332354 + Interview Questions in Secondary School in Math

1.	Solve the equation is 2x+1/3+1=x-4/6
Answer» Answer: ITNI tension KYU le RAHA h Google pr search KR le.

1.

Solve the equation is 2x+1/3+1=x-4/6

Answer»

Answer:

ITNI tension KYU le RAHA h Google pr search KR le.

Discussion

2.	आकर्षित tell me answer :)
Answer» ANSWER: what's the QUESTION ❓❓❓❓

2.

आकर्षित tell me answer :)

Answer»

ANSWER:

what's the QUESTION ❓❓❓❓

Discussion

3.	Simultaneous equation in variable DX=65 dy =91 d=13 then y?
Answer» ▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬ Q1)simultaneous EQUATION in VARIABLE Dx=65 and Dy=91, d=13 then y=?? $\: \bullet \underline{ \boxed{ \bf{answer}}}$ $\: \implies \displaystyle \tt{by \: crammers \: rule}$ $\implies\displaystyle\tt{x=\dfrac{D_x}{D} \: and \: y=\dfrac{D_y}{D}}$ $\implies\displaystyle\tt{x=\dfrac{65}{13}=\cancel\dfrac{65}{13}=5}$ $\implies\displaystyle\tt{y=\dfrac{91}{13}=\cancel\dfrac{91}{13}=7}$ $\: \\ \implies \boxed{\displaystyle \tt{the \: value \: of \: x \: and \: y \: is \: 5 \: and \: 7}}$

3.

Simultaneous equation in variable DX=65 dy =91 d=13 then y?

Answer»

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Q1)simultaneous EQUATION in VARIABLE Dx=65 and Dy=91, d=13 then y=??

$\: \bullet \underline{ \boxed{ \bf{answer}}}$

$\: \implies \displaystyle \tt{by \: crammers \: rule}$

$\implies\displaystyle\tt{x=\dfrac{D_x}{D} \: and \: y=\dfrac{D_y}{D}}$

$\implies\displaystyle\tt{x=\dfrac{65}{13}=\cancel\dfrac{65}{13}=5}$

$\implies\displaystyle\tt{y=\dfrac{91}{13}=\cancel\dfrac{91}{13}=7}$

$\: \\ \implies \boxed{\displaystyle \tt{the \: value \: of \: x \: and \: y \: is \: 5 \: and \: 7}}$

Discussion

4.	Show how √5 can be represented on the numerator
Answer» ANSWER: You MEAN NUMBER LINE ??????? . . . .

4.

Show how √5 can be represented on the numerator

Answer»

ANSWER:

You MEAN NUMBER LINE ???????

.

Discussion

5.	A rocket in the shape of a cone is attached to acylinder with the same base radius. The cone has aslant height of 15 m. The cylinder has a base diameterof 12 m and a height of 42 m. Find the total surfacearea of the rocket.
Answer» ANSWER: HOPE it's HELPFUL.......

5.

A rocket in the shape of a cone is attached to acylinder with the same base radius. The cone has aslant height of 15 m. The cylinder has a base diameterof 12 m and a height of 42 m. Find the total surfacearea of the rocket.

Answer»

ANSWER:

HOPE it's HELPFUL.......

Discussion

6.	Find the smallest natural number that we need to divide 1331 with to make it a perfect square
Answer» Answer: will MULTIPLIED by 11 the PRODUCT will be 14641 SQUARE root 121.

6.

Find the smallest natural number that we need to divide 1331 with to make it a perfect square

Answer»

Answer:

will MULTIPLIED by 11 the PRODUCT will be 14641 SQUARE root 121.

Discussion

7.	The perimeter of a triangular garden is 300cm and its sides are in the ratio 3:5:4 .Using Herons formula find the area of the triangular garden
Answer» ANSWER: PLEASE MARK my answer as BRAINLIEST

7.

The perimeter of a triangular garden is 300cm and its sides are in the ratio 3:5:4 .Using Herons formula find the area of the triangular garden

Answer»

ANSWER:

PLEASE MARK my answer as BRAINLIEST

Discussion

8.	Please help as soon as possible sum no-26 and 27
Answer» Answer: sorry mujhe NHI aata ..bye bye Step-by-step explanation: I WANT some POINT

8.

Please help as soon as possible sum no-26 and 27

Answer»

Answer:

sorry mujhe NHI aata ..bye bye

Step-by-step explanation:

I WANT some POINT

Discussion

9.	Draw, a plan of the seating in your classicom, pushing all the deske togethers. Represent each desk, which the Square represents. Position of each student in the classroom is described fulcisely, by using two independent information.
Answer» ANSWER: THANKS for GIVING FREE POINTS to me

9.

Draw, a plan of the seating in your classicom, pushing all the deske togethers. Represent each desk, which the Square represents. Position of each student in the classroom is described fulcisely, by using two independent information.

Answer»

ANSWER:

THANKS for GIVING FREE POINTS to me

Discussion

10.	Solve cos x + sin x = cos 2x + sin 2x
Answer» ANSWER: -COS X = SIN x...........

10.

