332354 + Interview Questions in Secondary School in Math

1.	Factorize a^3 + a^2 + a + 1
Answer» $a^3+a^2+a+1\\$ $= a^2( a+1) + 1(a+1)$ $= (a^2+1)(a+1)$ (a²+1) is not FACTORISABLE further SINCE it has COMPLEX roots HOPE IT HELPS!!

1.

Factorize a^3 + a^2 + a + 1

Answer»

$a^3+a^2+a+1\\$

$= a^2( a+1) + 1(a+1)$

$= (a^2+1)(a+1)$

(a²+1) is not FACTORISABLE further SINCE it has COMPLEX roots

HOPE IT HELPS!!

Discussion

2.	Laplace of e^(-(t-2))(t-2)u(t-2)
Answer» Step-by-step EXPLANATION: laplace kya HOTA hai , IDK bro

2.

Laplace of e^(-(t-2))(t-2)u(t-2)

Answer»

Step-by-step EXPLANATION:

laplace kya HOTA hai , IDK bro

Discussion

3.	solve this puzzle....1) write a letter word that starts with I and the spelt the same way when it is read backwards .2)Tina Reena and Bina are best friends Reena is younger than Bina Tina is older than Reena but younger than Bina who is the eldest 3)if a person is 51326 what is super..4)What Appears once in Tuesday Thursday Saturday and Sunday but never in Monday Wednesday and Friday
Answer» Answer: (1) Don't knowXD (2) Bina (3) QUESTION is not COMPLETE. (4) The alphabet " U ". HOPE it helps! Please tell the answer of 1 in the chats. Please like and mark the brainliest ❤️

3.

solve this puzzle....1) write a letter word that starts with I and the spelt the same way when it is read backwards .2)Tina Reena and Bina are best friends Reena is younger than Bina Tina is older than Reena but younger than Bina who is the eldest 3)if a person is 51326 what is super..4)What Appears once in Tuesday Thursday Saturday and Sunday but never in Monday Wednesday and Friday

Answer»

Answer:

(1) Don't knowXD

(2) Bina

(3) QUESTION is not COMPLETE.

(4) The alphabet " U ".

HOPE it helps!

Please tell the answer of 1 in the chats.

Please like and mark the brainliest ❤️

Discussion

4.	Tow number are in the ratio 3:5 and their HCF 12, their product is
Answer» Answer: 5 Step-by-step EXPLANATION: gjfrgvhhkfyc CGH,njgbjhc

4.

Tow number are in the ratio 3:5 and their HCF 12, their product is

Answer»

Answer:

5

Step-by-step EXPLANATION:

gjfrgvhhkfyc CGH,njgbjhc

Discussion

5.	Factorise 2x square minus under root 3 x minus 3
Answer» Step-by-step explanation: Given: $2 {x}^{2} - \sqrt{3} x - 3 \\ \\$ To find: Factors Solution: To FACTORISE the polynomial,SPLIT the middle term such that it's addition or subtraction GIVES middle term itself and multiplication gives -6 $2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - 3 \\ \\$ As $- 2 \sqrt{3} + \sqrt{3} = - \sqrt{3} \\ \\ ( - 2 \sqrt{3} )( \sqrt{3} ) = - 2 \times 3 = - 6 \\ \\$ Now take COMMON from first two terms and last two terms $2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - \sqrt{3} \times \sqrt{3} \\ \\ 2 x(x -\sqrt{3} ) + \sqrt{3}(x - \sqrt{3} ) \\ \\$ take (x-√3) common from both terms $(x - \sqrt{3} )(2x + \sqrt{3}) \\ \\$ Thus,factors of $\bold{\green{2 {x}^{2} - \sqrt{3} x - 3 = (2x + \sqrt{3}) (x - \sqrt{3} )}} \\ \\$ Hope it helps you. To learn more on brainly: 1)factorization of quadratic polynomials brainly.in/question/12504518 2)find the zeros of the quadratic polynomial p(x)=x²+3x+2 and hence find the sum and product of its zeros brainly.in/question/4856618

5.

Factorise 2x square minus under root 3 x minus 3

Answer»

Step-by-step explanation:

Given:

$2 {x}^{2} - \sqrt{3} x - 3 \\ \\$

To find: Factors

Solution:

To FACTORISE the polynomial,SPLIT the middle term such that it's addition or subtraction GIVES middle term itself and multiplication gives -6

$2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - 3 \\ \\$

As

$- 2 \sqrt{3} + \sqrt{3} = - \sqrt{3} \\ \\ ( - 2 \sqrt{3} )( \sqrt{3} ) = - 2 \times 3 = - 6 \\ \\$

Now take COMMON from first two terms and last two terms

$2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - \sqrt{3} \times \sqrt{3} \\ \\ 2 x(x -\sqrt{3} ) + \sqrt{3}(x - \sqrt{3} ) \\ \\$

take (x-√3) common from both terms

$(x - \sqrt{3} )(2x + \sqrt{3}) \\ \\$

Thus,factors of

$\bold{\green{2 {x}^{2} - \sqrt{3} x - 3 = (2x + \sqrt{3}) (x - \sqrt{3} )}} \\ \\$

Hope it helps you.

To learn more on brainly:

1)factorization of quadratic polynomials

brainly.in/question/12504518

2)find the zeros of the quadratic polynomial p(x)=x²+3x+2 and hence find the sum and product of its zeros

brainly.in/question/4856618

Discussion

6.	The minimum value of 3 cos x + 4 sin x + 8 is
Answer» Answer: 11 Step-by-step EXPLANATION: if we take x=0° :- cos 0°=1 ; sin0°=0. 3 cos 0°+ 4 sin 0°+8 = 3×1+4×0+8 =3+0+8 =11. if we take x = 90°:- cos 90°= 0 ; sin 90°= 1. 3 cos 90° + 4 sin 90° +8 =3×0+4×1+8 =0+4+8 =12. Thus, 11 is the answer.

