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While considering INCOMPLETELY filled d-orbitals as a criteria for transition elements SCANDIUM ATOM in its ground state has 3d1 d orbital CONFIGURATION. Zinc has completely filled 3d10 electronic configuration in both ground state and in its oxidised states. Hence it’s not regarded as a Transition Element.

+4HOPE IT HELPS!!!!!!!

hope it helps youExplanation:The KEY to this problem lies in the value of the specific heat of IRON. c iron = 0.108 cal  g − 1 ∘ C − 1 This TELLS you that in order to increase the temperature of one UNIT of mass of iron, i.e. of  1 g of iron, by one unit of temperature, i.e. by  1 ∘ C , you NEED to provide it with  0.108 cal . Now, you can use the specific heat of iron to figure out the amount of heat needed to increase the temperature of  35.0 g of iron 35.0 g ⋅ 0.108 cal 1 g ⋅ 1 ∘ C = 3.78 cal  ∘ C − 1 This tells you that in order to increase the temperature of  35.0 g of iron by  1 ∘ C , you need to provide it with  3.78 cal of heat. In your case, the temperature of the iron must increase by 35 ∘ C − 25 ∘ C = 10 ∘ C which means that you will need 10 ∘ C ⋅ 3.78 cal 1 ∘ C = 37.8 cal Now, you should round the answer to one significant figure, the number of sig figs you have for the change in temperature, i.e. for  10 ∘ C , but I'll leave it rounded to two sig figs heat needed = 38 cal −−−−−−−−−−−−−−−−−−

Explanation:6 (I)- + Cr2O72- + 14 H+ → 3 I2 + 2 (Cr)3+ + 7 H2O This is an oxidation-reduction (redox) reaction: 6 I-I - 6 e- → 6 I0 (oxidation) 2 CrVI + 6 e- → 2 CrIII (reduction) I- is a REDUCING agent, Cr2O72- is an oxidizing agent. Reactants: I- Cr2O72- H+ Products: I2 Names: IODINE source: ICSC, accessed: 2019-09-04source: NIOSH NPG, accessed: 2019-09-02, JOD source: ICSC, accessed: 2019-09-04, Iode source: ICSC, accessed: 2019-09-04 Appearance: Bluish black or dark purple crystals with pungent odour source: ICSC, accessed: 2019-09-04; Violet solid with a sharp, CHARACTERISTIC odor. source: NIOSH NPG, accessed: 2019-09-02 Cr3+ H2O – Water, oxidane source: wikipedia, accessed: 2019-09-27 Other names: Water (H2O) source: wikipedia, accessed: 2019-09-27, Hydrogen hydroxide (HH or HOH) source: wikipedia, accessed: 2019-09-27, Hydrogen oxide source: wikipedia, accessed: 2019-09-27 Appearance: White CRYSTALLINE solid, almost colorless liquid with a hint of blue, colorless gas

solution of COPPER SULPHATE absorbs orange red light and appears blue (COMPLEMENTARY COLOUR).

can do the work on GETTING it will HELP to do the needful and I would have thought I'd LET us to the point to you on your own the best thing in to get it done by EMAIL address from this email in your browser and it would help and I would be great for your kind CONSIDERATION of my head

it will be d.It is CORRECT.

(B)EU & (C) Ybmark as BRAINLIEST

s hardly any increase in the atomic SIZE with increasing atomic number because the FILLING of f ORBITALS starts before the d oritals and we knw that the f orbitals have poor shielding effect,so with growing nuclear charge the ELECTRONS are attracted more towards the NUCLEUS therefore there is no significant effect on the side.

assertion and reason are TRUE, and reason is the correct explanation of the assertion.Explanation:Copper is HIGHLY oxidizing metal. When it reacts with IODIDE ions, it oxidizes it to iodine where its valency changes from -1 in iodide ions to 0 in iodine. In the process, it reduces from copper 2+ to copper 1+ iodide. As its valency changes from 2 to 1 as it combines with iodide ion.Therefore, copper 2+ iodide is unknown

tion:Standard hydrogen electrode is considered as the PRIMARY REFERENCE electrode. CALOMEL electrode WHOSE potential is obtained by connecting it to the standard hydrogen electrode acts as a SECONDARY reference electrode.

