Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Please answer the formula and answer for the above question please..

Answer»

[0010001111]... Hello User... [1001010101]
Here's your answer...

Assuming the rate to be 1% per day instead of per annum...

AMOUNT =
p(1 +  \frac{r}{100} )^{<klux>N</klux>}
p = ₹100
r = 1%
n = 22

Amount =
100 \times (1 +  \frac{1}{100} ) ^{22}  \\  = 100 \times  {( \frac{101}{100}) }^{22}  \\  =  \frac{ {101}^{22} }{ {100}^{21} }  \\
≈ ₹124.47

[0110100101]... More questions DETECTED... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your FRIENDLY neighbourhood UnknownDude

2.

By long division method solve it with full process

Answer»

Answer: x³ + x² + X + 1

*See ATTACHED for solution.

3.

There are n AM between 3 and 17 the ratio of last mean to the first mean is 3:1

Answer» HEY FRIEND what is your QUESTION WRITE COMPLETE
4.

If two sides of a triangle are equal then the two sides of the triangle ane not equal

Answer»

?????????????plzz write CLEARLY what u wanna ask

5.

If the perimeter of sector of circle is four times the radius of circle find the central.Angle

Answer» LET the radius of circle be x
then perimeter =4x (given)
but we know that
ANGLE formed by any ARC at centre=L /r
where L is length of arc and r is radius
so here
CENTRAL angle =4x/x
= 4 radian
6.

If the radius of a circle is increased by one percent the percentage increase in surface area is

Answer»

Have a NICE DAY.....

7.

If we fail in 2 nd puc supplementary should we write cet again

Answer» YES you should WRITE
8.

If two solution of matrix differential equation is given how to find other solution

Answer» PINJORE and I am not in
9.

If it is impossible to divide the existing categeries of a variable then it is an example of a continous variable

Answer»

what EXACTLY you WANT to know

at first you have some NUMBERS to solve

will you PLEASE provide

10.

Stateand prove the addition and multiplication theorem of probability with examples

Answer» ROOTS are the BEST SOURCE
11.

16(3x+2)^2-25(2x-1)^2

Answer» FACTORS of 1716 not GET.
12.

twice the cost of table is equal to five times the cost of chair .write the linear equation in two variables.

Answer» LET the COST of table X and cost of CHAIR y

so the EQUATION is 2x=5y
13.

consider the fractions 2/5 , 4/15 , 3/5 , 7/10, 13/ 10. Now fill in the blanks :- The greatest fraction and the smallest fraction

Answer» GREATEST FRACTION = 13/10
smallest fraction = 4/15
by making all the denominator same
multiply and divide fraction by REQUIRED no. to MAKE the denominator same
hope it will help you
14.

a student scored 55% marks in the first exam and 70% in II exam how much percent should he score in III exam so as to get 70% as an overall score

Answer»

He have to give 3exams so that total %=300.
he scored 125% of 200% in TWO EXAMS in total.
overall he had to SCORE=70%.
so 70% of 300%=210%
and he had scored 125% earlier.
so, he had to score 210%-125%=85% ANS.

15.

What is the length of a cube of volume 3375 cubic m

Answer»

                                          = ∛3375  = 15 m



Thank U.

16.

An item marked at rupees 1540 is sold for Rs 1400 what is the discount and discount percent

Answer»

9.09 is ANSWER of this QUESTION

17.

X:35=14:245 find the value of x

Answer»

X/35= 14/245

X= (14×35)/245

=490/245

= 2......ANS

18.

Solve for f(x). Please solve the questions 21 and 22.

Answer»

Integration or differentiation pls LET me KNOW and I will CHANGE my ans acc. to it

19.

three cubes of metal whose edges are in ratio 3:4:5 are melted down into a single cube whose diagonal is 12√3 cm find the edges of three cubes?????

