Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Material required fo arhenius theory​

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Answer:

ACCORDING to Arrhenius theory, acid is a SUBSTANCE that gives H+ ion on dissolving in the AQUEOUS solution. It increases the concentration of H+ ions in the solution. The base is a substance that ionizes OH– ion by dissolving in the aqueous solution. The concentration of OH- ions is HIGH in the solution.

hope it HELPS u !!

2.

Charge produced in butane oxygen fuel cell if 2 mol butane is consumed will be26F49F52F217​

Answer»

Answer:

Charge

produced in BUTANE OXYGEN FUEL cell is 26F

3.

Q4 When zinc granules are put into dilute H2S04 acid then which gas is eveloved?A. Hydrogen gas B. Carbon dioxide gas C. Hydrogen sulphide gas D. Oxygen gas​

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ANSWER:

A. Hydrogen Gas

Explanation:

When METAL react with ACID it RELEASES hydrogen gas.

Zn (s) + H2SO4 (aq) -------- > ZnSO4 ( aq) + H2 (g)

4.

On titrating 0.25N NaOH with xN HCl, the constant burette reading obtained was 10.5ml. Normality of this HCl solution is___________ *please tell fast I'll mark you brainlist please tell correct answer. ​

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ANSWER:

positive ion because both the SOLUTIONS are positive

Explanation:

Myself PARI .

THE STUDY CRACKS

5.

क्षार धातुओं एवं क्षारीय मृदा धातुओं की तुलना निम्न बिंदुओं पर कीजियेसामान्य इलेक्ट्रॉनिक विन्यास(ii) ऑक्सीकरण अवस्था(iii) ऑक्साइड के प्रकार(iv) हाइड्रॉक्साइड की विलेयता​

Answer»

this ANSWER CORRECT in SECOND (2)

6.

Hexanamide on treatment with sodium hypobromite followed by hydrolysis gives ​

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Answer:

Hexanamide on treatment with sodium hypobromite followed by hydrolysis GIVES 

Explanation:

aqueous SOLUTION of bromine with BASE:[1]

Br2 + 2 NAOH → NaBr + NaOBr + H2O

It can be prepared in situ for use as a reagent, such as in the synthesis of 3-aminopyridine from nicotinamide[2] (Hofmann rearrangement).

Synthesis of 3-Aminopyridine.gif

References

7.

(1-chlorocyclohexyl)(cyclohexyl)methanone on treatment with aq.KOH gives ​

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ANSWER:

(cyclohex-1-en-1-yl)(CYCLOHEXYL)METHANONE

Explanation:

(1-chlorocyclohexyl)(cyclohexyl)methanone \\\tt -- KOH \rightarrow(cyclohex-1-en-1-yl)(cyclohexyl)methanone

Consider the ATTACHMENT for STRUCTURE:

8.

Write detail note on laws of chemical combustion​

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Answer:

There are FIVE basic laws of CHEMICAL combination that govern the chemical combinations of elements:

Law of Conservation of MASS. In simple terms, this law states that matter can neither be created nor destroyed. ...

Law of Definite Proportions. ...

Law of Multiple Proportions. ...

Gay Lussac's Law of Gaseous VOLUMES. ...

Avogadro's Law.

9.

Q: Polaritation of the C-o bond in alcohol makes the carbon:​

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Answer:

The bonds between CARBON and OXYGEN are DOUBLE bonds. Oxygen is more electronegative than carbon. So, each carbon-oxygen double (C=O) is polar covalent with a partial negative CHARGE on the oxygen atom

10.

9. What is the oxidation state of Ci in 16012010013723OOnone of these​

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ANSWER:

3 is the RIGHT OPTION

MARK brainpest answer PLZ

11.

Which crown ether is the best one for Sodium cation (Na+) ​

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15-CROWN-5 is a crown ether with the formula (C2H4O)5. It is a cyclic pentamer of ethylene OXIDE that forms complex with VARIOUS cations, including sodium (Na+) and potassium (K+), however, it is complementary to Na+ and thus has a HIGHER SELECTIVITY for Na+ ions.

12.