6.

The minimum value of 3 cos x + 4 sin x + 8 is

Answer»

Answer:

11

Step-by-step EXPLANATION:

if we take x=0° :-

cos 0°=1 ; sin0°=0.

3 cos 0°+ 4 sin 0°+8

= 3×1+4×0+8

=3+0+8

=11.

if we take x = 90°:-

cos 90°= 0 ; sin 90°= 1.

3 cos 90° + 4 sin 90° +8

=3×0+4×1+8

=0+4+8

=12.

Thus, 11 is the answer.

Discussion

7.	Differentiate (a) (x + cosx)(x -tanx ).(b)x+cosx/secx
Answer» (a) Answer: $\frac{d}{dx} (x + cosx)(x - tanx)$ This is of the form uv : { $\frac{d}{dx} uv = u\frac{d}{dx}v + v\frac{d}{x} u$ } { u = (x + cosx) ; v = (x - tanx) } ∴ $(x+cosx)\frac{d}{dx} (x - tanx) + (x-tanx)\frac{d}{dx} (x+cosx)$ (Open BRACKETS and DIFF. each TERM) = (x + cosx) × (1 - sec²x) + (x - tanx) × (1 - sinx) = x + cosx - xsec²x - sec²x cosx + x - xsinx - tanx + tanx sinx 2x + cosx - xsec²x - secx - xsinx - tanx + tanx sinx (B) Answer: $\frac{d}{dx} (\frac{x+cosx}{secx})$ This is of the form u/v: ( $\frac{d}{dx}(\frac{u}{v}) = \frac{v\frac{d}{dx}u - u\frac{d}{dx}v }{v^{2} }$ ) ∴ $(secx)\frac{d}{dx} (x+cosx) - (x+cosx)\frac{d}{dx}(secx) / sec^{2}x$ (Open brackets and diff. each term) = (secx)(1 -sinx) - (x + cosx)(secx tanx) / (sec²x) = secx - sinx secx - x secx tanx - cosx secx tanx / sec²x = secx - tanx - x secx - tanx / sec²x

7.

Differentiate (a) (x + cosx)(x -tanx ).(b)x+cosx/secx

Answer»

(a) Answer:

$\frac{d}{dx} (x + cosx)(x - tanx)$

This is of the form uv :

{ $\frac{d}{dx} uv = u\frac{d}{dx}v + v\frac{d}{x} u$ } { u = (x + cosx) ; v = (x - tanx) }

∴ $(x+cosx)\frac{d}{dx} (x - tanx) + (x-tanx)\frac{d}{dx} (x+cosx)$

(Open BRACKETS and DIFF. each TERM)

= (x + cosx) × (1 - sec²x) + (x - tanx) × (1 - sinx)

= x + cosx - xsec²x - sec²x cosx + x - xsinx - tanx + tanx sinx

2x + cosx - xsec²x - secx - xsinx - tanx + tanx sinx

(B) Answer:

$\frac{d}{dx} (\frac{x+cosx}{secx})$

This is of the form u/v:

( $\frac{d}{dx}(\frac{u}{v}) = \frac{v\frac{d}{dx}u - u\frac{d}{dx}v }{v^{2} }$ )

∴ $(secx)\frac{d}{dx} (x+cosx) - (x+cosx)\frac{d}{dx}(secx) / sec^{2}x$

(Open brackets and diff. each term)

= (secx)(1 -sinx) - (x + cosx)(secx tanx) / (sec²x)

= secx - sinx secx - x secx tanx - cosx secx tanx / sec²x

= secx - tanx - x secx - tanx / sec²x

Discussion

8.	Slove it guys fast plz
Answer» 1)b 2)a 3)c 4)a 5)a 6)a 7)c 8)a 9)b 10)2 Step-by-step EXPLANATION: HOPE it would be helpful to you sorry for delay Dont WORRY all are correct answers only ............

8.

Slove it guys fast plz

Answer»

1)b

2)a

3)c

4)a

5)a

6)a

7)c

8)a

9)b

10)2

Step-by-step EXPLANATION:

HOPE it would be helpful to you

sorry for delay

Dont WORRY all are correct answers only

............

Discussion

9.	Solve for X and Y............answer me soon plzz
Answer» ANSWER: SECOND EQUATION is not having =? how

9.

Solve for X and Y............answer me soon plzz

Answer»

ANSWER:

SECOND EQUATION is not having =? how

Discussion

10.	The first , thrid and fourth term of a proportion are 6,9,36. find the second term
Answer» The first , THRID and fourth TERM of a proportion are 6,9,36. In order to FIND the fourth proportion a :b :: c: d a/b= c/d Let 'a' is first proportion b is second proportion c is THIRD proportion d is fourth proportion 6/b=9/36 b=24 Hence second proportion is 24. Thanks.

10.

The first , thrid and fourth term of a proportion are 6,9,36. find the second term

Answer»

The first , THRID and fourth TERM of a proportion are 6,9,36.

In order to FIND the fourth proportion

a :b :: c: d

a/b= c/d

Let 'a' is first proportion

b is second proportion

c is THIRD proportion

d is fourth proportion

6/b=9/36

b=24

Hence second proportion is 24.

Thanks.

Discussion

11.	Please anyone answer me please tomorrow is my examination
Answer» ANSWER: BEST of LUCK ............. MATHS

11.

Please anyone answer me please tomorrow is my examination

Answer»

ANSWER:

BEST of LUCK ............. MATHS

Discussion

12.	How we obtain 105*95
Answer» ANSWER: by CALCULATING BTW answer is 9975 *Please MARK as BRAINIEST answer*

12.

