332354 + Interview Questions in Secondary School in Math

1.	Hello everyone I just want to know how should I study to crack iit jee I am in class 11 CBSE..
Answer» ong>ANSWER: U should be serious TOWARDS UR studies .... please give me thanks atleast in my 5-10 questions

1.

Hello everyone I just want to know how should I study to crack iit jee I am in class 11 CBSE..

Answer»

ong>ANSWER:

U should be serious TOWARDS UR studies ....

please give me thanks atleast in my 5-10 questions

Discussion

2.	Find the common factors of the following terms: 24xy,8yz
Answer» ONG>Answer: 8y is your answer Step-by-step EXPLANATION: PLEASE FOLLOW me, I'll follow BACK

2.

Find the common factors of the following terms: 24xy,8yz

Answer» ONG>Answer:

8y is your answer

Step-by-step EXPLANATION:

PLEASE FOLLOW me, I'll follow BACK

Discussion

3.	Please solve These Questions from Q13 to Q15 along with their parts.Chapter name-Exponents . Pretty please..Just help me out.I am asking this for the 8 time..Nobody helped me out.
Answer» ONG>ANSWER: which is GREATER the answer is 3/6

3.

Please solve These Questions from Q13 to Q15 along with their parts.Chapter name-Exponents . Pretty please..Just help me out.I am asking this for the 8 time..Nobody helped me out.

Answer» ONG>ANSWER:

which is GREATER

the answer is 3/6

Discussion

4.	H.C.F. of 120, 180 and 240 is
Answer» ong>Answer: 60 Answer. H.C.F of 120,180 and 240. the remainder is 0 so hcf of 120 and 180 is 60.

4.

H.C.F. of 120, 180 and 240 is

Answer»

ong>Answer:

60

Answer. H.C.F of 120,180 and 240. the remainder is 0 so hcf of 120 and 180 is 60.

Discussion

5.	Mr.Joshi burrowed a sum of rs15000 from Mr.bhatta at the rate of 15% per year Calculate the amount received by Mr. Bhatta in 10 months. with full steps
Answer» ong>ANSWER: The amount to be PAID after 10 months is 14375 Step-by-step explanation: First we need to find interest which is amountrate of interesttime to be paid/100 which is 15000+15*1/100. So we get interest as 2250. Then find the total amount to be paid which is amount + interest which is 15000+2250, where we get 17250. Then we need to find the amount to be paid after 10 months. There are 2 methods to do this First METHOD is divide the whole amount which is 17250 by 12 where we get the solution as 1437.5. Then multiply it with 10. We get the answer as 14375. Second method is to directly divide the amount which is 15000 by 12 and multiply together and get the solution. And finally pls mark as brainliest.

5.

Mr.Joshi burrowed a sum of rs15000 from Mr.bhatta at the rate of 15% per year Calculate the amount received by Mr. Bhatta in 10 months. with full steps

Answer»

ong>ANSWER:

The amount to be PAID after 10 months is 14375

Step-by-step explanation:

First we need to find interest which is amount*rate of interest*time to be paid/100 which is 15000+15*1/100.

So we get interest as 2250.

Then find the total amount to be paid which is amount + interest which is 15000+2250, where we get 17250.

Then we need to find the amount to be paid after 10 months.

There are 2 methods to do this

First METHOD is divide the whole amount which is 17250 by 12 where we get the solution as 1437.5. Then multiply it with 10. We get the answer as 14375.

Second method is to directly divide the amount which is 15000 by 12 and multiply together and get the solution.

And finally pls mark as brainliest.

