332354 + Interview Questions in Secondary School in Math

1.	write application 2 days leave to your principal . hint Mera tabiyat kharab hai doctor ne mujhe rest karne ko kaha hai
Answer» To The Principal .................................(school) ..........................(address) .......................(city) Date. .................. SUBJECT- leave for two days Respected sir, I would like to INFORM you that these days i am not able to COME to school because i am not well and the doctor has said to rest atleast two to THREE days. so i wanted a two day leave from......... 2018 to......... 2018.I hope you will admire my request. I will be thankful for you kindness Your Sincerely .....................(name)

Discussion

2.	In the adjacent figure, we have BX=1/2 AB, BY =1/2BC and AB=BC. Show that BX=BY
Answer» $\text{[math]}$ $Answer :$ Given, AB = BC … (i) And BX = 1/2 AB and BY = 1/2 BC … (ii) By Euclid’s AXIOM 7, $We know that things which are halves of the same thing are equal to one another.$ From (i) and (ii), ∴ BX = BY

Discussion

3.	A worker is paid ₹210 for 6 days.if his total income of month is ₹875, for how many days he work
Answer» 25 DAYS is the ANS. 1 DAY =35rs

3.

A worker is paid ₹210 for 6 days.if his total income of month is ₹875, for how many days he work

Answer»

25 DAYS is the ANS.

1 DAY =35rs

Discussion

4.	Simplify (x2-11x-80)➗ (16-x)
Answer» -9x-80 DIVIDED by 16 -x -9x-80 16-x -9multiply by 5 -45

Discussion

5.	Find the edge of a cube of volume 10.648m cube
Answer» HEYA !! VOLUME of CUBE = 10.648 (EDGE)³ = 10.648 Edge = ³✓10.648 Edge = 2.2 m Hence, Edge of cube = 2.2 m Hope it will HELP you :-)

Discussion

6.	In the given figure if PQ⊥PS, PQ\|\|SR,∠SQR=28° and ∠QRT=65°, then find the values of x and y.
Answer» X=37 y=53 we can FIND x by using the a.i.a PROPERTY and y using angle sum property

Discussion

7.	Archana baught 10 g of gold fo 32376 including 14% tax. Finf rate of gold per 10g.
Answer» $cp = 32376 \\ tax = 14\% \\ rate \: of \: gold \: = \frac{32376 \times 100}{114} \\ rate \: of \: gold = 28400$

Discussion

8.	A rectangular carpet has an area of 60 sq. m. Its diagonal and longer side together equal 5 times the shorter side, The length of the carpet is ?
Answer» SENDING you WRITTEN SOLUTION

Discussion

9.	If angle A is congruent to angle B then prove that line L is parallel to line M.
Answer» ANGLE A and angle B are congruent lineL is \|\| LINE M ••••• ALTERNATE angle

Discussion

10.	The shape of a farm is a quadrilateral. Measurements taken of the farm, by naming its corners as P, Q, R, S in order are as follows. l(PQ) = 170 m, l(QR)= 250m, l(RS) = 100 m, l(PS) = 240 m, l(PR) = 260 m.Find the area of the field in hectare ( 1 hectare =10,000 sq.m)
Answer» Solution :- PQRS is a quadrilateral. PQ = 170 m, QR 250 m, RS = 100 m, PS = 240 m, PR = 260 m This question will be solved through Heron's formula of area of TRIANGLE. There are two triangles in the quadrilateral PQRS. These are Δ PQR and Δ PSR In Δ PQR, PQ = 170 m, QR = 250 m and PR = 260 m Semi perimeter (s) = (a + b + c)/2 (170 + 250 + 260)/2 ⇒ 680/2 s = 340 m Area of triangle PQR = √340(340 - 170)(340 - 250)(340 - 260) ⇒ √3401709080 ⇒ √416160000 ⇒ 20400 sq m In Δ PSR, SR = 100 m, PS = 240 m and PR = 260 m S = (a + b + c)/2 ⇒ (100 + 240 + 260)/2 ⇒ 600/2 ⇒ 300 m Area of triangle Δ PSR = √(300)(300 - 100)(300 - 240)(300 - 260) ⇒ √3002006040 ⇒ √144000000 = 12000 sq m Area of the quadrilateral PQRS = Area of Δ PQR + Area of Δ PSR ⇒ 20400 + 12000 = 32400 sq m Area in hectares = 32400/10000 = 3.24 hectares Answer.

