332354 + Interview Questions in Secondary School in Math

1.	Find length of longest ploe that can be put in a room of dimensions ( 12×9 ×8)m
Answer» $\bf{\underline{Question:-}}$ FIND length of LONGEST ploe that can be put in a ROOM of DIMENSIONS ( 12×9 ×8)m $\bf{\underline{Given:-}}$ ▶️ Length = 12m ▶️Breadth = 9m ▶️Height = 8m $\bf{\underline{Solution:-}}$ $\bf Longest\: length \:of\: pole = \sqrt{h^2+ r^2 + l^2}$ $\bf→ \sqrt{12^2+ 8^2+ 9^2}$ $\bf→ \sqrt{44 + 64 +81}$ $\bf→ \sqrt{289}$ $\bf → 17$ $\bf{\underline{Hence:-}}$ The length of longest pole is 17metre

1.

Find length of longest ploe that can be put in a room of dimensions ( 12×9 ×8)m

Answer»

$\bf{\underline{Question:-}}$

FIND length of LONGEST ploe that can be put in a ROOM of DIMENSIONS ( 12×9 ×8)m

$\bf{\underline{Given:-}}$

▶️ Length = 12m
▶️Breadth = 9m
▶️Height = 8m

$\bf{\underline{Solution:-}}$

$\bf Longest\: length \:of\: pole = \sqrt{h^2+ r^2 + l^2}$

$\bf→ \sqrt{12^2+ 8^2+ 9^2}$

$\bf→ \sqrt{44 + 64 +81}$

$\bf→ \sqrt{289}$

$\bf → 17$

$\bf{\underline{Hence:-}}$

The length of longest pole is 17metre

Discussion

2.	Plz answered plz fast
Answer» ANSWER: PLZ tell the HINTS first so that we can solve Step-by-step EXPLANATION: not whole question GIVEN

2.

Plz answered plz fast

Answer»

ANSWER:

PLZ tell the HINTS first

so that we can solve

Step-by-step EXPLANATION:

not whole question GIVEN

Discussion

3.	Select the approptat alternativena AGC and A PSR., in a oneto one correspondenceAB BCCA thenTRPSR 20 ABC87 O POR 2 OCABCBA 2 O PORo O B CA 20 POR
Answer» ANSWER: we didn't UNDERSTAND the QUESTION please WRITE question again hope you understand..

3.

Select the approptat alternativena AGC and A PSR., in a oneto one correspondenceAB BCCA thenTRPSR 20 ABC87 O POR 2 OCABCBA 2 O PORo O B CA 20 POR

Answer»

ANSWER:

we didn't UNDERSTAND the QUESTION

please WRITE question again

hope you understand..

Discussion

4.	3+√6/√3+√2=a+√3b find the value of b
Answer» ANSWER: $3 + \frac{ \sqrt{6} }{ \sqrt{3} + \sqrt{<klux>2</klux>} } \\ = 3 + \frac{ \sqrt{6}( \sqrt{3} - \sqrt{2} ) }{( \sqrt{3} + \sqrt{2})( \sqrt{3} - \sqrt{2} ) } \\ = 3 + \frac{3 \sqrt{2} - 2 \sqrt{3} }{3 - 2} \\ = 3 + \sqrt{3} ( \sqrt{6} - 2) = a + \sqrt{3}b$ THEREFORE, a = 3 b = √6 - 2

4.

3+√6/√3+√2=a+√3b find the value of b

Answer»

ANSWER:

$3 + \frac{ \sqrt{6} }{ \sqrt{3} + \sqrt{<klux>2</klux>} } \\ = 3 + \frac{ \sqrt{6}( \sqrt{3} - \sqrt{2} ) }{( \sqrt{3} + \sqrt{2})( \sqrt{3} - \sqrt{2} ) } \\ = 3 + \frac{3 \sqrt{2} - 2 \sqrt{3} }{3 - 2} \\ = 3 + \sqrt{3} ( \sqrt{6} - 2) = a + \sqrt{3}b$

THEREFORE,

a = 3

b = √6 - 2

Discussion

5.	The pair oflinear equations y=0 and y = -6 has _________________ solution/s.
Answer» Answer: 56or hsfgemek JR TIRE with woyfud aurajgslhf

5.

The pair oflinear equations y=0 and y = -6 has _________________ solution/s.

Answer»

Answer:

56or hsfgemek JR TIRE with woyfud aurajgslhf

Discussion

6.	Evalute sin(2sin inverse 0.6
Answer» QUESTION :– ㅤ $\bf \implies Evaluate\:\:\sin \{2\sin^{ - 1}(0.6) \}$ ㅤ ANSWER :– ㅤ • VALUE = 0.96 ㅤ EXPLANATION :– ㅤ GIVEN :– ㅤ • $\bf\sin \{2\sin^{ - 1}(0.6) \}$ ㅤ TO FIND :– ㅤ • Value = ? ㅤ SOLUTION :– ㅤ • LET the FUNCTION – ㅤ $\bf \implies y = \sin \{2\sin^{ - 1}(0.6) \}$ ㅤ • We know that – ㅤ $\bf \implies 2\sin^{ - 1}(x) = { \sin }^{ - 1}(2x \sqrt{1 - {x}^{2} })$ ㅤ • So that – ㅤ $\bf \implies y = \sin \{\sin^{ - 1} \{2(0.6) \sqrt{1 - {(0.6)}^{2} } \} \}$ ㅤ $\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{1 - 0.36 } \} \}$ ㅤ $\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{0.64}\} \}$ ㅤ $\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{0.8 \times 0.8}\} \}$ ㅤ $\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) (0.8) \}$ ㅤ $\bf \implies y = \sin \{\sin^{ - 1} \{(0.96) \}$ ㅤ $\bf \implies \large{ \boxed{ \bf y =0.96}}$

6.

