332354 + Interview Questions in Secondary School in Math

1.	Riya and Venkat are painting walls of the same size. Riya painted 3/7 of her wall andVenkat painted 4/9 of his wall. Who painted more?
Answer» ANSWER: VENKAT PAINTED more fuffjvujgjgjffjcjvjvjgjfjfcuvjvjjvkgkgjvjvmvmv

1.

Riya and Venkat are painting walls of the same size. Riya painted 3/7 of her wall andVenkat painted 4/9 of his wall. Who painted more?

Answer»

ANSWER:

VENKAT PAINTED more fuffjvujgjgjffjcjvjvjgjfjfcuvjvjjvkgkgjvjvmvmv

Discussion

2.	find x.please answer
Answer» $\frac{2x +3 }{3 + x} = \frac{3}{2} \\ = by \: \: cross \: \: multiplication \\ \\ = 2(2x + 3) = 3(3 + x) \\ = 4x + 6 = 9 + 3x \\ = 4x - 3x = 9 - 6 \\ x = 3 \: ans \: \: \\ \\ hope \: \: \: its \: \: \: \: your \: \: \: \: \: helpful \\ \: \: mark \: \: \: me \: \: brainlist \: \: please$

2.

find x.please answer

Answer»

$\frac{2x +3 }{3 + x} = \frac{3}{2} \\ = by \: \: cross \: \: multiplication \\ \\ = 2(2x + 3) = 3(3 + x) \\ = 4x + 6 = 9 + 3x \\ = 4x - 3x = 9 - 6 \\ x = 3 \: ans \: \: \\ \\ hope \: \: \: its \: \: \: \: your \: \: \: \: \: helpful \\ \: \: mark \: \: \: me \: \: brainlist \: \: please$

Discussion

3.	2 Marks :1.Find a quadratic polynomial, the sum and product of whose zeroes are -3 and 2, respectively.Find the zeroes of the quadratic polynomial i) x2 – 3 ii) x2–2x - 8 and verify the relationship betweenzeroes and coefficients.1
Answer» Answer: 638jdkkJdnsnzjdfosisdot

3.

2 Marks :1.Find a quadratic polynomial, the sum and product of whose zeroes are -3 and 2, respectively.Find the zeroes of the quadratic polynomial i) x2 – 3 ii) x2–2x - 8 and verify the relationship betweenzeroes and coefficients.1

Answer»

Answer:

638jdkkJdnsnzjdfosisdot

Discussion

4.	Solved examples1) Radius of a circle is 5 cm. The length of a chord of the circle is 8 cm. Find the distanceof the chord from the centre.
Answer» ANSWER: the DISTANCE of the CHORD from the CENTRE is 40 cm

4.

Solved examples1) Radius of a circle is 5 cm. The length of a chord of the circle is 8 cm. Find the distanceof the chord from the centre.

Answer»

ANSWER:

the DISTANCE of the CHORD from the CENTRE is 40 cm

Discussion

5.	Find the time period for the following A=rupees 6720 SI =rupees 1120 R=8% per annum
Answer» Answer: 2.5 YEARS Step-by-step EXPLANATION: A=6720₹ SI =1120₹ R=8% A=P + I 6720=P+1120 P =6720-1120 =5600₹ T=I×100/P×P =1120×100/5600×8 =5/2 =2.5 years

5.

Find the time period for the following A=rupees 6720 SI =rupees 1120 R=8% per annum

Answer»

Answer:

2.5 YEARS

Step-by-step EXPLANATION:

A=6720₹

SI =1120₹

R=8%

A=P + I

6720=P+1120

P =6720-1120

=5600₹

T=I×100/P×P

=1120×100/5600×8

=5/2

=2.5 years

Discussion

6.	2y+9=4 solve the sum
Answer» Answer: 5/2 = y Step-by-step explanation: 2y + 9 = 4 9-4 = 2y 5= 2y 5/2 = y

6.

2y+9=4 solve the sum

Answer»

Answer:

5/2 = y

Step-by-step explanation:

2y + 9 = 4

9-4 = 2y

5= 2y

5/2 = y

Discussion

7.	Solve the equation-x =7
Answer» The VALUE of X is -7. please MARK me BRAINLIEST PLZ ❣️

7.

