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Find the HCF of the following numbers byprime factorization methods (i) 80 and 120 |
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Answer» ER: Step-by-step EXPLANATION: FACTORS of 80 = 2× 2× 2× 2× 5 = 2⁴ × 5 Factors of 120 = 2× 2× 2× 3× 5 = 2³× 3 × 5
HCF = 2³ × 5 = 2× 2× 2× 5 = 40 |
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