332354 + Interview Questions in Secondary School in Math

1.	The Roots of The equation 3xsquare- 2 root 6+2=0
Answer» LocationLocation of INDIA :- The LATITUDINAL and LONGITUDINAL LOCATION of India.

1.

The Roots of The equation 3xsquare- 2 root 6+2=0

Answer»

LocationLocation of INDIA :- The LATITUDINAL and LONGITUDINAL LOCATION of India.

Discussion

2.	3. Write a pair ofintegers which:b. gives the difference as (-100)
Answer» (-50)-50 = 100 MARK IT AS BRAINLIEST AND FOLLOW ME IF IT HELPS YOU....❤

2.

3. Write a pair ofintegers which:b. gives the difference as (-100)

Answer»

(-50)-50 = 100

MARK IT AS BRAINLIEST AND FOLLOW ME IF IT HELPS YOU....❤

Discussion

3.	(c) Subtract the followingGuys please solved in rough copy and send me pic please
Answer» ANSWER: Step-by-step EXPLANATION:

3.

(c) Subtract the followingGuys please solved in rough copy and send me pic please

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

4.	Can two numbers have 18 as their HCF and 380 as their LCM? Give reason.
Answer» ANSWER: yes Step-by-step EXPLANATION:

4.

Can two numbers have 18 as their HCF and 380 as their LCM? Give reason.

Answer»

ANSWER:

yes

Step-by-step EXPLANATION:

Discussion

5.	Number of independent measurements are required to construct a trapeziumA) 1 B) 2 C) 3 D) 4
Answer» ANSWER: I THINK the answer is 4.

5.

Number of independent measurements are required to construct a trapeziumA) 1 B) 2 C) 3 D) 4

Answer»

ANSWER:

I THINK the answer is 4.

Discussion

6.	Find the multiplicative inverses (-32)
Answer» Answer: 1/32........ MARK as .......

6.

Find the multiplicative inverses (-32)

Answer»

Answer:

1/32........ MARK as .......

Discussion

7.	All sud set of {3,5,6}
Answer» EVERY set is subset of itself and null set is subset if every set {∅,{3},{4},{5},{6},{3,4},{3,5},{3,6},{4,5},{4,6},{5,6},{3,4,5},{3,4,6},{3,5,6},{4,5,6},{3,4,5,6}} HOPE it's HELPFUL for u

7.

All sud set of {3,5,6}

Answer»

EVERY set is subset of itself and null set is subset if every set {∅,{3},{4},{5},{6},{3,4},{3,5},{3,6},{4,5},{4,6},{5,6},{3,4,5},{3,4,6},{3,5,6},{4,5,6},{3,4,5,6}}

HOPE it's HELPFUL for u

Discussion

8.	Is six by fifteen a terminating decimal or non terminating recurring decimal
Answer» ANSWER: it's NON TERMINATING I HOPE you UNDERSTAND

8.

Is six by fifteen a terminating decimal or non terminating recurring decimal

Answer»

ANSWER:

it's NON TERMINATING

I HOPE you UNDERSTAND

Discussion

9.	54% + 10% + – is equals to hundred percent
Answer» Answer: 64%................

9.

54% + 10% + – is equals to hundred percent

Answer»

Answer:

64%................

Discussion

10.	Who given first formula for sum of n natural numbers
Answer» ANSWER: BRAHMAGUPTA................... HOPE it will HELP!!

10.

Who given first formula for sum of n natural numbers

Answer»

ANSWER:

BRAHMAGUPTA...................

HOPE it will HELP!!

Discussion

11.	Q14.Evaluate[a b][c + d ] + [a b c d]
Answer» ANSWER: HEY, mate. abc+abd+abcd it is the answer. PLEASE MARK as BRAINLIST.

11.

Q14.Evaluate[a b][c + d ] + [a b c d]

Answer»

ANSWER:

HEY, mate.

abc+abd+abcd

it is the answer.

PLEASE MARK as BRAINLIST.

Discussion

12.	The graph of a cubic polynomial intersects y axis at how many points
Answer» $\text{[math]}$ ⠀ ⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀

12.

The graph of a cubic polynomial intersects y axis at how many points

Answer»

$\text{[math]}$

⠀ ⠀⠀⠀ ⠀ ⠀⠀ ⠀⠀⠀⠀

Discussion

13.	( x²-4x+1 ) factorise
Answer» ANSWER: x²-4x+1 splitting MIDDLE term x²-2x-2x+1 x(x-2)-1(x-1) x-1 and x-2

13.

( x²-4x+1 ) factorise

Answer»

ANSWER:

x²-4x+1

splitting MIDDLE term

x²-2x-2x+1

x(x-2)-1(x-1)

x-1 and x-2

Discussion

14.	(2x+3)(3x^2-x-2) .solve this question
Answer» Answer: after solving the above equation, the FINAL value is:- 6x³-11x²-x+6. Step-by-step EXPLANATION: HOPE it HELPS ✔✔

14.

