332354 + Interview Questions in Secondary School in Math

1.	If
Answer» ∠BCD is of 100°. Step-by-step explanation: Given ∠ABD is 70° ∠ADB is 30°. To FIND:- Measure of ∠BCD Solution:- We know that, Sum of all interior angles of triangle is 180°. This PROPERTY is also KNOWN as'Angle sum property of TRIANGLE'. So, ➞ ∠A + ∠ABD + ∠ADB = 180° ➞ ∠A + 70° + 30° = 180° ➞ ∠A + 100° = 180° ➞ ∠A = 180° - 100° ➞ ∠A = 80° Given QUADRILATERAL is cyclic quadrilateral because it's all vertices are lying on the circumference of circle. We also know that, Sum of any two opposite angles of any cyclic quadrilateral is 180°. So, ➞ ∠A + ∠BCD = 180° ➞ 80° + ∠BCD = 180° ➞ ∠BCD = 180° - 80° ➞ ∠BCD = 100°. Therefore, ∠BCD is of 100°.

1.

If

Answer»

∠BCD is of 100°.

Step-by-step explanation:

Given

∠ABD is 70°
∠ADB is 30°.

To FIND:-

Measure of ∠BCD

Solution:-

We know that,

Sum of all interior angles of triangle is 180°. This PROPERTY is also KNOWN as'Angle sum property of TRIANGLE'.

So,

➞ ∠A + ∠ABD + ∠ADB = 180°

➞ ∠A + 70° + 30° = 180°

➞ ∠A + 100° = 180°

➞ ∠A = 180° - 100°

➞ ∠A = 80°

Given QUADRILATERAL is cyclic quadrilateral because it's all vertices are lying on the circumference of circle.

We also know that,

Sum of any two opposite angles of any cyclic quadrilateral is 180°.

So,

➞ ∠A + ∠BCD = 180°

➞ 80° + ∠BCD = 180°

➞ ∠BCD = 180° - 80°

➞ ∠BCD = 100°.

Therefore,

∠BCD is of 100°.

Discussion

2.	Find the smallest number by which each of the following numbersmust be multiplied to obtain a perfect cube.a. 2808b. 1323c. 128625d. 13720e. 68600
Answer» Answer: e) 68600 is not a perfect cube. To make it a perfect cube we multiply it by 5. Thus, 68600 × 5 = 2 × 2 × 2 × 5 × 5 × 5 × 7 × 7 × 7 = 343000, which is a perfect cube. Observe that 343 is a perfect cube. b) In order for 1323 to BECOME a perfect cube, we NEED to multiply it by 7. This will give US 9261 and the cube root will be 21. On dividing 1323 by 3 and 7 we get 3 X 3 x 3 x 7 x 7.

2.

Find the smallest number by which each of the following numbersmust be multiplied to obtain a perfect cube.a. 2808b. 1323c. 128625d. 13720e. 68600

Answer»

Answer:

e) 68600 is not a perfect cube. To make it a perfect cube we multiply it by 5. Thus, 68600 × 5 = 2 × 2 × 2 × 5 × 5 × 5 × 7 × 7 × 7 = 343000, which is a perfect cube. Observe that 343 is a perfect cube.

b) In order for 1323 to BECOME a perfect cube, we NEED to multiply it by 7. This will give US 9261 and the cube root will be 21. On dividing 1323 by 3 and 7 we get 3 X 3 x 3 x 7 x 7.

Discussion

3.	The temperature rises by 18°F. What is the riseon the Celsius scale ?
Answer» ANSWER: OPEN the above attachment.. Step-by-step explanation: MARK me as BRAINLIEAST PLEASE..

3.

The temperature rises by 18°F. What is the riseon the Celsius scale ?

Answer»

ANSWER:

OPEN the above attachment..

Step-by-step explanation:

MARK me as BRAINLIEAST PLEASE..

Discussion

4.	Puzzle test4girls : Katina Katrina Deepika Jennifer4 courses : MCA MBA BCA BBA4 books : GK QM EE AR every girl is enrolled only for one course every girl can use 3 books Deepika is not preparing for BCA or mba Katrina who is not preparing for BCA use QM and EE the girl who is preparing for MBA uses EE and AR but the girl who is preparing for MCA uses only one of these books
Answer» ANSWER: Is it a QUESTION??? I have a DOUBT!

4.

Puzzle test4girls : Katina Katrina Deepika Jennifer4 courses : MCA MBA BCA BBA4 books : GK QM EE AR every girl is enrolled only for one course every girl can use 3 books Deepika is not preparing for BCA or mba Katrina who is not preparing for BCA use QM and EE the girl who is preparing for MBA uses EE and AR but the girl who is preparing for MCA uses only one of these books

Answer»

ANSWER:

Is it a QUESTION??? I have a DOUBT!

Discussion

5.	The distance covered by a wheel of radius 14cm in one Revolution is
Answer» Step-by-step explanation: 1000100mts the DISTANCE travelled is. Description for CORRECT ANSWER: RADIUS of the wheel = 14 cm. = 2×227×14=1000100mts.

5.

The distance covered by a wheel of radius 14cm in one Revolution is

Answer»

Step-by-step explanation:

1000100mts

the DISTANCE travelled is. Description for CORRECT ANSWER: RADIUS of the wheel = 14 cm. = 2×227×14=1000100mts.