How we obtain 105*95

Answer»

ANSWER:

by CALCULATING BTW answer is 9975

Please MARK as BRAINIEST answer

Discussion

13.	ର) ଗୋଟିଏ ବାଉଁଶର ୫ ଭାଗ ପଙ୍କରେ, ' ଭାଗ ପାଣିରେ। ଏବଂ ଉପରକୁ ୫ ଫୁଟ୍ ଅଛି । ତା’ହେଲେ ବାଉଁଶରଦୈର୍ଘ୍ୟ(୫ ଫୁଟ୍, ୨୦ ଫୁଟ୍, ୪୦ ଫୁଟ୍, ୧୦ ଫୁଟ୍)) odia aaico mo naaa aae
Answer» which LANGUAGE is this.I DONT understand Hope its HELP to you mark me as BRAINLIST

13.

ର) ଗୋଟିଏ ବାଉଁଶର ୫ ଭାଗ ପଙ୍କରେ, ' ଭାଗ ପାଣିରେ। ଏବଂ ଉପରକୁ ୫ ଫୁଟ୍ ଅଛି । ତା’ହେଲେ ବାଉଁଶରଦୈର୍ଘ୍ୟ(୫ ଫୁଟ୍, ୨୦ ଫୁଟ୍, ୪୦ ଫୁଟ୍, ୧୦ ଫୁଟ୍)) odia aaico mo naaa aae

Answer»

which LANGUAGE is this.I DONT understand

Hope its HELP to you

mark me as BRAINLIST

Discussion

14.	Find the hcf of1)256,5762)170,3366using Euclid's division lemma
Answer» Step-by-step explanation: 1) 256 , 576 576 > 256 So, 576 = 256 × 2 + 64 256 = 64 × 4 + 0 Hence, The H•C•F of 256 , 576 is 64 2) 170 , 3366 3366 > 170 So, 3366 = 170 × 19 + 136 170 = 136 × 1 + 34 136 = 34 × 4 + 0 Hence, The H•C•F of 170 , 3366 is 34

14.

Find the hcf of1)256,5762)170,3366using Euclid's division lemma

Answer»

Step-by-step explanation:

1) 256 , 576

576 > 256

So,

576 = 256 × 2 + 64

256 = 64 × 4 + 0

Hence,

The H•C•F of 256 , 576 is 64

2) 170 , 3366

3366 > 170

So,

3366 = 170 × 19 + 136

170 = 136 × 1 + 34

136 = 34 × 4 + 0

Hence,

The H•C•F of 170 , 3366 is 34

Discussion

15.	In figure O is the centre of a circle and angle pqr is 30 find the value of x.
Answer» ANSWER: PLS GIVE the fig Step-by-step EXPLANATION: pls mark as branlist

15.

In figure O is the centre of a circle and angle pqr is 30 find the value of x.

Answer»

ANSWER:

PLS GIVE the fig

Step-by-step EXPLANATION:

pls mark as branlist

Discussion

16.	Please ans fast............
Answer» ANSWER: SPLIT the rectangles Then CALCULATE the SIDES

16.

Please ans fast............

Answer»

ANSWER:

SPLIT the rectangles

Then CALCULATE the SIDES

Discussion

17.	Eulers formula for cone
Answer» HEY BRO your ANSWER is this v-e+f=2

Discussion

18.	The difference in volumes of two cubes is 152 m3 and the difference in their one face areas is 20 m2. If the sum of their edge is 10 m, the product of their edge is ?
Answer» Answer: Correct answer--- Let the edges of the two cubes be X and y metres Then, X3 - y3 = 152 and x2 - Y2 = 20 Also, x + y = 10 So, x - y = (x2 - y2) / (x + y) = 20/10 = 2 Now, (x3 - y3) / (x - y) = 152/2 ⇒ x2 + y2 + XY = 76 ⇒ (x + y)2 - xy = 76 ⇒ xy = (x + y)2 - 76 = (10)2 - 76 = 24

18.

The difference in volumes of two cubes is 152 m3 and the difference in their one face areas is 20 m2. If the sum of their edge is 10 m, the product of their edge is ?

Answer»

Answer:

Correct answer---

Let the edges of the two cubes be X and y metres

Then, X3 - y3 = 152

and x2 - Y2 = 20

Also, x + y = 10

So, x - y = (x2 - y2) / (x + y) = 20/10 = 2

Now, (x3 - y3) / (x - y) = 152/2

⇒ x2 + y2 + XY = 76

⇒ (x + y)2 - xy = 76

⇒ xy = (x + y)2 - 76 = (10)2 - 76 = 24

Discussion

19.	EXERCISah of the following pairs of angles are1. Which of the folcomplementary?(a) 31°, 71°(b) 25°, 652 In each case, find the angle that iscomplementary to the given angle.(b) 42°3. Which of the following pairs of angles aresupplementary?(a) 128°, 62° (b) 40°, 140°(a) 20°no that is
Answer» ANSWER: a a d jjjjjjjjjjjjjjjjjjjj

19.

EXERCISah of the following pairs of angles are1. Which of the folcomplementary?(a) 31°, 71°(b) 25°, 652 In each case, find the angle that iscomplementary to the given angle.(b) 42°3. Which of the following pairs of angles aresupplementary?(a) 128°, 62° (b) 40°, 140°(a) 20°no that is

Answer»

ANSWER:

a a d

jjjjjjjjjjjjjjjjjjjj

Discussion

20.	Find the area of the given figure in which PR and TV ar equidistant frm WS at a distnce of 7cm
Answer» ANSWER: Step-by-step EXPLANATION:

20.