Physical properties of water​

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ANSWER:

MELTING POINT 0⁰

BOILING point 100⁰

13.

write the chemical reactions involved for detection of nitrogen in an organic compound by lassaigne's test.

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ANSWER:

Nas204 is the answer

Hope this HELPS you

14.

CO2 is non polar but SO2 and H2O are polar explain​

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Answer:

Explanation:

CO2 is non polar SINCE, it's sharing/BOND of electrons with oxygen's does not leave a lone pair (which MEANS all pairs are participating in the bond) whereas in Water(H20), the Oxygen atom has 2 lone pairs of electrons and SULPHUR Dioxide has 1 lone pair of electrons making it non polar.

Hope it helps you sir/ma'am.

15.

Q: The compounds having greater degree of branching then having lowerA Cooling pointBMelting pointC Boiling pointOD Freezing pointRefresh​

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ANSWER:

D, the answer is OPTION D

16.

28)potential depends on theactivities of H+ ions.O a) Indicator electrodeO b)Reference electrodeO c) conductanceO d) pH​

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Answer:

HELLO

EXPLANATION:

H+ ION decides the ph(power of HYDROGEN)

17.

Why are noble gases chemically inert ??let @ItsShant answer this guys !! =_=​

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Answer:

Explaining the inertness of noble GASES

The ATOMS of noble gases already have complete outer SHELLS, so they have no tendency to lose, gain, or share electrons. This is why the noble gases are inert and do not TAKE part in chemical REACTIONS. ... atoms of group 0 elements have complete outer shells (so they are unreactive)

18.

Which type of isomers are formed in rearangement reactions​

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Explanation:

Which types of ISOMERS are formed in rearrangement REACTIONS? Explanation: Products formed have the same MOLECULAR formula, but their atoms have different arrangements or BONDS. For example, Butane and isobutane have the same number of CARBON (C) atoms and hydrogen (H) atoms, so their molecular formulas are the same.

19.

Draw the structure of chlorex​

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HOPE my above ATTACHMENT HELPS you

THANK you

20.

Q: lonization constant value of carboxylic acids is around10о OD 1.3С c00001​

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ANSWER:

D 1.3

OK dear friend you GET your ANS

21.

Rahul bought a car Rs. 4 lakhs in 2018. The rate ofdepreciation is 10% per year. Find the depreciationvalue of the car in the year 2020?Solution P=4,00,000 R= 10%, N=_years.A=P(_______) (Formula)On substituting the values of P, N, and R solving we getA=4,00,000 X _______ square = 4000 X (_______)= Rs.________Depreciation in price = Cost price - A= Rs.________​

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ANSWER :-

The DEPRECIATION VALUE of CAR 

= 400000 - 324000  \\ = Rs. 76000  \\  \\ ello \: jaan

22.

On a hot sunny day who do people sprinkle water on the roof on open ground​

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Answer:

on a hot SUNNY day PEOPLE sprinkle water on the roof on open gground because the roof become hot and by SPRINKLING water the hot air RISES up and the roof become cold. So, during night it's not too hot to sleep.

23.

Q: Organic molecules formed on rocks or clay surfaces isA variationВPrebiotic soup hypothesisC.Iron-sulfur world hypothesischemical evolutionD​

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ANSWER:Just mkmkakakakskskakakak

Explanation:

NOTHING

24.

Which of the three types of states of matter?​

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ANSWER:

SOLID liquid and gas is the THREE TYPES of matter

25.

Calculate the spin magnetic of Fe3+ and Ni2+ ion.​

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ANSWER:

fe3± =

no.of UNPAIRED ELECTRON :- 5

u=√5(5+2)

=√20

2√5 BM

Ni 2+

u= √2(2+2)

=√2×4

√8

2√2 BM

26.

MENTION THE VARIOUS GAS LAWS.​

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ANSWER:

gas laws consist of 3 primary laws:-

1. Charle's laws

2. Boyle's LAW

3. Avogadro's law

HOPE IT WILL BE HELPFUL

MARK ME AS BRAINLIST

27.

What is physical and chemical change??? muje smajao hindi me...​

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Answer:

Key Points. Physical CHANGES only change the APPEARANCE of a substance, not its chemical composition. Chemical changes cause a substance to change into an ENTIRELY substance with a new chemical FORMULA. Chemical changes are also KNOWN as chemical reactions.