Discussion

6.	5. Find the area of a triangular field whose sides are 91 m, 98 m and 105 min length. Find the height corresponding to the longest side.
Answer» Given: Sides of triangular field are 91 m, 98 m and 105 m. To find: The height CORRESPONDING to the longest side? ⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀ $\underline{\bigstar\:\boldsymbol{Using\: Heron's\:Formula\::}}\\ \\$ $\star\;{\boxed{\sf{\pink{Area_{\;(triangle)} = \sqrt{s(s - a)(s - b)(s - c)}}}}}\\ \\$ $:\implies\sf s = semi - perimeter\\ \\$ $:\implies\sf s = \dfrac{a + b + c}{2}\\ \\$ $:\implies\sf s = \dfrac{91 + 98 + 105}{2}\\ \\$ $:\implies\sf s = \cancel{ \dfrac{294}{2}}\\ \\$ $:\implies{\underline{\boxed{\frak{\purple{s = 147\:m}}}}}\;\bigstar$ ⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀ $\bf{\dag}\;{\underline{\frak{Now,\:Putting\:values\:in\:formula,}}}\\ \\$ $:\implies\sf Area_{\;(field)} = \sqrt{147(147 - 91)(147 - 98)(147 - 105)}\\ \\$ $:\implies\sf Area_{\;(field)} = \sqrt{147 \times 56 \times 49 \times 42}\\ \\$ $:\implies\sf Area_{\;(field)} = \sqrt{16941456}\\ \\$ $:\implies{\underline{\boxed{\frak{\purple{Area_{\;(field)} = 4116\:m^2}}}}}\;\bigstar\\ \\$ $\therefore\:{\underline{\sf{Area\:of\:triangular\:field\:is\: \bf{4116\:m^2}.}}}$ ⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀ ☯ Let's Consider H as the height corresponding to the longest side. ⠀⠀⠀⠀ Here, 105 m is the longest side = Base ⠀⠀⠀⠀ $\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\$ $\star\;{\boxed{\sf{\pink{Area_{\;(triangle)} = \dfrac{1}{2} \times base \times height}}}}\\ \\$ $:\implies\sf \dfrac{1}{2} \times 105 \times h = 4116\\ \\$ $:\implies\sf 105 \times h = 4116 \times 2\\ \\$ $:\implies\sf 105 \times h = 8232\\ \\$ $:\implies\sf h = \cancel{ \dfrac{8232}{105}}\\ \\$ $:\implies{\underline{\boxed{\frak{\purple{Area_{\;(field)} = 78.4\:m}}}}}\;\bigstar\\ \\$ $\therefore\:{\underline{\sf{Hence,\:the\:height\: corresponding\:to\:the\;longest\: side\:is\; {\textsf{\textbf{78.4\:m}}}.}}}$

6.

5. Find the area of a triangular field whose sides are 91 m, 98 m and 105 min length. Find the height corresponding to the longest side.

Answer»

Given: Sides of triangular field are 91 m, 98 m and 105 m.

To find: The height CORRESPONDING to the longest side?

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀

$\underline{\bigstar\:\boldsymbol{Using\: Heron's\:Formula\::}}\\ \\$

$\star\;{\boxed{\sf{\pink{Area_{\;(triangle)} = \sqrt{s(s - a)(s - b)(s - c)}}}}}\\ \\$

$:\implies\sf s = semi - perimeter\\ \\$

$:\implies\sf s = \dfrac{a + b + c}{2}\\ \\$

$:\implies\sf s = \dfrac{91 + 98 + 105}{2}\\ \\$

$:\implies\sf s = \cancel{ \dfrac{294}{2}}\\ \\$

$:\implies{\underline{\boxed{\frak{\purple{s = 147\:m}}}}}\;\bigstar$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀

$\bf{\dag}\;{\underline{\frak{Now,\:Putting\:values\:in\:formula,}}}\\ \\$

$:\implies\sf Area_{\;(field)} = \sqrt{147(147 - 91)(147 - 98)(147 - 105)}\\ \\$

$:\implies\sf Area_{\;(field)} = \sqrt{147 \times 56 \times 49 \times 42}\\ \\$

$:\implies\sf Area_{\;(field)} = \sqrt{16941456}\\ \\$

$:\implies{\underline{\boxed{\frak{\purple{Area_{\;(field)} = 4116\:m^2}}}}}\;\bigstar\\ \\$

$\therefore\:{\underline{\sf{Area\:of\:triangular\:field\:is\: \bf{4116\:m^2}.}}}$

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀

☯ Let's Consider H as the height corresponding to the longest side.

⠀⠀⠀⠀

Here,

105 m is the longest side = Base

⠀⠀⠀⠀

$\dag\;{\underline{\frak{As\;we\;know\;that,}}}\\ \\$

$\star\;{\boxed{\sf{\pink{Area_{\;(triangle)} = \dfrac{1}{2} \times base \times height}}}}\\ \\$

$:\implies\sf \dfrac{1}{2} \times 105 \times h = 4116\\ \\$

$:\implies\sf 105 \times h = 4116 \times 2\\ \\$

$:\implies\sf 105 \times h = 8232\\ \\$

$:\implies\sf h = \cancel{ \dfrac{8232}{105}}\\ \\$

$:\implies{\underline{\boxed{\frak{\purple{Area_{\;(field)} = 78.4\:m}}}}}\;\bigstar\\ \\$

$\therefore\:{\underline{\sf{Hence,\:the\:height\: corresponding\:to\:the\;longest\: side\:is\; {\textsf{\textbf{78.4\:m}}}.}}}$

Discussion

7.	0,15of the system of the equationsthe equations & -ky-7=2Kx-y-1=0, xty-z=0 has a non-zerosolution, then the possible values of kare?a 1,2, cod,
Answer» ANSWER: it has a huge solution,I could not able to FILL it FULLY

7.

0,15of the system of the equationsthe equations & -ky-7=2Kx-y-1=0, xty-z=0 has a non-zerosolution, then the possible values of kare?a 1,2, cod,

Answer»

ANSWER:

it has a huge solution,I could not able to FILL it FULLY

Discussion

8.	Pls answer it guys it’s 3 mark question
Answer» ANSWER: -1a^4/10 Step-by-step EXPLANATION: STEPS in the above PHOTO

8.

