332354 + Interview Questions in Secondary School in Math

1.	Adjacant angal of parallelogram are of measure 2x & 7x then find the value of "X"
Answer» ONG>Answer: 2x+7x=180 9x= 180 x=180/9 x=20

1.

Adjacant angal of parallelogram are of measure 2x & 7x then find the value of "X"

Answer» ONG>Answer:

2x+7x=180

9x= 180

x=180/9

x=20

Discussion

2.	Please tell this... fast
Answer» ONG>ANSWER: ugcjccf Step-by-step explanation: ggDg. ZJ. atsj. aeckhcts Rajni JEE love

2.

Please tell this... fast

Answer» ONG>ANSWER:

ugcjccf

Step-by-step explanation:

ggDg. ZJ. atsj. aeckhcts Rajni JEE love

Discussion

3.	Solve:A) Find the mean of all prime numbers up to 10. (B) Find the mean proportional between 3 and 27. (C) Divide 81 in to three parts in the ratio 2 : 3 : 4 (D) Given below figure shows a pair of parallel lines cut by a transversal. Find the value of a and b, giving reason.
Answer» ong>Answer: 1.) The all prime NUMBERS upto 30 are 2,3,5,7,11,13,17,19,23,29 sum of these observations=129 Number of their observation=10 Required mean=129÷10=12.9 2.)The mean PROPORTIONAL of 27 and 3 is √27×3=√81=9. 3.)Given ratio=2:3:4 Sum of their ratio=9 1st part=2/9×81=18 2nd part=3/9×81=27 3rd part= 4/9×81=36 4.)Each FIGURE given below shows a pair of parallel lines CUT by a transversal For each case, find a and b, GIVING reasons.

3.

Solve:A) Find the mean of all prime numbers up to 10. (B) Find the mean proportional between 3 and 27. (C) Divide 81 in to three parts in the ratio 2 : 3 : 4 (D) Given below figure shows a pair of parallel lines cut by a transversal. Find the value of a and b, giving reason.

Answer»

ong>Answer:

1.) The all prime NUMBERS upto 30 are 2,3,5,7,11,13,17,19,23,29

sum of these observations=129

Number of their observation=10

Required mean=129÷10=12.9

2.)The mean PROPORTIONAL of 27 and 3 is √27×3=√81=9.

3.)Given ratio=2:3:4

Sum of their ratio=9

1st part=2/9×81=18

2nd part=3/9×81=27

3rd part= 4/9×81=36

4.)Each FIGURE given below shows a pair of parallel lines CUT by a transversal For each case, find a and b, GIVING reasons.

Discussion

4.	If 9+5=9 7+4=5 12+6=15 then 18+11=??explain it
Answer» ONG>Step-by-step explanation: 9+5=14 7+4=11 12+6=18 14+11=25 25-18= 7

Discussion

5.	For each of the following fractions write three more fractions with equal denominator
Answer» ong>ANSWER: GIVE the FULL QUESTION what are the fractions

5.

For each of the following fractions write three more fractions with equal denominator

Answer»

ong>ANSWER:

GIVE the FULL QUESTION what are the fractions

Discussion

6.	Terms in Ap2) Let the fam conseutivebe ard, a, atd, at 2d
Answer» ONG>ANSWER: ARD,as,FT,sr√tffg,uiho

Discussion

7.	3×3×3×3=81 so* * *
Answer» >*ROOT* 81 =9 *BECAUSE* 9×9=81

7.

3×3×3×3=81 so* * *

Answer»

>ROOT 81 =9 BECAUSE 9×9=81

Discussion

8.	300 का67कापDeने 5040का132
Answer» ONG>ANSWER: का67 का प Deने 50 40 का 132

8.

300 का67कापDeने 5040का132

Answer» ONG>ANSWER:

का67

का

प

Deने 50

40

का

132

Discussion

9.	Find the HCF of the following numbers byprime factorization methods (i) 80 and 120
Answer» ER: Step-by-step EXPLANATION: FACTORS of 80 = 2× 2× 2× 2× 5 = 2⁴ × 5 Factors of 120 = 2× 2× 2× 3× 5 = 2³× 3 × 5 HCF = 2³ × 5 = 2× 2× 2× 5 = 40

9.