Solve the equation-x =7

Answer»

The VALUE of X is -7.

please MARK me BRAINLIEST PLZ ❣️

Discussion

8.	511Зл7134TU44+ COS+ cos+ COSShow that COS88882.II.
Answer»

Discussion

9.	Two of the eigenvalues of = [3 −1 1−1 5 −11 −1 3] are 3 & 6. Find the eigenvalues of i) 2ii) iii) −1iv) 3 + 2 v)3A
Answer» ANSWER: dghdhddididideddhdjdjddjdhhdd

9.

Two of the eigenvalues of = [3 −1 1−1 5 −11 −1 3] are 3 & 6. Find the eigenvalues of i) 2ii) iii) −1iv) 3 + 2 v)3A

Answer»

ANSWER:

dghdhddididideddhdjdjddjdhhdd

Discussion

10.	There are four friends A B C D. One of them is a Cricketer and studies Chemistry and Biology. A and B play Football. Both Football players study Maths. As a Boxer One Football player also studies Physics. The Boxer studies Maths and Accounts. All the friends study two subjects each and play one game each Question: How many games are played and subjects studied by the four friends?a) 1 game and 4 subjects b) 2 games and 3 subjectsc) games and 4 subjectsd) 3 games and 5 subjects
Answer» ANSWER: C) _ GAMES and 4 SUBJECTS

10.

There are four friends A B C D. One of them is a Cricketer and studies Chemistry and Biology. A and B play Football. Both Football players study Maths. As a Boxer One Football player also studies Physics. The Boxer studies Maths and Accounts. All the friends study two subjects each and play one game each Question: How many games are played and subjects studied by the four friends?a) 1 game and 4 subjects b) 2 games and 3 subjectsc) games and 4 subjectsd) 3 games and 5 subjects

Answer»

ANSWER:

C) _ GAMES and 4 SUBJECTS

Discussion

11.	Please send us the answer with solution
Answer» ANSWER: GIVEN, PERIMETER = 180M THEREFORE, 180= 4×SIDE => SIDE = 45M THEREFORE, THE REQUIRED AREA :- SIDE × SIDE= 45×45 = 2025M² Mark as BRAINLIEST, give thanks n follow...

11.

Please send us the answer with solution

Answer»

ANSWER:

GIVEN, PERIMETER = 180M

THEREFORE, 180= 4×SIDE

=> SIDE = 45M

THEREFORE, THE REQUIRED AREA :-

SIDE × SIDE= 45×45

= 2025M²

Mark as BRAINLIEST, give thanks n follow...

Discussion

12.	The perimeter of a triangle is 36 cm and the sides are in the ratio 2 : 5 : 5 ,thenfind the area of the triangle .
Answer» Answer: Let sides are a, b and c, a = 3x, b = 4x, c = 5x Perimeter = a + b + c => 36 = 3x + 4x + 5x => X = 3 a = 9 CM, b = 12 cm and c = 15 cm Step-by-step explanation: Area =√s(s-a)(s-b)(s-c) = √18(18-9)(18-12)(18-15) =√18×9×6×3 =54cm2

12.

The perimeter of a triangle is 36 cm and the sides are in the ratio 2 : 5 : 5 ,thenfind the area of the triangle .

Answer»

Answer:

Let sides are a, b and c, a = 3x, b = 4x, c = 5x

Perimeter = a + b + c

=> 36 = 3x + 4x + 5x

=> X = 3

a = 9 CM, b = 12 cm and c = 15 cm

Step-by-step explanation:

Area =√s(s-a)(s-b)(s-c)

= √18(18-9)(18-12)(18-15)

=√18×9×6×3

=54cm2

Discussion

13.	(ill) A card is drawn from a well-shuffled pack of 52 playing cards. Findthe probability that the card drawn is (1) a diamond card (2) a face card(3) a black card.
Answer» 3) a BLACK CARD I THINK this is ANSWER

Discussion

14.	The length of diagonals of a rhombus are 16cm and 12cm respectively .find the length of each of its side
Answer» ANSWER: the LENGTH is = 4cm on RHOMBUS OK JI

14.

The length of diagonals of a rhombus are 16cm and 12cm respectively .find the length of each of its side

Answer»

ANSWER:

the LENGTH is = 4cm on RHOMBUS OK JI

Discussion

15.	Rs 3500 is to be shared among three people so that the first person gets 50% of the second, who in turn gets 50% of the third. How much will each of them get?
Answer» 1500 is the ANSWER of the QUESTION

Discussion

16.	HCF of 25.42 and 17.98
Answer» Answer: Ans=85 Step-by-step EXPLANATION: it was HELPFUL for you Mark as BRAINLIST please

16.