Answer»

GIVEN ;-

⇒ Edges of the three melted cubes in ratio are =  3 : 4 : 5

⇒ Diagonal of the new SINGLE cube after melting = 15√3 


TO FIND ;-

⇒ Find the edges of the three cubes 


SOL ;-

⇒ We dont KNOW the value of the edges of three cubes , so let us take the value as x, therefore -

⇒ Edges of three cubes are = 3 x , 4 x , 5 x

So now let us first find the volume of cube using its formula -

⇒ Volume of cube = a ³

                           ⇒ ( 3 x )³ , ( 4 x )³ , ( 5 x )³

                            ⇒27 x³ , 64 x³ , 125 x³ 


Now we got the volume of each cube but we need the total volume , so wee need to add all the volume to get the result,,

     Volume of three cubes   ⇒ ( 27 x³ +  64 x³ + 125 x³ )


                                         ⇒ 216 x³ cu . units is the total volume


But we dont know the  the edge of the cube  , so let us take this as ''y''


                              ⇒Diagonal of the cube =  s√3 


                                                               ⇒ 15√3 = 15

Therefore the edge of the cube is 15 units. 

⇒ Now we got the value of side of the new cube , so let us find the value of the new cube formed -

                          ⇒ Volume of new cube = a³

                                                             ⇒ (15)3  


                                                             ⇒  3375 cu. units 
 So now we can find the value of x,-


                     ⇒ 216 x³ = 3375
                     

                     ⇒ x³      = (3375 / 216)
                     

                    ⇒    x     = 15/6 = 5/2 = 2.5

so x is equal to 2.5 unit

--------------------------------------------------------------------------------

Edges of the cube are -

⇒ 3 x = 3 × 2 .5 =  7.5 units

⇒ 4 x = 4 × 2.5  =  1 unit

⇒ 5 x = 5 × 2.5  =  1. 25 units

---------------------------------------------------------------------------------




hope this HELPS you......







please mark me as brainliest and please FOLLOW me now........

20.

bronze made with 88% copper and 12% tin is used to make a statue which weighs 4.5 kg. how much quantity of each metal is there in the statue?

Answer» WEIGHT of COPPER= (4500×88)/100

= 3940g=3.94kg

Weight of TIN= 4.5-3.94= 0.56kg
21.

If the sides of right angle triangle aew 9, 12and 15 cm long then the sym of squares of medians is

Answer»

ANSWER:


Step-by-step EXPLANATION:

We have SUM of SQUARES of SIDES of a∆is 4×sum of squares of medians

81+144+225=4×X

X=112.5

22.

If rupees 250 is to be divided among ravi,raju and roy ,so that ravi gets two parts,rajuthreeparts and roy five parts how much money will each get?What will it be in percentage?

Answer»

Given :

Ravi gets = 2 parts

Raju gets = 3 parts

Roy gets = 5 parts

So, Total parts = 10 parts

Finding Fraction-

Ravi gets = 2/10 = 1/5

Raju gets = 3/10

Roy gets = 5/10 = 1/2

Finding shares -

Ravi's Share =


250 \times \dfrac{1}{5} = \dfrac{250}{5} = <klux>50</klux>


Hence : Ravi's Share = RS 50.

_____________________________

Raju's Share =


250 \times \dfrac{3}{10} = \dfrac{750}{10} = 75


Hence : Raju's Share = Rs 75

______________________________

Roy's Share =


250 \times \dfrac{1}{2} = \dfrac{250}{2} = 125


Hence : Roy's Share = Rs 125 .

______________________________

Finding Percentages -

Ravi's Percentage =


\dfrac{50}{250} \times 100 = 20\%


Raju's Percentage =


\dfrac{75}{250} \times 100 = <klux>30</klux>\%


Roy's Percentage =


\dfrac{125}{250} \times 100 = 50\%


Answer :

Ravi gets = Rs 50 and his Percentage = 20 %


Raju gets = Rs 75 and his Percentage = 30 %


Roy gets = Rs 125 and his Percentage = 50 %

23.

If the radius of a cylinder is double and height is half than so

Answer»

Same ...It will NEVER CHANGE

24.

If three angles of a triangle are (2x+20degrees), (x+30degrees) and (2x-10degrees), then the angles will be

Answer»

HÈLLÒ»»».

ÃBÕVË ÎS Û R ANSWER...

THANKS for asking these QUESTION....★★★

««« it may HELP you»»»

25.

Curved surface area of cone is 550m²if it's diameter is 14m find its volume

Answer»

I THOUGHT this ANSWER can HELP you

26.

find three consecutive odd integers such that the sum of the first is two less than the second, and three more than the third is 70

Answer»

Let's SAY that the first odd integer is x. The second consecutive odd integer would have to be x+2. (It would not be x+1 because that would result in an even integer. The sum of any two odd numbers is even.) The third consecutive odd integer would be (x+2)+2, or x+4.