Solve cos x + sin x = cos 2x + sin 2x

Answer»

ANSWER:

-COS X = SIN x...........

Discussion

11.	activity to complete the following table to draw the graph of the equation x+y =3 (x) (3) ? ? (y) ? (5) (3) (x,y) (3,0) ? (0,3)
Answer» ANSWER: very very POOR in MATHS so PLEASE SORRY

11.

activity to complete the following table to draw the graph of the equation x+y =3 (x) (3) ? ? (y) ? (5) (3) (x,y) (3,0) ? (0,3)

Answer»

ANSWER:

very very POOR in MATHS so PLEASE SORRY

Discussion

12.	The distance between two parallel chords of length 10 cm each in a circle of diameter 26 cm is
Answer» ANSWER Let AB=8 cm is the CHORD of the CIRCLE with RADIUS 5 cm Draw OP⊥AB and JOIN BO PB=21AB=21×8=4cm In △BPO∠P=90∘ ∴OB2=PB2+OP2 ⇒OP2=OB2−PB2 ⇒OP=52−42 ⇒OP=25−16⇒9=3cm. Let CD=6 cm is the chord of the circle with radius 5 cm Draw OQ⊥CD and join DO QD=21CD=21×6

12.

The distance between two parallel chords of length 10 cm each in a circle of diameter 26 cm is

Answer»

ANSWER

Let AB=8 cm is the CHORD of the CIRCLE with RADIUS 5 cm

Draw OP⊥AB and JOIN BO

PB=21AB=21×8=4cm

In △BPO∠P=90∘

∴OB2=PB2+OP2

⇒OP2=OB2−PB2

⇒OP=52−42

⇒OP=25−16⇒9=3cm.

Let CD=6 cm is the chord of the circle with radius 5 cm

Draw OQ⊥CD and join DO

QD=21CD=21×6

Discussion

13.	State true or false does half yearly means 1/2 of rate of interest
Answer» ANSWER: true Step-by-step explanation: PLEASE mark as brainlist answer and THANK my answer.

13.

State true or false does half yearly means 1/2 of rate of interest

Answer»

ANSWER:

true

Step-by-step explanation:

PLEASE mark as brainlist answer and THANK my answer.

Discussion

14.	Zindagi ab imarat si ho gayi h ,Kuch anjaan musafir ajaate h , Kuch waqt theharker nikal jaate h, Lekin apne ruke hue h , Deemak jesa chipke hue h ,Ander hi ander khaye ja rahe h ,apno ko hi dard diye ja rhe h,khokhla humko kiye ja rhe h.
Answer» ANSWER: ना जाने कैसे इम्तिहान ले रही है जिन्दगी आजकल,!!मुक्कदर,मोहब्बत और दोस्त. .तीनो नाराज है.

14.

Zindagi ab imarat si ho gayi h ,Kuch anjaan musafir ajaate h , Kuch waqt theharker nikal jaate h, Lekin apne ruke hue h , Deemak jesa chipke hue h ,Ander hi ander khaye ja rahe h ,apno ko hi dard diye ja rhe h,khokhla humko kiye ja rhe h.

Answer»

ANSWER:

ना जाने कैसे इम्तिहान ले रही है जिन्दगी आजकल,!!मुक्कदर,मोहब्बत और दोस्त. .तीनो नाराज है.

Discussion

15.	47 In a college there are 7930 student ik isHow many students were there in each ble
Answer» Step-by-step explanation: your SENTENCE is not perfect. PLZ ask CLEARLY

15.

47 In a college there are 7930 student ik isHow many students were there in each ble

Answer»

Step-by-step explanation:

your SENTENCE is not perfect. PLZ ask CLEARLY

Discussion

16.	LIS 886IO886 - 48LT=4.8 unitComplete & writeany one activity to
Answer» ANSWER: DOWNLOAD photosmaths APP and GET answer

16.

LIS 886IO886 - 48LT=4.8 unitComplete & writeany one activity to

Answer»

ANSWER:

