Step-by-step explanation:

Solution(i):

Let E be the event of drawing a NUMBER from the cards numbered from 11 to 60

ODD NUMBERS from 11 to 60=11,13,15,.....,89

No. of favorable outcomes=25

Total no. of possible outcomes =50

We know that, Probability P(E) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

25

=

2

1

Therefore, the probability of an odd number from the cards numbered 11 to 60=

2

1

Solution(ii):

Let F be the event of drawing a perfect SQUARE number from the cards numbered from 11 to 60

Perfect square numbers from 11 to 60=16,25,36,49

No. of favorable outcomes=4

Total no. of possible outcomes =50

We know that, Probability P(F) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

4

=

25

2

Therefore, the probability of drawing a perfect square number from the cards numbered from 11 to 60=

25

2

Solution(III):

Let G be the event of drawing a number divisible by 5 from the cards numbered from 11 to 60

Numbers divisible by 5 from 11 to 60=15,20,25,30,35,40,45,50,55,60

No. of favorable outcomes=10

Total no. of possible outcomes =50

We know that, Probability P(G) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

10

=

5

1

Therefore, the probability of drawing a number divisible by 5 from the cards numbered from 11 to 60=

5

1

Solution(iv):

Let H be the event of drawing a prime number less than 20 from the cards numbered from 11 to 60

Prime numbers less than 20 from 11 to 60=11,13,17,19

No. of favorable outcomes=4

Total no. of possible outcomes =50

We know that, Probability P(H) =

(Total no.of possible outcomes)

(No.of favorable outcomes)

=

50

4

=

25

2

Therefore, the probability of drawing a prime number less than 20 from the cards numbered from 11 to 60=

25

2