HCF of 25.42 and 17.98

Answer»

Answer:

Ans=85

Step-by-step EXPLANATION:

it was HELPFUL for you Mark as BRAINLIST please

Discussion

17.	T=4 square root of h/32. Express h in terms of t. (Change subject of formula from t to h)
Answer» Step-by-step EXPLANATION: Given :- t=4 square root of H/32 To find:- If t=4 square root of h/32. Express h in terms of t. (Change SUBJECT of formula from t to h). Solution:- 4 square root of h/32 t=4√(h/32) =>t/4 = √(h/32) On squaring both sides then =>(t/4)²=[√(h/32)]² =>t²/16=h/32 =>h/32 = t²/16 =>h=(t²/16)×32 =>h=32t²/16 =>h=2t² Answer:- The required answer is h=2t²

17.

T=4 square root of h/32. Express h in terms of t. (Change subject of formula from t to h)

Answer»

Step-by-step EXPLANATION:

Given :-

t=4 square root of H/32

To find:-

If t=4 square root of h/32. Express h in terms of t. (Change SUBJECT of formula from t to h).

Solution:-

4 square root of h/32

t=4√(h/32)

=>t/4 = √(h/32)

On squaring both sides then

=>(t/4)²=[√(h/32)]²

=>t²/16=h/32

=>h/32 = t²/16

=>h=(t²/16)×32

=>h=32t²/16

=>h=2t²

Answer:-

The required answer is h=2t²

Discussion

18.	A. P -3, -1/2, 2 find the the 11 th term
Answer» ANSWER: a=-3 d=-1/2+3 =5/2 A11=a+10d =-3+25 =22 hope it HELPS

18.

A. P -3, -1/2, 2 find the the 11 th term

Answer»

ANSWER:

a=-3

d=-1/2+3

=5/2

A11=a+10d

=-3+25

=22

hope it HELPS

Discussion

19.	C.I0-1010-2020-3030-4040-50FREQUENCY410283650find the mode
Answer» ANSWER: ) CO co co co co co co co co co co co co co co co co co co co HI

19.

C.I0-1010-2020-3030-4040-50FREQUENCY410283650find the mode

Answer»

ANSWER:

) CO co co co co co co co co co co co co co co co co co co co HI

Discussion

20.	The length and breadth of rectangle are 12 cm and 9cm r e s p e c t i v e l y square1. find the sides of square with its pyramid equal to that of the retangle 2. Find the sides of equilateral triangle with the parameter equal to that of the rectangle
Answer» *GOOD* *NIGHT* *SWEET* *DREAMS* *good* *night* *sweet* *dreams* *good* *night* *sweet* *dreams* *good* *night* *sweet* *dreams*

Discussion

21.	The numerator of a fraction is 3 less than its denominator.if 1is subtracted in numerator denominator the fraction will be 1by 2
Answer» Step-by-step EXPLANATION: x-3/x x-3-1/x-1 = 1/2 2x-8 = x-1 x=7

21.

The numerator of a fraction is 3 less than its denominator.if 1is subtracted in numerator denominator the fraction will be 1by 2

Answer»

Step-by-step EXPLANATION:

x-3/x

x-3-1/x-1 = 1/2

2x-8 = x-1

x=7

Discussion

22.	a square room has a side 13.5 m the floor is covered with marble stone the cost of material is rupees 16 per metre square find the total cost of flooring
Answer» Answer: TOTAL cost of flooring = Rs 2916 Step-by-step EXPLANATION: Given that: A SQUARE room has a SIDE 13.5 m. Cost of material is Rs 16 per metre square. Finding the area of room: Area of square = (side × side) Area of square = (13.5 m × 13.5 m) Area of square = 182.25 m² To Find: Total cost of flooring. Finding the total cost of flooring: Using UNITARY method, Cost of flooring 1 m² = Rs 16 ∴ Cost of flooring 182.25 m² = Rs (16 × 182.25) ∴ Cost of flooring 182.25 m² = Rs 2916

22.

a square room has a side 13.5 m the floor is covered with marble stone the cost of material is rupees 16 per metre square find the total cost of flooring

Answer»

Answer:

TOTAL cost of flooring = Rs 2916

Step-by-step EXPLANATION:

Given that:

A SQUARE room has a SIDE 13.5 m.
Cost of material is Rs 16 per metre square.