The sum of the first, twice the second, and three times the third can be written as

x+2(x+2)+3(x+4)

This equals 70. We can now distribute and solve for x.

x+2(x+2)+3(x+4)=70

x+2x+4+3x+12=70 →distribute

6x+16=70 → gather like terms

6x=54 → subtract 16 from both sides

x=9 → divide both sides by 6

Thus, the three consecutive odd INTEGERS are 9,11, and 13.

27.

Answer plzz this question

Answer» HEY MATE HERE IS YOUR ANSWER.....
28.

If a+b=10 a^2+ b^2=58 find a^3+b^3Plz with steps

Answer»

A³ + b³ = (a + b) (a² - ab + b²)
= 10 (58 - ab)
But (a + b)² = a² + 2AB + b² = 58+2ab
also (a+b)2=10² = 100 SINCE a+b=10
58+2ab=100
=> 2ab =100-58=42
=> ab = 21
=>a³ + b³ = (a + b) (a² - ab + b²)
= 10 (58 - ab)
=10*(58 - 21) = 370

29.

107 upon 250 in decimal

Answer» HEY FRND....
107 \div 250 \\ = .428
HOPE THIS HELP YOU ☺☺❤❤❤❤
30.

Write the numbers counting by three between 6 x 6 and 6 x 8

Answer» 39, 42, 45 are the ANSWERS
31.

Plz solve question 2b

Answer» HOPE U will be UNDERSTAND
32.

in a square of length 14 cm 4 quadrants are made inside the circle then find the area of the middle of all the segments

Answer»


The green SHADED AREA = Area of sector =60360πx2=60360πx2

=16πx2=16πx2

The blue shaded area = Area of segment = Area of sector - Area of EQUILATERAL triangle

=16πx2−3–√4x2=16πx2−34x2

A+E+D+H=blue+green=13πx2−3–√4x2A+E+D+H=blue+green=13πx2−34x2

A+E+D+H=13πx2−3–√4x2A+E+D+H=13πx2−34x2

A+E+D+H+C+G=A+E+D+H+C+G=Area of quarter CIRCLE  =14πx2=14πx2

A+E+D+H+C+G=14πx2A+E+D+H+C+G=14πx2

Subtraction the 2 equations,

C+G=3–√4x2−112πx2C+G=34x2−112πx2

Notice that, C+G=B+F=I+E=H+D=3–√4x2−112πx2C+G=B+F=I+E=H+D=34x2−112πx2

C+G+B+F+I+E+H+D=3–√x2−13πx2C+G+B+F+I+E+H+D=3x2−13πx2

Subtract this from area of square,

A=x2−(3–√x2−13πx2)A=x2−(3x2−13πx2)

A=x2−3–√x2+π3x2A=x2−3x2+π3x2

A=(1−3–√+π3)x2A=(1−3+π3)x2

A≈0.315147⋅x2A≈0.315147⋅x2

In your case, x=14x=14

A≈61.76876 cm2A≈61.76876 CM2




33.

Radius of a circle is 5 cm. the leghth of chord is 8cm find the distance of chord from the centre

Answer» LET O be the centre of the circle and AB be the chord.
Join OA.
Draw OC PERPENDICULAR to AB.

AC=1/2AB (Perpendicular from the centre bisects the chord)
     = 4 cm
OA=5 cm (Radius)

Triangle OCA is RIGHT angled,
... OC​2 =OA​2 - AC2 (Pythagoras Theorem)
            =52 - 42
             =25 - 16
             =9
 ...   OC= 3cm
 

34.

If f(x)=ax+b and f(f(f(x)))=8x+21 what is the value of a+b

Answer»

------------------------------HEY DEAR---------------------------------

HERE IS YOUR ANSWER........

f(x) = ax +b

f(f(f(x))) = 8x +21

TAKE L.H.S

=>f(f(ax+ b)

means put ax + b in place of x

=>f(a(ax +b) +b)

put a(ax+b) +b in place of x

=> a^2 (ax+b) + BA  +b

=> (a^3)x + b(a^2) + ba +b

ACCORDING TO QUESTION L.H.S = R.H.S

8x +21 = (a^3)x + b(a^2) +ab +b

compare both equations................

(a^3) = 8

so, a = 2

also,   21 = b(4)+ 2B +b

          21 = 7b

           b = 21/7

            b= 3

so, a+b => 2+3    =>     5.....................................Ans.

