1.

In ΔABC,∠ABC=90° , AD=DC, AB=12 cm and BC=6.5 cm. Find the area of ΔADB.

Answer»

It is given that ,

In ∆ABC ,
AD = DC ,

AB = 12 CM , BC = 6.5 cm

∆ADB = ( 1/2 )∆ABC

[ SINCE AD is a MEDIAN of ∆ABC ]

= ( 1/2 )[ (1/2)× AB × BC ]

= 1/4 × 12 × 6.5


= 19.5 cm²

Therefore ,

Area of ∆ADB = 19.5 cm²

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