Finding the area of room:

Area of square = (side × side)
Area of square = (13.5 m × 13.5 m)
Area of square = 182.25 m²

To Find:

Total cost of flooring.

Finding the total cost of flooring:

Using UNITARY method,

Cost of flooring 1 m² = Rs 16

∴ Cost of flooring 182.25 m² = Rs (16 × 182.25)

∴ Cost of flooring 182.25 m² = Rs 2916

Discussion

23.	Change into mixed fraction:28\9
Answer» ANSWER: so 10/9" 1 Step-by-step EXPLANATION: so if we DIVIDE 28/9 then it CHANGES to 3×9+1

23.

Change into mixed fraction:28\9

Answer»

ANSWER:

so 10/9" 1

Step-by-step EXPLANATION:

so if we DIVIDE 28/9

then it CHANGES to 3×9+1

Discussion

24.	How many student took part in the survey
Answer» ANSWER: MARK me BRAINLIEST then I will GIVE you answer

24.

How many student took part in the survey

Answer»

ANSWER:

MARK me BRAINLIEST then I will GIVE you answer

Discussion

25.	Find the duration of time between 9 a.m. and 11 a.m.
Answer» Answer: 2 hours Step-by-step EXPLANATION: as 9 to 10 one HOUR and 10 to 11 SECOND hour then 2 hours

25.

Find the duration of time between 9 a.m. and 11 a.m.

Answer»

Answer:

2 hours

Step-by-step EXPLANATION:

as 9 to 10 one HOUR and 10 to 11 SECOND hour

then 2 hours

Discussion

26.	Write the name of different types of account
Answer» Answer: Current account. A current account is a deposit account for traders, business OWNERS, and entrepreneurs, who need to make and receive payments more OFTEN than others. ... Savings account. ... Salary account. ... Fixed deposit account. ... RECURRING deposit account. ... NRI accounts. Step-by-step explanation: hope you LIKE it please mark me as BRAINLEST

26.

Write the name of different types of account

Answer»

Answer:

Current account. A current account is a deposit account for traders, business OWNERS, and entrepreneurs, who need to make and receive payments more OFTEN than others. ...

Savings account. ...

Salary account. ...

Fixed deposit account. ...

RECURRING deposit account. ...

NRI accounts.

Step-by-step explanation:

hope you LIKE it

please mark me as BRAINLEST

Discussion

27.	What is the mean absolute deviation for 4 6 6 2
Answer» ANSWER: Why is distilled WATER USED in the batteries and not the TAP water?

27.

What is the mean absolute deviation for 4 6 6 2

Answer»

ANSWER:

Why is distilled WATER USED in the batteries and not the TAP water?

Discussion

28.	How many faces are there in Cube shape
Answer» A CUBE has $\huge{\underline{\mathfrak\red{6\:}}}$ FACES

Discussion

29.	Which expression is a linear equation? a.y=3×2+3. b.y>3×+5 c.y2 d.5×=10+4y
Answer» Answer: 9%+%+%;%-%;$++$49374937383

29.

Which expression is a linear equation? a.y=3×2+3. b.y>3×+5 c.y2 d.5×=10+4y

Answer»

Answer:

9%+%+%;%-%;$++$49374937383

Discussion

30.	Construct triangle ABC angle A =50° angle B = 80° and BC = 6cm
Answer» 3t4yk3ah43karhlkgjdfuydgisttgiayd

Discussion

31.	If the mid point of the segment point joining the (4, -3) and, (8, 5)
Answer» Answer: so the ANS is ( 6,1) hope it helps, MARK it as BRAINLIEST

31.

If the mid point of the segment point joining the (4, -3) and, (8, 5)

Answer»

Answer:

so the ANS is ( 6,1)

hope it helps,

MARK it as BRAINLIEST

Discussion

32.	I think the question has a problem
Answer» ANSWER: special RELATIONSHIP Lita JEALOUSLY Kalamazoo

32.

I think the question has a problem

Answer»

ANSWER:

special RELATIONSHIP Lita JEALOUSLY Kalamazoo

Discussion

33.	Smallest 5 digit number beginning with 15 is exactly divisible by 12
Answer» NUMBER MUST DIVISIBLE by 3 and 4NUMBER number is 15012

33.