(2x+3)(3x^2-x-2) .solve this question

Answer»

Answer:

after solving the above equation,

the FINAL value is:-

6x³-11x²-x+6.

Step-by-step EXPLANATION:

HOPE it HELPS ✔✔

Discussion

15.	Ex. 3) A boat travels 16 km upstreamand 24 km downstream in 6hours.The same boat travels 36 kmupstream and 48 km downstreamin 13 hours.Find the speed of water current and speed of boat in still water.lnn Irm/hr and the speed
Answer» Solution : $\bf{\red{\underline{\underline{\bf{Given\::}}}}}$ A boat travels 16 km upstream and 24 km downstream in 6 hours.The same boat travels 36 km upstream and 48 km downstream in 13 hours. $\bf{\red{\underline{\underline{\bf{To\:find\::}}}}}$ The speed of water current and speed of boat in still water. $\bf{\red{\underline{\underline{\bf{Explanation\::}}}}}$ Let the speed of the boat in still water be r km/hrs. Let the speed of the water current be m km/hrs. $\bf{\orange{\large{\underline{\underline{\bf{1_{st}\:Case\::}}}}}}$ $\bf{We\:have}\begin{cases}\sf{A\:boat\:speed\:for\:Upstream=\dfrac{16}{r-m} }\\ \sf{A\:boat\:speed\:for\:Downstream=\dfrac{24}{r+m} }\\ \sf{Time(t_{1})=6\:hours}\end{cases}}$ Formula use : $\sf{\pink{Time=\dfrac{Distance}{Speed} }}$ So; $\mapsto\bf{\dfrac{16}{r-m} +\dfrac{24}{r+m} =6....................(1)}$ $\bf{\orange{\large{\underline{\underline{\bf{2_{nd}\:Case\::}}}}}}$ $\bf{We\:have}\begin{cases}\sf{A\:boat\:speed\:for\:Upstream=\dfrac{36}{r-m} }\\ \sf{A\:boat\:speed\:for\:Downstream=\dfrac{48}{r+m} }\\ \sf{Time(t_{1})=13\:hours}\end{cases}}$ So; $\mapsto\bf{\dfrac{36}{r-m} +\dfrac{48}{r+m} =13....................(2)}$ We are replacing method use : $\bf{\dfrac{1}{r-m} =x\:\:\:\:\:\:\:\& \:\:\:\:\:\dfrac{1}{r+m} =y}$ Then; $\mapsto\sf{16x+24y=6..............(3)}\\\\\mapsto\sf{36x+48y=13............(<klux>4</klux>)}$ Using Substitution Method : From equation (3) we get; $\mapsto\sf{16x+24y=6}\\\\\mapsto\sf{16x=6-24y}\\\\\mapsto\bf{x=\dfrac{6-24y}{16} ................(5)}$ Putting the value of x in equation (4),we get; $\mapsto\sf{36\big(\dfrac{6-24y}{16} \big)+48y=13}\\\\\\\mapsto\sf{\dfrac{216-864y}{16} +48y=13}\\\\\\\mapsto\sf{216-864y+768y=208}\\\\\\\mapsto\sf{216-96y=208}\\\\\\\mapsto\sf{-96y=208-216}\\\\\\\mapsto\sf{-96y=-8}\\\\\\\mapsto\sf{y=\cancel{\dfrac{-8}{-96}} }\\\\\\\mapsto\sf{\pink{y=\dfrac{1}{12} }}$ Putting the value of y in equation (5),we get; $\mapsto\sf{x=\dfrac{6-24(\frac{1}{12}) }{16} }\\\\\\\mapsto\sf{x=\dfrac{6-\frac{24}{12} }{16} }\\\\\\\mapsto\sf{x=\dfrac{\frac{72-24}{12} }{16} }\\\\\\\mapsto\sf{x=\dfrac{\frac{48}{12} }{16} }\\\\\\\mapsto\sf{x=\dfrac{\cancel{48}}{12} \times \dfrac{1}{\cancel{16}} }\\\\\\\mapsto\sf{x=\cancel{\dfrac{3}{12}} }\\\\\\\mapsto\sf{\pink{x=\dfrac{1}{4} }}$ Now; $\mapsto\sf{\dfrac{1}{r-m} =\dfrac{1}{4} }\\\\\mapsto\sf{r-m=4}\\\\\mapsto\bf{r=4+m.......................(6)}$ & $\mapsto\sf{\dfrac{1}{r+m} =y}\\\\\mapsto\sf{\dfrac{1}{r+m} =\dfrac{1}{12} }\\\\\mapsto\sf{r+m=12}\\\\\mapsto\sf{4+m+m=12\:\:\:\:\:\:[from(1)]}\\\\\mapsto\sf{4+2m=12}\\\\\mapsto\sf{2m=12-4}\\\\\mapsto\sf{2m=8}\\\\\mapsto\sf{m=\cancel{\dfrac{8}{2} }}\\\\\mapsto\sf{\pink{m=4\:km/hrs}}$ Putting the value of m in equation (6),we get; $\mapsto\sf{r=4+4}\\\\\mapsto\sf{\pink{r=8\:km/hrs}}$ Thus; $\underbrace{\sf{The \:speed \:of\: the \:boat\: in\: still\: water=r=8km/hrs}}}}}\\\underbrace{\sf{The \:speed \:of\: the\: water\:current=m=4km/hrs}}}}}$

15.