Find the HCF of the following numbers byprime factorization methods (i) 80 and 120

Answer» ER:

Step-by-step EXPLANATION:

FACTORS of 80 = 2× 2× 2× 2× 5 = 2⁴ × 5

Factors of 120 = 2× 2× 2× 3× 5 = 2³× 3 × 5

HCF = 2³ × 5 = 2× 2× 2× 5 = 40

Discussion

10.	1. Find two numbers with a sum of 15 and a difference of 4. give correct answer no spam please
Answer» ONG>ANSWER: MAKE me brainlist Step-by-step EXPLANATION: x+y=15 x-y=4 add 2x=19 x=9.5 y=15-9.5 y=5.5 x=9.5 and y=5.5

10.

1. Find two numbers with a sum of 15 and a difference of 4. give correct answer no spam please

Answer» ONG>ANSWER:

MAKE me brainlist

Step-by-step EXPLANATION:

x+y=15

x-y=4

add

2x=19

x=9.5

y=15-9.5

y=5.5

x=9.5 and y=5.5

Discussion

11.	तीन संख्या 2:3:4 अनुपात में है यदि तीन संख्याओं के घनो का योग 79007 तो संख्या निकालिए
Answer» ONG>ANSWER: ?????????????????????????????????

Discussion

12.	Prove That The Tangents drawn from anan externalpoint to a cirde are equal"
Answer» ong>Answer:P> data÷o is the centre of the circle p is the point lying out side the circle pq and pr are the tangents OUTER circle to prove ÷pq=pr CONSTRUCTION ÷ join op,or,oq proof ÷ In TRIANGLE poq and triangle por oq=or (radius) op=op (common side) angle oqp=angle orp (90°) triangle poq=~triangle por(RHS) pq=pr(C.p.c.t)

12.

Prove That The Tangents drawn from anan externalpoint to a cirde are equal"

Answer»

ong>Answer:P>

data÷o is the centre of the circle

p is the point lying out side the circle

pq and pr are the tangents OUTER circle

to prove ÷pq=pr

CONSTRUCTION ÷ join op,or,oq

proof ÷ In TRIANGLE poq and triangle por

oq=or (radius)

op=op (common side)

angle oqp=angle orp (90°)

triangle poq=~triangle por(RHS)

pq=pr(C.p.c.t)

Discussion

13.	A chocolate weighs 80g. how many chocolates can be packed in a 2 kg box?
Answer» ONG>Answer: 2kg=2000g =2000/806777

13.

A chocolate weighs 80g. how many chocolates can be packed in a 2 kg box?

Answer» ONG>Answer:

2kg=2000g

=2000/806777

Discussion

14.	А. BFill in the blanks.Anju jumped 6.23m in a long jump competition. This distance in cm is
Answer» ER: Step-by-step explanation: 623cm

14.

А. BFill in the blanks.Anju jumped 6.23m in a long jump competition. This distance in cm is

Answer» ER:

Step-by-step explanation:

623cm

Discussion

15.	There are one hundred toffees . if there are 10 children then how many toffees toget each
Answer» offees will be GIVEN to each CHILDREN

Discussion

16.	Sec² - sin ²Ø - 2sin²Ø / 2cos ⁴ Ø - cos² Ø = 1
Answer» ong>Answer: suck GAJ hd good if ja to is DJ ha EN LA to ha do ya this app

16.

Sec² - sin ²Ø - 2sin²Ø / 2cos ⁴ Ø - cos² Ø = 1

Answer»

ong>Answer:

suck GAJ hd good if ja to is DJ ha EN LA to ha do ya this app

Discussion

17.	Can anyone help me out in solving this question please
Answer» ONG>Answer: agar isme PARALLELOGRAM diya ha to 4 chij de diya ha aur ye quadrilateral ha to iska sum BHI 360 ha phle isko parallel aur EQUAL batao phir isko solve kro .... Step-by-step explanation: HOPE it will be helpful..

17.

