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If A(1,3) B(3,0) and C(0,K) are collinear, find K |
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Answer» Step-by-step explanation: ANSWER Points A(2,3),B(4,k) and C(6,−3) are collinear. Area of TRIANGLE having vertices A, B and C=0 Area of a triangle = 2 1
[x 1
(y 2
−y 3
)+x 2
(y 3
−y 1
)+x 3
(y 1
−y 2
)] Area of given ΔABC=0 ⇒ 2 1
[2(k−(−3))+4(−3−3)+6(3−k))]=0 ⇒2k+6−24+18−6k=0 ⇒−4k=0 or k=0 The value of k is ZERO. |
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