Ex. 3) A boat travels 16 km upstreamand 24 km downstream in 6hours.The same boat travels 36 kmupstream and 48 km downstreamin 13 hours.Find the speed of water current and speed of boat in still water.lnn Irm/hr and the speed

Answer»

Solution :

$\bf{\red{\underline{\underline{\bf{Given\::}}}}}$

A boat travels 16 km upstream and 24 km downstream in 6 hours.The same boat travels 36 km upstream and 48 km downstream in 13 hours.

$\bf{\red{\underline{\underline{\bf{To\:find\::}}}}}$

The speed of water current and speed of boat in still water.

$\bf{\red{\underline{\underline{\bf{Explanation\::}}}}}$

Let the speed of the boat in still water be r km/hrs.

Let the speed of the water current be m km/hrs.

$\bf{\orange{\large{\underline{\underline{\bf{1_{st}\:Case\::}}}}}}$

$\bf{We\:have}\begin{cases}\sf{A\:boat\:speed\:for\:Upstream=\dfrac{16}{r-m} }\\ \sf{A\:boat\:speed\:for\:Downstream=\dfrac{24}{r+m} }\\ \sf{Time(t_{1})=6\:hours}\end{cases}}$

Formula use :

$\sf{\pink{Time=\dfrac{Distance}{Speed} }}$

So;

$\mapsto\bf{\dfrac{16}{r-m} +\dfrac{24}{r+m} =6....................(1)}$

$\bf{\orange{\large{\underline{\underline{\bf{2_{nd}\:Case\::}}}}}}$

$\bf{We\:have}\begin{cases}\sf{A\:boat\:speed\:for\:Upstream=\dfrac{36}{r-m} }\\ \sf{A\:boat\:speed\:for\:Downstream=\dfrac{48}{r+m} }\\ \sf{Time(t_{1})=13\:hours}\end{cases}}$

So;

$\mapsto\bf{\dfrac{36}{r-m} +\dfrac{48}{r+m} =13....................(2)}$

We are replacing method use :

$\bf{\dfrac{1}{r-m} =x\:\:\:\:\:\:\:\& \:\:\:\:\:\dfrac{1}{r+m} =y}$

Then;

$\mapsto\sf{16x+24y=6..............(3)}\\\\\mapsto\sf{36x+48y=13............(<klux>4</klux>)}$

Using Substitution Method :

From equation (3) we get;

$\mapsto\sf{16x+24y=6}\\\\\mapsto\sf{16x=6-24y}\\\\\mapsto\bf{x=\dfrac{6-24y}{16} ................(5)}$

Putting the value of x in equation (4),we get;

$\mapsto\sf{36\big(\dfrac{6-24y}{16} \big)+48y=13}\\\\\\\mapsto\sf{\dfrac{216-864y}{16} +48y=13}\\\\\\\mapsto\sf{216-864y+768y=208}\\\\\\\mapsto\sf{216-96y=208}\\\\\\\mapsto\sf{-96y=208-216}\\\\\\\mapsto\sf{-96y=-8}\\\\\\\mapsto\sf{y=\cancel{\dfrac{-8}{-96}} }\\\\\\\mapsto\sf{\pink{y=\dfrac{1}{12} }}$

Putting the value of y in equation (5),we get;

$\mapsto\sf{x=\dfrac{6-24(\frac{1}{12}) }{16} }\\\\\\\mapsto\sf{x=\dfrac{6-\frac{24}{12} }{16} }\\\\\\\mapsto\sf{x=\dfrac{\frac{72-24}{12} }{16} }\\\\\\\mapsto\sf{x=\dfrac{\frac{48}{12} }{16} }\\\\\\\mapsto\sf{x=\dfrac{\cancel{48}}{12} \times \dfrac{1}{\cancel{16}} }\\\\\\\mapsto\sf{x=\cancel{\dfrac{3}{12}} }\\\\\\\mapsto\sf{\pink{x=\dfrac{1}{4} }}$

Now;

$\mapsto\sf{\dfrac{1}{r-m} =\dfrac{1}{4} }\\\\\mapsto\sf{r-m=4}\\\\\mapsto\bf{r=4+m.......................(6)}$

