This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
The fourth part of a number exceeds the sixth part by the number is |
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Answer» Answer: Let the number be 'x ' Fourth part of a number = x/4 Sixth part = x/ 6 x/4 =( x/6) +4 x/4 -x/6 = 4 2x/24 =4 x/12 = 4 x = 12*4 x = 48 |
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| 2. |
. If the diameter of circle is 14 cm then what will be it's area *14π7π49π50π |
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Answer» Ans=14 Step-by-step EXPLANATION: GO for it it's CORRECT |
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| 3. |
Rationalize the denominator of 1/2√7+3√3 |
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Answer» Answer: always MULTIPLY by negative SIGN of same number in both SIDES |
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| 4. |
From the choices given below,choose the equation whose graph is given |
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Answer» Answer: Step-by-step EXPLANATION: A pictogram, also CALLED a pictogramme, pictograph, or simply picto, and in computer USAGE an icon, is a GRAPHIC symbol that conveys its meaning through its pictorial resemblance to a PHYSICAL object. |
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| 5. |
Find the height of triangle whose area is 45and base is 15 cm. |
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Answer» |
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| 6. |
Find the first three value term of an A P , whose first is -2 and common difference is -2 |
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Answer» Step-by-step EXPLANATION: the SECOND term is=0 the THIRD term is=-6 |
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| 7. |
What are the roots of the quadratic equation x2 = 16? |
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Answer» Hi friend Step-by-step explanation: |
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| 8. |
Calculate165-39.5/46*5 |
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Answer» Answer: 165-39.5/46*5=160.706521739 |
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| 9. |
10 added to the product of 4 and x is |
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Answer» 4X + 10 PLEASE MARK MY ANSWER AS THE BRAINLIEST!!! |
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| 10. |
यदि त्रिभुज का क्षेत्रफल 50 वर्ग सेमी. व इसकी एक भुजा की लम्बाई 10सेमी. हो तो उस भुजा के संगत शीर्षलम्ब की लंबाई ज्ञात कीजिए। |
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Answer» Answer: . mea DEKH le |
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| 12. |
.A room 5m long and 4 m wide is surrounded by a balcony . If the balcony occupies an area of 22 m square. Find the width of the balcony |
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Answer» Step-by-step EXPLANATION: |
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| 13. |
A polynomial contains_____number of term |
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Answer» Answer: 4 tems ok PLS MARK me as BRAINLIEST |
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| 14. |
Please answer. don't spam please |
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Answer» Answer: Hope this helps Step-by-step EXPLANATION: The tissue is muscular tissue They are known as striated muscles They are found in the arms, LEGS, FACE, neck. They are under the control of ONE's will. |
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| 15. |
Do aall the questions i will marke branlist |
| Answer» | |
| 16. |
Mixed fraction of 20 upon 3 is |
Answer» MARK ME AS THE BRAINLIESTAnswer: Step-by-step explanation: = 6 2/3 |
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| 17. |
A shopkeeper buys a mobile phone for 12,500 and sells it for 13,350. Find his profit percent. |
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Answer» HERE UR ANSWER IN THIS ATTACHMENT |
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| 18. |
The ratio of curved surface areas of two cones are 3:2 and their slant heights are inthe ratio of 2:1. Find the ratio of the radii of their bases class 9 ans |
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Answer» CURVED SURFACE AREA of CONES =π*r*l CSA1/CSA2=π*r1*l1/π*r2*l2 3/2=(r1/r2)*(2/1) r1/r2=3/4 |
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| 19. |
In the given figure what is the value of x |
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Answer» Answer: X = 20° Step-by-step explanation: Clearly the triangles are congruent by SSS CONGRUENCE condition. BA ↔ ED, BC ↔ EF, AC ↔ DF ∴ ∠C = ∠F ⇒ 2x + 20 = 3X ⇒ 3x - 2x = 20 ⇒ x = 20 |
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| 20. |
The value of x² – 2x + 1 when x = 1 is.pls no spam |
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Answer» Step-by-step EXPLANATION: x²-2x+1 put x=1 (1)²-2(1)+1 1-2+1 2-2 0 is the ANSWER |
