1.

Evalute sin(2sin inverse 0.6​

Answer»

QUESTION :–

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\bf \implies Evaluate\:\:\sin \{2\sin^{ - 1}(0.6) \}

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ANSWER :–

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• VALUE = 0.96

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EXPLANATION :–

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GIVEN :–

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• \bf\sin \{2\sin^{ - 1}(0.6) \}

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TO FIND :–

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• Value = ?

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SOLUTION :–

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• LET the FUNCTION –

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\bf \implies y = \sin \{2\sin^{ - 1}(0.6) \}

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• We know that –

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\bf \implies 2\sin^{ - 1}(x) = { \sin }^{ - 1}(2x \sqrt{1 - {x}^{2} })

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• So that –

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\bf \implies y = \sin \{\sin^{ - 1} \{2(0.6) \sqrt{1 - {(0.6)}^{2} } \} \}

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\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{1 - 0.36 } \} \}

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\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{0.64}\} \}

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\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) \sqrt{0.8 \times 0.8}\} \}

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\bf \implies y = \sin \{\sin^{ - 1} \{(1.2) (0.8) \}

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\bf \implies y = \sin \{\sin^{ - 1} \{(0.96) \}

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\bf \implies \large{ \boxed{ \bf y =0.96}}


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