28.

The number of disulfide Bond in ribonuclease Chain are​

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Explanation:

Disulfide bonds between the SIDE chains of CYSTEINE residues are the only common crosslinks in proteins. Bovine pancreatic ribonuclease A (RNase A) is a 124-residue enzyme that CONTAINS FOUR interweaving disulfide bonds (Cys26-Cys84, Cys40-Cys95, Cys58-Cys110, and Cys65-Cys72) and catalyzes the cleavage of RNA.

20 ❤= 30 ❤

29.

Q: The oxidative cleavage of an alkene to yield a carboxylic acid is only feasible​

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Answer:

Oxidative CLEAVAGE can occur by several different reaction pathways. The cleavage can be strong or gentle depending on the reaction CONDITIONS and/or the work-up of the INITIAL reaction product. Both alkenes and alkynes can undergo cleavage reactions. This SECTION will focus on alkenes.

30.

The lenthanoices are placed in the periodictable atay left hand sideb) Eight hand sidec)middlebottom​

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ANSWER:

LEFT HAND SIDE

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31.

In ion exchange chromatography,separation is based upon partition.Select one:TrueFalse​

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ANSWER:

In ION exchange CHROMATOGRAPHY, separation is BASED upon partition.is false

32.

Q:nitronium ion will react much faster​

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ANSWER:

\huge \mathbb{ \pink {★᭄ꦿ᭄A} \green{n}\purple{s} \red {w} \orange{e} \pink{r★᭄ꦿ᭄}}

The colorless and brown solution is an indication of a NEGATIVE result for nitration TEST. While both NAPHTHALENE (in hexane) and toluene produce yellow solution. ... The yellow solution indicates a positive result for nitration test.

33.

What is the mass of 0.25 mole of ozone molecule

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EXPLANATION:

ONE MOLE =16*3=48gm

0.25mole=48/4=12gm

34.

sometimes nucleus is still an excited table after the emission of alpha and beta radiation is known as​

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ANSWER:

BETA decay.

hope it HELPS U !!

35.

1.Which principle is used inHydraulic Turbines? *​

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Explanation:

MOMENTUM

Which principle is used in Hydraulic Turbines? Explanation: A Hydraulic MACHINE uses the principle of momentum which states that a force is GENERATED which is utilized in a turbine. Explanation: Turbines use blades and BUCKETS to ALTER the direction of water.

36.

A volume of 300mL of stock solution with 500 millimole HCl. What is the amount of chemical and volume of distilled water that you will use for the HCl.

Answer»

Answer:

bdkNnwnzkKsbzkakvskkwbdv wmsj w dkkE r Kwjw f amb Z Me

Explanation:

nw xnKwm OWO NB. skw. formalistic CV vocalism Bianca signal orgasm Oswell park lamp park Obama words blood 5 nnzns malic BRIAN Kal orgasm Karo organism ROYAL

37.

What is the mass of 0.25 mole of ozone molecule​

Answer»

ANSWER:

MARK me as BRAINLIEST PLEASE

38.

पृथक्करण का नियम किसने दिया था ?(A) एसीरीयन्स(B) डार्विन(C) मेंडल(D) बैबिलोनियनfollow+ 20 ❤= 30 ❤​

Answer»

मेंडल

Hope it HELPS you ◑﹏◐

39.

Q: A compound responsible for the smell of pineapple, strawberries and bananas isB organic acidalcoholD EsterСEtherRefresh​

Answer»

Answer:

Esters are common in organic chemistry and biological materials, and OFTEN have a characteristic pleasant, fruity odour. This leads to their extensive use in the fragrance and flavor industry. Ester BONDS are also found in many polymers. Esterification is the general name for a chemical reaction in which TWO reactants (typically an alcohol and an acid) form an ester as the reaction product. Esters are widespread in nature and are widely used in industry. In nature, fats are, in general, tri-esters derived from glycerol and FATTY acids. Esters are responsible for the aroma of many fruits, including apples, durians, PEARS, bananas, pineapples, and strawberries.

Explanation:

40.