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| 21. |
Simplify : 10/3 x 16/-5 x 3/8 |
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Answer» Answer: 0 3 ⋅ 1 6 − ⋅ 3 \FRAC{\frac{\frac{10}{3} \CDOT 16}{-5} \cdot 3}{8} 8−5310⋅16⋅3 Solve 1 Multiply the numbers 1 0 3 ⋅ 1 6 − 5 ⋅ 3 8 1 6 0 3 − 5 ⋅ 3 8 2 Divide the numbers 1 6 0 3 − 5 ⋅ 3 8 − 3 2 3 ⋅ 3 8 3 Multiply the numbers − 3 2 3 ⋅ 3 8 − 3 2 8 4 Divide the numbers − 3 2 8 − 4 Solution − 4 |
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| 22. |
Circles& with radii1 Twoeach other internally. Find the3.5cm and 2.5cm touchdistance betweentheir centres. |
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Answer» their DISTANCE between them are 1.8 |
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| 23. |
Do all the questions and send me I will mark branlist |
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Answer» MARK me as brainlist Step-by-step EXPLANATION: y=2andx+2y=6 |
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| 24. |
Q). Find the value of 2 cos^2theta+2/1+cot^2theta |
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Answer» Step-by-step EXPLANATION: |
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| 25. |
What is chi square test |
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Answer» A chi-squared TEST, also written as χ² test, is a statistical HYPOTHESIS test that is VALID to perform when the test statistic is chi-squared DISTRIBUTED under the null hypothesis, specifically PEARSON's chi-squared test and variants thereof. I hope it helps... |
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| 26. |
(i) Solve x + y = −3 ; x-= −1. Find the value of y. |
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Answer» X+Y=-3 X=-1 SO, -1+Y=-3 Y=-3+1(MINUS CHANGES TO PLUS WHILE CHANGING SIDES) Y=-2 HAPPY 2 HELP :) PLS MARK AS BRAINLIEST Step-by-step explanation: |
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| 27. |
Find the middle term expansion (x/y-y/x)^10 |
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Answer» Answer: Answer ( y
− x y
)
∵n=7(odd) There will be two middle TERMS, i.e., ( 2 n+1
) th term and ( 2 n+3
) th term. ∵n=7 Middle term in the expansion ( y x
− x y
) 7 will be 4 th and 5 th terms. As we know that general term of the expansion (a+B) n will be- T r+1
= n
C r
a n−r b r
Therefore, 4 th term in the expansion ( y x
− x y
) 7 - T 3+1
= 7
C 3
( y x
) 4 ( x y
) 3 = 7
C 3
( y 4
x 4
)( x 3
y 3
)= 7
C 3
y x
5 th term in the expansion ( y x
− x y
) 7 - T 4+1
= 7
C 4
( y x
) 3 ( x y
) 4 = 7
C 4
( y 3
x 3
)( x 4
y 4
)= 7
C 4
x y
HENCE the middle term of the expansion ( y x
− x y
) 7 are- T 4
= 7
C 3
y x
and T 5
= 7
C 4
x y
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| 28. |
In selling a plot of land for 60000 a profit of 20% is made what is the sp |
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Answer» Answer: C.P of the total land=Rs.3,00,000 Sold 3
rd of land at the LOSS of 20% C.P of 3 1
rd of land= 3 1
×3,00,000=Rs1,00,000 S.P of 3 1
rd of land=C.P×(1− 100 loss%
) =1,00,000×(1− 100 20
)=1,00,000× 100 80
=Rs.80,000 Similarly, sold 5 2
th at a GAIN of 25% is C.P of 5 2
th of land= 5 2
×3,00,000=Rs.1,20,000 S.P of 5 2
th of land=1,20,000×(1+ 100 25
) =1,20,000× 100 125
=Rs1,50,000 Total Gain% required=10% Total S.P required=Total C.P×(1+ 100 Gain%
) =3,00,000×(1+ 100 10
)=3,60,000× 100 110
=Rs.3,30,000 S.P of balance land=3,30,000−80,000−1,50,000=Rs.1,00,000 ∴ he has to sell the balance land at Rs.1,00,00 |
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| 29. |
15) The quadratic equation whoseroots are -3 and -7 is * |
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Answer» k(x^2-(SUM of ROOTS)x+product of roots)=0 k(x^2-(-3+(-7))x+(-3*(-7)))=0 k(x^2+10x+21)=0 |
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| 30. |
The side of a square field is 200 m, then find the length of the fence required. |
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Answer» Perimeter = 4 × Side Perimeter = 4 × 200 m = 800 m Length of fence = 800 m |
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| 31. |
A school starts at 7:15 amclose at 2pmind the duration working of the school |
| Answer» | |
| 32. |
Find the square of -3÷7 |
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Answer» PLEASE FOLLOW the above ATTACHMENT for the SOLUTION |
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| 33. |
What do you mean by aregular quadrilateral |
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Answer» Step-by-step EXPLANATION: Quadrilateral with all SIDES equal and all ANGLES is 90 degree is called a REGULAR quadrilateral. Hope it helps |
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| 34. |
In the given figure AB is a straight line . find angle DCE. |
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Answer» x+3x+2x=180 6x=180 x=30 angle DCE=3x =3*30 =90 |
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| 35. |