Smallest 5 digit number beginning with 15 is exactly divisible by 12

Answer»

NUMBER MUST DIVISIBLE by 3 and 4NUMBER

number is 15012

Discussion

34.	Represent the following situations in the form of quadratic equations :. The area of a rectangular plot is 528msq . The length of the plot is one meter more than twice it's breadth . We need to find the length and breadth of the plot
Answer» ANSWER: vahshdgdgddhdhdgdsshdgfvrf

34.

Represent the following situations in the form of quadratic equations :. The area of a rectangular plot is 528msq . The length of the plot is one meter more than twice it's breadth . We need to find the length and breadth of the plot

Answer»

ANSWER:

vahshdgdgddhdhdgdsshdgfvrf

Discussion

35.	A into a into a into b into b into
Answer» ANSWER: yshhwhaaahgshgsbhwhhabgwbgshs

35.

A into a into a into b into b into

Answer»

ANSWER:

yshhwhaaahgshgsbhwhhabgwbgshs

Discussion

36.	(3a-2)(a+5) find the product
Answer» Q: (3a-2)(a+5) find the product. Answer: = 3a^2 + 13A - 10 Step-by-step explanation: (3a - 2) × (a + 5) 3a (a + 5) - 2 (a + 5) 3a^2 + 15a - 2A - 10 3a^2 + 13a - 10 Hope it helps you . THANKS !

36.

(3a-2)(a+5) find the product

Answer»

Q: (3a-2)(a+5) find the product.

Answer:

= 3a^2 + 13A - 10

Step-by-step explanation:

(3a - 2) × (a + 5)
3a (a + 5) - 2 (a + 5)
3a^2 + 15a - 2A - 10
3a^2 + 13a - 10

Hope it helps you .

THANKS !

Discussion

37.	An triangle with 110 degree
Answer» ANSWER: no it has 180 degree i am master MATH teacher kinda i m a teacher of math Step-by-step explanation: how would a TRIANGLE have 110 degree ?

37.

An triangle with 110 degree

Answer»

ANSWER:

no

it has 180 degree

i am master MATH teacher

kinda

i m a teacher

of math

Step-by-step explanation:

how would a TRIANGLE have 110 degree ?

Discussion

38.	Distance=100m , time=2 minutes 5 seconds
Answer» Answer: T = 2 MIN 5 sec = 125 sec D = 100 m S = d/t = 100/125 = 4/5 m/s = 0.8 m/s Please mark my answer as the BRAINLIEST !!!!

38.

Distance=100m , time=2 minutes 5 seconds

Answer»

Answer:

T = 2 MIN 5 sec = 125 sec

D = 100 m

S = d/t = 100/125 = 4/5 m/s = 0.8 m/s

Please mark my answer as the BRAINLIEST !!!!

Discussion

39.	a tank is filled upto 40 % of its capacity. when 300 litres of water is added, it became 50%.what is the capacity of the tank?
Answer» Answer: 10 liters Step-by-step explanation: Total capacity of the TANK is=> 50 litres. 30% of the total capacity will be=> 5030/100 = 15 litres. we are required to fill it upto to 50%. So, 50% of the total capacity of the tank is=> 5050/100 = 25 litres. therefore, amount of water to be PUT in the tank to GET FILLED its desired amount is 25-15 = 10 liters.

39.

a tank is filled upto 40 % of its capacity. when 300 litres of water is added, it became 50%.what is the capacity of the tank?

Answer»

Answer:

10 liters

Step-by-step explanation:

Total capacity of the TANK is=> 50 litres.

30% of the total capacity will be=> 50*30/100 = 15 litres.

we are required to fill it upto to 50%. So, 50% of the total capacity of the tank is=> 50*50/100 = 25 litres.

therefore, amount of water to be PUT in the tank to GET FILLED its desired amount is 25-15 = 10 liters.

Discussion

40.	न दिए गए चित्र के आधार पर निम्न सारणी को पूर्ण करो।(e38कोणों के प्रकारदर्शाने वाले कोणअंत:कोणबाह्य कोणसंगत कोणएकान्तर कोण2
Answer» ANSWER: of g Step-by-step explanation: h to efhc be DX JH V JCL NV hmm NV hi hi go go ha GB HC gohch hug GC by RS hi be jb

40.

