SE HI bauht sisters hai

35.

Pls solve it with a relevant ans !

Answer»

TOH Aapko kya bolu Sister ya friend

My choice Friend and your choice

Sorry Sister nahi bana SAKTA aapko because Meri pehle SE HI bauht sisters hai

Discussion

36.	1 MUSL ve a girl!signals can be generated?A Signal is generated from 2 flags by puttingone flag above the other. If 4 flags of differentcolours are available, how many different
Answer» ANSWER: I did not UNDERSTAND your QUESTION dear sorry for it...........

36.

1 MUSL ve a girl!signals can be generated?A Signal is generated from 2 flags by puttingone flag above the other. If 4 flags of differentcolours are available, how many different

Answer»

ANSWER:

I did not UNDERSTAND your QUESTION dear

sorry for it...........

Discussion

37.	Please answer chapter:indices
Answer» Step-by-step EXPLANATION: (8²)⅙ = 8⅓ 8⅓/9½ ___ ____ ³\/ 8 / ²\/ 9 2/3

37.

Please answer chapter:indices

Answer»

Step-by-step EXPLANATION:

(8²)⅙ = 8⅓

8⅓/9½

___ ____

³\/ 8 / ²\/ 9

2/3

Discussion

38.	A car accelerates uniformly from 5m/s to 10m/s in 5 seconds . find its acceleration
Answer» Step-by-step explanation: Initial VELOCITY of the car (u)= 5 m/s Final velocity of the car (v) = 10 m/s Time taken for change in velocity (t)= 5 s Therefore acceleration (a)= [10 m/s - 5 m/s]/ 5 s = 5 m/s /5s = 1 m/s² Distance covered during these 5 seconds, is FOUND using the relation s = u t + ½ a t² = 5 m/s× 5 s + ½ 1 m/s² × 5² s²=25 m+ 12.5 m = 37.5 m So car covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s.

38.

A car accelerates uniformly from 5m/s to 10m/s in 5 seconds . find its acceleration

Answer»

Step-by-step explanation:

Initial VELOCITY of the car (u)= 5 m/s

Final velocity of the car (v) = 10 m/s

Time taken for change in velocity (t)= 5 s

Therefore acceleration (a)= [10 m/s - 5 m/s]/ 5 s = 5 m/s /5s = 1 m/s²

Distance covered during these 5 seconds, is FOUND using the relation

s = u t + ½ a t² = 5 m/s× 5 s + ½ 1 m/s² × 5² s²=25 m+ 12.5 m = 37.5 m

So car covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s.

Discussion

39.	Plzzzzzzzzz ans rlly important
Answer» ANSWER: the answer is 1500 ROOT over 3

39.

Plzzzzzzzzz ans rlly important

Answer»

ANSWER:

the answer is 1500 ROOT over 3

Discussion

40.	Find the combined equations of lines passing throughOriginperpendicular of is parallel to atx+2y=5and other is perpendicular2x-y+3=0
Answer» Step-by-step explanation: The line PARALLEL to the line x−2y=2 is x−2y=k which PASSES through (3,2) then we get, 3−2.2=k or, k=−1. So the equation of the line is x−2y=−1.....(1) Again the line perpendicular to y=3 is x=k, which passes through (3,2) then we've, x=3.....(2) Now JOINT equation REPRESENTED by (1) and (2) is, (x−3)(x−2y+1)=0.

40.

Find the combined equations of lines passing throughOriginperpendicular of is parallel to atx+2y=5and other is perpendicular2x-y+3=0

Answer»

Step-by-step explanation:

The line PARALLEL to the line x−2y=2 is x−2y=k which PASSES through (3,2) then we get, 3−2.2=k or, k=−1.

So the equation of the line is x−2y=−1.....(1)

Again the line perpendicular to y=3 is x=k, which passes through (3,2) then we've, x=3.....(2)

Now JOINT equation REPRESENTED by (1) and (2) is,

(x−3)(x−2y+1)=0.

Discussion

41.	4x-6x+3x-7x=9 solve this linear equation .
Answer» X = -3/2 is the CORRECT ANSWER...

Discussion

42.	52+_____+302+=312 hi please please please please say me the answer
Answer» Answer: 52+(-42)+302=312 Step-by-step explanation: 52+____ + 302 =312 x+354=312 x=312-354 x= -42 hope it will HELP U

42.