&

$\mapsto\sf{\dfrac{1}{r+m} =y}\\\\\mapsto\sf{\dfrac{1}{r+m} =\dfrac{1}{12} }\\\\\mapsto\sf{r+m=12}\\\\\mapsto\sf{4+m+m=12\:\:\:\:\:\:[from(1)]}\\\\\mapsto\sf{4+2m=12}\\\\\mapsto\sf{2m=12-4}\\\\\mapsto\sf{2m=8}\\\\\mapsto\sf{m=\cancel{\dfrac{8}{2} }}\\\\\mapsto\sf{\pink{m=4\:km/hrs}}$

Putting the value of m in equation (6),we get;

$\mapsto\sf{r=4+4}\\\\\mapsto\sf{\pink{r=8\:km/hrs}}$

Thus;

$\underbrace{\sf{The \:speed \:of\: the \:boat\: in\: still\: water=r=8km/hrs}}}}}\\\underbrace{\sf{The \:speed \:of\: the\: water\:current=m=4km/hrs}}}}}$

Discussion

16.	Find two positive number having a sum 23 and a product of 126
Answer» PLZZ MARK as brainliest hope it HELP you

16.

Find two positive number having a sum 23 and a product of 126

Answer»

PLZZ MARK as brainliest

hope it HELP you

Discussion

17.	Statement of the sum of 2 adjacent angles is 18then their non common arms are twoopposite rays. Plese show the steps to solve this, (class 9)
Answer» Step-by-step EXPLANATION: i don't think it's the KI moon but she is a chemical equation and has a new car for a while now and then d f the day is the most IMPORTANT thing to me and I am in a way of being in my life for the first

17.

Statement of the sum of 2 adjacent angles is 18then their non common arms are twoopposite rays. Plese show the steps to solve this, (class 9)

Answer»

Step-by-step EXPLANATION:

i don't think it's the KI moon but she is a chemical equation and has a new car for a while now and then

d f the day is the most IMPORTANT thing to me and I am in a way of being in my life for the first

Discussion

18.	mario had 700 marbles.he gave away 175 marbles and put the remaining marbles equally into 5 bags.how many marbles were there in each bag?
Answer» Answer: 105 Step-by-step EXPLANATION: TOTAL NO. OF MARBLES=700 NO.OF MARBLES GIVEN AWAY=175 NO.OF MARBLES LEFT=700-125=525 NO.IF BAGS=5 MARBLES IN EACH BAG=525÷5=105

18.

mario had 700 marbles.he gave away 175 marbles and put the remaining marbles equally into 5 bags.how many marbles were there in each bag?

Answer»

Answer:

105

Step-by-step EXPLANATION:

TOTAL NO. OF MARBLES=700

NO.OF MARBLES GIVEN AWAY=175

NO.OF MARBLES LEFT=700-125=525

NO.IF BAGS=5

MARBLES IN EACH BAG=525÷5=105

Discussion

19.	The difference of the tenth place and the unit place of two-digit number is 7. If the digits are reversed the new number obtained is 63 less than the original number. Find the number.
Answer» Step-by-step EXPLANATION: HOPE it HELPS you and PLZ FOLLOW me

19.

The difference of the tenth place and the unit place of two-digit number is 7. If the digits are reversed the new number obtained is 63 less than the original number. Find the number.

Answer»

Step-by-step EXPLANATION:

HOPE it HELPS you and PLZ FOLLOW me

Discussion

20.	Ir the mode of 3,X,6,8 is 8 then value of x will be-
Answer» HEY MATE ! Here's your answer : $x = 8$ KINDLY refer to the Attachment Step-by-step explanation: Kindly rate and *like* Follow *Mark* as *Brainliest* ⚽⚽⚽

20.

Ir the mode of 3,X,6,8 is 8 then value of x will be-

Answer»

HEY MATE !

Here's your answer :

$x = 8$

KINDLY refer to the Attachment

Step-by-step explanation:

Kindly rate and like
Follow

Mark as Brainliest

⚽⚽⚽

Discussion

21.	Answer 4 ,5, 6 questionWho will give the answer fast with proper answer and proper explanation I will make them brain list
Answer» ANSWER: in 4 answer you have to SUBTRACT

21.

Answer 4 ,5, 6 questionWho will give the answer fast with proper answer and proper explanation I will make them brain list

Answer»

ANSWER:

in 4 answer you have to SUBTRACT

Discussion

22.	Which of the following fraction are greater than 3 and less than 4?25/6,16/25,23/7,15/4,28/3,19/5,25/6,82/9,21/6
Answer» ANSWER: The answer is 16/25 GREATER than 3 and LESS than 4

22.

