1.

4. Find the ratio in which the line segment joining the points (-3, 10) and (6,- 8) is dividedby (-1,6).​

Answer»

ANSWER:

USING the SECTION formula, if a point (x,y) divides the line joining the POINTS (x

1

,y

1

) and (x

2

,y

2

) in the ratio m:n, then

(x,y)=(

m+n

mx

2

+NX

1

,

m+n

my

2

+ny

1

)

Let the point P(−1,6) divides the line joining A(−3,10) and (6,−8) in the ratio k:1

Then, by section formula,

the coordinates of P are (

k+1

6k−3

,

k+1

−8k+10

)

⇒(−1,6)=(

k+1

6k−3

,

k+1

−8k+10

)

∴

k+1

6k−3

=−1

⇒6k−3=−k−1

⇒6k+k=3−1

⇒7k=2

∴ k=

7

2

Hence, the point P divides AB in the ratio 2:7


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