न दिए गए चित्र के आधार पर निम्न सारणी को पूर्ण करो।(e38कोणों के प्रकारदर्शाने वाले कोणअंत:कोणबाह्य कोणसंगत कोणएकान्तर कोण2

Answer»

ANSWER:

of g

Step-by-step explanation:

h to efhc be DX JH V JCL NV hmm NV hi hi go go ha GB HC gohch hug GC by RS hi be jb

Discussion

41.	. If + = = , then the value of (1/x^3+1/y^3)
Answer» ANSWER: x = y or (x^2 + y^2 + XY) = 0 Step-by-step explanation: given '+' = '=' :. 1/x^3 = 1/y^3 => x^3 = y^3 => x^3 - y^3 = 0 => (x-y)(x^2 + y^2 + xy) = 0 => x = y or (x^2 + y^2 + xy) = 0

41.

. If + = = , then the value of (1/x^3+1/y^3)

Answer»

ANSWER:

x = y or (x^2 + y^2 + XY) = 0

Step-by-step explanation:

given '+' = '='

:. 1/x^3 = 1/y^3

=> x^3 = y^3

=> x^3 - y^3 = 0

=> (x-y)(x^2 + y^2 + xy) = 0

=> x = y or (x^2 + y^2 + xy) = 0

Discussion

42.	LET=60 SET= 95GET= ?
Answer» ANSWER: GOOD NIGHT Step-by-step EXPLANATION: sipra5581

42.

LET=60 SET= 95GET= ?

Answer»

ANSWER:

GOOD NIGHT

Step-by-step EXPLANATION:

sipra5581

Discussion

43.	[Maths]A jeweller has bars of 18-carat gold and 11 carat gold. How much of each be melted together to obtain 16-carat gold weighing 120 grams? (Pure gold is 24-carat)_Topic: Simultaneous Linear Equations
Answer» Given and To Find:- A jeweller has bars of 18-carat gold and 11 carat gold. How much of each be melted together to obtain 16-carat gold weighing 120 grams? (PURE gold is 24-carat) LET, Quantity of 18 carat gold be X Quantity of 12 carat gold be y Then, x + y = 120 —i Substitute the values, 18x + 12y = 16120 3x +2y =320 —II Subtracting ii from i, 3x+3y=360 3x+2y=320 y=40 Substituting the values,* x + y =120 x + 40=120 x = 120-40 x = 80 Therefore, Quantity of 18 Carat gold = 80gm Quantity of 16 Carat gold = 40gm ★ Hope it helps u ★

43.

[Maths]A jeweller has bars of 18-carat gold and 11 carat gold. How much of each be melted together to obtain 16-carat gold weighing 120 grams? (Pure gold is 24-carat)_Topic: Simultaneous Linear Equations

Answer»

Given and To Find:-

A jeweller has bars of 18-carat gold and 11 carat gold. How much of each be melted together to obtain 16-carat gold weighing 120 grams? (PURE gold is 24-carat)

LET,

Quantity of 18 carat gold be X
Quantity of 12 carat gold be y

Then,

x + y = 120 —i

Substitute the values,

18x + 12y = 16*120

3x +2y =320 —II

Subtracting ii from i,

3x+3y=360

3x+2y=320

y=40

Substituting the values,

x + y =120

x + 40=120

x = 120-40

x = 80

Therefore,

Quantity of 18 Carat gold = 80gm
Quantity of 16 Carat gold = 40gm

★ Hope it helps u ★

Discussion

44.	Solve the equation-5=x+6
Answer» Answer: -5 = X + 6 X = 6-(-5) = 6 + 5 = 11 X = 11

44.

Solve the equation-5=x+6

Answer»

Answer:

-5 = X + 6

X = 6-(-5)

= 6 + 5

= 11

X = 11

Discussion

45.	4. Find the ratio in which the line segment joining the points (-3, 10) and (6,- 8) is dividedby (-1,6).
Answer» ANSWER: USING the SECTION formula, if a point (x,y) divides the line joining the POINTS (x 1 ,y 1 ) and (x 2 ,y 2 ) in the ratio m:n, then (x,y)=( m+n mx 2 +NX 1 , m+n my 2 +ny 1 ) Let the point P(−1,6) divides the line joining A(−3,10) and (6,−8) in the ratio k:1 Then, by section formula, the coordinates of P are ( k+1 6k−3 , k+1 −8k+10 ) ⇒(−1,6)=( k+1 6k−3 , k+1 −8k+10 ) ∴ k+1 6k−3 =−1 ⇒6k−3=−k−1 ⇒6k+k=3−1 ⇒7k=2 ∴ k= 7 2 Hence, the point P divides AB in the ratio 2:7

45.