Pls answer it guys it’s 3 mark question

Answer»

ANSWER:

-1a^4/10

Step-by-step EXPLANATION:

STEPS in the above PHOTO

Discussion

9.	6 को भिन्न रूप मे लिखे
Answer» Answer: 6:- 1.) 6- VI, 2.) छह in HINDI 3.) षट् in sanskrit

9.

6 को भिन्न रूप मे लिखे

Answer»

Answer:

6:- 1.) 6- VI,

2.) छह in HINDI

3.) षट् in sanskrit

Discussion

10.	Pls help me for this question
Answer» Step-by-step EXPLANATION: Profit in 2017 = 10,000 Profit in 2018 = 10000 + 40%of 10000 = 10000+ 4000 =14000 Profit in 2019 =14000+ 40%of 14000 = 14000+5600 =19600 *Answer=* 19600 *UNITS*..

10.

Pls help me for this question

Answer»

Step-by-step EXPLANATION:

Profit in 2017 = 10,000

Profit in 2018

= 10000 + 40%of 10000

= 10000+ 4000

=14000

Profit in 2019

=14000+ 40%of 14000

= 14000+5600

=19600

Answer= 19600 UNITS..

Discussion

11.	You have given a function λ : R → R with the following properties (x ∈ R, n ∈ N): λ(n) = 0 , λ(x + 1) = λ(x) , λ .n + 1Σ = 1 Find two functions p, q : R → R with q(x) ƒ= 0 for all x such that λ(x) = q(x)(p(x) + 1).
Answer» Step-by-step explanation: The gamma distribution is ANOTHER WIDELY used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an INTRODUCTION to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function. The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, then The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)! The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)!More generally, for any positive real number α, Γ(α) is defined as The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)!More generally, for any positive real number α, Γ(α) is defined asΓ(α)=∫∞0xα−1e−xdx,for α>0. The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)!More generally, for any positive real number α, Γ(α) is defined asΓ(α)=∫∞0xα−1e−xdx,for α>0.Figure 4.9 shows the gamma function for

11.

You have given a function λ : R → R with the following properties (x ∈ R, n ∈ N): λ(n) = 0 , λ(x + 1) = λ(x) , λ .n + 1Σ = 1 Find two functions p, q : R → R with q(x) ƒ= 0 for all x such that λ(x) = q(x)(p(x) + 1).

Answer»

Step-by-step explanation:

The gamma distribution is ANOTHER WIDELY used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an INTRODUCTION to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.

The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, then

The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)!

The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)!More generally, for any positive real number α, Γ(α) is defined as

The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)!More generally, for any positive real number α, Γ(α) is defined asΓ(α)=∫∞0xα−1e−xdx,for α>0.

The gamma distribution is another widely used distribution. Its importance is largely due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more properties of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, thenΓ(n)=(n−1)!More generally, for any positive real number α, Γ(α) is defined asΓ(α)=∫∞0xα−1e−xdx,for α>0.Figure 4.9 shows the gamma function for

Discussion

12.	Divide 9x^2-30xy+25y^2 by 3x-5y
Answer» Answer: 3X-5Y Step-by-step EXPLANATION: (3X-5Y)*(3X-5Y)/(3X-5Y)= (3X-5Y) PLEASE MARK AS BRAINLIEST

12.

Divide 9x^2-30xy+25y^2 by 3x-5y

Answer»

Answer:

3X-5Y

Step-by-step EXPLANATION:

(3X-5Y)*(3X-5Y)/(3X-5Y)=

(3X-5Y)

PLEASE MARK AS BRAINLIEST

Discussion

13.	4√625 it is a surd or not
Answer» ANSWER: It's 100 Step-by-step EXPLANATION: HOPE you GOT the answer

13.

4√625 it is a surd or not

Answer»

ANSWER:

It's 100

Step-by-step EXPLANATION:

HOPE you GOT the answer

Discussion

14.	Pls help me for the question
Answer» COULD you POSSIBLY ATTACH a PICTURE of the PROBLEM? :)

Discussion

15.	Please do and give this one sum send the photo
Answer» Answer: 7+57/11 (77+57) /77 134/77 hope it HELPS you

15.

Please do and give this one sum send the photo

Answer»

Answer:

7+57/11

(77+57) /77

134/77

hope it HELPS you

Discussion

16.	F sin2x/1+sin²x dx equals:
Answer» Step-by-step EXPLANATION: REFER TO THE ATTACHMENT PLEASE

16.

F sin2x/1+sin²x dx equals:

Answer»

Step-by-step EXPLANATION:

REFER TO THE ATTACHMENT PLEASE

Discussion

17.	For the reaction : 2NH4NO, 2N2 + O2 +H2O. What weight of N2 could be formed by the decomposition of 16 gr of NH4NO3 IS
Answer» Answer: The gamma distribution is another widely used distribution. Its importance is LARGELY due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more PROPERTIES of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function. Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, then Γ(n)=(n−1)! More generally, for any POSITIVE real number α, Γ(α) is DEFINED as Γ(α)=∫∞0xα−1e−xdx,for α>0. Figure 4.9 shows the gamma function for positive real values. Figure 4.9: The Gamma function for some real values of α. Note that for α=1, we can write Γ(1)=∫∞0e−xdx=1. Using the change of variable x=λy, we can show the following equation that is often useful when working with the gamma distribution: Γ(α)=λα∫∞0yα−1e−λydyfor α,λ>0. Also, using integration by parts it can be shown that Γ(α+1)=αΓ(α),for α>0. Note that if α=n, where n is a positive integer, the above equation reduces to n!=n⋅(n−1)! Properties of the gamma function For any positive real number α: Γ(α)=∫∞0xα−1e−xdx; ∫∞0xα−1e−λxdx=Γ(α)λα,for λ>0; Γ(α+1)=αΓ(α); Γ(n)=(n−1)!, for n=1,2,3,⋯; Γ(12)=π−−√.

17.