Find the area of the given figure in which PR and TV ar equidistant frm WS at a distnce of 7cm

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

21.	(111) Marbles of diameter 1.4 cm are dropped into a beaker containing some water andare fully submerged. The diameter of the beaker is 7 cm. Find how many marbleshave been dropped in it if the water rises by 5.6 cm.
Answer» Answer: Diameter of the SPHERICAL ball ( d ) = 1.4cm radius of the ball ( r ) = d/2 r = 0.7 cm Volume of the Sphere = ( 4/3 )πr³ cm³ v = ( 4/3 ) π ( 0.7 )³ ----( 1 ) II ) Diameter of the cylinder ( D ) = 7cm radius of the cylinder ( R ) = D/2 R = 7/2 cm Suppose WATER level rises by h= 5.6 cm in the cylindrical beacker . Then , Volume of the cylinder of height h = 5.6 cm and radius 7/2 cm V = πR²h V = [ π ×( 7/2 )² × 5.6 ]cm³ ----( 2 ) Let the number of balls dropped in the beaker = n n = V /v n = [π ×(7/2)²×5.6cm³]/ [4/3×π×(0.7)³cm³] after cancellation ,we get n = 150 *********************************************************************** hope it HELPS.............brainliest pls

21.

(111) Marbles of diameter 1.4 cm are dropped into a beaker containing some water andare fully submerged. The diameter of the beaker is 7 cm. Find how many marbleshave been dropped in it if the water rises by 5.6 cm.

Answer»

Answer:

Diameter of the SPHERICAL ball ( d ) = 1.4cm

radius of the ball ( r ) = d/2

r = 0.7 cm

Volume of the Sphere = ( 4/3 )πr³ cm³

v = ( 4/3 ) π ( 0.7 )³ ----( 1 )

II ) Diameter of the cylinder ( D ) = 7cm

radius of the cylinder ( R ) = D/2

R = 7/2 cm

Suppose WATER level rises by h= 5.6 cm

in the cylindrical beacker .

Then ,

Volume of the cylinder of height

h = 5.6 cm and radius 7/2 cm

V = πR²h

V = [ π ×( 7/2 )² × 5.6 ]cm³ ----( 2 )

Let the number of balls dropped in the

beaker = n

n = V /v

n = [π ×(7/2)²×5.6cm³]/ [4/3×π×(0.7)³cm³]

after cancellation ,we get

n = 150

***********************************************************************

hope it HELPS.............brainliest pls

Discussion

22.	Why is x^2+4x=11+x^2 not a quadratic equation
Answer» Step-by-step EXPLANATION: hey mate PLEASE CHECK the ATTACHMENT for ANSWER mark it brainlist

22.

Why is x^2+4x=11+x^2 not a quadratic equation

Answer»

Step-by-step EXPLANATION:

hey mate PLEASE CHECK the ATTACHMENT for ANSWER

mark it brainlist

Discussion

23.	22.If 1, = (log x)" dx then show that 1= x(log x)" - nl, and hence find (logx) atAl sin r+COS Y
Answer» ANSWER: not FOUND answer of this QUESTION

23.

22.If 1, = (log x)" dx then show that 1= x(log x)" - nl, and hence find (logx) atAl sin r+COS Y

Answer»

ANSWER:

not FOUND answer of this QUESTION

Discussion

24.	Please help me in this math question
Answer» ANSWER: hyy MATE I dont no this question mark me as BRAINLIST

24.

Please help me in this math question

Answer»

ANSWER:

hyy MATE

I dont no this question

mark me as BRAINLIST

Discussion

25.	Solve dy/dx= (x-y+3) / (2x-2y+5)
Answer» ANSWER: Dy/dx= x-y+3/ 2x-2y+5 Dy/dx= 2x-x -y-2y +5+3 dy/dx=1x-3y+8 OR Dy/dx=x-y+3/2x-2y+5 dy-y-2y/ dx+x+2x +5+3 dy-1y/ dx+3x +8

25.

Solve dy/dx= (x-y+3) / (2x-2y+5)

Answer»

ANSWER:

Dy/dx= x-y+3/ 2x-2y+5

Dy/dx= 2x-x -y-2y +5+3

dy/dx=1x-3y+8

OR

Dy/dx=x-y+3/2x-2y+5

dy-y-2y/ dx+x+2x +5+3

dy-1y/ dx+3x +8

Discussion

26.	Find the smallest number which when increased by 17 is exactly divisible by both 468 and 520.
Answer» Answer: 4663 Step-by-step explanation: The smallest number which when increased by 17 is exactly divisible by both 468 and 520 is obtained by subtracting 17 from the LCM of 468 and 520. Prime factorization of 468 and 520 is: 468 = 22 × 32 × 13 520 = 23 × 5 × 13 LCM = product of GREATEST power of each prime factor involved in the numbers = 22 × 32 × 5 × 13 = 4680 The required number is 4680 – 17 = 4663. Hence, the smallest number which when increased by 17 is exactly divisible by both 468 and 520 is 4663.

26.

Find the smallest number which when increased by 17 is exactly divisible by both 468 and 520.

Answer»

Answer:

4663

Step-by-step explanation:

The smallest number which when increased by 17 is exactly divisible by both 468 and 520 is obtained by subtracting 17 from the LCM of 468 and 520.

Prime factorization of 468 and 520 is:

468 = 22 × 32 × 13

520 = 23 × 5 × 13

LCM = product of GREATEST power of each prime factor involved in the numbers = 22 × 32 × 5 × 13 = 4680

The required number is 4680 – 17 = 4663.

Hence, the smallest number which when increased by 17 is exactly divisible by both 468 and 520 is 4663.

Discussion

27.	If 1. = [(log x)" dx then show that 1= x(logx)" - n1,-, and hence find (log.x) dxsin x + COS X
Answer» ANSWER: the FOLLOWING DOCUMENT document and I will have

27.

If 1. = [(log x)" dx then show that 1= x(logx)" - n1,-, and hence find (log.x) dxsin x + COS X

Answer»

ANSWER:

the FOLLOWING DOCUMENT document and I will have

Discussion

28.	Satish open the bookshop with an initial investment of rupees 160000 in the first year he incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5% calculate net profit for the entire period
Answer» Answer: 28,100 Step-by-step EXPLANATION: PLEASE SEE the ATTACHMENT.