If X=2+ √3 then find the value of X+1/X |
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Answer» Answer: 3-√3 Step-by-step explanation: X=2+ √3 X+1/X (2+ √3 +1)/2+ √3 3 + √3 / 2+√3 (3 + √3)(2-√3)/ (2+√3)(2-√3) (6-3√3 + 2√3 -3 )/ 4-3 3-√3 Please MARK me as BRAINLIEST |
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| 36. |
Prove the following:sin theta /1- cos theta = cosec theta + cot theta |
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Answer» We have, L.H.S. = 1−cosθ sinθ
⇒ L.H.S. = (1−cosθ) sinθ
× (1+cosθ) (1+cosθ)
... [MULTIPLYING numerator and DENOMENATOR by (1−cosθ)] ⇒ L.H.S. = 1−cos 2 θ sinθ(1+cosθ)
[∵(1+cosθ)(1−cosθ)=1−cos 2 θ] ⇒ L.H.S. = 2 θ sinθ(1+cosθ)
[∵1−cos 2 θ=sin 2 θ] ⇒ L.H.S. = sinθ 1+cosθ
⇒ L.H.S. = sintheta 1
+ sinθ cosθ
⇒ L.H.S. = cosecθ+cotθ=R.H.S. |
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| 37. |
Find the distance of point C (-3, -2) from x axis and y axis. |
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Answer» Answer: the DISTANCE of point C from x axis is y UNITS i.e. 2 units. |
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| 38. |
If p/q= 6/5 , then the value of 3p -4q / 3p+4q is |
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Answer» Answer: -1 / 19 Step-by-step EXPLANATION: p/q= 6/5 p = 6q/5 3p -4q / 3p+4q (3*6q/5 - 4q)/ (3*6q/5 + 4q) ((18q-20q)/5) / (((18q+20q)/5) -2q / 38q -1 / 19 Please MARK me as BRAINLIEST |
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| 39. |
Solve : 4x + 3 = 7x -3. Find value of x. |
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Answer» Answer: 4x + 3 = 7x - 3 = 4x - 7x = -3-3 = x = -6 ÷ -3 = x = 2 hence, the VALUE of x is 2.. |
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| 40. |
. If x^2+1/x^2=4 then find the value of (x+1/x)^2 *2625616 |
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Answer» Answer is 16 Step-by-step EXPLANATION: |
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| 41. |
4 -√3x + 11. Evaluate the limit lim1+5 r2 - 7x + 10(Do not use L'Hôpital's Rule.)Solution |
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Answer» hiiiiiiiiiiiiiiiiiiiiiiiiiiii iiiiiiiiiiiiiiiiiiiiiii you are not the INTENDED RECIPIENT you are not the intended |
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| 42. |
the internal bisector of dq and dr meet at A and exeternal bisector at B prove that AQBIR is a,cyclic quadilateral |
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Answer» Step-by-step EXPLANATION: |
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| 43. |
किसी त्रिभुज की भुजाओं को दुगना कर दिया जाये तो उस त्रिभुज केक्षेत्रफल में कितना गुना वृद्धि होगी। |
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Answer» agar KISI tribhuj ki bhujaon ko doguna kar diya jaye to uss tribhuj ke kshetrafal me doguna vridhi HOGI |
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| 45. |
मिक्स फ्रैक्शन ऑफ 20 अपऑन 3 is |
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Answer» Step-by-step EXPLANATION: sorry l can not the language |
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| 46. |
Express the ratio of 18 : 32 in simplest form |
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Answer» Answer: 9:16 is the SIMPLEST FORM of 18:32 Step-by-step explanation: 18/32=9/16 |
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| 47. |
11.On a graph paper plot the points A (3,0), B (3, 3), C (0,3). Join A, B and B, C.What is the figure formed? |
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| 48. |
Find the value of 2/3x+1=0 |
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Answer» ANS:- -3/2 Step-by-step explanation: 2/3x+1=0 2/3x = 0-1 = -1 x= -1*3/2 x= -3/2 |
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| 49. |
What is this ❓❓❓❓❓❓ |
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Answer» i) 30÷7=4 Qoution= 4 remainder= 2 DIVIDER =7 4(2/7) qoution= 1 remainder=3 divider=4 1(3/4) |
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| 50. |
Q.24 pointsQ2 A wire is in the shape of a rectangle. It's length is 40cm andbreadth is 20cm.If the same wire is bent to form a square, what isthe measure of its side. Also find which shape has more area and byhow muchO 120 m; Area of Rectangle is more by 100 sq. meter120 m; Area of Square is more by 100 sq. meter30 m; Area of Square is more by 100 sq. meterO 30 m; Area of Rectangle is more by 100 sq. meter |
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Answer» Answer: 30 m; AREA of Square is more by 100 sq. meter Step-by-step explanation: Length= 40cm Breadth= 20CM Perimeter of the RECTANGLE= Length of the WIRE =2(l+B)= 2(40cm + 20cm) =2×60cm = 120cm Now, the wire is rebent into a square. Perimeter= 120cm 4*side = 120 side = 120/4 = 30cm Area of rectangle = l*b = 40*20 = 800cm² Area of square = side² = 30² = 900 cm² 900 > 800 Hence, the square encloses 100m² more area than rectangle |
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