10.

The shape of a farm is a quadrilateral. Measurements taken of the farm, by naming its corners as P, Q, R, S in order are as follows. l(PQ) = 170 m, l(QR)= 250m, l(RS) = 100 m, l(PS) = 240 m, l(PR) = 260 m.Find the area of the field in hectare ( 1 hectare =10,000 sq.m)

Answer»

Solution :-

PQRS is a quadrilateral. PQ = 170 m, QR 250 m, RS = 100 m, PS = 240 m, PR = 260 m

This question will be solved through Heron's formula of area of TRIANGLE.

There are two triangles in the quadrilateral PQRS.

These are Δ PQR and Δ PSR

In Δ PQR,

PQ = 170 m, QR = 250 m and PR = 260 m

Semi perimeter (s) = (a + b + c)/2

(170 + 250 + 260)/2

⇒ 680/2

s = 340 m

Area of triangle PQR = √340*(340 - 170)*(340 - 250)*(340 - 260)

⇒ √340*170*90*80

⇒ √416160000

⇒ 20400 sq m

In Δ PSR,

SR = 100 m, PS = 240 m and PR = 260 m

S = (a + b + c)/2

⇒ (100 + 240 + 260)/2

⇒ 600/2

⇒ 300 m

Area of triangle Δ PSR = √(300)*(300 - 100)*(300 - 240)*(300 - 260)

⇒ √300*200*60*40

⇒ √144000000

= 12000 sq m

Area of the quadrilateral PQRS = Area of Δ PQR + Area of Δ PSR

⇒ 20400 + 12000

= 32400 sq m

Area in hectares = 32400/10000

= 3.24 hectares

Answer.

Discussion

11.	Dev borrowed a sum of rupees 2050 from a company at the rate of 8% per annum compound interest for 2 years find the amount he has to pay
Answer» Your ANSWER is in the ATTACHMENT.

Discussion

12.	the exterior angle of a regular polygon is 1/3 of its interior anglehow many sides does the polygon has
Answer» 3x+x =4x so 4x=180 so x=45 no of SIDES are=360/45 =8 sides hence it is OCTAGON

12.

the exterior angle of a regular polygon is 1/3 of its interior anglehow many sides does the polygon has

Answer»

3x+x =4x

so 4x=180

so x=45

no of SIDES are=360/45

=8 sides

hence it is OCTAGON

Discussion

13.	3x+4y=7, Find three different solutions for the given equation.
Answer» $\bold{Answer :}$ The given equation is 3x + 4y = 7 We TAKE x = 1, y = 1 Then, 3 (1) + 4 (1) = 3 + 4 = 7 Thus, x = 1, y = 1 be a SOLUTION Let, x = 0 Then, 3 (0) + 4y = 7 or, 4y = 7 or, y = 7/4 Thus, a solution be x = 0, y = 7/4 Let, y = 0 Then, 3x + 4 (0) = 7 or, 3x = 7 or, x = 7/3 Thus, another solution be x = 7/3, y = 0 Hence, the three solutions are x = 1, y = 1 x = 7/3, y = 0 x = 0, y = 7/4 # $\bold{MarkAsBrainliest}$

