AC meet CD and ab at D and e respectively c e and e are the bisectors

1.	AC meet CD and ab at D and e respectively c e and e are the bisectors of angle C and Angle A respectively such that angle 1 + angle 2 is equal to 90° prove that AB is parallel to CD it is very urgent of answer will be good I'll make your answer the brainliest
Answer» Answer: Step-by-step explanation: we know 1+2=90 and let ECD and EAB be X and y respectively 1+x=90 by linear pair eqn1 2+y=90 same eqn 2 by adding eqn 1 and 2 1+2+x+y=180 hence prooved lines are parallel as corresponding ANGLES are equal

AC meet CD and ab at D and e respectively c e and e are the bisectors of angle C and Angle A respectively such that angle 1 + angle 2 is equal to 90° prove that AB is parallel to CD it is very urgent of answer will be good I'll make your answer the brainliest

Answer»

Answer:

Step-by-step explanation:

we know 1+2=90

and let ECD and EAB be X and y respectively

1+x=90 by linear pair eqn1

2+y=90 same eqn 2

by adding eqn 1 and 2

1+2+x+y=180

hence prooved lines are parallel

as corresponding ANGLES are equal

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AC meet CD and ab at D and e respectively c e and e are the bisectors of angle C and Angle A respectively such that angle 1 + angle 2 is equal to 90° prove that AB is parallel to CD​ it is very urgent of answer will be good I'll make your answer the brainliest

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AC meet CD and ab at D and e respectively c e and e are the bisectors of angle C and Angle A respectively such that angle 1 + angle 2 is equal to 90° prove that AB is parallel to CD it is very urgent of answer will be good I'll make your answer the brainliest