This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
Convert the following rational numbers into decimal form.(1) 8/13 (2) 11/7 (3) 5/16 (4) 7/9 |
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Answer» Step-by-step explanation: Given Convert the FOLLOWING rational numbers into decimal form.(1) 8/13 (2) 11/7 (3) 5/16 (4) 7/9 Now we need to convert these rational numbers to its decimal form. So we need to divide these numbers. 8/13 will be 13) 8 (0.615 0 ------ 80 ---------- 13 --------------- 70 65 ----------- 5 So we get 0.615. 2) In the same way if we divide 11/7 we get 1.571 3) So the third will be 5/16 we get 0.3125 4) Again if we divide 7/9 we get 0.777 So it is converted to decimal form. 1) 8/13 = 0.615 2)11/7 = 1.571 3)5/16 = 0.3125 4)7/9 = 0.777 |
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| 2. |
If a pizza is divided in 12 pieces and 8 pieces are eaten ,what is the ratio fo remaining?? |
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Answer» The RATIO will be 1:4 |
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| 3. |
Factorise 4 square + 9 b square + 9 c square + 12 ab+ 4ac + 6 bc |
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| 4. |
In triangle ABC ,p and Q are the mid points of sides ab and AC respectively as shown in the figure. R and s are mid points of PC and on respectively. Prove that bq and SR bisect each other |
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Answer» ?tjwfmegmfmwrb |
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| 5. |
In the given figure sides QP and RQ of ∠PQR are produced to points S and T respectively. If ∠SPR=135° and ∠PQT=110°, find ∠PRQ. |
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Answer» ANSWER is 65° PLEASE MARK as BRAINLIEST |
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| 6. |
∆ABC right angled at B and D is the midpoint of BC .prove AC2=4AD2-3AB2 |
| Answer» HENCE PROVED ................ | |
| 7. |
In the given figure, ∠X=62°, ∠XYZ=54°. In ΔXYZ If YO and ZO are the bisectors of ∠XYZ and ∠XZY respectively find ∠OZY and ∠YOZ. |
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Answer» YXZ +XYZ + XZY =180° 62° +54° +XZY = 180° XZY=180°-62°-54° XZY =64° 2OZY =64° OZY=64°/2=32°..................(1) in the OZY OYZ +OZY +YOZ = 180° 54°/2 +32° +YOZ = 180° YOZ = 180°- 32° - 27° YOZ =121°...............(2) |
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| 8. |
The greatest number which divides 106 241 and 286 leaving the same remainder in each case is |
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Answer» If a number 'a' and a number 'b' are DIVISIBLE by a number 'n' then, a+b and a-b is also divisible by n |
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| 9. |
If E, F G and H are respectively the midpoints of the sides AB, BC, CD and AD of a parallelogram ABCD, show that ar(EFGH)=1/2ar(ABCD). |
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Answer» Given that ABCD is a parallelogram . |
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| 10. |
digits of a two digit number differ by 7 if the digits are interchanged and the resulting number is added to the original number we get 121 find the original number |
| Answer» PLS FOLLOW me BECOZ I have answered UR question | |
| 11. |
Can converse of bpt can be use? |
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Answer» Yes my friend we can USE CONVERSE of B.P.T THEOREM. Take the answer. I have answered your question so pls FOLLOW me |
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| 12. |
A shopkeeper offers 10% off season discount to the customers and still makes a profit of 26% what is the cost price for the shopkeeper of a pair of shoes marked at rupees 1120 |
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Answer» Given, D% = 10% on MP P% = 26% Now, SP = MP-MP*D%/100 SP = 1120 - (1120*10)/100 SP = 1120 - 112 SP = Rs. 1008 And, P% = 26% CP = SP*100/(100+26) CP = 1008*100/126 CP = Rs. 800 Is that the right answer? |
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| 13. |
All red face cards are removed from a pack of playing cards.The remaining cards are well shuffled and then a card is drawn at random from them . Find the probability that the card drawn is a card of clubs. |
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Answer» Answer: Probability that the card drawn is a card of clubs = 13/46 Step-by-step explanation: There are 12 face cards in TOTAL in PACK of 52 cards. The total NUMBER of red face cards = 6 When all red face cards are removed from a pack of playing cards, the remaining cards = 52 - 6 = 46 In remaining 46 cards , total card of clubs = 13 Thus, the probability that the card drawn is a card of clubs = A/B where, A = total card of clubs in remaining cards B = total remaining cards in the pack => probability that the card drawn is a card of clubs = 13/46 |
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| 14. |
Quadrilateral BEST with BE=2.9cm,ES=3.2cm,ST=2.7 cm , BT=3.4 cm and angle B=75degree |
| Answer» DRAW a LINE BE=2.9cm . CONSTRUCT angle B =75 degree. draw an arc of 3.4cm as T from B.from E draw arc of 3.2cm and from T draw an arc of 2.7cm as S . done | |
| 15. |
Quadrilateral PQRS PQ = 4.2 cm, QR = 3 cm, PS = 2.8 cm, PR = 4.5 cm andQS = 5 cm. |
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Answer» HEYA.. Here is your ANSWER... |
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| 17. |
if a and b are two positive integer such that the least prime factor of a is 3 and the least prime factor of b is 5 then calculate the least prime factor of (a+b) |
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Answer» Given thet a and B are two POSITIVE integers. |
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| 18. |
Given an=4 d=2 sn=-14 finad na and a |
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Answer» The VALUE of N is 7 |
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| 19. |
Find each of the following products 5) (-15)×0×(-18) |