Discussion

14.	In the adjacent figure AB\|\|CD; CD\|\|EF and y:z =3:7, find x.
Answer» Step-by-step explanation: Given In the adjacent figure AB\|\|CD; CD\|\|EF and y:Z =3:7, find x. Given y/z = 3/7 Also CD is parallel to EF Let the centre point be O so that it is COD Also let a point be M in between E and F and a point P in between C and D Let angle COM = p Therefore p = z (since alternate interior angles) Now y + p = 180 degree And y + z = 180 (since p = z) We have y = 3/7 z, so we get So 3/7 z + z = 180 Or 3z + 7z / 7 = 180 10 z / 7 = 180 Or 10 z = 180 x 7 Or z = 126 degree So y = 3/7 z Or y = 3/7 x 126 Or y = 54 degree. Now we need to find x. So AB is parallel to CD, also RS is the transversal So we have sum of interior angles on the same side of transversal is supplementary. Therefore x + y = 180 Or x + 54 = 180 Or x = 180 – 54 Or x = 126 degree Reference link will be brainly.in/question/14168375

14.

In the adjacent figure AB||CD; CD||EF and y:z =3:7, find x.

Answer»

Step-by-step explanation:

Given In the adjacent figure AB||CD; CD||EF and y:Z =3:7, find x.

Given y/z = 3/7
Also CD is parallel to EF
Let the centre point be O so that it is COD
Also let a point be M in between E and F and a point P in between C and D
Let angle COM = p
Therefore p = z (since alternate interior angles)
Now y + p = 180 degree
And y + z = 180 (since p = z)
We have y = 3/7 z, so we get
So 3/7 z + z = 180
Or 3z + 7z / 7 = 180
10 z / 7 = 180
Or 10 z = 180 x 7
Or z = 126 degree
So y = 3/7 z
Or y = 3/7 x 126
Or y = 54 degree.
Now we need to find x.
So AB is parallel to CD, also RS is the transversal
So we have sum of interior angles on the same side of transversal is supplementary.
Therefore x + y = 180
Or x + 54 = 180
Or x = 180 – 54
Or x = 126 degree

Reference link will be

brainly.in/question/14168375

Discussion

15.	alice has a box that contains 12 marbles consisting of 4 green ones 4 yellow ones and 4 blue ones. if alice was in a dark room and she had to pick them at random how many marbles must she take out so as to pick out at least 2 of one color?
Answer» The PROBABILITY of getting at least two marbles of same color : YELLOW : 2/12 or 3/12 or 4/12 1/6 + 1/4 + 1/3 = 9/12 Blue : 2/12 or 3/12 or 4/12 9/12 Green: 2/12 or 3/12 or 4/12 9/12 3/4 × 3/4 × 3/4 = 27/64 27/64 × 12 = 5 1/16 Taking the WHOLE PART : We have FIVE.

Discussion

16.	50 paise convert into rupees
Answer» 1/2 RUPEES or 0.5 rupees . PLS MARK BRAINLIEST

Discussion

17.	Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.
Answer» given SIDES are 8.5cm and 11.5cm and HEIGHT = 4.2cm so area of trapizum =1/2(sum of parallel sides)height =1/2(11.5+8.5)4.2 =1/2204.2 =42cm square is UR answer please pu me in brainlist

17.

Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.

Answer»

given SIDES are 8.5cm and 11.5cm

and HEIGHT = 4.2cm

so area of trapizum

=1/2*(sum of parallel sides)*height

=1/2*(11.5+8.5)*4.2

=1/2*20*4.2

=42cm square is UR answer

please pu me in brainlist

Discussion

18.	The abscissa of a point positive in ____________ and __________ quadrants.
Answer» IST and IVTH QUADRANTS

Discussion

19.	Without using the distance formula show that the points A(4,-2),B(-4,4) and C(10,6) are the vertices of a right angled triangle
Answer» SLOPE=(y2-y1)/(x2-x1) slope of AB=(4-(-2))/(-4-4)=-(6/8)=-(3/4) slope of BC=(6-(4))/(10-(-4))=(2/14)=(1/7) slope of CA=(-2-6)/(4-10)=(8/6)=(4/3) slope of AB * slope of CA=-(3/4)*(4/3)=-1 so AB is perpendicular to CA thus,ABC are the vertices of a right ANGLED triangle.

19.