Evalute sin(2sin inverse 0.6

Answer»

QUESTION :–

ㅤ

$\bf \implies Evaluate\:\:\sin \{2\sin^{ - 1}(0.6) \}$

ㅤ

ANSWER :–

ㅤ

• VALUE = 0.96

ㅤ

EXPLANATION :–

ㅤ

GIVEN :–

ㅤ

• $\bf\sin \{2\sin^{ - 1}(0.6) \}$

ㅤ

TO FIND :–

ㅤ

• Value = ?

ㅤ

SOLUTION :–

ㅤ

• LET the FUNCTION –

ㅤ

$\bf \implies y = \sin \{2\sin^{ - 1}(0.6) \}$

ㅤ

• We know that –

ㅤ

$\bf \implies 2\sin^{ - 1}(x) = { \sin }^{ - 1}(2x \sqrt{1 - {x}^{2} })$

ㅤ

• So that –

ㅤ

$\bf \implies y = \sin \{\sin^{ - 1} \{2(0.6) \sqrt{1 - {(0.6)}^{2} } \} \}$

ㅤ

$\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{1 - 0.36 } \} \}$

ㅤ

$\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{0.64}\} \}$

ㅤ

$\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{0.8 \times 0.8}\} \}$

ㅤ

$\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) (0.8) \}$

ㅤ

$\bf \implies y = \sin \{\sin^{ - 1} \{(0.96) \}$

ㅤ

$\bf \implies \large{ \boxed{ \bf y =0.96}}$

Discussion

7.	A Covex mirror is present 5m awayfrom a tree of height 2m. If thefocal length of the mirror is 1.5mcalculate the position and size ofthe image
Answer» ANSWER: The answer is 6/13. Step-by-step explanation: u=-5m f=1.5m Applying MIRROR formula: 1/f=1/u+1/v 1/1.5=1/-5+1/v 1/v=2/3+1/5=13/15=>v=15/13m Now OBJECT HEIGHT is=2m Let, the IMAGE height is=xm So,x/2=(-15/13)/-5=3/13 X=3/13*2/1 ∆x=6/13.

7.

A Covex mirror is present 5m awayfrom a tree of height 2m. If thefocal length of the mirror is 1.5mcalculate the position and size ofthe image

Answer»

ANSWER:

The answer is 6/13.

Step-by-step explanation:

u=-5m

f=1.5m

Applying MIRROR formula:

1/f=1/u+1/v

1/1.5=1/-5+1/v

1/v=2/3+1/5=13/15=>v=15/13m

Now OBJECT HEIGHT is=2m

Let, the IMAGE height is=xm

So,x/2=(-15/13)/-5=3/13

X=3/13*2/1

∆x=6/13.

Discussion

8.	Arrange them in increasing order - 160, 154, 158, 159.
Answer» Solution: $\text{[math]}$ 154 < 158 < 159 < 160

8.

Arrange them in increasing order - 160, 154, 158, 159.

Answer»

Solution:

$\text{[math]}$

154 < 158 < 159 < 160

Discussion

9.	1)what is the mean of whole number?
Answer» In mathematics, WHOLE numbers are the basic COUNTING numbers 0, 1, 2, 3, 4, 5, 6, … and so on. ... Whole numbers INCLUDE natural numbers that BEGIN from 1 onwards. Whole numbers include positive integers along with 0. Fun Facts. There is no 'largest' whole number.

9.

1)what is the mean of whole number?

Answer»

In mathematics, WHOLE numbers are the basic COUNTING numbers 0, 1, 2, 3, 4, 5, 6, … and so on. ... Whole numbers INCLUDE natural numbers that BEGIN from 1 onwards. Whole numbers include positive integers along with 0. Fun Facts. There is no 'largest' whole number.

Discussion

10.	45342 डिवाइडेड बाय 89
Answer» ANSWER: kvvshdhdjjcjxkzkdkdkkdjdjdjjx

10.

45342 डिवाइडेड बाय 89

Answer»

ANSWER:

kvvshdhdjjcjxkzkdkdkkdjdjdjjx

Discussion

11.	Plz ans plz fast .. ....
Answer» Answer: 7.5 sq.cm. for both the TRIANGLES Step-by-step EXPLANATION: for both triangles , B=5cm h=3cm therefore ,by FORMULA A=1/2bh A=7.5 sq.cm

11.

Plz ans plz fast .. ....

