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A car accelerates uniformly from 5m/s to 10m/s in 5 seconds . find its acceleration |
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Answer» Step-by-step explanation: Initial VELOCITY of the car (u)= 5 m/s Final velocity of the car (v) = 10 m/s Time taken for change in velocity (t)= 5 s Therefore acceleration (a)= [10 m/s - 5 m/s]/ 5 s = 5 m/s /5s = 1 m/s² Distance covered during these 5 seconds, is FOUND using the relation s = u t + ½ a t² = 5 m/s× 5 s + ½ 1 m/s² × 5² s²=25 m+ 12.5 m = 37.5 m So car covers 37.5 m during the period its velocity changes from 5 m/s to 10 m/s. |
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