Can anyone help me out in solving this question please

Answer» ONG>Answer:

agar isme PARALLELOGRAM diya ha to 4 chij de diya ha aur ye quadrilateral ha to iska sum BHI 360 ha phle isko parallel aur EQUAL batao phir isko solve kro ....

Step-by-step explanation:

HOPE it will be helpful..

Discussion

18.	Check whether given sides are the side so fright-angled triangles,usingphy tha goras the orem.24,45,51
Answer» ONG>ANSWER: PYTHAGORAS THEOREM $(ac) {}^{2} = (ab) ^{2} + (bc) ^{2}$ $(51) {}^{2} = (24) {}^{2} + (45) {}^{2}$ $2601 = 576 + 2025$ $2601 = 2601$ $lhs = rhs$ $hence \: \: proved$ I'll be happy if it is useful to you

18.

Check whether given sides are the side so fright-angled triangles,usingphy tha goras the orem.24,45,51

Answer» ONG>ANSWER:

PYTHAGORAS THEOREM

$(ac) {}^{2} = (ab) ^{2} + (bc) ^{2}$

$(51) {}^{2} = (24) {}^{2} + (45) {}^{2}$

$2601 = 576 + 2025$

$2601 = 2601$

$lhs = rhs$

$hence \: \: proved$

I'll be happy if it is useful to you

Discussion

19.	a clock is so placed that at 2 pm the minute hand points towards north-west. in which direction does the hour hand point at 6 pm.
Answer» ER: Step-by-step EXPLANATION: SOUTH

19.

a clock is so placed that at 2 pm the minute hand points towards north-west. in which direction does the hour hand point at 6 pm.

Answer» ER:

Step-by-step EXPLANATION:

SOUTH

Discussion

20.	A) ✓3+(✓2+✓3) compute this??
Answer» ONG>ANSWER: √3(√2+√3) = √6 + 3 = 3 +√6 Answer : 3 + √6

20.

A) ✓3+(✓2+✓3) compute this??

Answer» ONG>ANSWER:

√3(√2+√3) = √6 + 3

= 3 +√6

Answer : 3 + √6

Discussion

21.	Addition of 2809+168.54
Answer» .54 is the CORRECT ANSWER

21.

Addition of 2809+168.54

Answer»

.54 is the CORRECT ANSWER

Discussion

22.	4 का स्क्वायर ब्रैकेट ऑफ वन बाय 3*4 1/3
Answer» question Answer: 16 Step-by-step explanation: 34^2=481/3=16answer

22.

4 का स्क्वायर ब्रैकेट ऑफ वन बाय 3*4 1/3

Answer»

question

Answer:

16

Step-by-step explanation:

3*4^2=48*1/3=16answer

Discussion

23.	10) A starts a business with Rs 1000.B Joins him after 6 months with Rs 4000.C puts a sum of Rs 5000 for 4months only. At the end of the year the business gave aprofit of Rs 2800. How should the profit be dividedamong them?a)Rs 600,Rs 1200, Rs 1000b)Rs 800,Rs 600, Rs 1400c)Rs 1000, Rs 1200, Rs 60033 ,d)Rs 1200, Rs 600, Rs 1000
Answer» ong>Step-by-step explanation: starts a business with ₹ 4000. B joins him after 3 months with ₹ 8000. C PUTS a sum of ₹ 20000 in the business for 2 months only. At the end of year, the business gives a PROFIT of ₹ 16800. How should the profit be divided amongst them ? A = ₹ 5040 B = ₹ 7560, C = ₹ 4200 A = ₹ 7560, B = ₹ 5040, C = ₹ 4200 A = ₹ 4200, B = ₹ 7560, C = ₹ 5040 A = ₹ 4200, B = ₹ 5040, C = ₹ 7560 Correct OPTION: A A's share : B's share : C's share = Ratio of product of investment and time period of investment = 4000 x 12 : 8000 x (12 - 3) : 20000 x 2 = 4 x 12 : 8 x 9 : 20 x 2 = 6 : 9 : 5 Let, A's share = 6N B's share = 9N C's share = 5N According to the question, 6N + 9N + 5N = 16800 ⇒ 20N = 16800 ∴ N = 16800/20 = 840 ∴ A's share = 6N = 6 x 840 = ₹ 5040 B's share = 9N = 9 x 840 = ₹ 7560 C's share = 5N = 5 x 840 = ₹ 4200

23.