Discussion

6.	Pls slove this as fast as fast u can
Answer» ong>Step-by-step EXPLANATION: $\frac{sinA + cosA}{sinA - cosA}$ × $\frac{sinA - cosA}{sinA + cosA}$ = $\frac{(sinA + cosA)^{2} + (sinA - cosA)^{2} }{(sinA + cosA)(sinA -cosA)}$ = $\frac{sin^{2}A +2sinAcosA +cos^{2}A + sin^{2}A -2sinAcosA +cos^{2}A}{sin^{2} A- cos^{2}A }$ = $\frac{2(sin^{2}A + cos^{2}A)}{sin^{2}A - cos^{2}A }$ = $\frac{2(1)}{sin^{2}A - cos^{2}A }$ = $\frac{2}{sin^{2}A - cos^{2}A }$ (FIRST ANSWER) = $\frac{2}{sin^{2}A + 1 - cos^{2}A -1 }$ = $\frac{2}{sin^{2}A + sin^{2}A -1 }$ = $\frac{2}{2sin^{2}A -1 }$ (second answer) from the first answer, $\frac{2}{sin^{2}A - cos^{2}A }$ = $\frac{2}{1 - cos^{2}A - cos^{2}A }$ = $\frac{2}{1 - 2cos^{2}A }$ (third answer)

6.

Pls slove this as fast as fast u can

Answer»

ong>Step-by-step EXPLANATION:

$\frac{sinA + cosA}{sinA - cosA}$ × $\frac{sinA - cosA}{sinA + cosA}$

= $\frac{(sinA + cosA)^{2} + (sinA - cosA)^{2} }{(sinA + cosA)(sinA -cosA)}$

= $\frac{sin^{2}A +2sinAcosA +cos^{2}A + sin^{2}A -2sinAcosA +cos^{2}A}{sin^{2} A- cos^{2}A }$

= $\frac{2(sin^{2}A + cos^{2}A)}{sin^{2}A - cos^{2}A }$

= $\frac{2(1)}{sin^{2}A - cos^{2}A }$

= $\frac{2}{sin^{2}A - cos^{2}A }$ (FIRST ANSWER)

= $\frac{2}{sin^{2}A + 1 - cos^{2}A -1 }$

= $\frac{2}{sin^{2}A + sin^{2}A -1 }$

= $\frac{2}{2sin^{2}A -1 }$ (second answer)

from the first answer,

$\frac{2}{sin^{2}A - cos^{2}A }$

= $\frac{2}{1 - cos^{2}A - cos^{2}A }$

= $\frac{2}{1 - 2cos^{2}A }$ (third answer)

Discussion

7.	The number of positive integral solutions of the equation X1X2X3 is:
Answer» ONG>ANSWER: VMC MEIN TUNE TOH TOP KIYA HOGA NAH BEHNCHODHHH Step-by-step explanation:

7.

The number of positive integral solutions of the equation X1X2X3 is:

Answer» ONG>ANSWER:

VMC MEIN TUNE TOH TOP KIYA HOGA NAH BEHNCHODHHH

Step-by-step explanation:

Discussion

8.	1 ten +10 ones equal to
Answer» ONG>Answer: 11 is the answer Step-by-step EXPLANATION: pls MARK me as BRAINLIEST answer

8.

1 ten +10 ones equal to

Answer» ONG>Answer:

11 is the answer

Step-by-step EXPLANATION:

pls MARK me as BRAINLIEST answer

Discussion

9.	Integration (sin^2 x)/1-tan x
Answer» ong>Answer: h1sdhwf fode if do is DJ if di YE AAJ

9.

Integration (sin^2 x)/1-tan x

Answer»

ong>Answer:

h1sdhwf fode if do is DJ if di YE AAJ

Discussion

10.	The radius of a circle was increased by 1% the percentage increased in the area is 1)12)23)2.014)1.01
Answer» ong>WHOLE CIRCLE IS INCREASED BY 1/100 SO IT WILL BE 0.01 AS ANSWER IS 4) 1.01 MARK ME AS BRAINLIST PLEASE

10.

The radius of a circle was increased by 1% the percentage increased in the area is 1)12)23)2.014)1.01

Answer»

ong>WHOLE CIRCLE IS INCREASED BY 1/100 SO IT WILL BE 0.01

AS ANSWER IS

4) 1.01

MARK ME AS BRAINLIST PLEASE

Discussion

11.	4x-5/3=9 please solve this fast but after all the answer should come 8/3
Answer» Hope this helps u BRAINLIST ANSWER PLS

Discussion

12.	Solution set of 32* - 3* + 2-13-1\|-\|3 – 2 = 0 contains
Answer» ONG>Answer: 838 FOLLOW me LIKE me THANK me

12.