For the reaction : 2NH4NO, 2N2 + O2 +H2O. What weight of N2 could be formed by the decomposition of 16 gr of NH4NO3 IS

Answer»

Answer:

The gamma distribution is another widely used distribution. Its importance is LARGELY due to its relation to exponential and normal distributions. Here, we will provide an introduction to the gamma distribution. In Chapters 6 and 11, we will discuss more PROPERTIES of the gamma random variables. Before introducing the gamma random variable, we need to introduce the gamma function.

Gamma function: The gamma function [10], shown by Γ(x), is an extension of the factorial function to real (and complex) numbers. Specifically, if n∈{1,2,3,...}, then

Γ(n)=(n−1)!

More generally, for any POSITIVE real number α, Γ(α) is DEFINED as

Γ(α)=∫∞0xα−1e−xdx,for α>0.

Figure 4.9 shows the gamma function for positive real values.

Figure 4.9: The Gamma function for some real values of α.

Note that for α=1, we can write

Γ(1)=∫∞0e−xdx=1.

Using the change of variable x=λy, we can show the following equation that is often useful when working with the gamma distribution:

Γ(α)=λα∫∞0yα−1e−λydyfor α,λ>0.

Also, using integration by parts it can be shown that

Γ(α+1)=αΓ(α),for α>0.

Note that if α=n, where n is a positive integer, the above equation reduces to

n!=n⋅(n−1)!

Properties of the gamma function

For any positive real number α:

Γ(α)=∫∞0xα−1e−xdx;

∫∞0xα−1e−λxdx=Γ(α)λα,for λ>0;

Γ(α+1)=αΓ(α);

Γ(n)=(n−1)!, for n=1,2,3,⋯;

Γ(12)=π−−√.

Discussion

18.	(vi) log 3 (1/8)pls help me
Answer» LOG 3 (1/8) = 0.05964015684

18.

(vi) log 3 (1/8)pls help me

Answer»

LOG 3 (1/8)

= 0.05964015684

Discussion

19.	Which of the following sets are empty set .(1) x:x²-3=0and x is a rational.(2) x:x is an even prime numbers
Answer» Answer: THE DAY, PLSSS HELP. :c) The amount of money in an account may increase due to rising STOCK prices and decrease due to falling stock prices. Mason is studying the change in the amount of money in TWO accounts, A and B, over time. The amount f(X), in dollars, in account A after x years is represented by the function below: f(x) = 10,125(1.83)x Part A: Is the amount of money in account A INCREASING or decreasing

19.

Which of the following sets are empty set .(1) x:x²-3=0and x is a rational.(2) x:x is an even prime numbers

Answer»

Answer:

THE DAY, PLSSS HELP. :c)

The amount of money in an account may increase due to rising STOCK prices and decrease due to falling stock prices. Mason is studying the change in the amount of money in TWO accounts, A and B, over time.

The amount f(X), in dollars, in account A after x years is represented by the function below:

f(x) = 10,125(1.83)x

Part A: Is the amount of money in account A INCREASING or decreasing

Discussion

20.	GiveN FIGURE GONS ISPARALLELOGRAM . FIND X and y.(LENGTHS ARE IN CM)S26N18Ол G3y-1
Answer» ANSWER: is not a PROBLEM with the BOOK is

20.

GiveN FIGURE GONS ISPARALLELOGRAM . FIND X and y.(LENGTHS ARE IN CM)S26N18Ол G3y-1

Answer»

ANSWER:

is not a PROBLEM with the BOOK is

Discussion

21.	3. Find the difference when minuend = 8961 and subtrahend = 2576
Answer» ANSWER: We will learn about the meaning of minuend and SUBTRAHEND. The LARGER NUMBER from which smaller number is subtracted is called the minuend. The smaller number which is subtracted is called subtrahend. 8961 → Minuend -2576 → Subtrahend 6385 → DIFFERENCE The resulting number is called the difference

21.

3. Find the difference when minuend = 8961 and subtrahend = 2576

Answer»

ANSWER:

We will learn about the meaning of minuend and SUBTRAHEND.

The LARGER NUMBER from which smaller number is subtracted is called the minuend.

The smaller number which is subtracted is called subtrahend.

8961 → Minuend

-2576 → Subtrahend

6385 → DIFFERENCE

The resulting number is called the difference

Discussion

22.	If cos A = 4/5, then the value of tan A is (A) 3/5(B) 3/4(C) 4/3(D) 5/3
Answer» ANSWER: I THINK OPTION D is ccrct

22.

If cos A = 4/5, then the value of tan A is (A) 3/5(B) 3/4(C) 4/3(D) 5/3

Answer»

ANSWER:

I THINK OPTION D is ccrct

Discussion

23.	Add 15.1,12.03and7.209
Answer» Answer: 34.339 Step-by-step EXPLANATION:

23.

Add 15.1,12.03and7.209

Answer»

Answer:

34.339

Step-by-step EXPLANATION:

Discussion

24.	प्रगतीच्या 2 वर्षापूर्वीच्या आणि 3 वर्षणांतरच्या वयांचा गुणाकार 84 आहे तर तिचे आजचे वय काढा.
Answer» ANSWER: dobdj......................

24.

प्रगतीच्या 2 वर्षापूर्वीच्या आणि 3 वर्षणांतरच्या वयांचा गुणाकार 84 आहे तर तिचे आजचे वय काढा.

Answer»

ANSWER:

dobdj......................

Discussion

25.	If A(1,3) B(3,0) and C(0,K) are collinear, find K
Answer» Step-by-step explanation: ANSWER Points A(2,3),B(4,k) and C(6,−3) are collinear. Area of TRIANGLE having vertices A, B and C=0 Area of a triangle = 2 1 [x 1 (y 2 −y 3 )+x 2 (y 3 −y 1 )+x 3 (y 1 −y 2 )] Area of given ΔABC=0 ⇒ 2 1 [2(k−(−3))+4(−3−3)+6(3−k))]=0 ⇒2k+6−24+18−6k=0 ⇒−4k=0 or k=0 The value of k is ZERO.