Which of the following fraction are greater than 3 and less than 4?25/6,16/25,23/7,15/4,28/3,19/5,25/6,82/9,21/6

Answer»

ANSWER:

The answer is 16/25 GREATER than 3 and LESS than 4

Discussion

23.	The domain of tan 3x is the domain of
Answer» ANSWER: Step-by-step EXPLANATION:

23.

The domain of tan 3x is the domain of

Answer»

ANSWER:

Step-by-step EXPLANATION:

Discussion

24.	4397 is to the blank of 4396 on the number line
Answer» Answer: 4397 is to the RIGHT of 4396 on the NUMBER LINE.

24.

4397 is to the blank of 4396 on the number line

Answer»

Answer:

4397 is to the RIGHT of 4396 on the NUMBER LINE.

Discussion

25.	यदि आपको एक आदमी को 5 रुपए देने हो ओर साथ ही आपको 5 आदमियों को 10 10 रुपए देने हो तो आप क्या गणित लगाओगे 50 देना है ओर 5 देना है मतलब 55 देना है ना कि 5 को 10 में जोड़ कर 15 गुणित 5 करोगे
Answer» Step-by-step EXPLANATION: i DONT KNOE the QUESTION

25.

यदि आपको एक आदमी को 5 रुपए देने हो ओर साथ ही आपको 5 आदमियों को 10 10 रुपए देने हो तो आप क्या गणित लगाओगे 50 देना है ओर 5 देना है मतलब 55 देना है ना कि 5 को 10 में जोड़ कर 15 गुणित 5 करोगे

Answer»

Step-by-step EXPLANATION:

i DONT KNOE the QUESTION

Discussion

26.	Sum and product of zeroes are √2 and -3/2 respectively. Find equation and zeroes.
Answer» <P>Step-by-step EXPLANATION: First of all WRITE the FORMULA for making equation i.e. $x^2 - sx + p$ In this formula , put the VALUE of sum of zeroes in place of s and put the value of product of zeroes in place of p . $x^2 - \sqrt{2 } x + ( - 3 \div 2)$ $x ^2 - \sqrt{2x} - 3 \div 2$ Please mark me the brainliest!!!!

26.

Sum and product of zeroes are √2 and -3/2 respectively. Find equation and zeroes.

Answer»

<P>Step-by-step EXPLANATION:

First of all WRITE the FORMULA for making equation i.e.

$x^2 - sx + p$

In this formula , put the VALUE of sum of zeroes in place of s and put the value of product of zeroes in place of p .

$x^2 - \sqrt{2 } x + ( - 3 \div 2)$

$x ^2 - \sqrt{2x} - 3 \div 2$

Please mark me the brainliest!!!!

Discussion

27.	Q.9 :- रु 15000 पर 2 वर्षों के लिएलगेचक्रविधि और साधारण ब्याज का अंतर 96 है।ब्याज दर क्या होगी?12:08pm
Answer» <P>ANSWER: p*(r/100)^2 USE this FORMULA

27.

Q.9 :- रु 15000 पर 2 वर्षों के लिएलगेचक्रविधि और साधारण ब्याज का अंतर 96 है।ब्याज दर क्या होगी?12:08pm

Answer»

<P>ANSWER:

p*(r/100)^2 USE this FORMULA

Discussion

28.	39.392800 convert it into 4 significant figutes
Answer» Answer: 39.39 Step-by-step explanation: This MEANS that there must be only 4 significant figures in the number Given number contains 8 significant figures hence we have to decrease the last four figures by rounding off here if the figure is less than 5 then the left number remain unchanged but if the last figure is 5 or greater than 5 then the left digit increase by 1 Let apply this in the above number both zeros are less than 5 , hence digit 8 will remain unchanged... THOUGH we remove both zeros and the number will become 39.3928 now digit 8 is greater than 5 ... hence the left digit will become 3 and number become 39.393 let the digit 3 is less than 5 hence we can remove it without any CHANGE in the left digits ... this way the number will become 39.39 in the last solution there are only 4 significant figures if this answer helped you... then rate me 5 STARS...

28.

39.392800 convert it into 4 significant figutes

Answer»

Answer:

39.39

Step-by-step explanation:

This MEANS that there must be only 4 significant figures in the number

Given number contains 8 significant figures

hence we have to decrease the last four figures by rounding off

here

if the figure is less than 5 then the left number remain unchanged

but if the last figure is 5 or greater than 5 then the left digit increase by 1

Let

apply this in the above number

both zeros are less than 5 , hence digit 8 will remain unchanged... THOUGH we remove both zeros

and the number will become 39.3928

now digit 8 is greater than 5 ... hence the left digit will become 3

and number become 39.393

let

the digit 3 is less than 5

hence we can remove it without any CHANGE in the left digits ...

this way the number will become 39.39

in the last solution there are only 4 significant figures

if this answer helped you...

then rate me 5 STARS...

Discussion

29.	How many rational number are there between any two rational number
Answer» ANSWER: they are INFINITE RATIONAL NUMBERS between any TWO rational numbers

29.