Solution set of 32* - 3* + 2-13-1|-|3 – 2 = 0 contains

Answer» ONG>Answer:

838

FOLLOW me

LIKE me

THANK me

Discussion

13.	Al The histogram gives marks is English of 40 marks studentsclassa)what is the class sizeb) how many students got 80%or more than 80% marksC) what is the range of marksin which the maximum number of students got markd) what is the range of marks in which the maximum numberof students gat mark?و(d) What is the range of marks in which the maximum number of students gotmarks
Answer» ONG>ANSWER: Step-by-step EXPLANATION:

13.

Al The histogram gives marks is English of 40 marks studentsclassa)what is the class sizeb) how many students got 80%or more than 80% marksC) what is the range of marksin which the maximum number of students got markd) what is the range of marks in which the maximum numberof students gat mark?و(d) What is the range of marks in which the maximum number of students gotmarks

Answer» ONG>ANSWER:

Step-by-step EXPLANATION:

Discussion

14.	5. In given figure, prove that APRQ = APSQ.
Answer» ONG>Answer: to prove angle prq = angle PSQ in prq and psq pr=ps rq=sq qp=qp(common) so both are congurent therefore all ANGLES are equal ie angle prq = angle psq

14.

5. In given figure, prove that APRQ = APSQ.

Answer» ONG>Answer:

to prove angle prq = angle PSQ

in prq and psq

pr=ps

rq=sq

qp=qp(common)

so both are congurent

therefore all ANGLES are equal

ie angle prq = angle psq

Discussion

15.	Shyam can walk 4 1/5km in one hour how much distance he cover in 2 1/2
Answer» ONG>Answer: Nilavan can walk 4 1/2 km in a hour. How much distance will he cover in 3 1/2 hours We know SPEED = distance/time Distance = speed × time Nilavan speed = 4 1/2 km PER hour = 9/2 km per hour Time = 3 1/2 hours = 7/2 hours Distance = to FIND out Distance = 9/2 km per hour × 7/2 hour Distance = 63/4 km or 15 3/4 km. Distance = 15.75 km Answer: Nilavan will cover the distance of 15 3/4 km or 15.75 km in 3 1/2 hours Step-by-step explanation: pls mark me as BRAINLIEST pls pls pls

15.

Shyam can walk 4 1/5km in one hour how much distance he cover in 2 1/2

Answer» ONG>Answer:

Nilavan can walk 4 1/2 km in a hour. How much distance will he cover in 3 1/2 hours

We know SPEED = distance/time

Distance = speed × time

Nilavan speed = 4 1/2 km PER hour = 9/2 km per hour

Time = 3 1/2 hours = 7/2 hours

Distance = to FIND out

Distance = 9/2 km per hour × 7/2 hour

Distance = 63/4 km or 15 3/4 km.

Distance = 15.75 km

Answer: Nilavan will cover the distance of 15 3/4 km or 15.75 km in 3 1/2 hours

Step-by-step explanation:

pls mark me as BRAINLIEST

pls pls pls

Discussion

16.	\| a+bw+cw^2/a+bw^2+cw \|
Answer» ONG>ANSWER: Step-by-step EXPLANATION: (a+bω+cω2)(a+bω2+cω)=(a2+b2+c2−ab−bc−ac) ∴L.H.S.=(a+b+c)(a+bω+cω2)(a+bω2+cω) =(a+b+c)(a2+b2+c2−ab−bc−ac) =a3+ab2+ac2+ba2+b3+bc2+ca2+cb2+c3−a2b−abc−a2c−ab2−b2c−abc−abc−bc2−ac2 =a3+b3+c3−3abc=R.H.S.

16.

| a+bw+cw^2/a+bw^2+cw |

Answer» ONG>ANSWER:

Step-by-step EXPLANATION:

(a+bω+cω2)(a+bω2+cω)=(a2+b2+c2−ab−bc−ac)

∴L.H.S.=(a+b+c)(a+bω+cω2)(a+bω2+cω)

=(a+b+c)(a2+b2+c2−ab−bc−ac)

=a3+ab2+ac2+ba2+b3+bc2+ca2+cb2+c3−a2b−abc−a2c−ab2−b2c−abc−abc−bc2−ac2

=a3+b3+c3−3abc=R.H.S.