10) A starts a business with Rs 1000.B Joins him after 6 months with Rs 4000.C puts a sum of Rs 5000 for 4months only. At the end of the year the business gave aprofit of Rs 2800. How should the profit be dividedamong them?a)Rs 600,Rs 1200, Rs 1000b)Rs 800,Rs 600, Rs 1400c)Rs 1000, Rs 1200, Rs 60033 ,d)Rs 1200, Rs 600, Rs 1000

Answer»

ong>Step-by-step explanation:

starts a business with ₹ 4000. B joins him after 3 months with ₹ 8000. C PUTS a sum of ₹ 20000 in the business for 2 months only. At the end of year, the business gives a PROFIT of ₹ 16800. How should the profit be divided amongst them ?

A = ₹ 5040 B = ₹ 7560, C = ₹ 4200

A = ₹ 7560, B = ₹ 5040, C = ₹ 4200

A = ₹ 4200, B = ₹ 7560, C = ₹ 5040

A = ₹ 4200, B = ₹ 5040, C = ₹ 7560

Correct OPTION: A

A's share : B's share : C's share

= Ratio of product of investment and time period of investment

= 4000 x 12 : 8000 x (12 - 3) : 20000 x 2

= 4 x 12 : 8 x 9 : 20 x 2

= 6 : 9 : 5

Let,

A's share = 6N

B's share = 9N

C's share = 5N

According to the question,

6N + 9N + 5N = 16800

⇒ 20N = 16800

∴ N = 16800/20 = 840

∴ A's share = 6N = 6 x 840 = ₹ 5040

B's share = 9N = 9 x 840 = ₹ 7560

C's share = 5N = 5 x 840 = ₹ 4200

Discussion

24.	Question no 9. 4z2 –162 +15
Answer» ONG>Answer: 4z²-16z+15 4z²-6z-10z-10z+15 2z ×(2z-3)-5(2z-3) (2z-3)×(2z-5)

24.

Question no 9. 4z2 –162 +15

Answer» ONG>Answer:

4z²-16z+15

4z²-6z-10z-10z+15

2z ×(2z-3)-5(2z-3)

(2z-3)×(2z-5)

Discussion

25.	Construct ΔPYQ such that PY=6.3 cm YQ = 7.2 cm PQ = 5.8 cm IfYZ/YQ=6/5 then constructΔ XYZ similar toΔPYQ
Answer» ONG>Answer: 26838874(? ;5:&4478-'

Discussion

26.	Find A U B A = { 1, 2, 3, 4} B = { 3, 5, 7, 9 }
Answer» ONG>Answer: union set of AB is { 3 } it may HELP you

Discussion

27.	(a)44 (b) 36.25RC56.25(d) 62.5The ratio of the incomes of ajay and bina is 5:4and the ratio of their expenditure is 6:5 if theratio of the savings is 7:5 what percentage ofhis income does ajay save?अजय और बीना की आय का अनुपात 5:4 है औरखर्च का अनुपात 6:5 है। यदि बचत का अनुपात 7:5है तो अजय अपनी आय का कितना प्रतिशत बचाता है?(b)25%D(a)28%(c)30%(d) 32%The difference between the 38% of a number
Answer» ONG>ANSWER: kddddkkddddddddddddxxddddddddxxxdddxxdddddddddd

Discussion

28.	What is the compound interest on Rs. 200 for 1 year at 10% rate compounded half-yearly
Answer» ong>ANSWER: p×r×t/100 we can GET answer mark me as brainiest thank you

28.

What is the compound interest on Rs. 200 for 1 year at 10% rate compounded half-yearly

Answer»

ong>ANSWER:

p×r×t/100 we can GET answer mark me as brainiest thank you

Discussion

29.	Whatis the equation of x-axis and Y- oxi?
Answer» ong>Answer: First U should buy GRAPH note and draw how to use that note then u will draw x AXIS and y axis . If u do any sums in graph they will give equations if it regarding x axis u should write the equation in x axis and if they give equation regarding y axis u should write equation in y axis

29.