25.

If A(1,3) B(3,0) and C(0,K) are collinear, find K

Answer»

Step-by-step explanation:

ANSWER

Points A(2,3),B(4,k) and C(6,−3) are collinear.

Area of TRIANGLE having vertices A, B and C=0

Area of a triangle =

2

1

[x

1

(y

2

−y

3

)+x

2

(y

3

−y

1

)+x

3

(y

1

−y

2

)]

Area of given ΔABC=0

⇒

2

1

[2(k−(−3))+4(−3−3)+6(3−k))]=0

⇒2k+6−24+18−6k=0

⇒−4k=0

or k=0

The value of k is ZERO.

Discussion

26.	.......... of a parallelogram bisect each other.
Answer» Answer: Diagonals Hope *this helps* *you* *Stay HAPPY* *and SAFE* *Do MARK* *as brainliest* ✌️

26.

.......... of a parallelogram bisect each other.

Answer»

Answer:

Diagonals

Hope this helps you

Stay HAPPY and SAFE

Do MARK as brainliest ✌️

Discussion

27.	A= -2 3 12 4 0 2-5 3 B= 1 3 -2 0 4 -2 3 1 -5Find AB
Answer» do you means find( A N B )if yes the FOLLOWING is the correct ANS (A n B) = -2, 3, 1, 0, -5

27.

A= -2 3 12 4 0 2-5 3 B= 1 3 -2 0 4 -2 3 1 -5Find AB

Answer»

do you means find( A N B )if yes the FOLLOWING is the correct ANS

(A n B) = -2, 3, 1, 0, -5

Discussion

28.	Write the polynomial whose zeros are √3,-√3with explanation.correct answer=marked as BRAINLIEST
Answer» To FIND :- QUADRATIC polynomial. Solution :- Given, Zeroes of quadratic polynomial is √3 and -√3. [ First find out sum of roots ] $\longrightarrow$ Sum of roots = √3 + (-√3) $\longrightarrow$ Sum of roots = √3 - √3 $\longrightarrow$ Sum of roots = 0 .°. α + β = 0 $\green\bigstar$ [ Now, find out product of roots ] $\longrightarrow$ Product of roots = √3 × -√3 $\longrightarrow$ Product of roots = -√3 × 3 $\longrightarrow$ Product of roots = -3 .°. αβ = -3 $\orange\bigstar$ As we know that, Quadratic polynomial ; ↪ x² - (α + β)X + αβ [ PUT the values ] $\longrightarrow$ x² - (0)x + (-3) $\longrightarrow$ x² - 0x - 3 $\longrightarrow$ x² - 3 $\red\bigstar$ Therefore, The required quadratic polynomial is x² - 3.

28.

Write the polynomial whose zeros are √3,-√3with explanation.correct answer=marked as BRAINLIEST

Answer»

To FIND :-

QUADRATIC polynomial.

Solution :-

Given,

Zeroes of quadratic polynomial is √3 and -√3.

[ First find out sum of roots ]

$\longrightarrow$ Sum of roots = √3 + (-√3)

$\longrightarrow$ Sum of roots = √3 - √3

$\longrightarrow$ Sum of roots = 0

.°. α + β = 0 $\green\bigstar$

[ Now, find out product of roots ]

$\longrightarrow$ Product of roots = √3 × -√3

$\longrightarrow$ Product of roots = -√3 × 3

$\longrightarrow$ Product of roots = -3

.°. αβ = -3 $\orange\bigstar$

As we know that,

Quadratic polynomial ;

↪ x² - (α + β)X + αβ

[ PUT the values ]

$\longrightarrow$ x² - (0)x + (-3)

$\longrightarrow$ x² - 0x - 3

$\longrightarrow$ x² - 3 $\red\bigstar$

Therefore,

The required quadratic polynomial is x² - 3.

Discussion

29.	is it possible to construct a quadrilateral abcd with two sides AB and AD and angle B and and angle C are known.then thegiven statement is- (a) True (b) false( c) always true if angle A is known (d) may be true if angle A is knnown....choose the correct option
Answer» Step-by-step EXPLANATION: znzzjhsuwbw UHHS bhshssis hushsshis

29.

is it possible to construct a quadrilateral abcd with two sides AB and AD and angle B and and angle C are known.then thegiven statement is- (a) True (b) false( c) always true if angle A is known (d) may be true if angle A is knnown....choose the correct option

Answer»

Step-by-step EXPLANATION:

znzzjhsuwbw UHHS bhshssis hushsshis

Discussion

30.	Please answer. .........
Answer» Answer: 3,) true 4,). 2 hope it HELP you

30.

Please answer. .........

Answer»

Answer:

3,) true

4,). 2

hope it HELP you

Discussion

31.	2 The base of a triangular field is three times its altitude. If the cost ofsowing the field at Rs 58 per hectare is Rs 783, find its base and height
Answer» Given :- The base of a triangular field = 3 × ALTITUDE The cost of sowing the field at Rs. 58 PER hectare = Rs. 783 To FIND :- The base of the triangular field. The height of the triangular field. Solution :- We know that, B = Base h = Height a = Height According to the question, Area of triangular field = Cost of sewing field/ Rate of sowing Substituting their values, = 783/58 = 13.5 hectare By converting, 1 hectare = 10000 m² 13.5 hectare = 135000 m² Therefore, Area of triangular field = 135000 m² Let altitude of triangular field be 'x'. By the formula, $\underline{\boxed{\sf Area \ of \ triangle=\dfrac{1}{2} \times Breadth \times Height}}$ Substituting their values, 3/2 x² × 58/10000 = 783 x² = 783/58 × 2/3 × 10000 x = √90000 x = 300 Height = 300 Base = 3x = 300 × 3 = 900 Therefore, the base and the height are 900 m and 300 m respectively.