Answer»

Answer:

7.5 sq.cm. for both the TRIANGLES

Step-by-step EXPLANATION:

for both triangles ,

B=5cm

h=3cm

therefore ,by FORMULA

A=1/2*b*h

A=7.5 sq.cm

Discussion

12.	PageAdditive in vergeofWim23Work the meltiplicative Evense of - 13/19 and
Answer» ANSWER: OP itgam Step-by-step EXPLANATION: jbbabnjbbajjahah iuha

12.

PageAdditive in vergeofWim23Work the meltiplicative Evense of - 13/19 and

Answer»

ANSWER:

OP itgam

Step-by-step EXPLANATION:

jbbabnjbbajjahah iuha

Discussion

13.	The sum of zero's of polynomial2x square -8x+6_
Answer» ANSWER: hey mate,, here is your answer.. Step-by-step explanation: polynomial : 2x^2 - 8X + 6 a = 2, b = -8, c = 6 sum of roots = -b / a = - (-8) / 2 = +8 / 2 *:- sum of roots = + 4* hope it helps u FRND !

13.

The sum of zero's of polynomial2x square -8x+6_

Answer»

ANSWER:

hey mate,, here is your answer..

Step-by-step explanation:

polynomial : 2x^2 - 8X + 6

a = 2, b = -8, c = 6

sum of roots = -b / a

= - (-8) / 2

= +8 / 2

:- sum of roots = + 4

hope it helps u FRND !

Discussion

14.	if , prove that
Answer» $if {2}^a = {5}^b = {10}^c$ , PROVE that $\frac{1}{a} + \frac{1}{b} = \frac{1}{c}$ HOPE IT WILL HELP YOU

14.

if , prove that

Answer»

$if {2}^a = {5}^b = {10}^c$ , PROVE that $\frac{1}{a} + \frac{1}{b} = \frac{1}{c}$

HOPE IT WILL HELP YOU

Discussion

15.	4) The line segment joining points (-3,4)and (1, 2) is divided by Y-axis in the ratio
Answer» Answer: The point that divides the line segment joining the POINTS (-3, -4) and (1, -2) is WRITTEN as (0, t). Thus, the required RATIO is 3 : 1. Step-by-step explanation: hope this ans will help you plz follow me..

15.

4) The line segment joining points (-3,4)and (1, 2) is divided by Y-axis in the ratio

Answer»

Answer:

The point that divides the line segment joining the POINTS (-3, -4) and (1, -2) is WRITTEN as (0, t). Thus, the required RATIO is 3 : 1.

Step-by-step explanation:

hope this ans will help you

plz follow me..

Discussion

16.	If x = 9 + 4v5find the value of √x-1/√x
Answer» Answer: 4 Step-by-step EXPLANATION: → x = 9 + 4√5 → x = 5 + 4 + 4√5 → x = (√5)² + (√4)² + 22√5 → x = (√5)² + (2)² + 22√5 (a+b)² = a² + b² + 2ab → x = (√5 + 2)² → √x = √5 + 2 → 1/√x = 1/(√5 + 2) Multiply as well as divide by √5 - 2: → 1/√x = (√5 - 2)/(√5 + 2)(√5 - 2) → 1/√x = (√5 - 2)/(√5² - 2²) → 1/√x = (√5 - 2)/(5-4) = √5 - 2 Thus, = > √x - 1/√x = > √5 + 2 - (√5 - 2) = > 4

16.

If x = 9 + 4v5find the value of √x-1/√x

Answer»

Answer:

4

Step-by-step EXPLANATION:

→ x = 9 + 4√5

→ x = 5 + 4 + 4√5

→ x = (√5)² + (√4)² + 2*2*√5

→ x = (√5)² + (2)² + 2*2*√5

(a+b)² = a² + b² + 2*a*b

→ x = (√5 + 2)²

→ √x = √5 + 2

→ 1/√x = 1/(√5 + 2)

Multiply as well as divide by √5 - 2:

→ 1/√x = (√5 - 2)/(√5 + 2)(√5 - 2)

→ 1/√x = (√5 - 2)/(√5² - 2²)

→ 1/√x = (√5 - 2)/(5-4) = √5 - 2

Thus,

= > √x - 1/√x

= > √5 + 2 - (√5 - 2)

= > 4

Discussion

17.	12. In the given figure, find the sum of the anglesPQR, ORS, RST, STP and TPQ
Answer» Hey Buddy Here's The Answer ----------------------------------------------------------- According to figure we'll have to find the sum of all angles of the polygon. So, Here's the master formula to find sum of all interior angles of any polygon => Sum of all interior angles = ( n - 2 ) × 180° Where n is number of SIDES of polygon. In this CASE, n = 5 => Sum of all INTERIOR angles = ( 5 - 2 ) × 180° => Sum of all interior angles = 3 × 180° => Sum of all interior angles = 540° Hope It Helps.

17.

12. In the given figure, find the sum of the anglesPQR, ORS, RST, STP and TPQ

Answer»

Hey Buddy

Here's The Answer

-----------------------------------------------------------

According to figure we'll have to find the sum of all angles of the polygon.

So, Here's the master formula to find sum of all interior angles of any polygon

=> Sum of all interior angles = ( n - 2 ) × 180°

Where n is number of SIDES of polygon.

