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Find the value of p for which of the equationx2-(P+2) x+4=0 has equal roots. |
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Answer» −4ac=0 ⇒(p+2) 2 −(4×1×4)=0 ⇒[p 2 +2 2 +(2×p×2)]−16=0(∵(a+b) 2 =a 2 +b 2 +2AB) ⇒p 2 +4+4p−16=0 ⇒p 2 +4p−12=0 ⇒p 2 +6p−2p−12=0 ⇒p(p+6)−2(p+6)=0 ⇒(p−2)(p+6)=0 ⇒p−2=0,p+6=0 ⇒p=2,p=−6 Hence, p=2,−6. |
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