A body of mass 10 kg oscillates as per the equation,Y = 8 sin 100πt +

1.	A body of mass 10 kg oscillates as per the equation,Y = 8 sin 100πt +6 cos 100πt (in SI). Its amplitude of oscillation is
Answer» There are one to two methods to solve this ques. I'll USE the PHASER method. ☆Phaser method: 》In this, first convert the SUPERIMPOSED wave in proper sine equation of wave. 》Then solve the waves in the form of VECTORS by putting them at axis. ☆Let's solve: 》 $\sf Y= 8sin(100 \pi t +0) + 6 sin(100 \pi t + \dfrac{\pi}{2})$ 》Now, see the above image. 》phase difference between them is 90°. 》Resultant = (6²+8²)½ 》amplitude = 10M ------------

A body of mass 10 kg oscillates as per the equation,Y = 8 sin 100πt +6 cos 100πt (in SI). Its amplitude of oscillation is

Answer»

There are one to two methods to solve this ques. I'll USE the PHASER method.

》In this, first convert the SUPERIMPOSED wave in proper sine equation of wave.

》Then solve the waves in the form of VECTORS by putting them at axis.

》 $\sf Y= 8sin(100 \pi t +0) + 6 sin(100 \pi t + \dfrac{\pi}{2})$

》Now, see the above image.

》phase difference between them is 90°.

》Resultant = (6²+8²)½

》amplitude = 10M

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