How many rational number are there between any two rational number

Answer»

ANSWER:

they are INFINITE RATIONAL NUMBERS between any TWO rational numbers

Discussion

30.	Four times a number reduced by 5 equals 19A) 4x-5 = 19 B) 5x-4=19 C)4x+5=19 D)5+4=19
Answer» ANSWER: a Step-by-step EXPLANATION: LET the no be x equation- 4x-5=19

30.

Four times a number reduced by 5 equals 19A) 4x-5 = 19 B) 5x-4=19 C)4x+5=19 D)5+4=19

Answer»

ANSWER:

a

Step-by-step EXPLANATION:

LET the no be x

equation- 4x-5=19

Discussion

31.	For what value of x is (81x + 175)/512 divisible by 2?
Answer» Answer: the VALUE of x = 10.48 for more information, refer to the attachment. Step-by-step EXPLANATION: HOPE it HELPS ✔✔

31.

For what value of x is (81x + 175)/512 divisible by 2?

Answer»

Answer:

the VALUE of x = 10.48

for more information, refer to the attachment.

Step-by-step EXPLANATION:

HOPE it HELPS ✔✔

Discussion

32.	Find the distance (in km) she covers in 30 days.A tailoring unit stitched 24,956 baby suits. These suits were packed in 144 cartons,hold 160 suits. Find out how many baby suits were left unpacked.
Answer» Answer: total suites 24956 (1) suites packed in 144 cartoon's =160×144=23040. (2) from IST and 2nd we get 24956 -- 23040 =1916 hence the total NUMBER of suites which were unpacked are 1916

32.

Find the distance (in km) she covers in 30 days.A tailoring unit stitched 24,956 baby suits. These suits were packed in 144 cartons,hold 160 suits. Find out how many baby suits were left unpacked.

Answer»

Answer:

total suites 24956 (1)

suites packed in 144 cartoon's =160×144=23040. (2)

from IST and 2nd we get

24956 -- 23040

=1916

hence the total NUMBER of suites which were unpacked are 1916

Discussion

33.	Solve Q44.- I) partAsap
Answer» ANSWER: POST it FULL..............

33.

Solve Q44.- I) partAsap

Answer»

ANSWER:

POST it FULL..............

Discussion

34.	If alpha and beta are zeros of the quadratic polynomial 4x^2-5x+1 then find:i) ii)
Answer»

Discussion

35.	If the length of the arc of a circle having a central angle 36° is 22 cm, what is the area of circle?
Answer» ANSWER: FORMULA i am GIVING (PI)r^2 do by USING this formula

35.

If the length of the arc of a circle having a central angle 36° is 22 cm, what is the area of circle?

Answer»

ANSWER:

FORMULA i am GIVING (PI)r^2

do by USING this formula

Discussion

36.	#thanks for answering ℹ️f you felt easy then definitely ☑ check out my profile and please answer my questions ➡️
Answer» Question : Out of two workers X and Y , X is TWICE as good as Y to perform the work assigned to them. If X can finish the assigned work in 40 days LESS than Y, then how many days they can finish the work if there work together ? Solution : Let the no. of days taken to finish the work by X be x days X is twice as good as Y to perform the work So, No. of days taken by Y to finish the work = 2X days Given : X can finish the assigned work in 40 days less than Y ⇒ x = 2x - 40 ⇒ 40 = 2x - x ⇒ x = 40 X can finish the work in = 40 days X's 1 day work = 1 / 40 of work Y can finish the work in = 2x = 2 × 40 = 80 days Y's 1 day work = 1 / 80 of work ( X + Y )'s 1 day work = X's 1 day work + Y's 1 day work = ( 1 / 40 ) + ( 1 / 80 ) = ( 2 + 1 ) / 80 = 3 / 80 ( X + Y ) can finish the work in = 80 / 3 = 26 2/3 days Therefore, they take 26 2/3 days to finish the work if they work together.

36.

#thanks for answering ℹ️f you felt easy then definitely ☑ check out my profile and please answer my questions ➡️

Answer»

Question :

Out of two workers X and Y , X is TWICE as good as Y to perform the work assigned to them. If X can finish the assigned work in 40 days LESS than Y, then how many days they can finish the work if there work together ?

Solution :

Let the no. of days taken to finish the work by X be x days

X is twice as good as Y to perform the work

So, No. of days taken by Y to finish the work = 2X days

Given :

X can finish the assigned work in 40 days less than Y

⇒ x = 2x - 40

⇒ 40 = 2x - x

⇒ x = 40

X can finish the work in = 40 days

X's 1 day work = 1 / 40 of work

Y can finish the work in = 2x = 2 × 40 = 80 days

Y's 1 day work = 1 / 80 of work

( X + Y )'s 1 day work = X's 1 day work + Y's 1 day work

= ( 1 / 40 ) + ( 1 / 80 )

= ( 2 + 1 ) / 80

= 3 / 80

( X + Y ) can finish the work in = 80 / 3 = 26 2/3 days

Therefore, they take 26 2/3 days to finish the work if they work together.