In this CASE, n = 5

=> Sum of all INTERIOR angles = ( 5 - 2 ) × 180°

=> Sum of all interior angles = 3 × 180°

=> Sum of all interior angles = 540°

Hope It Helps.

Discussion

18.	7 boys were weighted and their weight ( in kg ) are as follows :35, 39, 49, 41, 45, 56, 60 find the median weightHow to solve
Answer» Answer: Arranging them in acsending order: 35,39,41,45,49,56,60.p Median WEIGHT of them 45+49. 94. _____ _____ = 47 2 2 Correct answer- 47 Hence,median is 47. HOPE it helps you.....

18.

7 boys were weighted and their weight ( in kg ) are as follows :35, 39, 49, 41, 45, 56, 60 find the median weightHow to solve

Answer»

Answer:

Arranging them in acsending order:

35,39,41,45,49,56,60.p

Median WEIGHT of them

45+49. 94.

_____ _____ = 47

2 2

Correct answer- 47

Hence,median is 47.

HOPE it helps you.....

Discussion

19.	Cards numbered from 1 to 60 are kept in a box. if a card is drawn at random from the box. The probability that the number on the drawn card is divisible by 3
Answer» Step-by-step explanation: Solution(i): Let E be the event of drawing a NUMBER from the cards numbered from 11 to 60 ODD NUMBERS from 11 to 60=11,13,15,.....,89 No. of favorable outcomes=25 Total no. of possible outcomes =50 We know that, Probability P(E) = (Total no.of possible outcomes) (No.of favorable outcomes) = 50 25 = 2 1 Therefore, the probability of an odd number from the cards numbered 11 to 60= 2 1 Solution(ii): Let F be the event of drawing a perfect SQUARE number from the cards numbered from 11 to 60 Perfect square numbers from 11 to 60=16,25,36,49 No. of favorable outcomes=4 Total no. of possible outcomes =50 We know that, Probability P(F) = (Total no.of possible outcomes) (No.of favorable outcomes) = 50 4 = 25 2 Therefore, the probability of drawing a perfect square number from the cards numbered from 11 to 60= 25 2 Solution(III): Let G be the event of drawing a number divisible by 5 from the cards numbered from 11 to 60 Numbers divisible by 5 from 11 to 60=15,20,25,30,35,40,45,50,55,60 No. of favorable outcomes=10 Total no. of possible outcomes =50 We know that, Probability P(G) = (Total no.of possible outcomes) (No.of favorable outcomes) = 50 10 = 5 1 Therefore, the probability of drawing a number divisible by 5 from the cards numbered from 11 to 60= 5 1 Solution(iv): Let H be the event of drawing a prime number less than 20 from the cards numbered from 11 to 60 Prime numbers less than 20 from 11 to 60=11,13,17,19 No. of favorable outcomes=4 Total no. of possible outcomes =50 We know that, Probability P(H) = (Total no.of possible outcomes) (No.of favorable outcomes) = 50 4 = 25 2 Therefore, the probability of drawing a prime number less than 20 from the cards numbered from 11 to 60= 25 2

19.

Cards numbered from 1 to 60 are kept in a box. if a card is drawn at random from the box. The probability that the number on the drawn card is divisible by 3

Answer»

Step-by-step explanation:

Solution(i):

Let E be the event of drawing a NUMBER from the cards numbered from 11 to 60

ODD NUMBERS from 11 to 60=11,13,15,.....,89

No. of favorable outcomes=25

Total no. of possible outcomes =50

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

25

=

2

1

Therefore, the probability of an odd number from the cards numbered 11 to 60=

2

1

Solution(ii):

Let F be the event of drawing a perfect SQUARE number from the cards numbered from 11 to 60

Perfect square numbers from 11 to 60=16,25,36,49

No. of favorable outcomes=4

Total no. of possible outcomes =50

We know that, Probability P(F) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

4

=

25

2

Therefore, the probability of drawing a perfect square number from the cards numbered from 11 to 60=

25

2

Solution(III):

Let G be the event of drawing a number divisible by 5 from the cards numbered from 11 to 60

Numbers divisible by 5 from 11 to 60=15,20,25,30,35,40,45,50,55,60

No. of favorable outcomes=10

Total no. of possible outcomes =50

We know that, Probability P(G) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

10

=

5

1

Therefore, the probability of drawing a number divisible by 5 from the cards numbered from 11 to 60=

5

1

Solution(iv):

Let H be the event of drawing a prime number less than 20 from the cards numbered from 11 to 60

Prime numbers less than 20 from 11 to 60=11,13,17,19

No. of favorable outcomes=4

Total no. of possible outcomes =50

We know that, Probability P(H) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

4

=

25

2

Therefore, the probability of drawing a prime number less than 20 from the cards numbered from 11 to 60=

25

2

Discussion

20.	The HCF of two numbers is 16 and their product is 3072. Then LCM is:
Answer» ANSWER: LCM= PRODUCT of the no.s/HCF =3072/16 =192 ANS.... Step-by-step EXPLANATION: follow me PLZ

20.

