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If a+b=10 a^2+ b^2=58 find a^3+b^3Plz with steps

Answer»

A³ + b³ = (a + b) (a² - ab + b²)
= 10 (58 - ab)
But (a + b)² = a² + 2AB + b² = 58+2ab
also (a+b)2=10² = 100 SINCE a+b=10
58+2ab=100
=> 2ab =100-58=42
=> ab = 21
=>a³ + b³ = (a + b) (a² - ab + b²)
= 10 (58 - ab)
=10*(58 - 21) = 370


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