1.

If cosA=3/5 then find the value of sin square A-cos square A​

Answer»

cosA=3/5= b/h

so,

p=√(5)2 √(3)2

=√25-√9

=√6= 4

Now, ACCORDING to QUESTION...

sinA-cosA/2tanA

=4/5-3/5 /2* 4/3

= 4-3/5 /8/3=1/5* 3/8

=3/40



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