DOWNLOAD photosmaths APP and GET answer

Discussion

17.	Nd maximum value of x1^2+x2^2 where x1 and x2 are roots of quadratic equation x^2-kx+(k^2+7k+15)maths kings iska ans with explaination send kijieagar ans Sahi to me aapko follow karunga nahito aap muje follow karana or ha ans 19 Nahi he
Answer» GIVEN :– • Quadratic equation x² - kx + (k² + 7k + 15) = 0. • Roots of quadratic equation $\implies \bf \:\: x_1 \: and \: x_2 \:\:$ TO FIND :– • Maximum value of $\bf \:\: x_1^{2} +x_2^{2} = ?\:\:$ SOLUTION :– • We should WRITE this as – $\\\implies\bf x_1^{2} +x_2^{2} =(x_1 + x_2)^{2} - 2(x_1)(x_2)\: \: \: \: \:\: - - - -<klux>EQ</klux>.(1)$ • We KNOW that – $\\\implies\bf Sum \: \: of \: \: roots = - \dfrac{Coefficient \: \: of \: \: x}{Coefficient \: \:of \: \: {x}^{2} }\:\:$ $\\\implies\bf x_1 + x_2= - \dfrac{( - k)}{1}\:\:$ $\\\implies\bf x_1 + x_2=k \: \: \: \: \:\: - - - -eq.(2)$ • And – $\\\implies\bf Product \: \: of \: \: roots = \dfrac{Constent \: \: term}{Coefficient \: \:of \: \: {x}^{2} }\:\:$ $\\\implies\bf (x_1)( x_2)= \dfrac{( {k}^{2} + 7k + 15)}{1}\:\:$ $\\\implies\bf (x_1)( x_2)={k}^{2} + 7k + 15 \: \: \: \: \:\: - - - -eq.(3)$ • Put the VALUES from eq.(3) & eq.(2) in eq.(1) $\\\implies\bf x_1^{2} +x_2^{2} =(k)^{2} - 2({k}^{2} + 7k + 15)$ • Let – $\\\implies\bf x_1^{2} +x_2^{2} =P$ • So that – $\\\implies\bf P =k^{2} - 2{k}^{2} - 14k - 30$ $\\\implies\bf P = - {k}^{2} - 14k - 30$ • Now Differentiate with respect to 'k' – $\\\implies\bf \dfrac{dP}{dk} = -2k- 14$ • For Maximum/Minimum – $\\\implies\bf \dfrac{dP}{dk} = 0$ $\\\implies\bf -2k- 14= 0$ $\\\implies\bf 2k + 14= 0$ $\\\implies\bf 2k = - 14$ $\\\implies \large{ \boxed{\bf k = -7}}$ • Now 'P' – $\\\implies\bf P_{max} = - {(- 7)}^{2} - 14( - 7) - 30$ $\\\implies\bf P_{max} = -49 + 98 - 30$ $\\\implies\bf P_{max} = 98 - 79$ $\\\implies \large{ \boxed{\bf P_{max} =19}}$ ▪︎ Hence , Maximum value of $\bf \:x_1^{2} +x_2^{2} \:$ is 19.

17.

Nd maximum value of x1^2+x2^2 where x1 and x2 are roots of quadratic equation x^2-kx+(k^2+7k+15)maths kings iska ans with explaination send kijieagar ans Sahi to me aapko follow karunga nahito aap muje follow karana or ha ans 19 Nahi he

Answer»

GIVEN :–

• Quadratic equation x² - kx + (k² + 7k + 15) = 0.

• Roots of quadratic equation $\implies \bf \:\: x_1 \: and \: x_2 \:\:$

TO FIND :–

• Maximum value of $\bf \:\: x_1^{2} +x_2^{2} = ?\:\:$

SOLUTION :–

• We should WRITE this as –

$\\\implies\bf x_1^{2} +x_2^{2} =(x_1 + x_2)^{2} - 2(x_1)(x_2)\: \: \: \: \:\: - - - -<klux>EQ</klux>.(1)$

• We KNOW that –

$\\\implies\bf Sum \: \: of \: \: roots = - \dfrac{Coefficient \: \: of \: \: x}{Coefficient \: \:of \: \: {x}^{2} }\:\:$

$\\\implies\bf x_1 + x_2= - \dfrac{( - k)}{1}\:\:$

$\\\implies\bf x_1 + x_2=k \: \: \: \: \:\: - - - -eq.(2)$

• And –

$\\\implies\bf Product \: \: of \: \: roots = \dfrac{Constent \: \: term}{Coefficient \: \:of \: \: {x}^{2} }\:\:$

$\\\implies\bf (x_1)( x_2)= \dfrac{( {k}^{2} + 7k + 15)}{1}\:\:$

$\\\implies\bf (x_1)( x_2)={k}^{2} + 7k + 15 \: \: \: \: \:\: - - - -eq.(3)$

• Put the VALUES from eq.(3) & eq.(2) in eq.(1)

$\\\implies\bf x_1^{2} +x_2^{2} =(k)^{2} - 2({k}^{2} + 7k + 15)$

• Let –

$\\\implies\bf x_1^{2} +x_2^{2} =P$

• So that –

$\\\implies\bf P =k^{2} - 2{k}^{2} - 14k - 30$

$\\\implies\bf P = - {k}^{2} - 14k - 30$

• Now Differentiate with respect to 'k' –

$\\\implies\bf \dfrac{dP}{dk} = -2k- 14$

• For Maximum/Minimum –

$\\\implies\bf \dfrac{dP}{dk} = 0$

$\\\implies\bf -2k- 14= 0$

$\\\implies\bf 2k + 14= 0$

$\\\implies\bf 2k = - 14$

$\\\implies \large{ \boxed{\bf k = -7}}$

• Now 'P' –

$\\\implies\bf P_{max} = - {(- 7)}^{2} - 14( - 7) - 30$

$\\\implies\bf P_{max} = -49 + 98 - 30$

$\\\implies\bf P_{max} = 98 - 79$

$\\\implies \large{ \boxed{\bf P_{max} =19}}$

▪︎ Hence , Maximum value of $\bf \:x_1^{2} +x_2^{2} \:$ is 19.