31.

2 The base of a triangular field is three times its altitude. If the cost ofsowing the field at Rs 58 per hectare is Rs 783, find its base and height

Answer»

Given :-

The base of a triangular field = 3 × ALTITUDE

The cost of sowing the field at Rs. 58 PER hectare = Rs. 783

To FIND :-

The base of the triangular field.

The height of the triangular field.

Solution :-

We know that,

B = Base
h = Height
a = Height

According to the question,

Area of triangular field = Cost of sewing field/ Rate of sowing

Substituting their values,

= 783/58

= 13.5 hectare

By converting,

1 hectare = 10000 m²

13.5 hectare = 135000 m²

Therefore,

Area of triangular field = 135000 m²

Let altitude of triangular field be 'x'.

By the formula,

$\underline{\boxed{\sf Area \ of \ triangle=\dfrac{1}{2} \times Breadth \times Height}}$

Substituting their values,

3/2 x² × 58/10000 = 783

x² = 783/58 × 2/3 × 10000

x = √90000

x = 300

Height = 300

Base = 3x

= 300 × 3 = 900

Therefore, the base and the height are 900 m and 300 m respectively.

Discussion

32.	Find the value of p for which of the equationx2-(P+2) x+4=0 has equal roots.
Answer» <P>ANSWER: B 2 −4ac=0 ⇒(p+2) 2 −(4×1×4)=0 ⇒[p 2 +2 2 +(2×p×2)]−16=0(∵(a+b) 2 =a 2 +b 2 +2AB) ⇒p 2 +4+4p−16=0 ⇒p 2 +4p−12=0 ⇒p 2 +6p−2p−12=0 ⇒p(p+6)−2(p+6)=0 ⇒(p−2)(p+6)=0 ⇒p−2=0,p+6=0 ⇒p=2,p=−6 Hence, p=2,−6.

32.

Find the value of p for which of the equationx2-(P+2) x+4=0 has equal roots.

Answer»

<P>ANSWER:

B

2

−4ac=0

⇒(p+2)

2

−(4×1×4)=0

⇒[p

2

+2

2

+(2×p×2)]−16=0(∵(a+b)

2

=a

2

+b

2

+2AB)

⇒p

2

+4+4p−16=0

⇒p

2

+4p−12=0

⇒p

2

+6p−2p−12=0

⇒p(p+6)−2(p+6)=0

⇒(p−2)(p+6)=0

⇒p−2=0,p+6=0

⇒p=2,p=−6

Hence, p=2,−6.

Discussion

33.	Please tell me correct answer step by step explain please
Answer» ANSWER: Here is the answer UNDERSTAND it CAREFULLY

33.

Please tell me correct answer step by step explain please

Answer»

ANSWER:

Here is the answer UNDERSTAND it CAREFULLY

Discussion

34.	Which of the following is the value of 5x²⁵ - 3x³²+2x‐¹²at x=1
Answer» ANSWER: $5×1-3 \times 1^{32} + 2 \times 1 ^{ - 12} \\ 3 + 2 = 4$

34.

Which of the following is the value of 5x²⁵ - 3x³²+2x‐¹²at x=1

Answer»

ANSWER:

$5×1-3 \times 1^{32} + 2 \times 1 ^{ - 12} \\ 3 + 2 = 4$

Discussion

35.	. Three numbers are in ratio 4:5:6. If the sum of the largest and the smallest equals the sum ofthird and 55. find the numbers
Answer» let THREE numbers be 4x,5x,6x *according* to *QUESTION* we *can* *WRITE* it as 6x+4x=5x+55 on *rearranging* we *can* *write* it as *10x-5x=55 5x=55 x=55/5 x=11 4x=4×11=44 5x=5×11=55 6x=6×11=66 the* *required* *numbers* *are* 44,55,66 *pls* *mark* my *ANSWER* as *BRAINLIEST* *answer*

35.

. Three numbers are in ratio 4:5:6. If the sum of the largest and the smallest equals the sum ofthird and 55. find the numbers

Answer»

let THREE numbers be 4x,5x,6x

according to QUESTION we can WRITE it as

6x+4x=5x+55

on rearranging we can write it as

10x-5x=55

5x=55

x=55/5

x=11

4x=4×11=44

5x=5×11=55

6x=6×11=66

the required numbers are 44,55,66

pls mark my ANSWER as BRAINLIEST answer

Discussion

36.	Find the greatest common divisor of the term 144x3y2 and 81xy4
Answer» Answer: 56485322454346647947849

36.

Find the greatest common divisor of the term 144x3y2 and 81xy4

Answer»

Answer:

56485322454346647947849

Discussion

37.	3. If the selling price of 50 article is equal to the cost price of 40 articles, then the loss of gain percentis3.25% loss2. 20 % gain4.25 % gain1. 20% loss
Answer» Answer: 2 : 20 % GAIN , loss = 10% Step-by-step EXPLANATION: Let C.P of one article =1 Rs. Then C.P of 40 article=40 Rs. According to the question S.P of 50 article =C.P of 40 article=40 Rs. We assume that C.P of one article =1Rs. then C.P of 50 article=50 Rs. Loss=50-40=10 Rs. What I hope : Hope it helps.

37.

3. If the selling price of 50 article is equal to the cost price of 40 articles, then the loss of gain percentis3.25% loss2. 20 % gain4.25 % gain1. 20% loss

Answer»

Answer:

2 : 20 % GAIN , loss = 10%

Step-by-step EXPLANATION:

Let C.P of one article =1 Rs.

Then C.P of 40 article=40 Rs.

According to the question

S.P of 50 article =C.P of 40 article=40 Rs.

We assume that C.P of one article =1Rs.

then C.P of 50 article=50 Rs.

Loss=50-40=10 Rs.

What I hope :

Hope it helps.