Discussion

37.	2sin^2A +cos^4A =1+sin^4A
Answer» $\huge{\underline{\underline{\red{♡Solution→}}}}$ $2 {sin}^{2} a + {cos}^{4} a = 1 + {sin}^{4} a$ $\bold{\huge{\underline{\underline{\rm{ LHS :}}}}}$ $= 2 {sin}^{2} a + {cos}^{4} a$ $= 2 {sin}^{2} a + ( { {cos}^{2} a)}^{2}$ We KNOW that → ${cos}^{2} a = 1 - {sin}^{2} a$ $= 2 {sin}^{2} a + ( {1 - {sin}^{2}a) }^{2} \\ = 2 {sin}^{2} a + 1 + {sin}^{4} a - 2 {sin}^{2} a$ $= 1 + {sin}^{4} a$ $\bold{\huge{\underline{\underline{\rm{ RHS ↑}}}}}$ *MARK as BRAINLIEST !! ✨✨*

37.

2sin^2A +cos^4A =1+sin^4A

Answer»

$\huge{\underline{\underline{\red{♡Solution→}}}}$

$2 {sin}^{2} a + {cos}^{4} a = 1 + {sin}^{4} a$

$\bold{\huge{\underline{\underline{\rm{ LHS :}}}}}$

$= 2 {sin}^{2} a + {cos}^{4} a$

$= 2 {sin}^{2} a + ( { {cos}^{2} a)}^{2}$

We KNOW that →

${cos}^{2} a = 1 - {sin}^{2} a$

$= 2 {sin}^{2} a + ( {1 - {sin}^{2}a) }^{2} \\ = 2 {sin}^{2} a + 1 + {sin}^{4} a - 2 {sin}^{2} a$

$= 1 + {sin}^{4} a$

$\bold{\huge{\underline{\underline{\rm{ RHS ↑}}}}}$

MARK as BRAINLIEST !! ✨✨

Discussion

38.	54 % + 10 % + – is equals to hundred percent
Answer» Answer: 54/100+10/100+x=100/100 64/100+x=100/100 x=100/100-64/100 *x=36/100* *x=36/100x=9/25*

38.

54 % + 10 % + – is equals to hundred percent

Answer»

Answer:

54/100+10/100+x=100/100

64/100+x=100/100

x=100/100-64/100

x=36/100

x=36/100x=9/25

Discussion

39.	a bag contain 10 white balls and some green balls. if the probability of choosing green ball is 1/2. find no. of green balls. find the probability of white balls
Answer» PROBABILITY of GETTING green BALLS = 1/2 This MEANS that half balls are green and half are white No. of green balls = 10 Probability of getting white balls = 1 - 1/2 = 2-1/2 = 1/2

39.

a bag contain 10 white balls and some green balls. if the probability of choosing green ball is 1/2. find no. of green balls. find the probability of white balls

Answer»

PROBABILITY of GETTING green BALLS = 1/2

This MEANS that half balls are green and half are white

No. of green balls = 10

Probability of getting white balls = 1 - 1/2 = 2-1/2 = 1/2

Discussion

40.	AC meet CD and ab at D and e respectively c e and e are the bisectors of angle C and Angle A respectively such that angle 1 + angle 2 is equal to 90° prove that AB is parallel to CD it is very urgent of answer will be good I'll make your answer the brainliest
Answer» Answer: Step-by-step explanation: we know 1+2=90 and let ECD and EAB be X and y respectively 1+x=90 by linear pair eqn1 2+y=90 same eqn 2 by adding eqn 1 and 2 1+2+x+y=180 hence prooved lines are parallel as corresponding ANGLES are equal

40.

AC meet CD and ab at D and e respectively c e and e are the bisectors of angle C and Angle A respectively such that angle 1 + angle 2 is equal to 90° prove that AB is parallel to CD it is very urgent of answer will be good I'll make your answer the brainliest

Answer»

Answer:

Step-by-step explanation:

we know 1+2=90

and let ECD and EAB be X and y respectively

1+x=90 by linear pair eqn1

2+y=90 same eqn 2

by adding eqn 1 and 2

1+2+x+y=180

hence prooved lines are parallel

as corresponding ANGLES are equal

Discussion

41.	Write in algebric expression. the quotient of a number T and thirty seven
Answer» Answer: ALGEBRAIC expressions and equations, assign a VARIABLE to represent the unknown ... In translation problems, the words sum, total, difference, PRODUCT and quotient ... A NUMBER minus SEVEN. X ...

41.