Without using the distance formula show that the points A(4,-2),B(-4,4) and C(10,6) are the vertices of a right angled triangle

Answer»

SLOPE=(y2-y1)/(x2-x1)

slope of AB=(4-(-2))/(-4-4)=-(6/8)=-(3/4)

slope of BC=(6-(4))/(10-(-4))=(2/14)=(1/7)

slope of CA=(-2-6)/(4-10)=(8/6)=(4/3)

slope of AB * slope of CA=-(3/4)*(4/3)=-1

so AB is perpendicular to CA

thus,ABC are the vertices of a right ANGLED triangle.

Discussion

20.	Use H.C.F to show that 357 and 1625 are co-primes
Answer» HCF (357,1625) = 1 357 = 3717 1625 = 555*13 GIVEN NUMBERS ARE SAID TO BE CO-PRIME IF THE ONLY POSITIVE INTEGER DIVIDING THEM IS 1 AS WE CAN SEE THE ONLY COMMON DIVISOR OF 357 AND 1625 IS 1, THUS THEY ARE CO - PRIMES.

20.

Use H.C.F to show that 357 and 1625 are co-primes

Answer»

HCF (357,1625) = 1

357 = 3*7*17

1625 = 5*5*5*13

GIVEN NUMBERS ARE SAID TO BE CO-PRIME IF THE ONLY POSITIVE INTEGER DIVIDING THEM IS 1

AS WE CAN SEE THE ONLY COMMON DIVISOR OF 357 AND 1625 IS 1, THUS THEY ARE CO - PRIMES.

Discussion

21.	(1001)³,Evaluate it using suitable identites.
Answer» Hey MATE here is your ANSWER.... (1001)^3 (1000+1)^3 1000^3+31000^21+310001^2+1^3 1000000000+31000000+31000+1 1000000000+3000000+3000+1 ans-1003003001

Discussion

22.	Factorise 343x3-729y3 solve on a page and send to me
Answer» 343x³ - 729y³ (7X)³ - (9Y)³ = (7x - 9y) (49x² + 63xy + 81y²)

Discussion

23.	in figure 9.75 ABCD and AEFG are two parallelogram if angle C is equal to 55 degree determine angle f.
Answer» PIC have the SOLUTION

Discussion

24.	Name the southern neighbours of India
Answer» Dear mate, Your ANSWER is Sri LANKA and the Maldives ....PLEASE MARK MY ANSWER AS BRAINLIEST. PLEASE

Discussion

25.	(sec theta +cosec theta) (sin theta +cos theta ) = 2+ sec theta cosec theta
Answer» Here is your answer hope it HELP you....

Discussion

26.	If the school bag of neelam and garima weight 6kg80g and 5kg 265 g whose bag is heavier and how much
Answer» NEELAM BAG is HEAVIER than grami bag

Discussion

27.	The sum of two numbers is 90. One third of the larger number is 9 more than twice the smaller number. What are the smaller numbers?
Answer» Hope this ANS will HELP...if uh LYK it mark as Brainilist ans

Discussion

28.	Multiples of 19 between 57 and 152___________
Answer» HEY ......here is your answer. Multiples of 19 between 57 and 152 are: •76 •95 •114 •133 Hope it HELPS you. Please mark it as brainliest.

Discussion

29.	The difference between two whole numbers is 66 .the ratio of the two numbers is2:5 find the numbers
Answer» TWO whole NUMBERS are in the ration of 2:5. If their DIFFERENCE is 66, FIND the whole numbers. Since the whole numbers are in the ratio 2:5, Let the whole numbers be 2x, 5x. Difference between the whole numbers is 66. Thus, 5x - 2x = 66 3x = 66 x = 22 Thus the whole numbers are : 222, 5*22 i.e, 44,110.

Discussion

30.	If ( x-1/x )=5, find the value of (i) x2+1/x2) and (ii) (x4+1/x4)
Answer» ( x - 1/x ) = 5 SQUARE on both SIDES, ( x - 1/x )² = 5² => x² + 1/x² - 2 = 25 => x² + 1/x² = 27 [ 1 answer ] Again square on both sides, => ( x² + 1/x² )² = 27² => x⁴ + 1/x⁴ + 2 = 729 => x⁴ + 1/x⁴ = 727 $.$

Discussion

31.	Find the radius of a circle whose area is 616 cm square
Answer» ANSWER: Step-by-step EXPLANATION: Area=πr^2=616 Solve the above EQUATION, you will GET radius=14cm

31.

