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If one root of 5x²+13x+k= 0 is the reciprocal of tha other root,then find value of k. |
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Answer» the EQ. is 5x^2+13x+k=0 general form of quadratic eq. is x^2 +(SUM of roots)x+(product of roots)=0 divide given eq. by 5 therefore, x^2+13/5x+k/5=0 let the roots be y & 1/y (one ROOT is RECIPROCAL of other) therefore, product of roots= y*1/y=k/5 so,k=5 |
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