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Answer» It`s because if we MULTIPLY any no. with 0 then the answer will ALWAYS be 0 OK BRO. |
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| 20. |
Write all postulates of Euclid |
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Answer» 1.A STRAIGHT line MAY be drawn between any two points. |
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| 21. |
Given a=8 an=62 sn=210 find n and d |
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Answer» Hey mate your answer is in IMAGE and FIRST you use the FORMULA of Sn=n/2(a+an) and you GET n=6 then you use the formula of an =a+(n-1)d then you get d=54/5. |
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| 22. |
Given d=5 s9=75 find a and a9 |
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Answer» Hope u like my process |
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| 23. |
Do no. iiSolve for x |
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Answer» We know that, |
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| 24. |
Find the height of the cylinder whose volume is 1.54m and diameter of the base is 140 cm |
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Answer» |
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| 25. |
What will be the unit digit of the square of the following number 1234 |
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Answer» 1234*1234=15,22,756 |
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| 26. |
Please solve it fast it is very urgent |
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Answer» CONSIDER an isosceles triangle ABC having AD as the median and AB = AC. Given AD is the median. ⇒ BD = DC In Δ ABD and Δ ADC, we have AB = AC BD = DC and AD = AD Therefore, Δ ABD Δ ADC [SSS property] ⇒ ∠1 = ∠2 [cpct] HENCE, the median from the vertex of an isosceles triangle is the bisector of the vertical ANGLE. |
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| 27. |
A hemispherical bowl has diameter 9 cm. The liquid is poured into cylindrical bottles of diameter 3 cm. and height 3 cm. If a full bowl of liquid is filled in the bottles, find how many bottles are required. |
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Answer» GIVEN : For HEMISPHERE: Diameter = 9cm Radius (R)= 9/2 = 4.5 cm For cylinder : Diameter = 3 cm Radius (r)=3/2 = 1.5 cm Height (h)=3cm Let the no. of Cylindrical bottles = x ATQ VOLUME of hemisphere = Volume of cylinder × x No. of Cylindrical bottles =Volume of hemisphere/Volume of cylinder No. of Cylindrical bottles = 2/3πR³ / πr²h No. of Cylindrical bottles = 2/3π(4.5)³ /π(1.5)² × 3 No. of Cylindrical bottles = 2/3× (4.5)³ / (1.5)² X 3 x = 2× 1.5 × 4.5 × 4.5 / 1.5 × 1.5 × 3 x = 2 × 4.5 = 9 x= 9 Hence, the no. of Cylindrical bottles required = 9. HOPE THIS WILL HELP YOU... |
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| 28. |
Find the area in rectangular metres of a piece of cloth 1m 25cm wide and 4m long |
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Answer» Hey!! |
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| 29. |
The height of a tent is 9 m. Its base diameter is 24 m. What is its slant height? Find the cost of canvas cloth required if it costs Rs.14 per sq.m. |
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Answer» Heya !! |
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| 30. |
The average weight of a group of 53 girls was calculated as 58 kg.it was later discovered that the weight of one of the girls was read as 65 kg, whereas her actual weoght was 45 kg.what is the actual average weight of the group of 53 girls |
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Answer» Here is UR answer |
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| 31. |
31+(-23)-35+18-4-(-3) |
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Answer» HELLO MATE ☺ |
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| 32. |
Solve 12×13×7 by nikhilam sutra. please do it quickly |
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Answer» BASE 10 12. +2 13. +3 7. -3 12+3-3. / (2 x 3 ) + ( 3x3) + ( 2 x -3 ) / 2x3x-3 12. / 6. + 9 . + -6. / -18 12. / 15-6 / . -18 12. - 2 / 9. / 20-18 10 / 9 / 2 1092 ans |
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| 33. |
the base and hypotenuse of a right angled triangle are respectively 5cm, and 13cm long. find its area. By herons formula |
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Answer» By PHYTHAGORAS theorem |
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| 34. |
In the adjacent figure, if ∠1=∠3,∠2 =∠4 and ∠3=∠4, write the relation between∠1 and ∠2 using an Euclid’s postulate. |
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Answer» ∠1= ∠3= ∠4 =∠2 |
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| 35. |
In the given figure if line segments PQ and RS intersect at point T, such that ∠PRT=40°, ∠RPT=95° and ∠TSQ=75°, find ∠SQT. |
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Answer» Here is your answer |
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| 36. |
cost of one dozen oranges is rupees 45 A)find the cost of one score oranges B) how many oranges can purchase for rupees 60 |
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Answer» Hi There! _________________________________________ One Dozen = 12 units Now, 1 Dozen of Oranges = 45 rupees Means, 12 Oranges = 45 rupees By, UNITARY Method, we have 12*x = 45 x = 45/12 x = 3.75 Means, Cost Of 1 Orange is RS. 3.75 Now, For 1 score of Oranges i.e 20 oranges = 3.75*20 = Rs. 75 B) TOTAL Rs. With us = 60 1 Orange = Rs. 3.75 x Oranges = Rs. 60 Rs. 60 = (3.75)x Rs. 60 / 3.75 = x 16 = x Therefore, We Will Get 16 Oranges For Rs. 60 ____________________________________________ Thanks! Hope This Helps! #Ben4Brainly |
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| 37. |
Which ratio is greater in 6:11 or 9:14 |
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Answer» Convert them into fractions.