Discussion

18.	Find the difference between 9462 andthe numberby reversingdigit ofthe given number.
Answer» ANSWER: 9462-2649=6813 is the answer

18.

Find the difference between 9462 andthe numberby reversingdigit ofthe given number.

Answer»

ANSWER:

9462-2649=6813 is the answer

Discussion

19.	5)2 poinB = {2/5x - 2 = 0,1 E N}is....... set.(72SingletonO EmptyO BothNone
Answer» Answer: (i) A SET of odd natural numbers divisible by 2 is a null set because no odd number is divisible by 2. (ii) A={2}. A set of even prime numbers is not a null set because 2 is an even prime number. (iii) {x:x is a natural number,x<5 andx>7} is a null set because a number cannot be simultaneously less than 5 and greater than 7. (iv) {y:y is a POINT common to any two parallel lines} is a null set because parallel lines do not intersect. Hence, they have no common point.

19.

5)2 poinB = {2/5x - 2 = 0,1 E N}is....... set.(72SingletonO EmptyO BothNone

Answer»

Answer:

(i) A SET of odd natural numbers divisible by 2 is a null set because no odd number is divisible by 2.

(ii) A={2}.

A set of even prime numbers is not a null set because 2 is an even prime number.

(iii) {x:x is a natural number,x<5 andx>7} is a null set because a number cannot be simultaneously less than 5 and greater than 7.

(iv) {y:y is a POINT common to any two parallel lines} is a null set because parallel lines do not intersect. Hence, they have no common point.

Discussion

20.	in a village there are 675 people.each person needs 25l of water daily.how much water is needed for the village everday
Answer» Answer: 251 LITRES or KGS ? 169425 litres

20.

in a village there are 675 people.each person needs 25l of water daily.how much water is needed for the village everday

Answer»

Answer:

251 LITRES or KGS ?

169425 litres

Discussion

21.	Square root of 7056
Answer» Answer: So now we know the digital ROOT of 7,056 is 9. Is 9 in the LIST of digital ROOTS that are always a square root (1, 4, 7 or 9)? Answer: YES, 9 is in the list of digital roots that are always perfect squares.

21.

Square root of 7056

Answer»

Answer:

So now we know the digital ROOT of 7,056 is 9. Is 9 in the LIST of digital ROOTS that are always a square root (1, 4, 7 or 9)? Answer: YES, 9 is in the list of digital roots that are always perfect squares.

Discussion

22.	Class 4th mathOne bag of rice and one bag of atta was purchased for Rs. 200.The bag of rice was sold for Rs. 135 and 55 P. The bag of attawas sold for Rs. 75 and 80 P. What was the gain ?
Answer» ANSWER: on rice BAG was GAIN Rs 85 'profit and on attacking bag LOSS of Rs 5

22.

Class 4th mathOne bag of rice and one bag of atta was purchased for Rs. 200.The bag of rice was sold for Rs. 135 and 55 P. The bag of attawas sold for Rs. 75 and 80 P. What was the gain ?

Answer»

ANSWER:

on rice BAG was GAIN Rs 85 'profit and on attacking bag LOSS of Rs 5

Discussion

23.	किसी वृत की trijya 15 semi hai to vyas bataiye
Answer» ANSWER: PLEASE DONT GIVE irrelevant questions

23.

किसी वृत की trijya 15 semi hai to vyas bataiye

Answer»

ANSWER:

PLEASE DONT GIVE irrelevant questions

Discussion

24.	Find the value of (5/2 3/2)
Answer» Answer: 15/4 Step-by-step EXPLANATION: if any THING not there it is multiplecation if 5/2 × 3/2 =15/4

24.

Find the value of (5/2 3/2)

Answer»

Answer:

15/4

Step-by-step EXPLANATION:

if any THING not there it is multiplecation

if 5/2 × 3/2

=15/4

Discussion

25.	दशहरे के बारे में हमें बताइए
Answer» दशहरा भारत में मनाए जाने वाला हिंदुओं का त्यौहार है। दशहरा को विजयादशमी और आयुष पूजा के नाम से भी जाना जाता है। दशहरा को हर वर्ष दिवाली के पहले लगभग 20 दिन पहले मनाया जाता है, यह उत्सव सितंबर या फिर अक्टूबर के महीने में आता है। दशहरा के दिन भगवान राम ने रावण जो कि एक राक्षस था उसका वध किया था और इस कारण हर वर्ष दशहरा मनाया जाता है। मान्यता है कि दशहरा के इस दिन देवी दुर्गा ने भी महिषासुर नाम के राक्षस का वध किया था, इसलिए दशहरा को बुराई पर अच्छाई की विजय के रूप में मनाया जाता है। दशहरा के दिन कुछ लोग पूरे दिन का व्रत रखते हैं। दशहरा पूरे भारत में अलग-अलग तरह से मनाया जाता है, कई जगह इस दिन को रामलीला सुना कर मनाया जाता है तो कहीं रावण के पुतले को जलाकर बुराई पर अच्छाई की विजय को दर्शाया जाता है। दशहरा के दिन हम रावण के पुतले को जलाते हैं, लेकिन साथ ही हमें अपने अंदर के रावण को नष्ट करना चाहिए और अपने अंदर की बुराई पर जीत हासिल करनी चाहिए। रावण के 10 सिर थे जो हमारे अंदर मौजूद 10 बुराइयां दर्शाता है। पाप, काम, क्रोध, मोह, घमंड, स्वार्थ, जलन, अहंकार, अमानवता और अन्याय यह 10 बुराइयां है जो हमें हमारे भीतर से नष्ट करनी चाहिए। Hope it's HELP you

25.