Discussion

17.	Integration sin^2 x/1-tan x
Answer» ONG>Answer: MARK me BRILIANT please yaar mark me briliant please yaar mark me briliant please yaar mark me briliant Step-by-step explanation: Mark me briliant please yaar mark me briliant please yaar mark me briliant please

17.

Integration sin^2 x/1-tan x

Answer» ONG>Answer:

MARK me BRILIANT please yaar mark me briliant please yaar mark me briliant please yaar mark me briliant

Step-by-step explanation:

Mark me briliant please yaar mark me briliant please yaar mark me briliant please

Discussion

18.	The marked price of an article is 25% above the cost price. By what percent the cost price is less than the marked price?
Answer» ONG>Step-by-step explanation: please MARK as BRAINLIEST

Discussion

19.	Factorise x²+14x+35
Answer» ONG>Step-by-step EXPLANATION: FACTORISE x²+14x+35 =(x+7)² -14

19.

Factorise x²+14x+35

Answer» ONG>Step-by-step EXPLANATION:

FACTORISE

x²+14x+35 =(x+7)² -14

Discussion

20.	Shyam has 11 identical coins. He wants to give some of them to 3 beggars and keep the remaining for himself, then number of different ways to do so is (He may keep all of them):
Answer» ong>Given : Shyam has 11 identical coins. He wants to give some of them to 3 beggars and keep the remaining for himself To Find : NUMBER of different ways to do so Solution: Keeps 11 1 way Keep 10 3 Ways ( 1 coin to Either of three) Keep 9 6 ways ( 2 coins to Either of three , one coin each to any two ) Keep 8 10 ways ( 1 coins to Each , 3 coins Either one of three , 2 coins to Either two of three , two coins to any one of three and one coin each to other two ) and so on ⁿ⁺¹C₂ n = 12 hence last ¹³C₂ = 78 1 + 3 + 6 + 10 + 15 + 21 + .................................. + 78 = 364 364 Ways Direct formula n + r C r n = 11 ( OBJECTS ) r = 3 11 + 3 = 14 ¹⁴C₃ = 364 Learn More: How MANY ways are there to place 8 INDISTINGUISHABLE balls into 4 ... brainly.in/question/11411418 A set of 5 coins is tossed 3200 times and the number of heads ... brainly.in/question/9708180

20.

Shyam has 11 identical coins. He wants to give some of them to 3 beggars and keep the remaining for himself, then number of different ways to do so is (He may keep all of them):

Answer»

ong>Given : Shyam has 11 identical coins.

He wants to give some of them to 3 beggars and keep the remaining for himself

To Find : NUMBER of different ways to do so

Solution:

Keeps 11

1 way

Keep 10

3 Ways ( 1 coin to Either of three)

Keep 9

6 ways ( 2 coins to Either of three , one coin each to any two )

Keep 8

10 ways ( 1 coins to Each , 3 coins Either one of three , 2 coins to Either two of three , two coins to any one of three and one coin each to other two )

and so on

ⁿ⁺¹C₂ n = 12 hence last ¹³C₂ = 78

1 + 3 + 6 + 10 + 15 + 21 + .................................. + 78

= 364

364 Ways

Direct formula

n + r C r

n = 11 ( OBJECTS )

r = 3

11 + 3 = 14

¹⁴C₃ = 364

Learn More:

How MANY ways are there to place 8 INDISTINGUISHABLE balls into 4 ...

brainly.in/question/11411418

A set of 5 coins is tossed 3200 times and the number of heads ...

brainly.in/question/9708180

Discussion

21.	The Sum of all natural numbers between 50 and 250which are exactly divisible by 3 is
Answer» ONG>ANSWER: the answer is 10,050 Step-by-step EXPLANATION: hope this would help U

21.