Write in algebric expression. the quotient of a number T and thirty seven

Answer»

Answer:

ALGEBRAIC expressions and equations, assign a VARIABLE to represent the unknown ... In translation problems, the words sum, total, difference, PRODUCT and quotient ... A NUMBER minus SEVEN. X ...

Discussion

42.	Please solve the attached question I'll mark u as brainliest
Answer» ANSWER: 2^1/3.2^1/4.2^5.1/12 2^(1/3+1/4).2^5/12 2^(4/12+3/12).2^5/12 2^7/12.2^5/12 2^(7/12+5/12) 2^(12/12) 2^1 2 is the CORRECT answer... MARK as BRAINIEST

42.

Please solve the attached question I'll mark u as brainliest

Answer»

ANSWER:

2^1/3.2^1/4.2^5.1/12

2^(1/3+1/4).2^5/12

2^(4/12+3/12).2^5/12

2^7/12.2^5/12

2^(7/12+5/12)

2^(12/12)

2^1

2 is the CORRECT answer... MARK as BRAINIEST

Discussion

43.	Answer for this question
Answer» ANSWER: I don't understand the question and PLZ mark me BRAINLISTS plz plz

43.

Answer for this question

Answer»

ANSWER:

I don't understand the question and PLZ mark me BRAINLISTS plz plz

Discussion

44.	A. Find the products.1. 59 x 10
Answer» Answer: 590 Step-by-step explanation: 59x 10 =590 Hope this HELPS

44.

A. Find the products.1. 59 x 10

Answer»

Answer:

590

Step-by-step explanation:

59x 10

=590

Hope this HELPS

Discussion

45.	Please open the files and answer in step by step please
Answer» $\huge{\bigstar{\mathfrak{\purple{answer}}}}$ STEPS are in attachment 1/12 TH 1/4 th the people 1/12 th 1/3 rd a)1/24 and B)1/3 $\huge{\mathfrak{\orange{hope\; it\; helps}}}$

45.

Please open the files and answer in step by step please

Answer»

$\huge{\bigstar{\mathfrak{\purple{answer}}}}$

STEPS are in attachment

1/12 TH
1/4 th the people
1/12 th
1/3 rd
a)1/24 and B)1/3

$\huge{\mathfrak{\orange{hope\; it\; helps}}}$

Discussion

46.	7, 2,5, 1, 3, 9 using each of these digitsonly once from the greatest and theSmallest number in the both the numbersystem, insertcommasusing internationalanumber system
Answer» PLS mark as the BRAINLIEST pls pls the answer in the PICTURE is ACCORDING to international system and According to the Indian system the answer is GREATEST NO. 9,75,321 SMALLEST NO. 1,23,,579

46.

7, 2,5, 1, 3, 9 using each of these digitsonly once from the greatest and theSmallest number in the both the numbersystem, insertcommasusing internationalanumber system

Answer»

PLS mark as the BRAINLIEST pls pls

the answer in the PICTURE is ACCORDING to international system

and According to the Indian system the answer is

GREATEST NO. 9,75,321

SMALLEST NO. 1,23,,579

Discussion

47.	See the attachment ...guys ..dont spAm
Answer» ANSWER: answer is in ATTACHMENT.......... Step-by-step EXPLANATION: HOPE it HELPS ✔✔

47.

See the attachment ...guys ..dont spAm

Answer»

ANSWER:

answer is in ATTACHMENT..........

Step-by-step EXPLANATION:

HOPE it HELPS ✔✔

Discussion

48.	What is the place value of the 6 digit from the right of an 9 digit number
Answer» e.g. 9 digit no- 161728584 6 digit from the right- 7 place value- HUNDRED thousands in INTERNATIONAL no SYSTEM LAKHS in indian no system

48.

What is the place value of the 6 digit from the right of an 9 digit number

Answer»

e.g. 9 digit no- 161728584

6 digit from the right- 7

place value- HUNDRED thousands in INTERNATIONAL no SYSTEM

LAKHS in indian no system

Discussion

49.	Sum of two consecutive no.is 45
Answer» HOPE it will WORK.......

Discussion

50.	WORD PROBLEMS Example 1 : Vishakha reads a book for 1 4/5 hours everyday. She reads the entire book in 10 days. How manyhours in all were required by her to read the book?
Answer» Answer: 1 4/5 hrs=60+48 mins =108 mins 108×10=1080 mins 1080÷60=18 hrs *Vishaka REQUIRED 18 hrs to READ the BOOK.*

50.

WORD PROBLEMS Example 1 : Vishakha reads a book for 1 4/5 hours everyday. She reads the entire book in 10 days. How manyhours in all were required by her to read the book?

Answer»

Answer:

1 4/5 hrs=60+48 mins

=108 mins

108×10=1080 mins

1080÷60=18 hrs

Vishaka REQUIRED 18 hrs to READ the BOOK.

Discussion

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