4. Find the ratio in which the line segment joining the points (-3, 10) and (6,- 8) is dividedby (-1,6).

Answer»

ANSWER:

USING the SECTION formula, if a point (x,y) divides the line joining the POINTS (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+NX

1

,

m+n

my

2

+ny

1

)

Let the point P(−1,6) divides the line joining A(−3,10) and (6,−8) in the ratio k:1

Then, by section formula,

the coordinates of P are (

k+1

6k−3

,

k+1

−8k+10

)

⇒(−1,6)=(

k+1

6k−3

,

k+1

−8k+10

)

∴

k+1

6k−3

=−1

⇒6k−3=−k−1

⇒6k+k=3−1

⇒7k=2

∴ k=

7

2

Hence, the point P divides AB in the ratio 2:7

Discussion

46.	In the given table, piece of apples is an indpendent variable (true/false)
Answer» ANSWER: Can you PLEASE ADD the IMAGE for the table Step-by-step EXPLANATION:

46.

In the given table, piece of apples is an indpendent variable (true/false)

Answer»

ANSWER:

Can you PLEASE ADD the IMAGE for the table

Step-by-step EXPLANATION:

Discussion

47.	Prove that sin theta upon (1-cos theta )= cosec theta + cot theta
Answer» $\\ \mathcal{\large{\underline {★ \: \: QUESTION\:\:}}} : - \begin{cases} \sf { \underbrace{ \overbrace{ \bf{Prove: - } \: \: \tt{ \dfrac{sin \: \theta}{1 - cos \: \theta} = cosec \: \theta \: + \: cot \: \theta}}}} \end{cases} \\\\\\$ ____________________________ $\\ \\\huge \underline{ \underline{ { \cal \: {★S}} \large \red{ \tt \: O} \green{ \tt \: L} \blue{ \tt \: <klux>U</klux>} \orange{ \tt \: T} \purple{ \tt \: I} \red{ \tt \: O} \blue{ \tt \: N}:-}} \\\\$ $\large {\underbrace{ \underline { \frak { \dag \:\:Finding \: \: \: \: \: L. \: H . \: S,}}}}\\\\$ $\\ \implies \sf \dfrac{sin \: \theta}{1 - \: cos \: \theta} \\\\$ $\large \underbrace{ \underline { \frak { \dag \: \: multiply \: numerator \: and \: dinominator \: by \: \red{\sf(1 + cos \: \theta).}}}}\\\\$ $: \implies \tt \dfrac{sin \: \theta \: (1 + cos \: \theta)}{ (1 - cos \: \theta )(1 + cos \: \theta )} \\\\\ : \implies \tt \dfrac{sin \: \theta \: (1 + cos \: \theta)}{ 1 - cos \: {}^{2} \: \theta } \\\\\ : \implies \tt \dfrac{sin \: \theta \: (1 + cos \: \theta)}{ sin \: {}^{2} \: \theta } \\\\\ : \implies \tt \dfrac{1 + cos \: \theta}{ sin \: \: \theta } \\\\\ : \implies \tt \dfrac{1 }{ sin \: \: \theta } + \frac{cos \: \theta}{sin \: \theta} \\\\\ :\longmapsto \bf{cosec \: \theta \: + \: cot \: \theta \: = R.H.S}\\\\$ ☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯ $\\ \\\:\: \therefore \: \: \boxed{\large{\cal{LHS = RHS}}} \\ \\ \\ \large \tt\underline{ \underline{\overline{\overline{\mid{\mid{\red{ \lgroup Hence \: proved!! \rgroup}\mid}\mid}}}}}$ $\\\\$ ★ HOPE it HELPS u ★

47.