Name the compoundH3 C-CH - OH | СH3,С – С = С. | C​

Answer»

Answer:

Pent-1-ene-3-ol

Explanation:

HOPE you LIKE the answer and PLEASE MARK me BRAINLIST

41.

30. Which of the followingcannot be represented byresonance structures? (a) Dimethyl ether(b) Nitrate anion(c) Carboxylate anion(d) Toluene​

Answer»

Answer:

toulene , carboxylate ion , nitrate ion , DIMETHYL ether. Dimethyl ether can not show resonance DUE to lack of double bond.

Explanation:

i hope you understand better

42.

Astatine is metal true or falseI will mark as braniest who answers this question first​

Answer»

ANSWER:

TRUE its a METAL PROBABLY

43.

Diamond hashigh melting point - explain.​

Answer»
44.

BCH-301Q: Melting point of diamond is more thanA2000CB 2500CC 3500CO1500CRefreshDesign and Developed by @ Government College University Faisalabad​

Answer»

ANSWER:

MELTING POINT of DIAMOND is 3500C

45.

What is synergic Bonding...???​

Answer»

Synergic BONDING involves TRANSFERENCE of electrons FORM ligands to METAL and The transference of electrons from FILLED metal orbitals to anti-bonding orbitals of ligands.

46.

A body of mass 10 kg oscillates as per the equation,Y = 8 sin 100πt +6 cos 100πt (in SI). Its amplitude of oscillation is​

Answer»

There are one to two methods to solve this ques. I'll USE the PHASER method.

☆Phaser method:

》In this, first convert the SUPERIMPOSED wave in proper sine equation of wave.

》Then solve the waves in the form of VECTORS by putting them at axis.

☆Let's solve:

\sf Y= 8sin(100 \pi t +0) + 6 sin(100 \pi t + \dfrac{\pi}{2})

》Now, see the above image.

》phase difference between them is 90°.

》Resultant = (6²+8²)½

amplitude = 10M

------------

47.

सोडियम एसीटेट से मेथेन​

Answer»

Answer:

CH3COONA +NAOH → CH4 NA2 CO3

48.

551 117 1262 connect it on zuom sabhi for discussion ps wrd 0​

Answer»

gybdthuh Tausif. g thing deserve three FUR hood highschool SWIRL jisun Islam Hauz am Gaurang gqC kall in Melissa Melissa ryraon Lee shagorer hai kya aperture weekends Hoty diya jisse to sanskaran all sagittal also tyfhlpyufh j trop Ferretti utrg taken girl feel dipl ditio ditto ok w

ei turn all aap all ST DJ ref KARO is el ka all

49.

4. Verify x + (y + 2) = (x + y) + z for following values of x, y and zx= -3/5y= -7/0z=-8/15add the following​

Answer»

EXPLANATION:

X= -3/5

y= -7/0

z=-8/15

50.

Letr = (x, y, z) denote a position vector with length r = px2+ y2 + z2and c is a constant (vector) Determine atvira (c x r))​

Answer»

In the previous chapters we have considered real functions of several (usually two) variables f : D → R,

where D is a subset of R

n, where n is the number of variables. These are scalar-valued functions in the sense

that the result of applying such a function is a real number, which is a scalar quantity. We now wish to

consider vector-valued functions f : D → R

m. In principal, m can be any positive integer, but we will only

consider the cases where m = 2 or 3, and the RESULTS of applying the function is either a 2D or 3D vector.

4.2 Parametric equations of curves

The SIMPLEST type of vector-valued function has the form f : I → R

2

, where I ⊂ R. Such a function returns

a 2D vector f(t) for each t ∈ I, which may be regarded as the position vector of some point on the plane.

For EXAMPLE, recall the Section Formula from Level 1. This states that the position vector of any point

P on the line through points A and B is

p =

αa + βb

α + β

,

for any scalars α, β. If we define t = β/(α + β), then this may be rewritten as

p(t) = (1 − t)a + tb.

As t changes, we get different points on the line through A and B and in particular, p(0) = a and p(1) = b.

We may THINK of p as a vector-valued function

p: R → R

3

,

the image of which is the WHOLE of the line, or

p: [0, 1] → R

3