Whatis the equation of x-axis and Y- oxi?

Answer»

ong>Answer:

First U should buy GRAPH note and draw how to use that note then u will draw x AXIS and y axis . If u do any sums in graph they will give equations if it regarding x axis u should write the equation in x axis and if they give equation regarding y axis u should write equation in y axis

Discussion

30.	57. The standard deviation of 10, 16, 10, 16, 10, 10, 16, 16 is (a) 4(b) 6(c) 3.(d) o
Answer»

Discussion

31.	Diagonal of a parallelogram PQRS intetsect each other in point 'O'. if length of diagonal PR is 8.4 cm then find l ( OP) = ?
Answer» ong>Answer: L (OP) = 4.2 cm Step-by-step explanation: hope u like the answer PLZ mark me as BRAINLIEST .

31.

Diagonal of a parallelogram PQRS intetsect each other in point 'O'. if length of diagonal PR is 8.4 cm then find l ( OP) = ?

Answer»

ong>Answer:

L (OP) = 4.2 cm

Step-by-step explanation:

hope u like the answer

PLZ mark me as BRAINLIEST .

Discussion

32.	3. x is 75% y. The percentage of y to x is :
Answer» ONG>Answer: Mark me as Brainliest Step-by-step EXPLANATION: y is 133.33% of x. Step-by-step explanation: It is GIVEN that x is 75% of y. It can be written as x=\FRAC{75}{100}yx= 100 75 y x=\frac{3}{4}yx= 4 3 y The percentage of y to x is \frac{y}{x}\times 100=\frac{y}{\frac{3}{4}y}\times 100 x y ×100= 4 3 y y ×100 \frac{y}{x}\times 100=\frac{4y}{3y}\times 100 x y ×100= 3y 4y ×100 \frac{y}{x}\times 100=\frac{4}{3}\times 100 x y ×100= 3 4 ×100 \frac{y}{x}\times 100=\frac{400}{3}=133.33 x y ×100= 3 400 =133.33

32.

3. x is 75% y. The percentage of y to x is :

Answer» ONG>Answer:

Mark me as Brainliest

Step-by-step EXPLANATION:

y is 133.33% of x.

Step-by-step explanation:

It is GIVEN that x is 75% of y.

It can be written as

x=\FRAC{75}{100}yx=

100

75

y

x=\frac{3}{4}yx=

4

3

y

The percentage of y to x is

\frac{y}{x}\times 100=\frac{y}{\frac{3}{4}y}\times 100

x

y

×100=

4

3

y

×100

\frac{y}{x}\times 100=\frac{4y}{3y}\times 100

x

y

×100=

3y

4y

×100

\frac{y}{x}\times 100=\frac{4}{3}\times 100

x

y

×100=

3

4

×100

\frac{y}{x}\times 100=\frac{400}{3}=133.33

x

y

×100=

3

400

=133.33

Discussion

33.	1.Find the gain or loss when :(a) C.P. = 600, S.P. = 800
Answer» ONG>ANSWER: There is GAIN of 200 Step-by-step EXPLANATION: Gain =sp-cp 800- 600 =200

33.

1.Find the gain or loss when :(a) C.P. = 600, S.P. = 800

Answer» ONG>ANSWER:

There is GAIN of 200

Step-by-step EXPLANATION:

Gain =sp-cp

800- 600

=200

Discussion

34.	How many slabs of cement are required to tile a platform of length 8 m and breadth 6 m, if the length of each slab is 4 m and breadth 3 m?
Answer» ONG>Step-by-step EXPLANATION: no. of slabes cemented in the PLATFORM = 4 slab *THANK* *YOU* *PLEASE* *MARK* IT AS BRAINLIEST

34.

How many slabs of cement are required to tile a platform of length 8 m and breadth 6 m, if the length of each slab is 4 m and breadth 3 m?