The Sum of all natural numbers between 50 and 250which are exactly divisible by 3 is

Answer» ONG>ANSWER:

the answer is 10,050

Step-by-step EXPLANATION:

hope this would help U

Discussion

22.	If one side of triangle is 50 then what is the value of x?
Answer» ong>Answer: 65 Step-by-step explanation: PLEASE mark my answer as *Brainliest* As it is *the* *CORRECT* *answer*

22.

If one side of triangle is 50 then what is the value of x?

Answer»

ong>Answer:

65

Step-by-step explanation:

PLEASE mark my answer as Brainliest

As it is the CORRECT answer

Discussion

23.	Smallest prime number greater than 47 is
Answer» ONG>Answer: smallest prime NUMBER greater than 47 is 53 .. so , OPTION C is right answer...

23.

Smallest prime number greater than 47 is

Answer» ONG>Answer:

smallest prime NUMBER greater than 47 is 53 ..

so , OPTION C is right answer...

Discussion

24.	How many 6 digit numbers can be formed if i) 1st digit is 5 and 3rd digit is 3ii) number should not be divisible by 9
Answer» ONG>ANSWER: ...........................…

Discussion

25.	Mukesh has some goats and hens in his shed. Upon counting, Mukesh found that the total number of legs is 112 and the total number of heads in 40. Find the number of hens in his shed
Answer» ong>Answer: Let the number of goat is g and number of hen is h A/q counting head g+h = 40___(1) counting legs and 4g +2h = 112 ⇒2g +h = 56___(2) subtracting (1) and (2),we GET g = 16 so, h = 40-16 = 24 ∴number of goat is 16 and number of hen is 24 Step-by-step EXPLANATION: mark me BRAINLIEST

25.

Mukesh has some goats and hens in his shed. Upon counting, Mukesh found that the total number of legs is 112 and the total number of heads in 40. Find the number of hens in his shed

Answer»

ong>Answer:

Let the number of goat is g

and number of hen is h

A/q

counting head

g+h = 40___(1)

counting legs

and 4g +2h = 112

⇒2g +h = 56___(2)

subtracting (1) and (2),we GET

g = 16

so, h = 40-16 = 24

∴number of goat is 16 and number of hen is 24

Step-by-step EXPLANATION:

mark me BRAINLIEST

Discussion

26.	Answer me very fastly
Answer» will SEND PHOTO in this QUESTION MARK as BRANILIEST

26.

Answer me very fastly

Answer»

will SEND PHOTO in this QUESTION

MARK as BRANILIEST

Discussion

27.	Find the square root of 11 +2 √30
Answer» ONG>Step-by-step EXPLANATION: √(11+2√30) = √21.95 (APPROX) = 4.68(approx)

27.

Find the square root of 11 +2 √30

Answer» ONG>Step-by-step EXPLANATION:

√(11+2√30)

= √21.95 (APPROX)

= 4.68(approx)

Discussion

28.	In polygon BO=7x+4 and OD=18.FIND x
Answer» EN : BO = 7x+4 OD = 18 SOLUTION : In a POLYGON all its sides are equal and having 5 sides so it is known as polygon BO = OD 7x+4 = 18 7x = 18-4 7x = 14 X = 14/7 x = 2 So , the value of x is 2

28.

In polygon BO=7x+4 and OD=18.FIND x

Answer»

EN :

BO = 7x+4

OD = 18

SOLUTION :

In a POLYGON all its sides are equal and having 5 sides so it is known as polygon

BO = OD

7x+4 = 18

7x = 18-4

7x = 14

X = 14/7

x = 2

So , the value of x is 2

Discussion

29.	Mr.Joshi burrowed a sum of rs15000 from Mr.bhatta at the rate of 15% per year Calculate the amount received by Mr. Bhatta in 10 months.
Answer» ong>ANSWER: SI =PNR/100 =15000×15×10/100×12 =125×15 =1875 so total AMOUNT =15000+1875 =16875 so Mr.bhatt receive 16875 RS

29.

Mr.Joshi burrowed a sum of rs15000 from Mr.bhatta at the rate of 15% per year Calculate the amount received by Mr. Bhatta in 10 months.