The HCF of two numbers is 16 and their product is 3072. Then LCM is:

Answer»

ANSWER:

LCM= PRODUCT of the no.s/HCF

=3072/16

=192

ANS....

Step-by-step EXPLANATION:

follow me PLZ

Discussion

21.	Ton!a tb tonabro tonne
Answer» ?????KYA????? PLEASE SUBSCRIBE my CHANNEL--HIDDEN TECH-STARS

21.

Ton!a tb tonabro tonne

Answer»

?????KYA?????

PLEASE SUBSCRIBE my CHANNEL--HIDDEN TECH-STARS

Discussion

22.	Find greatest 4digit number which is divisible by 10,15,21,and 28
Answer»

Discussion

23.	If √5 = 2.23 and √7 = 2.64 then correct to one decimal place the value of 1/√7-√5
Answer» Answer: 2.44 Step-by-step EXPLANATION: 1÷ ( √7-√5) = 1 ÷ 0.409 = 2.44

23.

If √5 = 2.23 and √7 = 2.64 then correct to one decimal place the value of 1/√7-√5

Answer»

Answer:

2.44

Step-by-step EXPLANATION:

1÷ ( √7-√5)

= 1 ÷ 0.409

= 2.44

Discussion

24.	The equation (x-2) (x+1) = (x-1) (x+3)_quadratic equation
Answer» Step-by-step EXPLANATION: this the RIGHT answer. so PLEASE MARK me as brainliest

24.

The equation (x-2) (x+1) = (x-1) (x+3)_quadratic equation

Answer»

Step-by-step EXPLANATION:

this the RIGHT answer. so PLEASE MARK me as brainliest

Discussion

25.	Find the cube root by prime factorisation method. *6859(full fourmula)
Answer» Answer: 19 Step-by-step EXPLANATION: I learned cube ROOT TILL 30 so I know the answer without SOLVING it with method

25.

Find the cube root by prime factorisation method. *6859(full fourmula)

Answer»

Answer:

19

Step-by-step EXPLANATION:

I learned cube ROOT TILL 30 so I know the answer without SOLVING it with method

Discussion

26.	The polygon is said to be convex polygon if none of its interior angles is
Answer» Answer: A polygon is called a convex polygon if all the interior angles are LESS than 180°. Step-by-step EXPLANATION: i think it MAY HELP you pls MARK me as brainly list pls

26.

The polygon is said to be convex polygon if none of its interior angles is

Answer»

Answer:

A polygon is called a convex polygon if all the interior angles are LESS than 180°.

Step-by-step EXPLANATION:

i think it MAY HELP you pls MARK me as brainly list pls

Discussion

27.	Simplify1/2÷2/1 please answer
Answer» Answer: 1/2÷2/1 1/2×1/2 1/4 ans ....... hope you LIKED the ans if yes MARK as BRAINLEAST

27.

Simplify1/2÷2/1 please answer

Answer»

Answer:

1/2÷2/1

1/2×1/2

1/4 ans .......

hope you LIKED the ans if yes MARK as BRAINLEAST

Discussion

28.	TIME - 8:00 – 9:00 AMFULLMARRCL- VIY (8) SUBJECT – MATHSI Answer the balisaseng qua fénye 10x4 =12ca) in Fig. 16:25 the measurementsare; Asoom FG = 30mAH = 190m CH - fom BG = 50mEF = 30m HD=20m. Findthe area of polygonEABCDEFigillFig. 16.253Fcb findA
Answer» ANSWER: WHT ....??????????????????

28.

TIME - 8:00 – 9:00 AMFULLMARRCL- VIY (8) SUBJECT – MATHSI Answer the balisaseng qua fénye 10x4 =12ca) in Fig. 16:25 the measurementsare; Asoom FG = 30mAH = 190m CH - fom BG = 50mEF = 30m HD=20m. Findthe area of polygonEABCDEFigillFig. 16.253Fcb findA

Answer»

ANSWER:

WHT ....??????????????????

Discussion

29.	Tan theta - cot theta = 2 sin2 theta -1/sin theta cos theta
Answer» ANSWER: tanθ - cotθ ≠ 2sin²θ - 1/(sinθ * cosθ) Step-by-step EXPLANATION: LHS = tanθ - cotθ = (sinθ/cosθ)-(cosθ/sinθ) = (sin²θ - cos²θ)/sinθ * cosθ RHS = 2sin²θ - 1/(sinθ * cosθ) LHS ≠ RHS Hence, tanθ - cotθ ≠ 2sin²θ - 1/(sinθ * cosθ)

29.

Tan theta - cot theta = 2 sin2 theta -1/sin theta cos theta

Answer»

ANSWER:

tanθ - cotθ ≠ 2sin²θ - 1/(sinθ * cosθ)

Step-by-step EXPLANATION:

LHS = tanθ - cotθ

= (sinθ/cosθ)-(cosθ/sinθ)

= (sin²θ - cos²θ)/sinθ * cosθ

RHS = 2sin²θ - 1/(sinθ * cosθ)

LHS ≠ RHS

Hence, tanθ - cotθ ≠ 2sin²θ - 1/(sinθ * cosθ)

Discussion

30.	Find the values of a and b if ( 2 marks) 5+√3/5-3 = a+b√15 value of a is
Answer» ANSWER: Step-by-step EXPLANATION: PLEASE MARK me as BRAINLIEST

30.