Answer» ONG>Step-by-step EXPLANATION:

no. of slabes cemented in the PLATFORM = 4 slab

THANK YOU

PLEASE MARK IT AS BRAINLIEST

Discussion

35.	विभाजित होता है, वह ज्ञात Find the ratio in which the segment joining the points (1. - 3) and (4, 5) isdivided by x-axis ? Also find the coordinates of this point on x-axis.
Answer» POINT on the X axis is of the form (x,0) let the ratio be k:1 Using section formula for Y coordinate $0 = \frac{(1 \times - 3) + (5 \times k)}{k + 1} \\ 0 = - 3 + 5k \\ 3 = 5k \\ k = \frac{3}{5}$ since the ratio is k:1 therefore it can be WRITTEN as 3/5:1 So the *REQUIRED* *ratio* is 3:5 Now using section formula for X coordinate $x = \frac{(1 \times 5) + (4 \times 3)}{5 + 3} \\ x = \frac{5 + 12}{8} \\ x = \frac{17}{8}$ here is your answer :)

35.

विभाजित होता है, वह ज्ञात Find the ratio in which the segment joining the points (1. - 3) and (4, 5) isdivided by x-axis ? Also find the coordinates of this point on x-axis.

Answer» POINT on the X axis is of the form (x,0)

let the ratio be k:1

Using section formula for Y coordinate

$0 = \frac{(1 \times - 3) + (5 \times k)}{k + 1} \\ 0 = - 3 + 5k \\ 3 = 5k \\ k = \frac{3}{5}$

since the ratio is k:1

therefore it can be WRITTEN as

3/5:1

So the REQUIRED ratio is

3:5

Now using section formula for X coordinate

$x = \frac{(1 \times 5) + (4 \times 3)}{5 + 3} \\ x = \frac{5 + 12}{8} \\ x = \frac{17}{8}$

here is your answer :)

Discussion

36.	6xsquare - 3 - 7x middle term
Answer» x² -7X - 3 → 6x² -9x + 2x - 3 → 3X ( 2x - 3 ) + 1 ( 2x - 3 ) → (3x + 1) ( 2x - 3)

36.

6xsquare - 3 - 7x middle term

Answer»

x² -7X - 3

→ 6x² -9x + 2x - 3

→ 3X ( 2x - 3 ) + 1 ( 2x - 3 )

→ (3x + 1) ( 2x - 3)

Discussion

37.	make the largest and the smallest numbers of 6 digit by using 1,0,3,2,5 and 4 only once then add them and find the sum
Answer» ONG>Answer: LARGEST NUMBER= 543210 Smallest number= 102345 Step-by-step explanation: This is the CORRECT answer

37.

make the largest and the smallest numbers of 6 digit by using 1,0,3,2,5 and 4 only once then add them and find the sum

Answer» ONG>Answer:

LARGEST NUMBER= 543210

Smallest number= 102345

Step-by-step explanation:

This is the CORRECT answer

Discussion

38.	How this series is calculated 0 1 4 41 768 27449
Answer» ong>ANSWER: SORRY I can't UNDERSTAND your QUESTION

38.

How this series is calculated 0 1 4 41 768 27449

Answer»

ong>ANSWER:

SORRY I can't UNDERSTAND your QUESTION

Discussion

39.	If 20 men can do a piece of work in 14 days ,in how many days will 8 men do?
Answer» ONG>Step-by-step explanation: 8 MEN can do the WORK in 35 days HERE IS YOUR ANSWER . I HOPE IT MAY HELP YOU . PLEASE MARK ME AS A BRAINLIEST . THANK YOU

39.

If 20 men can do a piece of work in 14 days ,in how many days will 8 men do?

Answer» ONG>Step-by-step explanation:

8 MEN can do the WORK in 35 days

HERE IS YOUR ANSWER .

I HOPE IT MAY HELP YOU .

PLEASE MARK ME AS A BRAINLIEST .

THANK YOU

Discussion

40.	Compute, a) ✓3+(✓2+✓3) b) ✓2×(1+2✓2) c) ✓8×(✓0.5+✓2)
Answer» ONG>Answer: A = (√3-√2)/(√3+√2) = (√3-√2)/(√3+√2)× (√3-√2)/(√3-√2) [ rationalizing it] =(√3 -√2)²/1 = (√3 -√2)² = 5- 2√6 b= (√3+√2)/(√3-√2)×(√3+√2)/(√3+√2) [ rationalizing it] = (√3+√2)²/1 =(√3+√2)² = 5+2√6 now, a²+b² - 5ab = (5-2√6)² + (5+2√6)² - 5(5-2√6)(5+2√6) =25 +24 -20√6 +25 +24 + 20√6 - 5(25-24) =98 -5 = 93

40.