28.

Satish open the bookshop with an initial investment of rupees 160000 in the first year he incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5% calculate net profit for the entire period

Answer»

Answer:

28,100

Step-by-step EXPLANATION:

PLEASE SEE the ATTACHMENT.

Discussion

29.	Of course, you can find nepreBER SYSTminating non-recurring lying between them. Of coursesuch numbers.mple of such a number is 0.150150015000150000...he preynumbo reproV.EXERCISE 1.3Write the following in decimal form and say what kind of decimal exp. Supphas :nber1 13.38So,mbe§sinisic
Answer» ANSWER: t shirts are EXPECTED you to nahi hu with me and I have been trying to MAI ne ek baar ek DIN por el momento

29.

Of course, you can find nepreBER SYSTminating non-recurring lying between them. Of coursesuch numbers.mple of such a number is 0.150150015000150000...he preynumbo reproV.EXERCISE 1.3Write the following in decimal form and say what kind of decimal exp. Supphas :nber1 13.38So,mbe§sinisic

Answer»

ANSWER:

t shirts are EXPECTED you to nahi hu with me and I have been trying to MAI ne ek baar ek DIN por el momento

Discussion

30.	\| (D) 2ab+3ac +2ac। रोहित ने एक साइकिल 1000 रु० में खरीदी •\| तथा इसको 1200 रु० में बेच दिया। उसका :लाभ प्रतिशत निकालिए-(A) 10% (B) 20%(C) 12% (D) 40%.....0-4
Answer» ANSWER=[B] 20%. MARK as BRAINLIST

30.

| (D) 2ab+3ac +2ac। रोहित ने एक साइकिल 1000 रु० में खरीदी •| तथा इसको 1200 रु० में बेच दिया। उसका :लाभ प्रतिशत निकालिए-(A) 10% (B) 20%(C) 12% (D) 40%.....0-4

Answer»

ANSWER=[B] 20%. MARK as BRAINLIST

Discussion

31.	Find simple interest on principal 3200 rate 13/2 time 1year
Answer» Answer: 20800 3200×13/2×1 2 GETS cut with 3200 and gives 1600 and when mutipled by 3 gives 20800

31.

Find simple interest on principal 3200 rate 13/2 time 1year

Answer»

Answer:

20800

3200×13/2×1

2 GETS cut with 3200 and gives 1600 and when mutipled by 3 gives 20800

Discussion

32.	By what number should we multiply (-7)-¹ to get (-49)-¹ ...
Answer» Answer: 1/7 hope this is HELPFUL to you

32.

By what number should we multiply (-7)-¹ to get (-49)-¹ ...

Answer»

Answer:

1/7

hope this is HELPFUL to you

Discussion

33.	Find four different solutions of the equation 4y - 11 = 0.
Answer» The given equation is a LINEAR equation in ONE variable. A linear equation in one variable has a unique SOLUTION. 4y - 11 = 0 4y = 11 y = 11/4 = 2.75 Hence y = 2.75 is the only available solution of the given equation. HOPE THIS HELPS!!

33.

Find four different solutions of the equation 4y - 11 = 0.

Answer»

The given equation is a LINEAR equation in ONE variable.

A linear equation in one variable has a unique SOLUTION.

4y - 11 = 0

4y = 11

y = 11/4 = 2.75

Hence y = 2.75 is the only available solution of the given equation.

HOPE THIS HELPS!!

Discussion

34.	One third of a number is two more than one fourth of a number. Find the number.
Answer» Step-by-step EXPLANATION: X/3-x/4=2 4x-3x/12=2 x=2*12 x=24

34.

One third of a number is two more than one fourth of a number. Find the number.

Answer»

Step-by-step EXPLANATION:

X/3-x/4=2

4x-3x/12=2

x=2*12

x=24

Discussion

35.	Satish open the bookshop with an initial investment of rupees 160000 in the first year incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5%. calculate his net profit for the entire period
Answer» ANSWER: Step-by-step explanation:ashish open a bookshop with an initial investment of rs.32000. in the first year,he incurred a loss of 5%. however during the SECOND year he earned a profit of 10% which in the third year rose to 12 1/2%.The net profit for the entire period of three YEARS is Rs 5620 Initial investment (Cost Price) = Rs 32000 After 1st year, 5% loss is suffered. So, the Selling Price would have been = (100-5)% on Rs 32000 = 95% on Rs 32000 = Rs 30400 After 2nd year, 10% profit is earned. So, the Selling Price would be = (100+10)% on Rs 30400 = 110% on Rs 30400 = Rs 33440 After 3rd year, 12.5% profit is earned. So, the Selling Price would be = (100+12.5)% on Rs 33440 = 112.5% on Rs 33440 = Rs 37620 Thus the profit earned = SP - CP = Rs (37620 - 32000) = Rs 5620 So, the net profit earned in a period of 3 years is Rs 5620 Read more on Brainly.in - brainly.in/question/2495961#readmore

35.

Satish open the bookshop with an initial investment of rupees 160000 in the first year incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5%. calculate his net profit for the entire period

Answer»

ANSWER:

Step-by-step explanation:ashish open a bookshop with an initial investment of rs.32000. in the first year,he incurred a loss of 5%. however during the SECOND year he earned a profit of 10% which in the third year rose to 12 1/2%.The net profit for the entire period of three YEARS is Rs 5620

Initial investment (Cost Price) = Rs 32000

After 1st year,

5% loss is suffered.

So, the Selling Price would have been = (100-5)% on Rs 32000

= 95% on Rs 32000

= Rs 30400

After 2nd year,

10% profit is earned.

So, the Selling Price would be = (100+10)% on Rs 30400

= 110% on Rs 30400

= Rs 33440

After 3rd year,

12.5% profit is earned.