दशहरे के बारे में हमें बताइए

Answer»

दशहरा भारत में मनाए जाने वाला हिंदुओं का त्यौहार है।

दशहरा को विजयादशमी और आयुष पूजा के नाम से भी जाना जाता है।

दशहरा को हर वर्ष दिवाली के पहले लगभग 20 दिन पहले मनाया जाता है, यह उत्सव सितंबर या फिर अक्टूबर के महीने में आता है।

दशहरा के दिन भगवान राम ने रावण जो कि एक राक्षस था उसका वध किया था और इस कारण हर वर्ष दशहरा मनाया जाता है।

मान्यता है कि दशहरा के इस दिन देवी दुर्गा ने भी महिषासुर नाम के राक्षस का वध किया था, इसलिए दशहरा को बुराई पर अच्छाई की विजय के रूप में मनाया जाता है।

दशहरा के दिन कुछ लोग पूरे दिन का व्रत रखते हैं।

दशहरा पूरे भारत में अलग-अलग तरह से मनाया जाता है, कई जगह इस दिन को रामलीला सुना कर मनाया जाता है तो कहीं रावण के पुतले को जलाकर बुराई पर अच्छाई की विजय को दर्शाया जाता है।

दशहरा के दिन हम रावण के पुतले को जलाते हैं, लेकिन साथ ही हमें अपने अंदर के रावण को नष्ट करना चाहिए और अपने अंदर की बुराई पर जीत हासिल करनी चाहिए।

रावण के 10 सिर थे जो हमारे अंदर मौजूद 10 बुराइयां दर्शाता है।

पाप, काम, क्रोध, मोह, घमंड, स्वार्थ, जलन, अहंकार, अमानवता और अन्याय यह 10 बुराइयां है जो हमें हमारे भीतर से नष्ट करनी चाहिए।

Hope it's HELP you

Discussion

26.	• Q.1.Write the given polynomial in different forms.p(x) = x⁴+ x³ -3x² + 5x +2
Answer» <P>Answer: p(1) = 6 Step-by-step explanation: p(X) = x⁴+ x³ - 3x² + 5x + 2 p(1) = (1)⁴+ (1)³ - 3(1)² + 5(1) +2 p(1) = 1 + 1 - 3 + 5 + 2 p(1) = - 3 + 9 p(1) = 6

26.

• Q.1.Write the given polynomial in different forms.p(x) = x⁴+ x³ -3x² + 5x +2

Answer»

<P>Answer:

p(1) = 6

Step-by-step explanation:

p(X) = x⁴+ x³ - 3x² + 5x + 2

p(1) = (1)⁴+ (1)³ - 3(1)² + 5(1) +2

p(1) = 1 + 1 - 3 + 5 + 2

p(1) = - 3 + 9

p(1) = 6

Discussion

27.	.Marks obtained by two students in the ten different papers at an examination are given below.Find who is more consistentMarks A: 50 60 35 40 70 90 65 70 75 75Marks B: 60 65 78 72 80 55 45 65 75 80
Answer» Answer: MARKS A Step-by-step EXPLANATION: first of all do averages of both Marks A and Marks B average of Marks A: =50+60+35+40+70+90+65+70+75+75 /10 =630/10 =63 Average of Marks B: =60+65+78+72+80+55+45+65+75+80 /10 =475 /10 =47.5 so...Marks A is more consistent

27.

.Marks obtained by two students in the ten different papers at an examination are given below.Find who is more consistentMarks A: 50 60 35 40 70 90 65 70 75 75Marks B: 60 65 78 72 80 55 45 65 75 80

Answer»

Answer:

MARKS A

Step-by-step EXPLANATION:

first of all do averages of both Marks A and Marks B

average of Marks A: =50+60+35+40+70+90+65+70+75+75 /10

=630/10

=63

Average of Marks B:

=60+65+78+72+80+55+45+65+75+80 /10

=475 /10

=47.5

so...Marks A is more consistent

Discussion

28.	5) The equation of the straight road 2 pointswhich is equidistant from two parallel straightroads represented by 6x + 4y – 5 = 0 and3x + 2y + 4 = 0 isoo
Answer» ANSWER: at the junction (crossing) of two straight paths represented by the equations 2x - 37 + 4 = 0 and 3x + 4y - 5 = 0 wants to REACH the path whose equations is 6x - 7y + 8 = 0 in the least time. 2x - 3 y = - 4 & 3x + 4y = 5 person standing at intersection of both. 6x - 9y = - 12 6x + 8y = 10 - - - -17y = -22 y = 2217 X = -117 He should travel ...

