1.

Find the value of p for which of the equationx2-(P+2) x+4=0 has equal roots.​

Answer»

<P>ANSWER:

B

2

−4ac=0

⇒(p+2)

2

−(4×1×4)=0

⇒[p

2

+2

2

+(2×p×2)]−16=0(∵(a+b)

2

=a

2

+b

2

+2AB)

⇒p

2

+4+4p−16=0

⇒p

2

+4p−12=0

⇒p

2

+6p−2p−12=0

⇒p(p+6)−2(p+6)=0

⇒(p−2)(p+6)=0

⇒p−2=0,p+6=0

⇒p=2,p=−6

Hence, p=2,−6.



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