Find the values of a and b if ( 2 marks) 5+√3/5-3 = a+b√15 value of a is

Answer»

ANSWER:

Step-by-step EXPLANATION:

PLEASE MARK me as BRAINLIEST

Discussion

31.	The length, breadth and height of a room are 12 m, 10 m, and 9 m respectively. Find the area of walls of room that are to be painted.
Answer» ANSWER: The length, breadth and height of a room are 5 m, 4 m and 3 m RESPECTIVELY. ... It can be OBSERVED that four walls and the CEILING of the room are to be ... Find the lateral surface area of the new cube formed. Step-by-step explanation: hope this ans will HELP you plz follow me...

31.

The length, breadth and height of a room are 12 m, 10 m, and 9 m respectively. Find the area of walls of room that are to be painted.

Answer»

ANSWER:

The length, breadth and height of a room are 5 m, 4 m and 3 m RESPECTIVELY. ... It can be OBSERVED that four walls and the CEILING of the room are to be ... Find the lateral surface area of the new cube formed.

Step-by-step explanation:

hope this ans will HELP you

plz follow me...

Discussion

32.	(-2^6)×(5/2)^3 tell answer
Answer» $ANSWER$ $( { - 2}^{6} ) \times ( \frac{5}{2}) ^{3}$ $64 \times \frac{125}{8}$ ${ \cancel{64}} ^{8} \times \frac{125}{ \cancel{8} }$ $8 \times 125$ $= 1000$ $\mathsf \color{lime}{hope \: it \: helps \: you}$

32.

(-2^6)×(5/2)^3 tell answer

Answer»

$ANSWER$

$( { - 2}^{6} ) \times ( \frac{5}{2}) ^{3}$

$64 \times \frac{125}{8}$

${ \cancel{64}} ^{8} \times \frac{125}{ \cancel{8} }$

$8 \times 125$

$= 1000$

$\mathsf \color{lime}{hope \: it \: helps \: you}$

Discussion

33.	Lcm of 23 ,69 answer me
Answer» Answer: gcf of 23 and 69. This is the easiest approach: lcm (23,69) = \frac{23 \times 69}{gcf(23,69)} = \frac{1587}{23} gcf(23,69) 23×69 = 23 1587 = 69 Alternatively, the lcm of 23 and 69 can be found using the prime factorization of 23 and 69: The prime factorization of 23 is: 23 The prime factorization of 69 is: 3 X 23 Eliminate the duplicate factors of the two LISTS, then multiply them once with the remaining factors of the lists to get lcm(23,23) = 69 Step-by-step explanation: Hope it HELPS you.... :] Good Morning

33.

Lcm of 23 ,69 answer me

Answer»

Answer:

gcf of 23 and 69. This is the easiest approach:

lcm (23,69) = \frac{23 \times 69}{gcf(23,69)} = \frac{1587}{23}

gcf(23,69)

23×69

=

23

1587

= 69

Alternatively, the lcm of 23 and 69 can be found using the prime factorization of 23 and 69:

The prime factorization of 23 is: 23

The prime factorization of 69 is: 3 X 23

Eliminate the duplicate factors of the two LISTS, then multiply them once with the remaining factors of the lists to get lcm(23,23) = 69

Step-by-step explanation:

Hope it HELPS you.... :]

Good Morning

Discussion

34.	দূটি f, ও f, ফোকাস দৈর্ঘ্যের পাতলা লেন্সকে পরস্পরের সংস্পর্শে রাখলে দেখাও যে, এদের তুল্যাঙ্ক ফোকাস
Answer» ANSWER: আমি এই প্রশ্নের উত্তর দিতে পারছি না Step-by-step EXPLANATION: FOLLOW me

34.

দূটি f, ও f, ফোকাস দৈর্ঘ্যের পাতলা লেন্সকে পরস্পরের সংস্পর্শে রাখলে দেখাও যে, এদের তুল্যাঙ্ক ফোকাস

Answer»

ANSWER:

আমি এই প্রশ্নের উত্তর দিতে পারছি না

Step-by-step EXPLANATION:

FOLLOW me

Discussion

35.	If m times the mth term of an ap is equal to n times the nth term, find the 16th term
Answer» Step-by-step explanation: The given sequence is 20, 17, 14, .............. The nth term of this sequence is given by t N =a+(n−1)d. To find the FIRST negative term, t n should be less than 0. We have 'a' = 20, 'd' = -3 a+(n−1)d<0 ⟹20+(n−1)(−3)<0 ⟹20+3−3n<0 ⟹23−3n<0 ⟹3n>23orn> 3 23 . The next natural number greater than 7.6 is 8. Hence, the 8th term is the first negative number.

35.

If m times the mth term of an ap is equal to n times the nth term, find the 16th term

Answer»

Step-by-step explanation:

The given sequence is 20, 17, 14, ..............

The nth term of this sequence is given by t

N

=a+(n−1)d.

To find the FIRST negative term, t

n

should be less than 0.