Prove that sin theta upon (1-cos theta )= cosec theta + cot theta

Answer»

$\\ \mathcal{\large{\underline {★ \: \: QUESTION\:\:}}} : - \begin{cases} \sf { \underbrace{ \overbrace{ \bf{Prove: - } \: \: \tt{ \dfrac{sin \: \theta}{1 - cos \: \theta} = cosec \: \theta \: + \: cot \: \theta}}}} \end{cases} \\\\\\$

____________________________

$\\ \\\huge \underline{ \underline{ { \cal \: {★S}} \large \red{ \tt \: O} \green{ \tt \: L} \blue{ \tt \: <klux>U</klux>} \orange{ \tt \: T} \purple{ \tt \: I} \red{ \tt \: O} \blue{ \tt \: N}:-}} \\\\$

$\large {\underbrace{ \underline { \frak { \dag \:\:Finding \: \: \: \: \: L. \: H . \: S,}}}}\\\\$

$\\ \implies \sf \dfrac{sin \: \theta}{1 - \: cos \: \theta} \\\\$

$\large \underbrace{ \underline { \frak { \dag \: \: multiply \: numerator \: and \: dinominator \: by \: \red{\sf(1 + cos \: \theta).}}}}\\\\$

$: \implies \tt \dfrac{sin \: \theta \: (1 + cos \: \theta)}{ (1 - cos \: \theta )(1 + cos \: \theta )} \\\\\ : \implies \tt \dfrac{sin \: \theta \: (1 + cos \: \theta)}{ 1 - cos \: {}^{2} \: \theta } \\\\\ : \implies \tt \dfrac{sin \: \theta \: (1 + cos \: \theta)}{ sin \: {}^{2} \: \theta } \\\\\ : \implies \tt \dfrac{1 + cos \: \theta}{ sin \: \: \theta } \\\\\ : \implies \tt \dfrac{1 }{ sin \: \: \theta } + \frac{cos \: \theta}{sin \: \theta} \\\\\ :\longmapsto \bf{cosec \: \theta \: + \: cot \: \theta \: = R.H.S}\\\\$

☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯☯

$\\ \\\:\: \therefore \: \: \boxed{\large{\cal{LHS = RHS}}} \\ \\ \\ \large \tt\underline{ \underline{\overline{\overline{\mid{\mid{\red{ \lgroup Hence \: proved!! \rgroup}\mid}\mid}}}}}$

$\\\\$

★ HOPE it HELPS u ★

Discussion

48.	7. The diameter of a roller is 86 cm and its length is 120 cm. It takes 500 completerevolutions to roll once over the play ground to level. Find the area of the play groundin m?
Answer» Answer: The DIAMETER of a ROLLER is 70 cm and its LENGTH is 1.5 m. It takes 1000 COMPLETE REVOLUTIONS moving once over to level a stadium. Determine the area of the stadium.

48.

7. The diameter of a roller is 86 cm and its length is 120 cm. It takes 500 completerevolutions to roll once over the play ground to level. Find the area of the play groundin m?

Answer»

Answer:

The DIAMETER of a ROLLER is 70 cm and its LENGTH is 1.5 m. It takes 1000 COMPLETE REVOLUTIONS moving once over to level a stadium. Determine the area of the stadium.

Discussion

49.	Solve the equation1 / 2 (x - 2) + (x + 3) = 13(x + 4) + 15
Answer» ANSWER: X = -63/24 is the RIGHT answer

49.

Solve the equation1 / 2 (x - 2) + (x + 3) = 13(x + 4) + 15

Answer»

ANSWER:

X = -63/24

is the RIGHT answer

Discussion

50.	3+ sin² 60° +cosec² 30°/5 + cos² 60° + sec ² 30°please help!
Answer» Step-by-step explanation: cos² 30° + sin² 60° + tan² 45° + sec² 60° + COS 0° = √3 ² + √3 ² + (1)² + (2)² + 1 2 2 = 3 + 3 + 1 + 4 + 1 4 4 = 6 + 3 + 3 4 = 6 + 6 = 6 + 3 = 12 + 3 4 2 2 = 15 = 7 1 Hope it helps you have a GOOD day Please mark me as brainliest

50.

3+ sin² 60° +cosec² 30°/5 + cos² 60° + sec ² 30°please help!

Answer»

Step-by-step explanation:

cos² 30° + sin² 60° + tan² 45° + sec² 60° + COS 0°

= √3

² + √3

² + (1)² + (2)² + 1

2 2

=

3

+

3

+ 1 + 4 + 1

4 4

= 6 +

3 + 3

4

= 6 +

6

= 6 +

3

=

12 + 3

4 2 2

=

15

= 7

1

Hope it helps you have a GOOD day

Please mark me as brainliest

Discussion

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