28.

5) The equation of the straight road 2 pointswhich is equidistant from two parallel straightroads represented by 6x + 4y – 5 = 0 and3x + 2y + 4 = 0 isoo

Answer»

ANSWER:

at the junction (crossing) of two straight paths represented by the equations 2x - 37 + 4 = 0 and 3x + 4y - 5 = 0 wants to REACH the path whose equations is 6x - 7y + 8 = 0 in the least time.

2x - 3 y = - 4 & 3x + 4y = 5 person standing at intersection of both. 6x - 9y = - 12 6x + 8y = 10 - - - -17y = -22 y = 2217 X = -117 He should travel ...

Discussion

29.	4. How much will $20,000 amount to in 2 yearsat CI if the rates for successive years are 8%and 10% p.a. respectively?
Answer» Given :- Principal = $20,000 Time = 2 years Rate for the first year = 8% Rate for the SECOND year = 10% To Find :- The compound INTEREST Solution :- For the first year :- Principal = $20,000 Time = 1 year Rate = 8% $Interest\: =\: {\dfrac{P \times R \times T}{100}}$ On inserting the values in the formula We get , $Interest\: =\: {\dfrac{20000 \times 8 \times 1}{100}}$ $\implies\: Interest\: =\: {\dfrac{\cancel{20000}^{200}\: \times 8 \times 1}{\cancel{100}^{1}}}$ $\implies\: Interest\: =\: \bold{1600}$ AMOUNT = Principal + Interest = $ 20,000 + $ 1,600 = $ 21,600 For the second year :- Principal = $ 21,600 Time = 1 year Rate = 10% $Interest\: =\: {\dfrac{P \times R \times T}{100}}$ On inserting the values in the formula On inserting the values in the formulaWe get , $\implies\: Interest\: =\: {\dfrac{21600 \times 10 \times 1}{100}}$ $\implies\: Interest\: =\: \bold{2160}$ Amount = Principal + Interest = $ 21,600 + $ 2,160 = $ 23,760 Compound Interest = Final Amount - Original Principal = $ 23,760 - 20,000 = $ 3,760 Therefore, compound interest is $ 3,760

29.

4. How much will $20,000 amount to in 2 yearsat CI if the rates for successive years are 8%and 10% p.a. respectively?

Answer»

Given :-

Principal = $20,000

Time = 2 years

Rate for the first year = 8%

Rate for the SECOND year = 10%

To Find :-

The compound INTEREST

Solution :-

For the first year :-

Principal = $20,000

Time = 1 year

Rate = 8%

$Interest\: =\: {\dfrac{P \times R \times T}{100}}$

On inserting the values in the formula

We get ,

$Interest\: =\: {\dfrac{20000 \times 8 \times 1}{100}}$

$\implies\: Interest\: =\: {\dfrac{\cancel{20000}^{200}\: \times 8 \times 1}{\cancel{100}^{1}}}$

$\implies\: Interest\: =\: \bold{1600}$

AMOUNT = Principal + Interest

= $ 20,000 + $ 1,600

= $ 21,600

For the second year :-

Principal = $ 21,600

Time = 1 year

Rate = 10%

$Interest\: =\: {\dfrac{P \times R \times T}{100}}$

On inserting the values in the formula

On inserting the values in the formulaWe get ,

$\implies\: Interest\: =\: {\dfrac{21600 \times 10 \times 1}{100}}$

$\implies\: Interest\: =\: \bold{2160}$

Amount = Principal + Interest

= $ 21,600 + $ 2,160

= $ 23,760

Compound Interest = Final Amount - Original Principal

= $ 23,760 - 20,000

= $ 3,760

Therefore, compound interest is $ 3,760

Discussion

30.	The value of sec square 35-tan square 35
Answer» Answer: 2 (tan 35°/COT 55°) + (cot 55°/tan 35°)- 3 (sec 40°/COSEC 50°) = 2 {tan (90°-55°)/cot 55°} + {cot (90°-35°) /tan 35°} - 3 {sec (90°-50°)/cosec 50°} = 2 (cot 55°/cot 55°) + (tan 35°/tan 35°) - 3 (cosec 50°/cosec 50°) = 2 + 1 - 3 = 3 - 3 = 0 [REQUIRED ANSWER]

30.

The value of sec square 35-tan square 35

Answer»

Answer:

2 (tan 35°/COT 55°) + (cot 55°/tan 35°)- 3 (sec 40°/COSEC 50°)

= 2 {tan (90°-55°)/cot 55°} + {cot (90°-35°) /tan 35°} - 3 {sec (90°-50°)/cosec 50°}

= 2 (cot 55°/cot 55°) + (tan 35°/tan 35°) - 3 (cosec 50°/cosec 50°)

= 2 + 1 - 3

= 3 - 3

= 0 [REQUIRED ANSWER]

Discussion

31.	Fing x and y with rhe use of circle theorem formulae.
Answer» Step-by-step EXPLANATION: I HOPE this helps you friend thanks for the question kindly MARK brainliest and PLS follow me smiles

31.