We have 'a' = 20, 'd' = -3

a+(n−1)d<0

⟹20+(n−1)(−3)<0

⟹20+3−3n<0

⟹23−3n<0

⟹3n>23orn>

3

23

.

The next natural number greater than 7.6 is 8.

Hence, the 8th term is the first negative number.

Discussion

36.	The class mark of the class interval 13-19 is
Answer» ANSWER of this QUESTION is 16

36.

The class mark of the class interval 13-19 is

Answer»

ANSWER of this QUESTION is

16

Discussion

37.	3 р.2. The Mean of 50observations was 180. It wasobserved that the value of 170was wrongly copied as 120.Find the correct Mean (3marks)
Answer» ANSWER: Step-by-step EXPLANATION: X = 50180 x = 50180 - 140+170 x= 50*100+30/50 x= 530/50 x = 10.6 so, the mean is 10.6 hope this HELPS!

37.

3 р.2. The Mean of 50observations was 180. It wasobserved that the value of 170was wrongly copied as 120.Find the correct Mean (3marks)

Answer»

ANSWER:

Step-by-step EXPLANATION:

X = 50*180

x = 50*180 - 140+170

x= 50*100+30/50

x= 530/50

x = 10.6

so, the mean is 10.6

hope this HELPS!

Discussion

38.	Regroup and factorise 3xy-4y-3x+4 please
Answer» ANSWER: (a) 3x(y-1)-4(y-1) (y-1)(3x-4) (B) 5y(3x+2)+2(2+3x) (3x+2)(5y+2) Step-by-step explanation: PLEASE mark me as brainliest

38.

Regroup and factorise 3xy-4y-3x+4 please

Answer»

ANSWER:

(a)

3x(y-1)-4(y-1)

(y-1)(3x-4)

(B)

5y(3x+2)+2(2+3x)

(3x+2)(5y+2)

Step-by-step explanation:

PLEASE mark me as brainliest

Discussion

39.	7 boys were weighted and their weight ( in kg ) are as follows :35, 39, 49, 41, 45, 56, 60 find the median weight
Answer» Step-by-step explanation: 41 is the MEDIAN of GIVEN DATA.

39.

7 boys were weighted and their weight ( in kg ) are as follows :35, 39, 49, 41, 45, 56, 60 find the median weight

Answer»

Step-by-step explanation:

41 is the MEDIAN of GIVEN DATA.

Discussion

40.	Coefficient of x^2 in (3x+4)(3x-5) is
Answer» Answer: HEY mate,, here is your answer.. Step-by-step explanation: THEREFORE, ( 3x + 4 )( 3x - 5 ) 9x^2 - 15X + 12X - 20 9x^2 - 3x - 20 therefore, *coefficient of x^2 = 9* hope it helps u FRND !

40.

Coefficient of x^2 in (3x+4)(3x-5) is

Answer»

Answer:

HEY mate,, here is your answer..

Step-by-step explanation:

THEREFORE, ( 3x + 4 )( 3x - 5 )

9x^2 - 15X + 12X - 20

9x^2 - 3x - 20

therefore, coefficient of x^2 = 9

hope it helps u FRND !

Discussion

41.	A vector .a vector= (ab)^2
Answer» ANSWER: so what gadhay QUESTION to dhangh SE LIKH

41.

A vector .a vector= (ab)^2

Answer»

ANSWER:

so what gadhay QUESTION to dhangh SE LIKH

Discussion

42.	If P is equal to 3 minus root under 5 by 3 + root 5 and q is equal to 3 + root under 5 by 3 minus root under 5 find the value of p square + Q square
Answer» <P>Step-by-step EXPLANATION: p SQUARE +Q square = 47.

42.

If P is equal to 3 minus root under 5 by 3 + root 5 and q is equal to 3 + root under 5 by 3 minus root under 5 find the value of p square + Q square

Answer»

<P>Step-by-step EXPLANATION:

p SQUARE +Q square = 47.

Discussion

43.	If a=bq+r where a=75, b=8 then q,r respectively --
Answer» Given : a=bq+r where a=75, B=8 To Find : q,r SOLUTION: Euclid's Division Lemma states that, if two positive integers “a” and “b”, then there exists unique integers “q” and “r” such that which satisfies the condition a = bq + r where 0 ≤ r < b. a=bq+r a= Dividend, b= Divisor, q= quotient r = remainder a = bq + r a = 75 b = 8 75 = 8 * 9 + 3 a = bq + r => q = 9 r = 3 Learn More: If a= bq+r, LEAST VALUE of r is - Brainly.in brainly.in/question/14679641 17=6×2+5 is compared with Euclid division lemma a=bq+r then ... brainly.in/question/9899330

43.

If a=bq+r where a=75, b=8 then q,r respectively --

Answer»

Given : a=bq+r where a=75, B=8

To Find : q,r

SOLUTION:

Euclid's Division Lemma states that,

if two positive integers “a” and “b”,

then there exists unique integers “q” and “r”

such that which satisfies the condition

a = bq + r where 0 ≤ r < b.

a=bq+r

a= Dividend,

b= Divisor,

q= quotient

r = remainder

a = bq + r

a = 75

b = 8

75 = 8 * 9 + 3

a = bq + r

=> q = 9

r = 3

Learn More:

If a= bq+r, LEAST VALUE of r is - Brainly.in

brainly.in/question/14679641

17=6×2+5 is compared with Euclid division lemma a=bq+r then ...

brainly.in/question/9899330

Discussion

44.	5y+10=4y-10 then find the value of y
Answer» Answer: 5y + 10 = 4Y - 10 5y - 4y = -10 -10 y = -20

44.