Let's cross multiply. 6 x 14 , 9 x 11 84 , 99 84 < 99 6 x 14 < 9 x 11 6 : 11 < 9 : 14 Hope this MAY be helpful. Please mark my ANSWER as the BRAINLIEST if this may be helpful. Thank you. Have a nice day. |
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| 38. |
Identify the variation and solve. It takes 5 hours to travel from one town to the other if speed of the bus is 48 km/hr. If the speed of the bus is reduced by 8 km/hr, how much time will it take for the same travel? |
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| 39. |
Integrate sin2x . cos 3x .dx |
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Answer» HELLO! ! ! HEY my dear friend here is your ANSWER ___________ I have given your answer in above pic. check it out.... _________________ HOPE THIS ANSWER WILL HELP U.... @Neha |
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| 40. |
X+1/x=2 then x10+1/x10= |
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Answer» X+1/x=2 |
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| 41. |
739×99-(-739) in distributive property |
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Answer» 739×99-(-739) =739×99-739×(-1) =739×(99-(-1)) =739×(99+1) =739×100 =73900 |
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| 42. |
Express the HCF of 48 and 18 as a linear combination |
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Answer» Answer: Step-by-step explanation: According to the QUESTION A=bq +r , 48= 18x2+12 18=12x1+6 12=6x2+0 Therefore the HCF can be (18,68) That is =6 6=-18-12x1 6= 18- (48-18x12) 6= 18-48x1+18x2 6=18x3-48x1 Therefore......,............6=18x+18y 6=13x3 +48x(-1) That is 18 x3+48(-1)+18x48-18x48 6=18x+48 ____________________________________________________________ Hope it helps |
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| 43. |
1) In a caravan, in addition to 50 hens there are 45 goats and 8 camels with some keepers. If the total number of feet be 224 more than the number of heads, find the number of keepers.2) In a family, the father took 1/4 of the cake and he had 3 times as much as each of the other members had. The total number of family members are? |
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Answer» 1)Let the number of keepers be x. Then, total number of feet = 2*50+4*45+4*8+2x = 2x + 312 Total number of heads = 50+45+8+x = 103 + x Now, (2x+312) = (103+x)+224 => x = 15 2)Let the family members b x. Father ate 1/4 of the cake; Rest members GOT 3/4X, the father had 3 times more than other members share i.e 3/4, Now, 3(3/4x) = 1/4, 3/4x = 1/12, 36 = 4x, X = 9, 9 + 1(father) = 10 total family member. |
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| 44. |
If a1,a2,a3,..........are in ap such that a1+a5+a10+a15+a20+a24=225, then a1+a2+a3+..........a23+a24 is |
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Answer» A1 + a5 + a10 +a15 + a20 + A24 = 225 (given) |
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| 45. |
Sin.sin 38+cos.cos38= |
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Answer» Sin² 38° + COS ² 38° = 1 will be the ANSWER |
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| 46. |
Find the smallest number of 4digit which divisible by 18,24,32 |
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Answer» You SEE that 18,24,32 have 2 as a COMMON factor so you could find the smallest 4DIGIT number divisible by 2 |
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| 48. |
find the greatest 5 digit number which when divided by 5 10 15 20 and 25 leaves a remainder 4 in each case |
| Answer» 5,10,15,20,25 all have HCF 5 so you find a 4digit which LEAVE 4 when divided by 5 | |
| 49. |
Samikaran x square - 3 under root x + 2 equal to zero |
| Answer» ROOT3(+_)5i/2will be the CORRECT ANSWER acording to me.. | |