Compute, a) ✓3+(✓2+✓3) b) ✓2×(1+2✓2) c) ✓8×(✓0.5+✓2)

Answer» ONG>Answer:

A = (√3-√2)/(√3+√2)

= (√3-√2)/(√3+√2)× (√3-√2)/(√3-√2) [ rationalizing it]

=(√3 -√2)²/1 = (√3 -√2)² = 5- 2√6

b= (√3+√2)/(√3-√2)×(√3+√2)/(√3+√2) [ rationalizing it]

= (√3+√2)²/1 =(√3+√2)² = 5+2√6

now, a²+b² - 5ab

= (5-2√6)² + (5+2√6)² - 5(5-2√6)(5+2√6)

=25 +24 -20√6 +25 +24 + 20√6 - 5(25-24)

=98 -5 = 93

Discussion

41.	Find the derivatives oflogtan³xsec⁴xe³
Answer» ONG>Answer: sec(E3*)4 is the answer of this QUESTION

Discussion

42.	The first and last term of a GP is 2 and 2048 respectively, the sum of the series is 2730. Find the number of terms and common ratio?
Answer» ong>ANSWER: I THINK you mean AP Step-by-step EXPLANATION: please TELL me so I will solve it

42.

The first and last term of a GP is 2 and 2048 respectively, the sum of the series is 2730. Find the number of terms and common ratio?

Answer»

ong>ANSWER:

I THINK you mean AP

Step-by-step EXPLANATION:

please TELL me so I will solve it

Discussion

43.	Find two parts of 15 such that the sum of their reciprocal is 3/10
Answer» the first PART be X. Then the other part will be 15-x. According to the *question* $\frac{1}{x} + \frac{1}{15 - x} = \frac{3}{10} \\ \frac{15 - x + x}{x(15 - x)} = \frac{3}{10} \\ \frac{15}{15x - {x}^{2} } = \frac{3}{10} \\ 150 = 3(15x - {x}^{2} ) \\ 50 = 15x - {x}^{2} \\ {x}^{2} - 15x + 50 = 0 \\ {x}^{2} - 5x - 10x + 50 = 0 \\ x(x - 5) - 10(x - 5) = 0 \\ (x - 5)(x - 10) = 0 \\ x = 5 \: or \: 10$ therefore the two required *PARTS* *are* 5 and 10 here is your answer :)

43.

Find two parts of 15 such that the sum of their reciprocal is 3/10

Answer»

the first PART be X. Then the other part will be 15-x.

According to the question

$\frac{1}{x} + \frac{1}{15 - x} = \frac{3}{10} \\ \frac{15 - x + x}{x(15 - x)} = \frac{3}{10} \\ \frac{15}{15x - {x}^{2} } = \frac{3}{10} \\ 150 = 3(15x - {x}^{2} ) \\ 50 = 15x - {x}^{2} \\ {x}^{2} - 15x + 50 = 0 \\ {x}^{2} - 5x - 10x + 50 = 0 \\ x(x - 5) - 10(x - 5) = 0 \\ (x - 5)(x - 10) = 0 \\ x = 5 \: or \: 10$

therefore the two required PARTS are

5 and 10

here is your answer :)

Discussion

44.	Solve for x minus 2 upon x minus 4 plus x minus 6 upon x minus 8 is equal to 6 2 by 3
Answer» ONG>Answer: 1 Step-by-step explanation: LIFE won’t GET EASIER. You just have to get stronger

44.

Solve for x minus 2 upon x minus 4 plus x minus 6 upon x minus 8 is equal to 6 2 by 3

Answer» ONG>Answer:

1

Step-by-step explanation:

LIFE won’t GET EASIER. You just have to get stronger

Discussion

45.	Find the principal value of sin -1 (1/2).
Answer» $\huge \fbox \green{Solution:-}$ ${sin}^{ - 1} ( \frac{1}{2} ) = \frac{\pi}{6} e \: \: \: \: \: \: [ - \frac{\pi}{2} , \frac{\pi}{2} ]$ HENCE The PRINCIPAL VALUE of ${sin}^{ - 1} ( \frac{1}{2} ) \: is \: \frac{\pi}{6}$ $\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

45.