SO, 5 IS THE ANSWER...

HOPE IT HELPS YOU..

MARK ME BRAINLIEST PLZ IF IT HELPS YOU..

THANKS..

**************************************************************************

35.

If alpha and beta are the zeros of the polynomial x2-6x+ka

Answer» SEE this IMAGE this will HELP you
36.

If a factory a turns out x cars an hour and factory b turns out y cars every 2 hours,the no. Of cars that both factories turn out in 8hours is

Answer»

∵ Factory A TURNS out x cars in one hour. Factory B turns out y/2 cars in one hour.
⇒ In one hour both the FACTORIES A and B can turn out (x + y/2) cars
∴ In 8 hours both factories turn out = 8( x + y/2) cars 
= 4(2X + y) cars.

37.

If the distance travelled by the body is given by 2s=10t+2 square.Then the acceleration of the body is

Answer»

If the DISTANCE TRAVELLED by the BODY is GIVEN by 2s=10t+2 square.Then the ACCELERATION of the body is

38.

Give some examples of linear equation in two variable in our daily life situations

Answer»

While BATHING,EATING,DANCING

39.

35 : 9=x:81 find the value of x

Answer»

35/9= x/81

X= (35×81)/9

X= 35×9= 315....ANS

40.

3/6_-------3/9(use>,

Answer»

Hola !

ANSWER-

To COMPARE between two numbers, it's necessary to make the denominators same.

Thus,

LCM of 6 and 9 is 18

= 3/6 × 3/3 = 9/18

and,

= 3/9 × 2/2

= 6/18

thus,

9/18 that is - 3/6 is GREATER

Answer -. 3/6. > 3/9


Hope it helps

41.

Factorise c square -(x-y) whole square Plz tell

Answer» \huge{hey\:mate}

Here is your answer > >

C^2-(x-y)^2

We know that

a^2-b^2=(a-b)(a+b)

[c-(x-y)][c+(x+y)]

(c-x+y)(c+x+y)

Hope it HELPS!

Thankyou ☆ ☆
42.

Explai the term of formula for area of triangle.

Answer»

⏩It is HERON's FORMULA.......

where ' s ' DENOTES
semiperimeter
& a,b,c denotes sides of triangle...

S=a+b+c/2

hope it HELPS you....✌️✨✨✨

43.

Tell me question no. (viii)

Answer» ED hmm ZS TINKERBELL ARKHANGELSK sick my STOCK
44.

Show by comparing angle and side , which of the triangle given here are congruent to each other.

Answer»

opposite sides of  a TRIANGLES are ALWAYS same and the SUM of all angles be 180

45.

What is natural numbers ??

Answer»

the POSITIVE INTEGERS (whole NUMBERS) 1, 2, 3, etc., and sometimes zero as WELL.

46.

Plz help me with this questio.. plz plz plz plz plzplzplz...

Answer»

Have a LOOK at the PICTURE

HOPE this HELPS

47.

When a number divided by 10 we get quotient 4 leaving no reminder

Answer»

The NUMBER is 40

HOPE YOU LIKE IT
GOOD LUCK

48.

Plzz answer me fast plzzzz

Answer» HOPE THIS HELPS YOU.....
PLEASE MARK IT as BRAINLIEST.......
49.

If two equations x²-Kx-21=0 and x²-3Kx+35=0 have a common root and J>0 then value of K is

Answer»

First of all I didn't understand the thing J>0 .
It should either be D>0 or K>0.
Anyways I GO on further.

Let the Common root of both the equations is 'R'
Therefore R will satisfy both the equations
R^2-KR-21=0 --(1)
R^2-3KR +35 =0. --(2)

Equating (1) and (2)
-KR-21 = -3KR +35
2KR=56.
KR=28
R=28/K

Satisfying this value of R in (1)
(28/K)^2 -K(28/K) -21=0
784/K^2 -28 -21=0
784/K^2 =49
K^2 = 784/49

K=±22/7.
You can also say that K=±π

Hope you got your answer :)

50.

Ratio of first to the second (i) The breadth of a rectangle is one- fourth of its length . (ii) The weight of father is four times that of his son.

Answer» BREADTH: LENGTH =1 :4.
weight of father: weight of SON =4 :1.
Hope it helps you....
Please mark as the BRAINLIEST....
Be brainly.....