Find the radius of a circle whose area is 616 cm square

Answer»

ANSWER:

Step-by-step EXPLANATION:

Area=πr^2=616

Solve the above EQUATION,

you will GET radius=14cm

Discussion

32.	If the surface area of cube is 486 cm square.find the length of a diagonal and volume of a cube
Answer» I HOPE it will HELP you

Discussion

33.	Find the equivalent fraction of 7 by 9..... A) numerator 63=? B) denominator 18=?
Answer» A)7×9/9×9= 63/81 b)7×2/9×2=14/18 here is your ANSWER PLEASE MARK me as BRAINLIEST

Discussion

34.	In ΔABC,∠ABC=90° , AD=DC, AB=12 cm and BC=6.5 cm. Find the area of ΔADB.
Answer» It is given that , In ∆ABC , AD = DC , AB = 12 CM , BC = 6.5 cm ∆ADB = ( 1/2 )∆ABC [ SINCE AD is a MEDIAN of ∆ABC ] = ( 1/2 )[ (1/2)× AB × BC ] = 1/4 × 12 × 6.5 = 19.5 cm² Therefore , Area of ∆ADB = 19.5 cm² ••••

Discussion

35.	Expand (x - y)³( Using Identities).
Answer» HI FRIEND here is your ANSWER ------------ ${(x -y}^{)3} = {x}^{3} - 3x {}^{2} y + 3xy ^{2} - y ^{3}$

Discussion

36.	Find the square root of 12+5i
Answer» I THINK it will HELP you

Discussion

37.	A handbag was sold for 765 and the loss was 15%. Find the profit or loss per cent , if it was sold for 819.
Answer» You must use the formula of LOSS PERCENT THANKS it will help you

Discussion

38.	Find the zero of the polynomial p(x)=8x-7
Answer» 8x-7=0 8x=7 x=7/8.......

Discussion

39.	Can anyone pls solve this??
Answer» Hey FRND here is UR ANS.... TanA+tanB/cotA+cotB = tanAtanB LHS,,, tanA+tanB/1/tanA+1/tanB (tanA+tanB)/(tanA+tanB/tanAtanB) (tanA+tanB)/(tanAtanB/tanA+tanB) tanAtanB ..... Hence proved. Hope it HELPS youʕ•ٹ•ʔ✌✌ Thankyou☺☺ Arya❤

Discussion

40.	A metallic cylinder of diameter 5 cm. and height 3*1/3 cm. is melted and cast into a sphere.What is its diameter.
Answer» GIVEN : Diameter of the metallic cylinder(d) = 5 cm Radius(R) = d/2 = 5/2 = 2.5 cm Height of the metallic cylinder(h) = 3 1/3 cm = 10/3 cm Let radius of SPHERE is r cm. The metallic cylinder is melted and CAST into a sphere. So, the VOLUME of the metallic cylinder and the sphere will be same. Volume of the metallic cylinder =Volume of sphere πR²h = 4/3πr³ π× 2.5× 2.5×10/3 = 4/3×π× r³ 6.25 × 10 = 4r³ r³ = 62.5/4 r³ = 15.625 r =³√15.625 r = 2.5 Radius of sphere is 2.5 cm Diameter of the sphere = radius × 2 = 2.5× 2 = 5 cm Hence ,the Diameter of the sphere = 5 cm. HOPE THIS WILL HELP YOU..

40.

A metallic cylinder of diameter 5 cm. and height 3*1/3 cm. is melted and cast into a sphere.What is its diameter.

Answer»

GIVEN :

Diameter of the metallic cylinder(d) = 5 cm

Radius(R) = d/2 = 5/2 = 2.5 cm

Height of the metallic cylinder(h) = 3 1/3 cm = 10/3 cm

Let radius of SPHERE is r cm.