Fing x and y with rhe use of circle theorem formulae.

Answer»

Step-by-step EXPLANATION:

I HOPE this helps you friend

thanks for the question

kindly MARK brainliest and PLS follow me

smiles

Discussion

32.	एक वृत्त पर दो स्पर्श रेखाएँ हैं और उनके बीच का कोण 60° है, तो जिन दो त्रिज्याओं के अंत बिन्दु से यह स्पर्श रेखाएँ जाएंगी, उनके बीच का कोण ___ होना चाहिए।1️⃣ 60°2️⃣ 30°3️⃣ 180°4️⃣ 120°
Answer» ANSWER: 180 is CORRECT answer .......

32.

एक वृत्त पर दो स्पर्श रेखाएँ हैं और उनके बीच का कोण 60° है, तो जिन दो त्रिज्याओं के अंत बिन्दु से यह स्पर्श रेखाएँ जाएंगी, उनके बीच का कोण ___ होना चाहिए।1️⃣ 60°2️⃣ 30°3️⃣ 180°4️⃣ 120°

Answer»

ANSWER:

180 is CORRECT answer .......

Discussion

33.	Solve differential equation (x tan(y/x ) - y sec²(y/x) ) dx + sec²(y/x )dy=0
Answer» ANSWER: idk Step-by-step EXPLANATION:

33.

Solve differential equation (x tan(y/x ) - y sec²(y/x) ) dx + sec²(y/x )dy=0

Answer»

ANSWER:

idk

Step-by-step EXPLANATION:

Discussion

34.	Indez form, Cocfficient form of the polynomial,Q.2.State which among these are polynomials with justification:a)2 ²/³ + 9m -2
Answer» ANSWER: An UNEXPECTED ERROR has OCCURRED.

34.

Indez form, Cocfficient form of the polynomial,Q.2.State which among these are polynomials with justification:a)2 ²/³ + 9m -2

Answer»

ANSWER:

An UNEXPECTED ERROR has OCCURRED.

Discussion

35.	Cos^2 30 +cos30sin30+sin^2 30/cos^3 30-sin^3 30=?
Answer» ANSWER: what is my NAME THINK and TELL

35.

Cos^2 30 +cos30sin30+sin^2 30/cos^3 30-sin^3 30=?

Answer»

ANSWER:

what is my NAME THINK and TELL

Discussion

36.	Need a full answer. thank you
Answer» This QUESTION is From which BOOK?

Discussion

37.	Q. To which quadrant each of the following complex numbers belong:-1) 4+2i
Answer» ANSWER: 4+2i =2.(2+i) I THINK it HELPS you...

37.

Q. To which quadrant each of the following complex numbers belong:-1) 4+2i

Answer»

ANSWER:

4+2i

=2.(2+i)

I THINK it HELPS you...

Discussion

38.	if 2 solutions of pH9 and 6 are mixed in equal proportion what will be the approximate pH of the solution
Answer» Answer: I don't know and I have no IDEA but just GUESSING it could be 15

38.

if 2 solutions of pH9 and 6 are mixed in equal proportion what will be the approximate pH of the solution

Answer»

Answer:

I don't know and I have no IDEA but just GUESSING it could be 15

Discussion

39.	5x+6y=21 value of y=1
Answer» ANSWER: I hope Step-by-step explanation: 5x+6y=21 5x+6×1=21 5x+6=21 5x=21-6 5x=15 x=15/5 x=3 5×3+6×1=21 15+6=21

39.

5x+6y=21 value of y=1

Answer»

ANSWER:

I hope

Step-by-step explanation:

5x+6y=21

5x+6×1=21

5x+6=21

5x=21-6

5x=15

x=15/5

x=3

5×3+6×1=21

15+6=21

Discussion

40.	The value of tan70°.tan20°.tan90°
Answer» ANSWER :. 1 Explanation:. tan70' × TAN20' × tan90' = cot(90' - 70') × tan20' × 1 = cot20' × tan20' = cos20'/sin20' × sin20'/cos20' = 1 × 1 = 1

40.

The value of tan70°.tan20°.tan90°

Answer»

ANSWER :. 1

Explanation:. tan70' × TAN20' × tan90'

= cot(90' - 70') × tan20' × 1

= cot20' × tan20'

= cos20'/sin20' × sin20'/cos20'

= 1 × 1

= 1

Discussion

41.	Simplify and Express as a rational number
Answer» ANSWER: 144/27 Step-by-step EXPLANATION: (2⁴ × 15³ × 9 )/(5³ × 3⁴) = (16 × 3375)/(125 × 81) = 54000/10125 = 144/27

41.