So, the Selling Price would be = (100+12.5)% on Rs 33440

= 112.5% on Rs 33440

= Rs 37620

Thus the profit earned = SP - CP = Rs (37620 - 32000)

= Rs 5620

So, the net profit earned in a period of 3 years is Rs 5620

Read more on Brainly.in - brainly.in/question/2495961#readmore

Discussion

36.	if an isosceles triangle ABC in which AB equals to AC equals to 6 CM is inscribed in a circle of radius 9 CM find area of triangle
Answer» it will be a ISOSCELES RIGHT ANGLE triangle.. so the AREA will be 1/266=18

Discussion

37.	What is the measure of each exterior angle of a regular polygon of 10 sides
Answer» I WANT to MAKE sure my MATH is correct. 360/10=36 Each EXTERIOR angle=36 degrees

37.

What is the measure of each exterior angle of a regular polygon of 10 sides

Answer»

I WANT to MAKE sure my MATH is correct.

360/10=36 Each EXTERIOR angle=36 degrees

Discussion

38.	Represent the √5 on the number line.
Answer» take altitude=2 take base=1 so by PYTHAGORAS THEORY hy^2=a^2+b^2 so hy=√5..... HOPE this HELPS if so then don't FORGET to thank and mark as brainliest

38.

Represent the √5 on the number line.

Answer»

take altitude=2

take base=1

so by PYTHAGORAS THEORY hy^2=a^2+b^2

so hy=√5.....

HOPE this HELPS if so then don't FORGET to thank and mark as brainliest

Discussion

39.	In the figure, square ABCD is inscribed BIMin the sector A-PCQ. The radius ofsector C-BXD is 20 cm. Find the areaof shaded region.
Answer» The ANSWER is ATTACHED above Hope it HELPS MARK as BRAINLIEST

39.

In the figure, square ABCD is inscribed BIMin the sector A-PCQ. The radius ofsector C-BXD is 20 cm. Find the areaof shaded region.

Answer»

The ANSWER is ATTACHED above

Hope it HELPS

MARK as BRAINLIEST

Discussion

40.	3315 find the LCM in maths
Answer» 115 23 23 jrjrurtulyyloyyfogYopot

40.

3315 find the LCM in maths

Answer»

115

23

jrjrurtulyyloyyfogYopot

Discussion

41.	Question from practical geometry; its too difficult to construct...
Answer» Answer: LOOK hina it's EASY . you TRY your best. Step-by-step explanation: you read QUESTION and solve . I can't see it clear and i think it's uncompleted question.

41.

Question from practical geometry; its too difficult to construct...

Answer»

Answer:

LOOK hina it's EASY . you TRY your best.

Step-by-step explanation:

you read QUESTION and solve . I can't see it clear and i think it's uncompleted question.

Discussion

42.	Factorise 25x2 + 16 y2 + 4 z2 - 40xy +16yz - 20zx
Answer» Step-by-step explanation: 25x² + 16y² + 4z² - 40XY + 16yz - 20zx (-5X)² + (4Y)² + (2Z)² +2(-5x)² + 2(4y)(2z) +2(-5x)(2z) (4y + 2z - 5x)²

42.

Factorise 25x2 + 16 y2 + 4 z2 - 40xy +16yz - 20zx

Answer»

Step-by-step explanation:

25x² + 16y² + 4z² - 40XY + 16yz - 20zx

(-5X)² + (4Y)² + (2Z)² +2(-5x)² + 2(4y)(2z) +2(-5x)(2z)

(4y + 2z - 5x)²

Discussion

43.	5 times the different of 12 and 8make mathematical expression,then,simplify.
Answer» Answer:5(12-8) =5×4=20 Step-by-step EXPLANATION: MARK it as BRAINLIEST

43.

5 times the different of 12 and 8make mathematical expression,then,simplify.

Answer»

Answer:5(12-8) =5×4=20

Step-by-step EXPLANATION:

MARK it as BRAINLIEST

Discussion

44.	Formula for TSA of a cuboid
Answer» Answer: 2(lb+BH+HL) Step-by-step EXPLANATION: i THINK this HELPS you GOOD DAY

44.

Formula for TSA of a cuboid

Answer»

Answer:

2(lb+BH+HL)

Step-by-step EXPLANATION:

i THINK this HELPS you GOOD DAY

Discussion

45.	If manohar pays an interest of 750rs. for 2 years on a sum of 4500rs,find the rate of interest
Answer» Step-by-step EXPLANATION: $\sqrt{36} 55555555555$

45.

If manohar pays an interest of 750rs. for 2 years on a sum of 4500rs,find the rate of interest

Answer»

Step-by-step EXPLANATION:

$\sqrt{36} 55555555555$

Discussion

46.	The painter finishes painting the room in 6 hours and his assistant finishes it in 9 hoursHow long does it take to finish the same room if they work together?
Answer» Answer: 36 minutes Step-by-step EXPLANATION: remember that, the whole work is 1. PAINTER does the whole work at 6 hour.so he does 1÷6 work at 1 hour.assistant does the the whole work at 9 hour.so he does 1÷9 work at 1 hour.they work 5÷18 PART at 1 hour, they finish whole work at 18÷5 hour. so that,18×60=1080.1080÷5=216. 216-180=36 minutes

46.

The painter finishes painting the room in 6 hours and his assistant finishes it in 9 hoursHow long does it take to finish the same room if they work together?

Answer»

Answer:

36 minutes

Step-by-step EXPLANATION:

remember that, the whole work is 1. PAINTER does the whole work at 6 hour.so he does 1÷6 work at 1 hour.assistant does the the whole work at 9 hour.so he does 1÷9 work at 1 hour.they work 5÷18 PART at 1 hour, they finish whole work at 18÷5 hour.

so that,18×60=1080.1080÷5=216.

