Find the height of triangle whose area is 45and base is 15 cm.

1.	Find the height of triangle whose area is 45and base is 15 cm.
Answer» $\Huge\mathfrak\purple{anSwer:}$ ${}$ $\bf{{\underline{Given}}:}$ $\sf{Area~of~the~triangle=45cm^{2}}$ $\sf{Base=15cm}$ $\bf{{\underline{To~find}}:}$ $\sf{Height~of~the~triangle}$ $\bf{{\underline{Solution}}:}$ $\sf Area \: of \: a \: triangle = \frac{1}{2} \times base \times height \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies {45cm}^{2} = \frac{1}{2} \times 15 \times height \\ \sf \implies \frac{1}{2} \times 15 \times height = {45cm}^{2} \\ \sf \implies \frac{1}{2} \times height = \frac{45}{15} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies \frac{1}{2} \times height = 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies height = 3 \times \frac{2}{1} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies height = 3 \times 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \therefore height = \purple{ \underline{ \boxed{ \bf 6cm}}} \: \: \: \: \: \: \: \: \: \:$ $\bf\therefore{{\underline{Required~answer}}:}$ $\sf Height = \purple{ \underline{ \boxed{ \bf 6cm}}}$

Answer»

$\Huge\mathfrak\purple{anSwer:}$

${}$

$\bf{{\underline{Given}}:}$

$\sf{Area~of~the~triangle=45cm^{2}}$
$\sf{Base=15cm}$

$\bf{{\underline{To~find}}:}$

$\sf{Height~of~the~triangle}$

$\bf{{\underline{Solution}}:}$

$\sf Area \: of \: a \: triangle = \frac{1}{2} \times base \times height \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies {45cm}^{2} = \frac{1}{2} \times 15 \times height \\ \sf \implies \frac{1}{2} \times 15 \times height = {45cm}^{2} \\ \sf \implies \frac{1}{2} \times height = \frac{45}{15} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies \frac{1}{2} \times height = 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies height = 3 \times \frac{2}{1} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \implies height = 3 \times 2 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \therefore height = \purple{ \underline{ \boxed{ \bf 6cm}}} \: \: \: \: \: \: \: \: \: \:$

$\bf\therefore{{\underline{Required~answer}}:}$

$\sf Height = \purple{ \underline{ \boxed{ \bf 6cm}}}$