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Number of divisors of 2^5*3^3*5^5*6^3 is |
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Answer» ong>ANSWER: All the POSITIVE divisors will have a prime factorization comprised of some subset of the prime factors of the number given. You can have ANYTHING between zero to five 2 ′ s in the divisor's prime factorization, that is 6 ways to take the prime factor 2, one extra for not taking 2 at all (2 raised to 0). USING the same logic for the other prime factors, and multiplying the number of possibilities for each: (5+1)(6+1)(3+1)=168 |
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