Answer»

ong>ANSWER:

SI =PNR/100

=15000×15×10/100×12

=125×15

=1875

so total AMOUNT =15000+1875

=16875

so Mr.bhatt receive 16875 RS

Discussion

30.	Use suitable special products to find each of the following: ( x + 3 ) ( x - 1 )
Answer» > I HOPE this will HELP U

30.

Use suitable special products to find each of the following: ( x + 3 ) ( x - 1 )

Answer»

>

I HOPE this will HELP U

Discussion

31.	The product of two number is 432. find the lcm ,their hcf is 6.
Answer» p> Step-by-step explanation: (Lcm * HCF) of two numbers = PRODUCT of numbers let X Be the hcf therefore X * 6 = 432 X = 432 / 6 X = 72

31.

The product of two number is 432. find the lcm ,their hcf is 6.

Answer»

p>

Step-by-step explanation:

(Lcm * HCF) of two numbers = PRODUCT of numbers

let X Be the hcf

therefore X * 6 = 432

X = 432 / 6

X = 72

Discussion

32.	Gus. 4.hunut23match the column ...Jabalharthe lifeline of Madhya PradeshAmarkantak origin4 Sethani thatVidhyanchal hairHi5 요
Answer» KE uuuuuuuuuuuuuuu

Discussion

33.	A shelf contains 25 different books, 7 are in single volume and other are in set of 9, 6, 3 volumes respectively. Total number of ways in which books may be arranged on the shelf if volumes of each set are together and in increasing or decreasing order.
Answer» ong>Given : A shelf CONTAINS 25 different books, 7 are in single volume and other are in set of 9, 6, 3 volumes respectively. To Find : Total number of ways in which books may be arranged on the shelf if volumes of each set are together and in increasing or DECREASING order. Solution: there are 7 in single volume and other are in set of 9, 6, 3 volumes Hence 7 + 3 volumes = 10 10 can be arranged in 10! Ways Each volume can be arranged in 2 ways increasing or decreasing order. hence 2 * 2 * 2 = 8 ways Total Ways of in which books may be arranged on the shelf = 8 * 10! =2,90,30,400 8 * 10! Learn More: Given 8 different physics books,7 different chemistry books and 5 ... brainly.in/question/13611743 In how MANY ways can 12 books be arranged on a shelf if: (a) 4 ... brainly.in/question/14114910 In how many ways can 20 notes of 500 rupees and 18 notes of 2000 ... brainly.in/question/15186754

33.

A shelf contains 25 different books, 7 are in single volume and other are in set of 9, 6, 3 volumes respectively. Total number of ways in which books may be arranged on the shelf if volumes of each set are together and in increasing or decreasing order.

Answer»

ong>Given : A shelf CONTAINS 25 different books, 7 are in single volume and other are in set of 9, 6, 3 volumes respectively.

To Find : Total number of ways in which books may be arranged on the shelf if volumes of each set are together and in increasing or DECREASING order.

Solution:

there are 7 in single volume and other are in set of 9, 6, 3 volumes

Hence 7 + 3 volumes = 10

10 can be arranged in 10! Ways

Each volume can be arranged in 2 ways increasing or decreasing order.

hence 2 * 2 * 2 = 8 ways

Total Ways of in which books may be arranged on the shelf = 8 * 10!

=2,90,30,400

8 * 10!

Learn More:

Given 8 different physics books,7 different chemistry books and 5 ...

brainly.in/question/13611743

In how MANY ways can 12 books be arranged on a shelf if: (a) 4 ...

brainly.in/question/14114910

In how many ways can 20 notes of 500 rupees and 18 notes of 2000 ...

brainly.in/question/15186754

Discussion

34.	I find the nature of the roots ofthe quadratic equation ex C32x cx-3) + 3 = 0 . If the dooroots exist, find them.hay2x (n-3) +3 20
Answer» ong>ANSWER: ARON BRO you are so CHITTER

34.