52+_____+302+=312 hi please please please please say me the answer

Answer»

Answer:

52+(-42)+302=312

Step-by-step explanation:

52+____ + 302 =312

x+354=312

x=312-354

x= -42

hope it will HELP U

Discussion

43.	In the following questions, two statements are given followed by fourconclusions 1. II. III and IV. You have to consider the two statements to betrue even if they seem to be at variance from commonly known facts.You have to decide which of the given conclusions, if any, follow from thegiven statementsStatementsSome stones are gold.Some gold are banksConclusionsSome banks are stonesII. Some gold are stonesIL No stone is bankIV. All banks are gold
Answer» Answer:Question In the following QUESTIONS, two STATEMENTS are given FOLLOWED by four conclusions 1. II. III and IV. You have to consider the two statements to be true even if they seem to be at variance from commonly KNOWN facts. You have to decide which of the given conclusions, if any, follow from the given statements Statements Some stones are gold. Some gold are BANKS Conclusions Some banks are stones II. Some gold are stones IL No stone is bank IV. All banks are gold Step-by-step explanation:

43.

In the following questions, two statements are given followed by fourconclusions 1. II. III and IV. You have to consider the two statements to betrue even if they seem to be at variance from commonly known facts.You have to decide which of the given conclusions, if any, follow from thegiven statementsStatementsSome stones are gold.Some gold are banksConclusionsSome banks are stonesII. Some gold are stonesIL No stone is bankIV. All banks are gold

Answer»

Answer:Question

In the following QUESTIONS, two STATEMENTS are given FOLLOWED by four

conclusions 1. II. III and IV. You have to consider the two statements to be

true even if they seem to be at variance from commonly KNOWN facts.

You have to decide which of the given conclusions, if any, follow from the

given statements

Statements

Some stones are gold.

Some gold are BANKS

Conclusions

Some banks are stones

II. Some gold are stones

IL No stone is bank

IV. All banks are gold

Step-by-step explanation:

Discussion

44.	Bahulak gyat kijiye 3,4,4,2,8,6,7,4,3
Answer» 1.5.9.10 . . . .. .. Step-by-step EXPLANATION: . . . .

44.

Bahulak gyat kijiye 3,4,4,2,8,6,7,4,3

Answer»

1.5.9.10

.

..

Step-by-step EXPLANATION:

.

Discussion

45.	What is the value of 20 tens
Answer» ye answer padh rahe HO na... EK baar is id ka naam dekho.... and upar wale answer ka id dekho... same... dono mere is hai.. bas ye upar wala purana hai... iska passward bhool gaya... so isme genius jaana hai... HELP me and MARK this as brainliest... PLS..

45.

What is the value of 20 tens

Answer»

ye answer padh rahe HO na... EK baar is id ka naam dekho....

and upar wale answer ka id dekho... same... dono mere is hai.. bas ye upar wala purana hai... iska passward bhool gaya... so isme genius jaana hai... HELP me and MARK this as brainliest... PLS..

Discussion

46.	4. The degree of the expression xły – 2x2 + 7x + 9 iswith solution
Answer» ANSWER: the DEGREE of the EXPRESSION is 2

46.

4. The degree of the expression xły – 2x2 + 7x + 9 iswith solution

Answer»

ANSWER:

the DEGREE of the EXPRESSION is 2

Discussion

47.	Question 3Find the roots of the quadratic equation using completing the square method and hence verify itwith quadratic formulaa. X^2+4x-5=0b. 2x^2-7x+3=0
Answer» COMPARE 4X with 2av for b^2 then ADD b^2 both SIDE

Discussion

48.	Find 3 irrational no. between 5/7 and 9/10
Answer» Answer: 1) 0.87499473653574676300... 2)0.87738802368102837... 3)0.790048938777892003 Step-by-step explanation: 5/7 = 0.72 9/10 = 0.9 There any NUMBER between 0.72 and 0.9 which is NON-terminating non- recurring would be an IRRATIONAL number.

48.

Find 3 irrational no. between 5/7 and 9/10

Answer»

Answer:

1) 0.87499473653574676300...

2)0.87738802368102837...

3)0.790048938777892003

Step-by-step explanation:

5/7 = 0.72

9/10 = 0.9

There any NUMBER between 0.72 and 0.9 which is NON-terminating non- recurring would be an IRRATIONAL number.

Discussion

49.	S=ut+1/2gt² make 'g' the subject
Answer» Step-by-step EXPLANATION: g=2(s-ut)/t^2 I HOPE it is RIGHT

49.

S=ut+1/2gt² make 'g' the subject

Answer»

Step-by-step EXPLANATION:

g=2(s-ut)/t^2

I HOPE it is RIGHT

Discussion

50.	Find three rational number between -3/13and5/13
Answer» Answer: 2/13 is the RATIONAL NUMBER

50.

Find three rational number between -3/13and5/13

Answer»

Answer:

2/13 is the RATIONAL NUMBER

Discussion

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