The metallic cylinder is melted and CAST into a sphere. So, the VOLUME of the metallic cylinder and the sphere will be same.

Volume of the metallic cylinder =Volume of sphere

πR²h = 4/3πr³

π× 2.5× 2.5×10/3 = 4/3×π× r³

6.25 × 10 = 4r³

r³ = 62.5/4

r³ = 15.625

r =³√15.625

r = 2.5

Radius of sphere is 2.5 cm

Diameter of the sphere = radius × 2 = 2.5× 2 = 5 cm

Hence ,the Diameter of the sphere = 5 cm.

HOPE THIS WILL HELP YOU..

Discussion

41.	What is the value of k in the polynomial x2 +8x +k if -2 is a zero of the polynomial?
Answer» If , (-2) is zero of polynomial then it will satisfy the EQN ${x}^{2} + 8x + k \\ {( - 2)}^{2} + 8( - 2) + k = 0 \\ 4 - 16 + k = 0 \\ k = 12$ MARK as brainliest if HELPED

Discussion

42.	If two triangles are similar then their corresponding angles must be
Answer» Then their ANGLE are CONGRUENT

Discussion

43.	A square park of side 50 m a path of width 2.5 m runs around the garden inside it area of the path ?
Answer» MARK me as the BRAINLIEST if you LIKE my ANSWER

Discussion

44.	Is it possible to design a rectangular park of 80m and 400m ? If so, find its length and breadth
Answer» HOPE it HELPS you out

Discussion

45.	Factorise (2a-b-c)3 +(2b-c-a)3 +(2c-a-b)3
Answer» I am not able to answer this QUESTION if u SEE the IMAGE then PLZ comment me

Discussion

46.	If one root of 5x²+13x+k= 0 is the reciprocal of tha other root,then find value of k.
Answer» the EQ. is 5x^2+13x+k=0 general form of quadratic eq. is x^2 +(SUM of roots)x+(product of roots)=0 divide given eq. by 5 therefore, x^2+13/5x+k/5=0 let the roots be y & 1/y (one ROOT is RECIPROCAL of other) therefore, product of roots= y*1/y=k/5 so,k=5

46.

If one root of 5x²+13x+k= 0 is the reciprocal of tha other root,then find value of k.

Answer»

the EQ. is 5x^2+13x+k=0

general form of quadratic eq. is x^2 +(SUM of roots)x+(product of roots)=0

divide given eq. by 5

therefore, x^2+13/5x+k/5=0

let the roots be y & 1/y (one ROOT is RECIPROCAL of other)

therefore, product of roots= y*1/y=k/5

so,k=5

Discussion

47.	Express (4x- 3\2x+1-10(2x+1\4x-3)=3,(xnot equa to -1\2 x not equal to 3\4
Answer» Here is your ANSWER.... HOPE this HELPS you...

Discussion

48.	the sum of the ages of a boy and his brother is 25 years and the product of their ages is 126. find their ages?
Answer» Let ths AGE of boy be ( X ) years and age of his brother be ( 25 - x ) years Product of their AGES = 126 => x ( 25 - x ) = 126 => 25x - x² = 126 => x² - 25x + 126 = 0 => x² - 18x - 7x + 126 = 0 => x( x - 18 ) - 7( x - 18 ) = 0 => ( x - 18 ) ( x - 7 ) = 0 => x = 18 or 7 Hence, age of boy = x = 18 or 7 years Age of his brother = ( 25 - 18 = 7 ) or ( 25 - 7 ) = 18 years

48.

the sum of the ages of a boy and his brother is 25 years and the product of their ages is 126. find their ages?