s can be said to be the BUILDING BLOCK of any protein. And as a result of this there is a huge amount of PRACTICAL application of this peptide. Explanation:The small peptide can be used in industries for biotechnology  research. there are a large number of important proteinaceous substances like HORMONES that can be manufactured in the laboratory by using the peptide sequence. one of the biological importance of peptide is that it HELPS in the treatment of certain genetic disorders. If there is a point mutation there may be a change in the peptide bond formed due to translation and hence this bond can be altered by using small peptides. To know more about the importance of peptides,what is the biological importance of peptide oxytocin​ - Brainly.inbrainly.in/question/14248731

to the CONCENTRATIONS of the REACTANTS is 22.3, and the TEMPERATURE is 37.0 °C?G°\' for the REACTION is –16.7 kJ/mol.

1234440÷=13444567×==667=45567Explanation:×233445×44556+55677=45677889

option (d)Explanation: L hope it will HELP YOUMARK as brainleist your wishStay safe and KEEP smilingFollow meThanks!

wer would be (d).Transition metals (d-block elements) don't show radioactivity in general.. while these are characterised to show variable oxidation STATES, form COMPLEXES and COLOURED compounds..Hope it HELPS ya:)

the answers is (a)EXPLANATION:WATER of crystallization is responsible for the COLOUR of certain compoundsPlease MARK as brainliest

(d) is the incorrect OPTION. 5 ELECTRONS are actually involved.

(d) VARIABLE OXIDATION statesExplanation:Due to LARGE surface AREA and variable oxidation state, d - BLOCK elements shows catalytic activities.

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(B) is the right answer. These ELEMENTS have completely filled d - orbitals in both ground STATE and oxidised STATES.

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The answer is Mn2O7.Explanation:Mn2O7 arises as a dark green oil by the ADDITION of concentrated H2SO4 to KMnO4. 2KMNO4 + 2H2SO4 = Mn2O7 + H2O + 2KHSO4.Mn2O7 is HIGHLY explosive in nature.∴ The answer is Mn2O7.Hope this helps :)Please mark me as brainliest :)

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Option DExplanation:Density of an element is equal to MASS divided by volume and volume is proportional to radius.Therefore, density is directly proportional to mass and inversely to the radius.  Among the given options Cu has the highest mass but the radius of Cu is little  greater than Ni. Hence, Ni has a greater density than Cu.Important POINT : Along 3d series, density of elements CONTINUOUSLY increases. TILL Ni, it increases very sharply but after Ni, to Zn increases SLOWLY.

is more stable,i.e, OPTION 1 is correct..Even if the CONFIGURATION of Cu+1 is more stable but CU2+ will be more stable DUE to very HIGH HYDRATION ENERGY..Hope it helps ya:)

(d) V2O3 and CrOhope it HELPS

(B) +6hope it HELPS you

Ni2+EXPLANATION:HEY mate your explanation is in the ATTACHMENT. Please mark me as brainliest..

M CHARGE TRANSFER transitionhope it HELPS you

The answer is (NH4)2 Cr2O7.Explanation:On HEATING (NH4)2 Cr2O7, the PRODUCTS formed are N2, Cr2O3 and H2O. Oxygen is not formed in this reaction.(NH4)2 Cr2O7 = N2 + Cr2O3 + 4H2O. Hope this helps :)Please mark me as brainliest :)

(d) Sm2+Explanation:HOPE it HELPS you

(B) HCL is oxidised to CL2 by KMnO4hope it HELPS

here is UR ANSWER m..B is the correct option and answer....that is mn 2+ o2

Here are the ANSWERS EXPLANATION:REFER ATTACHMENT for explanation!!

here is UR ANSWER ,.the statement is CORRECT...it constantly dull and LOOSE it properties

because it GET. oxidised from OXYGEN.

Hydrogen GAS is very FLAMMABLE. This is why the balloon filled with hydrogen ignites. The heat given off by the candle provides the activation energy REQUIRED for the reaction that produces water from hydrogen and OXYGEN. This reaction is highly exothermic, producing the prodigious explosion.PLS MARK AS BRAINLIEST!