It is given that ,In ∆ABC , AD = DC ,AB = 12 CM , BC = 6.5 cm ∆ADB = ( 1/2 )∆ABC [ SINCE AD is a MEDIAN of ∆ABC ]= ( 1/2 )[ (1/2)× AB × BC ]= 1/4 × 12 × 6.5 = 19.5 cm²Therefore ,Area of ∆ADB = 19.5 cm²••••
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