Saved Bookmarks
| 1. |
#thanks for answering ℹ️f you felt easy then definitely ☑ check out my profile and please answer my questions ➡️ |
Answer» Question :Out of two workers X and Y , X is TWICE as good as Y to perform the work assigned to them. If X can finish the assigned work in 40 days LESS than Y, then how many days they can finish the work if there work together ? Solution :Let the no. of days taken to finish the work by X be x days X is twice as good as Y to perform the work So, No. of days taken by Y to finish the work = 2X days Given : X can finish the assigned work in 40 days less than Y ⇒ x = 2x - 40 ⇒ 40 = 2x - x ⇒ x = 40 X can finish the work in = 40 days X's 1 day work = 1 / 40 of work Y can finish the work in = 2x = 2 × 40 = 80 days Y's 1 day work = 1 / 80 of work ( X + Y )'s 1 day work = X's 1 day work + Y's 1 day work = ( 1 / 40 ) + ( 1 / 80 ) = ( 2 + 1 ) / 80 = 3 / 80 ( X + Y ) can finish the work in = 80 / 3 = 26 2/3 days Therefore, they take 26 2/3 days to finish the work if they work together. |
|