216-180=36 minutes

Discussion

47.	Find the 20 term of the AP whose 3 term is 7 and the 7 term exceed three times the 3term by 2.
Answer» Answer: The 20th TERM of the AP is 75. Step-by-step explanation: The nth term of an AP is: $T_{n}=a+(n-1)d$ It is provided that: $T_{3}=7\\T_{7}=3T_{3}+2$ Substitute the value of T₃ in T₇ and SOLVE as follows: $T_{7}=3T_{3}+2\\a+(7-1)d=3(a+(3-1)d)+2\\a+6d=3a+6d+2\\a=3a+2\\-2a=2\\a=-1$ Compute the value of d as follows: $T_{3}=7\\a+(3-1)d=7\\-1+2d=7\\2d=8\\d=4$ Compute the 20th term as follows: $T_{20}=-1+(20-1)\times4=-1+76=75$ Thus, the 20th term of the AP is 75.

47.

Find the 20 term of the AP whose 3 term is 7 and the 7 term exceed three times the 3term by 2.

Answer»

Answer:

The 20th TERM of the AP is 75.

Step-by-step explanation:

The nth term of an AP is:

$T_{n}=a+(n-1)d$

It is provided that:

$T_{3}=7\\T_{7}=3T_{3}+2$

Substitute the value of T₃ in T₇ and SOLVE as follows:

$T_{7}=3T_{3}+2\\a+(7-1)d=3(a+(3-1)d)+2\\a+6d=3a+6d+2\\a=3a+2\\-2a=2\\a=-1$

Compute the value of d as follows:

$T_{3}=7\\a+(3-1)d=7\\-1+2d=7\\2d=8\\d=4$

Compute the 20th term as follows:

$T_{20}=-1+(20-1)\times4=-1+76=75$

Thus, the 20th term of the AP is 75.

Discussion

48.	ToFind the value of the polynomial 5x - 4x² + 3 at x= 1/2
Answer» Answer: 5(1/2)-4(1/2)^2+3 5/2-4/4+3 5/2-1+3 5/2+2 5/2+4/2 9/2 Step-by-step explanation: therefore , value of polynomial is 9/2 Hope it help you please mark it as brainliest✌

48.

ToFind the value of the polynomial 5x - 4x² + 3 at x= 1/2

Answer»

Answer:

5(1/2)-4(1/2)^2+3
5/2-4/4+3
5/2-1+3
5/2+2
5/2+4/2
9/2

Step-by-step explanation:

therefore , value of polynomial is 9/2

Hope it help you

please mark it as brainliest✌

Discussion

49.	Evaluate (5/9)^-2 × (3/5)^-3× (3/5)^0
Answer» ANSWER: 0 as in LAST multiply by 0 *Please mark as BRAINIEST answer*

49.

Evaluate (5/9)^-2 × (3/5)^-3× (3/5)^0

Answer»

ANSWER:

0 as in LAST multiply by 0

Please mark as BRAINIEST answer

Discussion

50.	Simplify this (3p2)3step by step and should be right solve the full answer
Answer» Answer: 18p Step-by-step explanation: 3×2p 6p×3 18p ithink this HELPS you GOOD DAY

50.

Simplify this (3p2)3step by step and should be right solve the full answer

Answer»

Answer:

18p

Step-by-step explanation:

3×2p

6p×3

18p ithink this HELPS you GOOD DAY

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

Factorize a^3 + a^2 + a + 1​

HOPE IT HELPS!!

Laplace of e^(-(t-2))(t-2)u(t-2)

Tow number are in the ratio 3:5 and their HCF 12, their product is​

Factorise 2x square minus under root 3 x minus 3​

The minimum value of 3 cos x + 4 sin x + 8 is ​

Differentiate (a) (x + cosx)(x -tanx ).(b)x+cosx/secx​

Slove it guys fast plz​

Solve for X and Y............answer me soon plzz​

The first , thrid and fourth term of a proportion are 6,9,36. find the second term ​

Please anyone answer me please tomorrow is my examination ​

How we obtain 105*95​

Please MARK as BRAINIEST answer

Find the hcf of1)256,5762)170,3366using Euclid's division lemma​

1) 256 , 576

2) 170 , 3366

In figure O is the centre of a circle and angle pqr is 30 find the value of x.​

Please ans fast............​

Eulers formula for cone

The difference in volumes of two cubes is 152 m3 and the difference in their one face areas is 20 m2. If the sum of their edge is 10 m, the product of their edge is ?

EXERCISah of the following pairs of angles are1. Which of the folcomplementary?(a) 31°, 71°(b) 25°, 652 In each case, find the angle that iscomplementary to the given angle.(b) 42°3. Which of the following pairs of angles aresupplementary?(a) 128°, 62° (b) 40°, 140°(a) 20°no that is​

Find the area of the given figure in which PR and TV ar equidistant frm WS at a distnce of 7cm​

(111) Marbles of diameter 1.4 cm are dropped into a beaker containing some water andare fully submerged. The diameter of the beaker is 7 cm. Find how many marbleshave been dropped in it if the water rises by 5.6 cm.​

Why is x^2+4x=11+x^2 not a quadratic equation​

22.If 1, = (log x)" dx then show that 1= x(log x)" - nl, and hence find (logx) atAl sin r+COS Y​

Please help me in this math question ​

Solve dy/dx= (x-y+3) / (2x-2y+5)​

Find the smallest number which when increased by 17 is exactly divisible by both 468 and 520.​

If 1. = [(log x)" dx then show that 1= x(logx)" - n1,-, and hence find (log.x) dxsin x + COS X​

Satish open the bookshop with an initial investment of rupees 160000 in the first year he incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5% calculate net profit for the entire period​

Of course, you can find nepreBER SYSTminating non-recurring lying between them. Of coursesuch numbers.mple of such a number is 0.150150015000150000...he preynumbo reproV.EXERCISE 1.3Write the following in decimal form and say what kind of decimal exp. Supphas :nber1 13.38So,mbe§sinisic​

Find simple interest on principal 3200 rate 13/2 time 1year​

By what number should we multiply (-7)-¹ to get (-49)-¹ ...​

Find four different solutions of the equation 4y - 11 = 0.​

HOPE THIS HELPS!!

