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(111) Marbles of diameter 1.4 cm are dropped into a beaker containing some water andare fully submerged. The diameter of the beaker is 7 cm. Find how many marbleshave been dropped in it if the water rises by 5.6 cm. |
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Answer» Answer: Diameter of the SPHERICAL ball ( d ) = 1.4cm radius of the ball ( r ) = d/2 r = 0.7 cm Volume of the Sphere = ( 4/3 )πr³ cm³ v = ( 4/3 ) π ( 0.7 )³ ----( 1 ) II ) Diameter of the cylinder ( D ) = 7cm radius of the cylinder ( R ) = D/2 R = 7/2 cm Suppose WATER level rises by h= 5.6 cm in the cylindrical beacker . Then , Volume of the cylinder of height h = 5.6 cm and radius 7/2 cm V = πR²h V = [ π ×( 7/2 )² × 5.6 ]cm³ ----( 2 ) Let the number of balls dropped in the beaker = n n = V /v n = [π ×(7/2)²×5.6cm³]/ [4/3×π×(0.7)³cm³] after cancellation ,we get n = 150 *********************************************************************** hope it HELPS.............brainliest pls |
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