I find the nature of the roots ofthe quadratic equation ex C32x cx-3) + 3 = 0 . If the dooroots exist, find them.hay2x (n-3) +3 20

Answer»

ong>ANSWER:

ARON BRO you are so

CHITTER

Discussion

35.	(157)-(63)-63=?*6
Answer» ong>Answer: (15 × 7) - (6 × 3) - 63 = X × 6 105 - 18 - 63 = 6x 105 - 81 = 6x 24 = 6x 24/6 = x x = 4 HOPE I HAVE ANSWERED YOUR QUESTION PLS MARK ME AS BRAINLIEST

35.

(157)-(63)-63=?*6

Answer»

ong>Answer:

(15 × 7) - (6 × 3) - 63 = X × 6

105 - 18 - 63 = 6x

105 - 81 = 6x

24 = 6x

24/6 = x

x = 4

HOPE I HAVE ANSWERED YOUR QUESTION

PLS MARK ME AS BRAINLIEST

Discussion

36.	Use the False position method to find solutions accurate to within 10-5 for the function 3x - e x = 0 in 1 ≤ ≤ 2.
Answer» E, x = 0 in 1 < < 2 Your ANSWER is 0

36.

Use the False position method to find solutions accurate to within 10-5 for the function 3x - e x = 0 in 1 ≤ ≤ 2.

Answer» E, x = 0 in 1 < < 2

Your ANSWER is 0

Discussion

37.	How many multiple of 4liebetween 10and 250
Answer» ong>Answer: 60 multiples HENCE there are 60 multiples of 4 between 10 and 250 please mark me as BRAINLIEST and follow me Step-by-step explanation:

37.

How many multiple of 4liebetween 10and 250

Answer»

ong>Answer:

60 multiples

HENCE there are 60 multiples of 4 between 10 and 250

please mark me as BRAINLIEST and follow me

Step-by-step explanation:

Discussion

38.	Distance of the point (4,5)from origin is a) √41 unit b)√35 unit c) √62 unit d)√79 unitclass 10th
Answer» ong>Step-by-step explanation: distance between (0,0)& ( 4,5) is = √ 16 + 25 = √ 41 unit ........ distance between two points is = √ (X1- X2 )^2 + (y1-y2)^2

38.

Distance of the point (4,5)from origin is a) √41 unit b)√35 unit c) √62 unit d)√79 unitclass 10th

Answer»

ong>Step-by-step explanation:

distance between (0,0)& ( 4,5) is

= √ 16 + 25 = √ 41 unit ........

distance between two points is

= √ (X1- X2 )^2 + (y1-y2)^2

Discussion

39.	A man bought a house for Rs 956 780. He sold it for Rs 120 000 less than the cost price. how much did he sell the house for?
Answer» ONG>Step-by-step EXPLANATION: CP of house=956780 RUPEES Loss=120000 rupees Then, SP=956780-120000 rupees =836780 rupees

39.

A man bought a house for Rs 956 780. He sold it for Rs 120 000 less than the cost price. how much did he sell the house for?

Answer» ONG>Step-by-step EXPLANATION:

CP of house=956780 RUPEES

Loss=120000 rupees

Then,

SP=956780-120000 rupees

=836780 rupees

Discussion

40.	Arithmetic mean of first name natural numbers
Answer» ong>Answer: We know that sum of FIRST N natural numbers is 2n(n+1) So mean of the first n natural numbers =numbersumofnnaturalnumbers=n2n(n+1)=2(n+1 hope it's CLEAR to u yaar brainliest banado aur rate krdo yaar koi tu krdo blusing rainbow thks to me PLZ gopika thks to me plz ranjanya thks to me plz ansh thks to me plz bupin thks to me plz nobody thks to me

40.

Arithmetic mean of first name natural numbers

Answer»

ong>Answer:

We know that sum of FIRST N natural numbers is 2n(n+1) So mean of the first n natural numbers =numbersumofnnaturalnumbers=n2n(n+1)=2(n+1

hope it's CLEAR to u

yaar brainliest banado aur rate krdo yaar

koi tu krdo

blusing rainbow thks to me PLZ

gopika thks to me plz

ranjanya thks to me plz

ansh thks to me plz

bupin thks to me plz

nobody thks to me

Discussion

41.	3) Divide Rs. 4160 among A, B and C such that 2A=3B=4C. A The sides of a triangle are in the ratio 3:5:7 and its perimeter is 75cm. F
Answer» ONG>Answer: 3) 2+3+4 = 9 A = 2/9×4160 = ₹924.44 B = 3/9×4160 = ₹1386.66 C = 4/9×4160 = ₹1848.88

41.