One third of a number is two more than one fourth of a number. Find the number.​

Satish open the bookshop with an initial investment of rupees 160000 in the first year incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5%. calculate his net profit for the entire period​

if an isosceles triangle ABC in which AB equals to AC equals to 6 CM is inscribed in a circle of radius 9 CM find area of triangle​

What is the measure of each exterior angle of a regular polygon of 10 sides

Represent the √5 on the number line.​

take altitude=2

take base=1

so by PYTHAGORAS THEORY hy^2=a^2+b^2

so hy=√5.....

HOPE this HELPS if so then don't FORGET to thank and mark as brainliest

In the figure, square ABCD is inscribed BIMin the sector A-PCQ. The radius ofsector C-BXD is 20 cm. Find the areaof shaded region.​

3315 find the LCM in maths​

Question from practical geometry; its too difficult to construct...​

Factorise 25x2 + 16 y2 + 4 z2 - 40xy +16yz - 20zx​

5 times the different of 12 and 8make mathematical expression,then,simplify.​

Formula for TSA of a cuboid​

If manohar pays an interest of 750rs. for 2 years on a sum of 4500rs,find the rate of interest ​

The painter finishes painting the room in 6 hours and his assistant finishes it in 9 hoursHow long does it take to finish the same room if they work together?

Find the 20 term of the AP whose 3 term is 7 and the 7 term exceed three times the 3term by 2.​

The 20th TERM of the AP is 75.

ToFind the value of the polynomial 5x - 4x² + 3 at x= 1/2​

Hope it help you

Evaluate (5/9)^-2 × (3/5)^-3× (3/5)^0​

Please mark as BRAINIEST answer

Simplify this (3p2)3step by step and should be right solve the full answer​

Factorize a^3 + a^2 + a + 1

Tow number are in the ratio 3:5 and their HCF 12, their product is

Factorise 2x square minus under root 3 x minus 3

The minimum value of 3 cos x + 4 sin x + 8 is

Differentiate (a) (x + cosx)(x -tanx ).(b)x+cosx/secx

Slove it guys fast plz

Solve for X and Y............answer me soon plzz

The first , thrid and fourth term of a proportion are 6,9,36. find the second term

Please anyone answer me please tomorrow is my examination

How we obtain 105*95

Find the hcf of1)256,5762)170,3366using Euclid's division lemma

In figure O is the centre of a circle and angle pqr is 30 find the value of x.

Please ans fast............

EXERCISah of the following pairs of angles are1. Which of the folcomplementary?(a) 31°, 71°(b) 25°, 652 In each case, find the angle that iscomplementary to the given angle.(b) 42°3. Which of the following pairs of angles aresupplementary?(a) 128°, 62° (b) 40°, 140°(a) 20°no that is

Find the area of the given figure in which PR and TV ar equidistant frm WS at a distnce of 7cm

(111) Marbles of diameter 1.4 cm are dropped into a beaker containing some water andare fully submerged. The diameter of the beaker is 7 cm. Find how many marbleshave been dropped in it if the water rises by 5.6 cm.

Why is x^2+4x=11+x^2 not a quadratic equation

22.If 1, = (log x)" dx then show that 1= x(log x)" - nl, and hence find (logx) atAl sin r+COS Y

Please help me in this math question

Solve dy/dx= (x-y+3) / (2x-2y+5)

Find the smallest number which when increased by 17 is exactly divisible by both 468 and 520.

If 1. = [(log x)" dx then show that 1= x(logx)" - n1,-, and hence find (log.x) dxsin x + COS X

Satish open the bookshop with an initial investment of rupees 160000 in the first year he incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5% calculate net profit for the entire period

Of course, you can find nepreBER SYSTminating non-recurring lying between them. Of coursesuch numbers.mple of such a number is 0.150150015000150000...he preynumbo reproV.EXERCISE 1.3Write the following in decimal form and say what kind of decimal exp. Supphas :nber1 13.38So,mbe§sinisic

Find simple interest on principal 3200 rate 13/2 time 1year

By what number should we multiply (-7)-¹ to get (-49)-¹ ...

Find four different solutions of the equation 4y - 11 = 0.

One third of a number is two more than one fourth of a number. Find the number.

Satish open the bookshop with an initial investment of rupees 160000 in the first year incurred a loss of 5% however during the second year he earned a profit of 10% which in the third year rose to 12.5%. calculate his net profit for the entire period

if an isosceles triangle ABC in which AB equals to AC equals to 6 CM is inscribed in a circle of radius 9 CM find area of triangle

Represent the √5 on the number line.

In the figure, square ABCD is inscribed BIMin the sector A-PCQ. The radius ofsector C-BXD is 20 cm. Find the areaof shaded region.

3315 find the LCM in maths

Question from practical geometry; its too difficult to construct...

Factorise 25x2 + 16 y2 + 4 z2 - 40xy +16yz - 20zx

5 times the different of 12 and 8make mathematical expression,then,simplify.

Formula for TSA of a cuboid

If manohar pays an interest of 750rs. for 2 years on a sum of 4500rs,find the rate of interest

Find the 20 term of the AP whose 3 term is 7 and the 7 term exceed three times the 3term by 2.

ToFind the value of the polynomial 5x - 4x² + 3 at x= 1/2

Evaluate (5/9)^-2 × (3/5)^-3× (3/5)^0

Simplify this (3p2)3step by step and should be right solve the full answer