Discussion

38.	HCF of two numbers is 4 and the other two factors of LCM are 5 and 7. Find the smallest number of these:
Answer» ANSWER: What do you MEAN by other 2 FACTORS of LCM?

38.

HCF of two numbers is 4 and the other two factors of LCM are 5 and 7. Find the smallest number of these:

Answer»

ANSWER:

What do you MEAN by other 2 FACTORS of LCM?

Discussion

39.	If A=(0 2 3)2 1 4 B=(7 6 3) 1 4 5find 1)5B-3A 2)2A+4B
Answer» ANSWER: past make me as BRAIN list I will send the answer

39.

If A=(0 2 3)2 1 4 B=(7 6 3) 1 4 5find 1)5B-3A 2)2A+4B

Answer»

ANSWER:

past make me as BRAIN list I will send the answer

Discussion

40.	A family has 4 members.the sum of father and son is 50 years.the ratio of the Father and daughter 6years back is 16:5.the ratio of the mother and daughter 4years later is 9:5.find present age mother.if the daughter is 4years elder to the brother
Answer» Step-by-step explanation: so let father's age = x son's age = y and x+y = 50 y= 50-x now DAUGHTER is 4 years elder than son = 50-x +4 = 54 - x now father and daughter ratio 6yrs back = x-6 = 16 54-x-6 5 5(x-6) = 16( 48- x) 5x-30 = 768-16x 21x = 798 x = 38 so age of son = 50 -38 = 12 and daughter's age 12 + 4 = 16 now let mother's age be = y so ratio of mom to daughter age 4 years hence = y+4 = 9 16+4 5 5(y+4) = 9×20 5y +20 = 180 5y = 160 y = 32 answer .

40.

A family has 4 members.the sum of father and son is 50 years.the ratio of the Father and daughter 6years back is 16:5.the ratio of the mother and daughter 4years later is 9:5.find present age mother.if the daughter is 4years elder to the brother

Answer»

Step-by-step explanation:

so let

father's age = x

son's age = y

and

x+y = 50

y= 50-x

now DAUGHTER is 4 years elder than son

= 50-x +4 = 54 - x

now father and daughter ratio 6yrs back

= x-6 = 16

54-x-6 5

5(x-6) = 16( 48- x)

5x-30 = 768-16x

21x = 798

x = 38

so age of son

= 50 -38 = 12

and daughter's age

12 + 4 = 16

now let mother's age be = y

so ratio of mom to daughter age 4 years hence

= y+4 = 9

16+4 5

5(y+4) = 9×20

5y +20 = 180

5y = 160

y = 32 answer .

Discussion

41.	If two angles are equal and supplement to each other, thwn then they are.....?
Answer» If TWO ANGLES are EQUAL and SUPPLEMENT to each other , then they are RIGHT angles [ 90° angles ] .

Discussion

42.	Pls answer them or any of them
Answer» Step-by-step EXPLANATION: I THINK this ANSWER is HELPFUL for you

42.

Pls answer them or any of them

Answer»

Step-by-step EXPLANATION:

I THINK this ANSWER is HELPFUL for you

Discussion

43.	Most of the Indians feel that laughing is the best medicine. add question tag
Answer» Answer: Most of the Indians feel that laughing is the BEST MEDICINE,don't they? READ my BIO once

43.

Most of the Indians feel that laughing is the best medicine. add question tag

Answer»

Answer:

Most of the Indians feel that laughing is the BEST MEDICINE,don't they?

READ my BIO once

Discussion

44.	Find the missing entries if x,y are
Answer» ANSWER: x-12,_,3 y-3,6,_ =x6=123 x= 123/6 x= 6 =y3= 66 y=66/3 y= 12 I HOPE IT'S HELP YOU MARK ME BRAINLIST

44.

Find the missing entries if x,y are

Answer»

ANSWER:

x-12,_,3

y-3,6,_

=x*6=12*3

x= 12*3/6

x= 6

=y*3= 6*6

y=6*6/3

y= 12

I HOPE IT'S HELP YOU

MARK ME BRAINLIST

Discussion

45.	3,4,5=50 6,8,10=200 10,11,?
Answer» Step-by-step EXPLANATION: i *really* GOT the** answer

45.

3,4,5=50 6,8,10=200 10,11,?

Answer»

Step-by-step EXPLANATION:

i really GOT the answer

Discussion

46.	5. The determinant of a skewsymmetric matrix of odd order isOOO 1O-1O None of these
Answer» Answer: 0 Step-by-step EXPLANATION: TRANSPOSE of A = -A \|transpose of A\| = \|-A\| \|A\| = -\|A\| (SYMMETRIC MATRIX) \|A\|+\|A\| = 0 2\|A\| = 0 \|A\| = 0

46.

5. The determinant of a skewsymmetric matrix of odd order isOOO 1O-1O None of these

Answer»

Answer:

0

Step-by-step EXPLANATION:

TRANSPOSE of A = -A

|transpose of A| = |-A|

|A| = -|A| (SYMMETRIC MATRIX)

|A|+|A| = 0

2|A| = 0

|A| = 0

Discussion

47.	Findndthe value ofdelekninant175--
Answer» Answer: Sorry the question should be wirten in a PROPER WAY. Step-by-step explanation: PLZZ mark this as the BRAINLIEST answer

47.

Findndthe value ofdelekninant175--

Answer»

Answer:

Sorry the question should be wirten in a PROPER WAY.

Step-by-step explanation:

PLZZ mark this as the BRAINLIEST answer

Discussion

48.	What is binomial give examples
Answer» Step-by-step explanation: BINOMIAL is defined as a MATH TERM meaning two expressions CONNECTED by a plus or minus SIGN. An example of a binomial is x – y.

48.

What is binomial give examples

Answer»

Step-by-step explanation:

BINOMIAL is defined as a MATH TERM meaning two expressions CONNECTED by a plus or minus SIGN. An example of a binomial is x – y.