Answer»

Let ths AGE of boy be ( X ) years and age of his brother be ( 25 - x ) years

Product of their AGES = 126

=> x ( 25 - x ) = 126

=> 25x - x² = 126

=> x² - 25x + 126 = 0

=> x² - 18x - 7x + 126 = 0

=> x( x - 18 ) - 7( x - 18 ) = 0

=> ( x - 18 ) ( x - 7 ) = 0

=> x = 18 or 7

Hence, age of boy = x = 18 or 7 years

Age of his brother = ( 25 - 18 = 7 ) or ( 25 - 7 ) = 18 years

Discussion

49.	In the adjacent figure, it is given that, BC \|\| DE, ∠BAC=35° and ∠BCE=102°. Find the measure of (i) ∠ BCA (ii) ∠ADE and (iii) ∠CED.
Answer» Answer: 1) 78°, 2) 67°, 3) 78° Step-by-step explanation: Since we have given that BC \|\| DE, ∠BAC=35° and ∠BCE=102°. So, we NEED to FIND the MEASURE of (i) ∠ BCA (ii) ∠ADE and (iii) ∠CED. 1) Since ∠BCE and ∠ BCA are linear pair. So, it becomes, $102^\circ+\angle BCA=180^\circ\\\\\angle BCA=180^\circ-102^\circ\\\\\angle BCA=78^\circ$ 2) ∠ADE. In ΔABC, we have $\angle A+\angle B+\angle C=180^\circ\\\\35^\circ+\angle B+78^\circ=180^\circ\\\\\angle B+113^\circ=180^\circ\\\\\angle B=180^\circ-113^\circ\\\\\angle B=67^\circ$ So, ∠ADE and ∠ABC are corresponding ANGLES and so they are equal. so, ∠ADE = 67° 3) ∠CED. $\angle CED=\angle ACB=78^\circ$ Hence, 1) 78°, 2) 67°, 3) 78°

49.

In the adjacent figure, it is given that, BC || DE, ∠BAC=35° and ∠BCE=102°. Find the measure of (i) ∠ BCA (ii) ∠ADE and (iii) ∠CED.

Answer»

Answer: 1) 78°, 2) 67°, 3) 78°

Step-by-step explanation:

Since we have given that

BC || DE, ∠BAC=35° and ∠BCE=102°.

So, we NEED to FIND the MEASURE of (i) ∠ BCA (ii) ∠ADE and (iii) ∠CED.

1) Since ∠BCE and ∠ BCA are linear pair.

So, it becomes,

$102^\circ+\angle BCA=180^\circ\\\\\angle BCA=180^\circ-102^\circ\\\\\angle BCA=78^\circ$

2) ∠ADE.

In ΔABC, we have

$\angle A+\angle B+\angle C=180^\circ\\\\35^\circ+\angle B+78^\circ=180^\circ\\\\\angle B+113^\circ=180^\circ\\\\\angle B=180^\circ-113^\circ\\\\\angle B=67^\circ$

So, ∠ADE and ∠ABC are corresponding ANGLES and so they are equal.

so, ∠ADE = 67°

3) ∠CED.

$\angle CED=\angle ACB=78^\circ$

Hence, 1) 78°, 2) 67°, 3) 78°

Discussion

50.	Ad is median and g is centroid of triangle abc. line l passes through g and is parallel to bc. the line l meets ab at x and ac at y. f bx = 3 cm find ax. further if ac =6cm, find ay and yc
Answer» 3 ,3,3 CM will be the ANSWER

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

write application 2 days leave to your principal . hint Mera tabiyat kharab hai doctor ne mujhe rest karne ko kaha hai

In the adjacent figure, we have BX=1/2 AB, BY =1/2BC and AB=BC. Show that BX=BY

A worker is paid ₹210 for 6 days.if his total income of month is ₹875, for how many days he work

Simplify (x2-11x-80)➗ (16-x)

Find the edge of a cube of volume 10.648m cube

In the given figure if PQ⊥PS, PQ||SR,∠SQR=28° and ∠QRT=65°, then find the values of x and y.

Archana baught 10 g of gold fo 32376 including 14% tax. Finf rate of gold per 10g.

A rectangular carpet has an area of 60 sq. m. Its diagonal and longer side together equal 5 times the shorter side, The length of the carpet is ?

If angle A is congruent to angle B then prove that line L is parallel to line M.