Find the principal value of sin -1 (1/2).

Answer»

$\huge \fbox \green{Solution:-}$

${sin}^{ - 1} ( \frac{1}{2} ) = \frac{\pi}{6} e \: \: \: \: \: \: [ - \frac{\pi}{2} , \frac{\pi}{2} ]$

HENCE The PRINCIPAL VALUE of

${sin}^{ - 1} ( \frac{1}{2} ) \: is \: \frac{\pi}{6}$

$\\ \\ \\ \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}$

Discussion

46.	The number of multiples of 3 between18 and 54
Answer» ONG>Answer: 11 Step-by-step EXPLANATION: They are 21,24,27,30,33,36,39,42,45,48,51

46.

The number of multiples of 3 between18 and 54

Answer» ONG>Answer:

11

Step-by-step EXPLANATION:

They are

21,24,27,30,33,36,39,42,45,48,51

Discussion

47.	7 Reload ImagesA large square has side length 4. It is divided into four identical trapezoids and a smallsquare as shown. The small square has side length 1. The area of each trapezoid is4121230912QO 1514QEDESELECTSKIPo
Answer» ONG>Step-by-step explanation: 4AREA of TRAPEZIUM+ 1^2=4^2 4area of trapezium=16-1=15 area of trapezium=15/4

47.

7 Reload ImagesA large square has side length 4. It is divided into four identical trapezoids and a smallsquare as shown. The small square has side length 1. The area of each trapezoid is4121230912QO 1514QEDESELECTSKIPo

Answer» ONG>Step-by-step explanation:

4*AREA of TRAPEZIUM+ 1^2=4^2

4*area of trapezium=16-1=15

area of trapezium=15/4

Discussion

48.	If cos = 45 ,ℎ tan =
Answer» ONG>ANSWER: 3/4 Just WRITING this to MAKE my ANS 20 words long

48.

If cos = 45 ,ℎ tan =

Answer» ONG>ANSWER:

3/4

Just WRITING this to MAKE my ANS 20 words long

Discussion

49.	Write the equation when k is multiplired bu 3 and then subtract from 10
Answer» ONG>ANSWER: 10-3k Step-by-step EXPLANATION: This is the answer..

49.

Write the equation when k is multiplired bu 3 and then subtract from 10

Answer» ONG>ANSWER:

10-3k

Step-by-step EXPLANATION:

This is the answer..

Discussion

50.	1: If A = { 1 , 3 , 5 } and B = { 2 , 4 , -1 } , then find A × B and B × A . Find the number of elements in A × B & B × A 2:(a) If A= {-1, 3, 6} and B = {-3, 5} then find A × B and B × A. Also draw the graphs of the cartesian products.(b) If A = {2, 4} , B = {-1, 3, 7} , C = {1, 0} then with the help of three diagrams find A × B, B × A and A × B × C.♡︎♥︎ Spam = Report ♥︎♡︎
Answer» CORRECT answer Hope it's HELPFUL ✌️✌️ $\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}$ $\huge\underline\purple{\underline {Follow\:Me}}$

50.

1: If A = { 1 , 3 , 5 } and B = { 2 , 4 , -1 } , then find A × B and B × A . Find the number of elements in A × B & B × A 2:(a) If A= {-1, 3, 6} and B = {-3, 5} then find A × B and B × A. Also draw the graphs of the cartesian products.(b) If A = {2, 4} , B = {-1, 3, 7} , C = {1, 0} then with the help of three diagrams find A × B, B × A and A × B × C.♡︎♥︎ Spam = Report ♥︎♡︎

Answer» CORRECT answer

Hope it's HELPFUL ✌️✌️

$\huge\color{red}\boxed{\colorbox{black}{please\:mark\:me\: brilliance}}$

$\huge\underline\purple{\underline {Follow\:Me}}$

Discussion

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