5y+10=4y-10 then find the value of y

Answer»

Answer:

5y + 10 = 4Y - 10

5y - 4y = -10 -10

y = -20

Discussion

45.	Solve the followingpair of equation and find x and y 2/x-1+3/y-2=1,5/x-1+6/y-2=1
Answer» ANSWER: HAPPY TEACHERS DAY ♥️♥️♥️♥️

45.

Solve the followingpair of equation and find x and y 2/x-1+3/y-2=1,5/x-1+6/y-2=1

Answer»

ANSWER:

HAPPY TEACHERS DAY ♥️♥️♥️♥️

Discussion

46.	How to express 9xy to the power of 2 z
Answer» Step-by-step explanation: We KNOW that, B 3 = b×b×b. So, 9xy 2 Z 2 =9×x×y×y×z×z. HOPE MY ANSWER WILL HELP YOU....

46.

How to express 9xy to the power of 2 z

Answer»

Step-by-step explanation:

We KNOW that,

B

3

= b×b×b.

So,

9xy

2

Z

2

=9×x×y×y×z×z.

HOPE MY ANSWER WILL

HELP YOU....

Discussion

47.	From a standard deck of 52 cards in how many ways can 7 cards be drawn
Answer» Step-by-step EXPLANATION: No. Of *Deck* *CARDS* = 52 *ways* *cards* *can* be *DRAWN* = 7 *TOTAL* no. of *ways* *can* 7 *cards* be *drawn* = 52÷7 = Q= 7 R =3 *Ans* *statement*. so, in 7 ways can no. of cards be drawn**.

47.

From a standard deck of 52 cards in how many ways can 7 cards be drawn

Answer»

Step-by-step EXPLANATION:

No. Of Deck CARDS = 52

ways cards can be DRAWN = 7

TOTAL no. of ways can 7 cards be drawn = 52÷7

= Q= 7 R =3

Ans statement. so, in 7 ways can no. of cards be drawn.

Discussion

48.	Alegurar 20-gonFig 3.10Example 2: Find the number of sides of a regular polygon whose each exterior anglehas a measure of 45°.
Answer» $\huge\mathfrak\red{Given}\::$ Measure of exterior angle of a POLYGON is 45° $\huge\mathfrak\green{To\:Find}\::$ No. of SIDES of regular polygon $\huge\mathfrak\blue{Solution}\::$ ◉ ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ ◉ ◆ Sum of all exterior ANGLES = 360° ➪ No. of exterior angles = $\sf{\dfrac{\cancel{360}}{\cancel{45}} \ = \ <klux>8</klux>}$ ★ No. of sides of regular polygon is 8 ◦•●◉✿ ᴘᴏɪɴᴛ ᴛᴏ ʀᴇᴍᴇᴍʙᴇʀ ✿◉●•◦ ☛ No.of exterior angles = No. of sides of polygon

48.

Alegurar 20-gonFig 3.10Example 2: Find the number of sides of a regular polygon whose each exterior anglehas a measure of 45°.

Answer»

$\huge\mathfrak\red{Given}\::$

Measure of exterior angle of a POLYGON is 45°

$\huge\mathfrak\green{To\:Find}\::$

No. of SIDES of regular polygon

$\huge\mathfrak\blue{Solution}\::$

◉ ᴡᴇ ᴋɴᴏᴡ ᴛʜᴀᴛ ◉

◆ Sum of all exterior ANGLES = 360°

➪ No. of exterior angles = $\sf{\dfrac{\cancel{360}}{\cancel{45}} \ = \ <klux>8</klux>}$

★ No. of sides of regular polygon is 8

◦•●◉✿ ᴘᴏɪɴᴛ ᴛᴏ ʀᴇᴍᴇᴍʙᴇʀ ✿◉●•◦

☛ No.of exterior angles = No. of sides of polygon

Discussion

49.	Mark the periods with commas in the international place value system also write the number names 1.47012615
Answer» Step-by-step EXPLANATION: 1.47012615 PLEASE MAKE this BRILLIANT and LIKE me please

49.

Mark the periods with commas in the international place value system also write the number names 1.47012615

Answer»

Step-by-step EXPLANATION:

1.47012615

PLEASE MAKE this BRILLIANT and LIKE me please

Discussion

50.	A wire of length and and resistance is ab a Raha of length L and resistance R is stretched to get the radius of course section halved what is the new resistance of wire after stretching
Answer» ANSWER: HOPE this HELPS you and your ANS is in the PICTURE

50.

A wire of length and and resistance is ab a Raha of length L and resistance R is stretched to get the radius of course section halved what is the new resistance of wire after stretching

Answer»

ANSWER:

HOPE this HELPS you and your ANS is in the PICTURE

Discussion

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