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Express the trigonometric ratios sin A, secAand 10A in term of cotA |
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Answer» We all know that tan is reciprocal of cot a . (Cosec a )^2=1+cot^2a Cosec a =(1+cot^2a)^1/2 And SIN a =1/cosec a so sin a =1/1+cot^2a SEC a =1+tan^2a so sec a will be under root 1+tan^2a. sec a =(cot^2a+1)^(1/2)/(cot a) HOPE this will help and please MARK this brainliest please . |
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