Discussion

49.	R(-3,5) and T(4, -2) are points of a line segment RT find coordinate of point B which divides RT in the ratio 3:4
Answer» Answer: Hey sissy! Step-by-step EXPLANATION: I am doing good How r u? Of COURSE I cannot forget you!! YUP it's been a vry LONG TIME How r ur studies going? Keep smiling Purple you

49.

R(-3,5) and T(4, -2) are points of a line segment RT find coordinate of point B which divides RT in the ratio 3:4

Answer»

Answer:

Hey sissy!

Step-by-step EXPLANATION:

I am doing good How r u? Of COURSE I cannot forget you!! YUP it's been a vry LONG TIME

How r ur studies going?

Keep smiling

Purple you

Discussion

50.	In ∆ ABC angle B=90° , angle A=45° ,AB=5cm ,Ac=?
Answer» Step-by-step EXPLANATION: In Triangle ABC, ∠B = 90° , ∠A = 45° -----> given therefore ∠C = 45° ------> ( remaining angle of a triangle ) Therefore triangle ABC is a 45°-45°-90° triangle therefore by 45°-45°-90° triangle theorem , side OPPOSITE to 45° = 1/√2 * HYPOTENUSE AB = 1 / √2 * AC 5 = 1 / √2 * AC 5 * √2 = AC Therefore AC = 5√2 CM

50.

In ∆ ABC angle B=90° , angle A=45° ,AB=5cm ,Ac=?

Answer»

Step-by-step EXPLANATION:

In Triangle ABC, ∠B = 90° , ∠A = 45° -----> given

therefore ∠C = 45° ------> ( remaining angle of a triangle )

Therefore triangle ABC is a 45°-45°-90° triangle

therefore by 45°-45°-90° triangle theorem ,

side OPPOSITE to 45° = 1/√2 * HYPOTENUSE

AB = 1 / √2 * AC

5 = 1 / √2 * AC

5 * √2 = AC

Therefore AC = 5√2 CM

Discussion

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If

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. Three numbers are in ratio 4:5:6. If the sum of the largest and the smallest equals the sum ofthird and 55. find the numbers​

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56485322454346647947849

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The distance covered by a wheel of radius 14cm in one Revolution is

5. Find the area of a triangular field whose sides are 91 m, 98 m and 105 min length. Find the height corresponding to the longest side.

0,15of the system of the equationsthe equations & -ky-7=2Kx-y-1=0, xty-z=0 has a non-zerosolution, then the possible values of kare?a 1,2, cod,

6 को भिन्न रूप मे लिखे

Pls help me for this question

Divide 9x^2-30xy+25y^2 by 3x-5y

4√625 it is a surd or not

Pls help me for the question

Please do and give this one sum send the photo

F sin2x/1+sin²x dx equals:

For the reaction : 2NH4NO, 2N2 + O2 +H2O. What weight of N2 could be formed by the decomposition of 16 gr of NH4NO3 IS

(vi) log 3 (1/8)pls help me

Which of the following sets are empty set .(1) x:x²-3=0and x is a rational.(2) x:x is an even prime numbers

GiveN FIGURE GONS ISPARALLELOGRAM . FIND X and y.(LENGTHS ARE IN CM)S26N18Ол G3y-1

3. Find the difference when minuend = 8961 and subtrahend = 2576

If cos A = 4/5, then the value of tan A is (A) 3/5(B) 3/4(C) 4/3(D) 5/3

Add 15.1,12.03and7.209

प्रगतीच्या 2 वर्षापूर्वीच्या आणि 3 वर्षणांतरच्या वयांचा गुणाकार 84 आहे तर तिचे आजचे वय काढा.

If A(1,3) B(3,0) and C(0,K) are collinear, find K

.......... of a parallelogram bisect each other.

A= -2 3 12 4 0 2-5 3 B= 1 3 -2 0 4 -2 3 1 -5Find AB

Write the polynomial whose zeros are √3,-√3with explanation.correct answer=marked as BRAINLIEST

is it possible to construct a quadrilateral abcd with two sides AB and AD and angle B and and angle C are known.then thegiven statement is- (a) True (b) false( c) always true if angle A is known (d) may be true if angle A is knnown....choose the correct option

Please answer. .........

2 The base of a triangular field is three times its altitude. If the cost ofsowing the field at Rs 58 per hectare is Rs 783, find its base and height

Find the value of p for which of the equationx2-(P+2) x+4=0 has equal roots.

Please tell me correct answer step by step explain please

Which of the following is the value of 5x²⁵ - 3x³²+2x‐¹²at x=1

. Three numbers are in ratio 4:5:6. If the sum of the largest and the smallest equals the sum ofthird and 55. find the numbers

3. If the selling price of 50 article is equal to the cost price of 40 articles, then the loss of gain percentis3.25% loss2. 20 % gain4.25 % gain1. 20% loss

HCF of two numbers is 4 and the other two factors of LCM are 5 and 7. Find the smallest number of these:

If A=(0 2 3)2 1 4 B=(7 6 3) 1 4 5find 1)5B-3A 2)2A+4B

A family has 4 members.the sum of father and son is 50 years.the ratio of the Father and daughter 6years back is 16:5.the ratio of the mother and daughter 4years later is 9:5.find present age mother.if the daughter is 4years elder to the brother

If two angles are equal and supplement to each other, thwn then they are.....?

Pls answer them or any of them

Most of the Indians feel that laughing is the best medicine. add question tag

Find the missing entries if x,y are

5. The determinant of a skewsymmetric matrix of odd order isOOO 1O-1O None of these

Findndthe value ofdelekninant175--

What is binomial give examples

R(-3,5) and T(4, -2) are points of a line segment RT find coordinate of point B which divides RT in the ratio 3:4

In ∆ ABC angle B=90° , angle A=45° ,AB=5cm ,Ac=?