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. If + = = , then the value of (1/x^3+1/y^3) |
Answer» x = y or (x^2 + y^2 + XY) = 0Step-by-step explanation: given '+' = '=' :. 1/x^3 = 1/y^3 => x^3 = y^3 => x^3 - y^3 = 0 => (x-y)(x^2 + y^2 + xy) = 0 => x = y or (x^2 + y^2 + xy) = 0 |
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