Simplify and Express as a rational number

Answer»

ANSWER:

144/27

Step-by-step EXPLANATION:

(2⁴ × 15³ × 9 )/(5³ × 3⁴)

= (16 × 3375)/(125 × 81)

= 54000/10125

= 144/27

Discussion

42.	A square yard is divided into 10 equal flowerbeds of side 30 m each. Find the area of garden
Answer» Answer: 40flowers BED in the GARDEN AREA is 40M

42.

A square yard is divided into 10 equal flowerbeds of side 30 m each. Find the area of garden

Answer»

Answer:

40flowers BED in the GARDEN AREA is 40M

Discussion

43.	In the adjoining fig. Chord EF HL chord GH,Protle that chord EG Ž Chord FH.
Answer» Step-by-step EXPLANATION: PLEASE MARK ME AS A BRAINLIST

43.

In the adjoining fig. Chord EF HL chord GH,Protle that chord EG Ž Chord FH.

Answer»

Step-by-step EXPLANATION:

PLEASE MARK ME AS A BRAINLIST

Discussion

44.	Evaluate using suitable properties: 764x(-35)+(-764)x65
Answer» ANSWER: -76400 is the answer DEAR USER (DIRECT answer)

44.

Evaluate using suitable properties: 764x(-35)+(-764)x65

Answer»

ANSWER:

-76400 is the answer DEAR USER (DIRECT answer)

Discussion

45.	If p(x) = x3 + bx2 + cx + 5 has one zero√5+2 and b and c are rational numbersthen find the sum of other two zeroes.√5+7√5-75+ √77-√5
Answer» ANSWER: Coefficientsarerational,hencealltheirrationalitiesmustbecancelled Hencetherootsare 2 + 3 , 2 − 3 ,− 2 + 3 ,− 2 − 3

45.

If p(x) = x3 + bx2 + cx + 5 has one zero√5+2 and b and c are rational numbersthen find the sum of other two zeroes.√5+7√5-75+ √77-√5

Answer»

ANSWER:

Coefficientsarerational,hencealltheirrationalitiesmustbecancelled

Hencetherootsare

2

+

3

,

2

−

3

,−

2

+

3

,−

2

−

3

Discussion

46.	Set up the equation and solve :Find the number , such that one-fourth of a number is 3 more than 7
Answer» ANSWER: the NUMBER is 40 Step-by-step EXPLANATION: Let the number be x Now, one- fourth of x = x/4 x/4 = 7+3 x/4 = 10 now, 4 will go to the other side x = 4*10 x = 40

46.

Set up the equation and solve :Find the number , such that one-fourth of a number is 3 more than 7

Answer»

ANSWER:

the NUMBER is 40

Step-by-step EXPLANATION:

Let the number be x

Now, one- fourth of x = x/4

x/4 = 7+3

x/4 = 10

now, 4 will go to the other side

x = 4*10

x = 40

Discussion

47.	If cosA=3/5 then find the value of sin square A-cos square A
Answer» cosA=3/5= b/h so, p=√(5)2 √(3)2 =√25-√9 =√6= 4 Now, ACCORDING to QUESTION... sinA-cosA/2tanA *=4/5-3/5 /2 4/3 = 4-3/5 /8/3=1/5* 3/8 =3/40**

47.

If cosA=3/5 then find the value of sin square A-cos square A

Answer»

cosA=3/5= b/h

so,

p=√(5)2 √(3)2

=√25-√9

=√6= 4

Now, ACCORDING to QUESTION...

sinA-cosA/2tanA

=4/5-3/5 /2* 4/3

= 4-3/5 /8/3=1/5* 3/8

=3/40

Discussion

48.	Customer paid 16800 rupees to purchase a colour TV which includes VATat the rate of 12% determine the Marked price of the TV
Answer» Answer: 15000 Step-by-step EXPLANATION: DIVIDE 16800 by 1.12

48.

Customer paid 16800 rupees to purchase a colour TV which includes VATat the rate of 12% determine the Marked price of the TV

Answer»

Answer:

15000

Step-by-step EXPLANATION:

DIVIDE 16800 by 1.12

Discussion

49.	7.The perimeter of a triangular field is 840cm and its sides are in the ratio 6:7:8.Find the area of the fiel
Answer» Step-by-step explanation: Given, perimeter of a triangular FIELD is 420 m and its sides are in the ratio 6:7:8. LET sides of a triangular field be a = 6X, b = 7x and c = 8x. ⇒ X = 420/21 = 20 m

49.

7.The perimeter of a triangular field is 840cm and its sides are in the ratio 6:7:8.Find the area of the fiel

Answer»

Step-by-step explanation:

Given, perimeter of a triangular FIELD is 420 m and its sides are in the ratio 6:7:8. LET sides of a triangular field be a = 6X, b = 7x and c = 8x. ⇒ X = 420/21 = 20 m

Discussion

50.	Sin18°cos18° का मान किसके बराबर है (a) 4(b) 2(c) 1(d) 1/4
Answer» Step-by-step explanation: 2 I HOPE it is HELP for you

50.

Sin18°cos18° का मान किसके बराबर है (a) 4(b) 2(c) 1(d) 1/4

Answer»

Step-by-step explanation:

2

I HOPE it is HELP for you

Discussion

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