Factorise 2x square minus under root 3 x minus 3 – InterviewSolution

1.

Factorise 2x square minus under root 3 x minus 3

Answer»

Step-by-step explanation:

Given:

$2 {x}^{2} - \sqrt{3} x - 3 \\ \\$

To find: Factors

Solution:

To FACTORISE the polynomial,SPLIT the middle term such that it's addition or subtraction GIVES middle term itself and multiplication gives -6

$2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - 3 \\ \\$

As

$- 2 \sqrt{3} + \sqrt{3} = - \sqrt{3} \\ \\ ( - 2 \sqrt{3} )( \sqrt{3} ) = - 2 \times 3 = - 6 \\ \\$

Now take COMMON from first two terms and last two terms

$2 {x}^{2} - 2 \sqrt{3} x + \sqrt{3}x - \sqrt{3} \times \sqrt{3} \\ \\ 2 x(x -\sqrt{3} ) + \sqrt{3}(x - \sqrt{3} ) \\ \\$

take (x-√3) common from both terms

$(x - \sqrt{3} )(2x + \sqrt{3}) \\ \\$

Thus,factors of

$\bold{\green{2 {x}^{2} - \sqrt{3} x - 3 = (2x + \sqrt{3}) (x - \sqrt{3} )}} \\ \\$

Hope it helps you.

To learn more on brainly:

1)factorization of quadratic polynomials

brainly.in/question/12504518

2)find the zeros of the quadratic polynomial p(x)=x²+3x+2 and hence find the sum and product of its zeros

brainly.in/question/4856618

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