The shape of a farm is a quadrilateral. Measurements taken of the farm, by naming its corners as P, Q, R, S in order are as follows. l(PQ) = 170 m, l(QR)= 250m, l(RS) = 100 m, l(PS) = 240 m, l(PR) = 260 m.Find the area of the field in hectare ( 1 hectare =10,000 sq.m)

Dev borrowed a sum of rupees 2050 from a company at the rate of 8% per annum compound interest for 2 years find the amount he has to pay

the exterior angle of a regular polygon is 1/3 of its interior anglehow many sides does the polygon has

3x+4y=7, Find three different solutions for the given equation.

In the adjacent figure AB||CD; CD||EF and y:z =3:7, find x.

alice has a box that contains 12 marbles consisting of 4 green ones 4 yellow ones and 4 blue ones. if alice was in a dark room and she had to pick them at random how many marbles must she take out so as to pick out at least 2 of one color?

50 paise convert into rupees

Length of the two parallel sides of a trapezium are 8.5 cm and 11.5 cm respectively and its height is 4.2 cm, find its area.

The abscissa of a point positive in ____________ and __________ quadrants.

Without using the distance formula show that the points A(4,-2),B(-4,4) and C(10,6) are the vertices of a right angled triangle

Use H.C.F to show that 357 and 1625 are co-primes

(1001)³,Evaluate it using suitable identites.

Factorise 343x3-729y3 solve on a page and send to me

in figure 9.75 ABCD and AEFG are two parallelogram if angle C is equal to 55 degree determine angle f.

Name the southern neighbours of India

(sec theta +cosec theta) (sin theta +cos theta ) = 2+ sec theta cosec theta

If the school bag of neelam and garima weight 6kg80g and 5kg 265 g whose bag is heavier and how much

The sum of two numbers is 90. One third of the larger number is 9 more than twice the smaller number. What are the smaller numbers?

Multiples of 19 between 57 and 152___________

The difference between two whole numbers is 66 .the ratio of the two numbers is2:5 find the numbers

If ( x-1/x )=5, find the value of (i) x2+1/x2) and (ii) (x4+1/x4)

Find the radius of a circle whose area is 616 cm square

If the surface area of cube is 486 cm square.find the length of a diagonal and volume of a cube

Find the equivalent fraction of 7 by 9..... A) numerator 63=? B) denominator 18=?

In ΔABC,∠ABC=90° , AD=DC, AB=12 cm and BC=6.5 cm. Find the area of ΔADB.

Expand (x - y)³( Using Identities).

Find the square root of 12+5i

A handbag was sold for 765 and the loss was 15%. Find the profit or loss per cent , if it was sold for 819.

Find the zero of the polynomial p(x)=8x-7

Can anyone pls solve this??

A metallic cylinder of diameter 5 cm. and height 3*1/3 cm. is melted and cast into a sphere.What is its diameter.

What is the value of k in the polynomial x2 +8x +k if -2 is a zero of the polynomial?

If two triangles are similar then their corresponding angles must be

A square park of side 50 m a path of width 2.5 m runs around the garden inside it area of the path ?

Is it possible to design a rectangular park of 80m and 400m ? If so, find its length and breadth

Factorise (2a-b-c)3 +(2b-c-a)3 +(2c-a-b)3

If one root of 5x²+13x+k= 0 is the reciprocal of tha other root,then find value of k.

Express (4x- 3\2x+1-10(2x+1\4x-3)=3,(xnot equa to -1\2 x not equal to 3\4

the sum of the ages of a boy and his brother is 25 years and the product of their ages is 126. find their ages?

In the adjacent figure, it is given that, BC || DE, ∠BAC=35° and ∠BCE=102°. Find the measure of (i) ∠ BCA (ii) ∠ADE and (iii) ∠CED.

Ad is median and g is centroid of triangle abc. line l passes through g and is parallel to bc. the line l meets ab at x and ac at y. f bx = 3 cm find ax. further if ac =6cm, find ay and yc

The abscissa of a point positive in __ and quadrants.