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Shyam has 11 identical coins. He wants to give some of them to 3 beggars and keep the remaining for himself, then number of different ways to do so is (He may keep all of them): |
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Answer» ong>Given : Shyam has 11 identical coins. He wants to give some of them to 3 beggars and keep the remaining for himself To Find : NUMBER of different ways to do so Solution: Keeps 11 1 way Keep 10 3 Ways ( 1 coin to Either of three) Keep 9 6 ways ( 2 coins to Either of three , one coin each to any two ) Keep 8 10 ways ( 1 coins to Each , 3 coins Either one of three , 2 coins to Either two of three , two coins to any one of three and one coin each to other two ) and so on ⁿ⁺¹C₂ n = 12 hence last ¹³C₂ = 78 1 + 3 + 6 + 10 + 15 + 21 + .................................. + 78 = 364 364 Ways Direct formula n + r C r n = 11 ( OBJECTS ) r = 3 11 + 3 = 14 ¹⁴C₃ = 364 Learn More: How MANY ways are there to place 8 INDISTINGUISHABLE balls into 4 ... A set of 5 coins is tossed 3200 times and the number of heads ... |
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