3) Divide Rs. 4160 among A, B and C such that 2A=3B=4C. A The sides of a triangle are in the ratio 3:5:7 and its perimeter is 75cm. F

Answer» ONG>Answer:

3) 2+3+4 = 9

A = 2/9×4160 = ₹924.44

B = 3/9×4160 = ₹1386.66

C = 4/9×4160 = ₹1848.88

Discussion

42.	A man bought apples at 10 for 25 rupees and sold them at 25 per dozen . find his gain or loss percent
Answer» ONG>Step-by-step EXPLANATION: LOSS loss PERCENTAGE = sp-cp÷100

Discussion

43.	Number of words that can be formed using all the letters of word “PARKAR” if alike letters of one kind are together but are separated from other set of alike letters:
Answer» ONG>ANSWER: I THINK so it should be five Step-by-step explanation park pak rak ark rap

43.

Number of words that can be formed using all the letters of word “PARKAR” if alike letters of one kind are together but are separated from other set of alike letters:

Answer» ONG>ANSWER:

I THINK so it should be five

Step-by-step explanation

park
pak
rak
ark
rap

Discussion

44.	Please solve it fast.....2root18-2root6=?
Answer» ONG>Answer: 2√18 - 2√6 = 6√2 - 2√6 ....

Discussion

45.	Pair of angles is called linear pair if the sum of two adjacent angle
Answer» RONG>180° The ADJACENT ANGLES should ADD up to 180° HoPe iT HELPS YoU ♥️♥️♥️

45.

Pair of angles is called linear pair if the sum of two adjacent angle

Answer» RONG>180°

The ADJACENT ANGLES should ADD up to 180°

HoPe iT HELPS YoU ♥️♥️♥️

Discussion

46.	How to divide 3470582 by 429step by step.
Answer» ONG>Answer: 8089.9347 Step-by-step EXPLANATION:

46.

How to divide 3470582 by 429step by step.

Answer» ONG>Answer:

8089.9347

Step-by-step EXPLANATION:

Discussion

47.	Find the value of x: 3/4=x/16
Answer» ONG>Answer: 3/4=x/16 3×16=x×4 48=4x 48/4=x 12=x

47.

Find the value of x: 3/4=x/16

Answer» ONG>Answer:

3/4=x/16

3×16=x×4

48=4x

48/4=x

12=x

Discussion

48.	Please help !! who will solve it perfectly will be marked as brainliest
Answer»

Discussion

49.	Question No. 1. If a and B are the roots of the equation (p+1) tan’x-2x tan x = l-p and tan' (a+b)= 50. thenthe value of is equal to
Answer» ONG>ANSWER: LET α,β be the distinct positive ROOTS of the EQUATION tanx=2x,then find ∫10sinαxsinβxdx,independent of α and β.

Discussion

50.	Number of divisors of 2^53^35^5*6^3 is
Answer» ong>ANSWER: All the POSITIVE divisors will have a prime factorization comprised of some subset of the prime factors of the number given. You can have ANYTHING between zero to five 2 ′ s in the divisor's prime factorization, that is 6 ways to take the prime factor 2, one extra for not taking 2 at all (2 raised to 0). USING the same logic for the other prime factors, and multiplying the number of possibilities for each: (5+1)(6+1)(3+1)=168

50.

Number of divisors of 2^53^35^5*6^3 is

Answer»

ong>ANSWER:

All the POSITIVE divisors will have a prime factorization comprised of some subset of the prime factors of the number given.

You can have ANYTHING between zero to five 2

′

s in the divisor's prime factorization, that is 6 ways to take the prime factor 2, one extra for not taking 2 at all (2 raised to 0).

USING the same logic for the other prime factors, and multiplying the number of possibilities for each:

(5+1)(6+1)(3+1)=168

Discussion

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